UJIAN MASUK BERSAMA

  • =

  4

  2 A # $ $ $ " " $ # 2 A B A = +

  = − A B

  7

  12

  3

  4

  6

  8

  2

  10

  4

  16

  4

  6

  3

  4

  7

  12

  4

  6

  10

  1

  3

  ! "# " # $ # % & " " " ' $ " " () 2 2

  3 2 2

  2 ) ) 1 ( ( a ax x a x f

  5 ) 1 ( = f =

  ) ( f

  ! " # $ % $

  = + = +

  10

  2

  3

  28

  2

  y x y x & '

  =

  6

  6

  2

  6

  3

  6

  5

  6

  6

  (

  16

  • 1

  2 3 = '

  8 2 = + −

  x x

  6

  5 2 = + −

  x x

  6

  2 2 = + −

  x x !

  " q p

  1 " 2 # $ $ 3 $ $ $ # # $ # !

  x x

  3 # " % $ , #

  4

  15

  8

  27

  2

  9

  8

  9

  8

  16

  13 2 = + −

  7

  8

  a

  = 27 log 16 = 2 log 2

  3 8a

  3 4a

  2

  a a

  4

  3

  a

  3

  36

  ) $ % $* $ $ %$ $

  2

  6 2 = + −

  x x % $ $ $ $* $ mn n m

  1 + n m

  mn 1 1

  ) ( #

  72

  17 2 = + −

  x x

  • # * % , * - , $ % $ $ . $ % - , / -

  x + 1 x 1 x 1 x + +

  = = + = + +

  a ( x

  1 ) b ( x 1 ) x a ( + x 1 )

  4 $

  > >

  a b c

  > >

  b a c

  > >

  a c b

  > >

  b c a

  > >

  c b a 2 +

  • = = +

  1

  m

  1 n

  1 $* $ $ % $ $ x #

  5 x

  3 − − 1 m

  1 n

  9 −

  2

  4 −

  9

  3 −

  5

  4

  9

  5

  9 xx 1

  % $

  7

  3

  7 4 # ≥

  • − ⋅ <

  x

  − < < 7 x <

  x

  1 < 1 < x

  7 <

  x

  ≤ ≤ ≥ ≥

  5 $ z = 2 x y , # x + y

  3 xy 1 x y

  • # ! ) ( "

  7

  6

  " % $ 2 5 #

  • − <

  − −

  x

  1 x

  1

  3 < − − < < >

  x

  1 x 1 x

  2

  5

  3 < − − < < >

  x

  2 x 1 x

  2

  5

  3 < − < > 1 < x

  1

  2

  x x

  5

  3 < − − < < >

  x

  1 x 1 x

  3

  5 < − >

  x

  1 x

  2

  ( $ % $

  • =

  y ax

  1

  • =

  y bx

  2 =

  y cx

  • % , #
  •   3

    • =

      a c

      2 b =

    • =

      a b

      2 c

      b c

      2 a

    • =

      a b c

      2 − + =

      a b c

      2 ∆ = = =

      6 ABC 3 a

      2 7 b 4 c

      6

      1

      2

      1

      2

      2

      1

      3

      2

      1

      2

      3

      1

      3

      3 2 − 1 tan x

      ) sin x = k 2

    • 1 tan x
    • 2 1 k 1 2 k 2

        1

        k 2

        1 2 k

        ! ABC A

      • ∠ = ∠ = ∆

        2 C AC

        50 ABC #

        3 3 )

      • 25 (

        4 3 )

      • 25 (

        5 3 )

      • 25 (

        6 3 )

      • 25 (

        7 3 )

      • 25 (

        2

        − =

        2 f (x ) #

        2 f ( x ) f ( 1 x ) x $ f (x )

      • 7

        1 2

        3

        1

        x x

        2

        2

        2

        1 2

        8

        1 −

        x x

      • 9

        9

        3

        2 2

        1

        1

        x x

        3

        2

        3

        1 2

        2

        1

        x x

        3

        3

        3

        1 2

        4 −

        x + x

        9

        9

        1

        1

        1 = − + =

        f ( x ) 2 1 f ' ( )

        2

        x x " !

        " 2

      • x

        3 =

        1 y $ , # . $8

        −

        x

        1 < − >

        x

        1 x

        3 > < −

        x

        1 x

        3 − < < − 3 x

        1 − < < 3 x

        1 − < < 1 x 4

        3 − 4 t

      • = lim

        4 t

        72

        " t 2 2

        − + + ( t 2 )( t 3 t 2 )

        11

        4

        11

        3

        "" ((

        " ) )

        < x

        1 ) ( 2

        ( 1 ) −

        = x x g % $ )( 1 ) ( <

        x g f #

        1 <

        x

        2

        1 ≤

        1 >

        9 ) $ , ! + # $ $ $ - !

        x

        2 ≥

        x

        1 <

        x

        2 ≥

        x ")

        3 2 = x 4 3 = y 5 4 = z = +1

        2 xyz

        ) ( " " x x x x f

        "(

        " # % $ ) % , - 3 #

        3

        216

        5

        32

        1 216

        15

        10

        1

        18

        "" + $ 3 $ ") " $ , ( % $ , , #

        1

        100

        77

        33

        20

        25

        3

        33

        2

        75

      • − =