Picture 4. 1 The chart bar of students pre-test result from the control class
Picture 4. 2 The chart bar of students pre-test result from experiment class
B. The Homogeneity Test
Homogeneity test on a research is aimed at analyzing the variable of the research. This test will reveal whether the variables of the research has the same
variants. The homogeneity test in this research is done to know whether the control and
the experiment class have a same ability in reading skill before being given any treatment. To know the classes‟ homogeneity, the writer uses the classes‟ pretest
result and analyze it using the SPSS program. The result of this analysis is shown on the table below.
Table 4.3 Group Statistics
Class N
Mean Std. Deviation Std. Error
Mean Pre-test
Score The Control Class
35 47.37
10.120 1.711
The Experiment Class
35 52.54
10.845 1.833
Table 4.4 The Homogeneity Test Result
F
From the table 4.3 above, it is found that the mean of the pre-test result from the control class is 47.37 and mean from the experiment class is 54.60. Being
analyzed, it is revealed that the Levene’s Test for Equality of Variances are F=0.962
and Sig.=0.330. It is known that the Sig. value is higher than Significance Level 0,05. It can be assumed that the classes the control and experiment class have
similarity level of reading before they are given the treatment.
Levenes Test for Equality of Variances F
Sig.
Pre-test score Equal variances
assumed .962
.330 Equal variances not
assumed
C. The Normality Test
The normality test is aimed at analyzing whether the sample distribution of the research comes from a normal population distribution. The Normality test is a
prerequisite of a hypothesis test. There are four ways in conducting a normality test, which are: Lilliefors Test,
Kolmogorov-Smirnov Test, Chi-Square Test, and Q-Q Plot Test. The writer chooses the Kolmogorov-Smirnov Test as the participant of the research are bigger than 30.
The result of the Normality Test using Kolmogorov-Smirnov Test are shown below.
Table 4.5 One-Sample Kolmogorov-Smirnov Test on Pretest Data
Pretest Experiment
Pretest Control
N 35
35 Normal Parameters
a,b
Mean 52.54
47.37 Std.
Deviation 10.845
10.120 Most Extreme
Differences Absolute
.132 .124
Positive .098
.124 Negative
-.132 -.090
Kolmogorov-Smirnov Z .784
.732 Asymp. Sig. 2-tailed
.571 .658
a. Test distribution is Normal. b. Calculated from data.
According to the table above, it can be seen that the Sig.Significant value of the test is 0.571 for the experiment class and 0.658 for the control class. Then,
compared with the value of α, which is 0.05, it can be assumed that 0.5710.05 and
0.658 0.05. Thus, the conclusion of the test is that Ho for the control class is accepted and the pretest data on the control and experiment class has a normal
distribution.
Table 4.6 One-Sample Kolmogorov-Smirnov Test on Post-test Data
Post Test Experiment
Post Test Control
N 35
35 Normal Parameters
a,b
Mean 62.86
54.60 Std.
Deviation 9.879
11.561 Most Extreme
Differences Absolute
.108 .132
Positive .063
.132 Negative
-.108 -.109
Kolmogorov-Smirnov Z .639
.780 Asymp. Sig. 2-tailed
.809 .577
a. Test distribution is Normal. b. Calculated from data.
From the table 4.6, it can be seen that the Sig.Significant value of the test is 0.809 on the experiment class and 0.577 on the control class. Then, compared with
the value of α, which is 0.05, it can be assumed that 0.809 0.05 and 0.5770.05.
Thus, the conclusion of the test is that Ho for the experiment class is accepted and the experiment class and the control class on the post-test has a normal distribution
D. The Hypothesis Test
To answer the question: 1.
Is there any significance difference on students‟ reading comprehension achievement after they are taught by using Think-Aloud?
2. Does Think-Aloud enhance the awareness of students toward their reading strategy
The writer analyzes the data obtained from the reading test‟ result pre and post-test, and the data obtained from the questionnaire to answer the question above.
Thus, the analyzing data in this section is divided in two, which are reading test data analysis to answer question number 1 and questionnaire analysis to answer
question number 2.
