soal matematika dasar snmptn 2008 101 Tahun 2008

  www.onlineschools.name − 4 3 2 3 − 3 2 2 6 x x = a b y = ab = 4 y 4 ab 3 4 ab a ab 4 b ab 4 ab b 2 3

  1 3 3 y = log 2 x ⋅ log + x = log 5 = 3 y 2 log

  10 log 2

  5 5 2 log

  5 log 5

  2 2 log

  2 2 2 2

  xpx p = , p > x + x = 1 2

  • ! " "

  48

  # $ % & 2 4 4 $ " " ' ( x px q x x x x 2 + + + = = 1 2 1 2 pq ( q

  3 p ) 2

  • pq ( q

  3 p ) − 2

  pq (

  3 qp ) 2 3 q p )

  • pq (
  • 2 3
  • pq ( 2 p )

  www.onlineschools.name 2

  4 xx + ! ++

  • + + ) ! ++ , y =

  ' + + + %

  1

  2

  1

  6

  • % ' , ' ' , , ! +
  • . . + ! . ). ' + ! + >

    + , ' )) - ' ! ! + ! , , ' + '

    # - ' ) ) 2 ' ' ! 3
  • / 1% , 4 - 5 55 555 ( $
  • 5 ! 55 !

  • ' ! 3 $

  3 ' %

  1 x

  2 xx

  2

  ( )( ) & ≤

  1 '

  6,

  • x

  1

  x

  1 1 x

  9 < − − < ≤

  1

  9

  xx

  1 ≤ x

  9 − 1 < x

  9

  x

  9

  1

  1 3 '

  6, + x + x <

  7 ≤ x <

  1

  9

  7

  x

  1 <

  9

  7 1 x

  1 − ≤ <

  9

  7 1 x

  1 − ≤ ≤

  9

  7 ≤ x

  1

  9

  www.onlineschools.name

  7

  3 x + z = 2 y ! ' ! x + y ≥ 3 , 3 xy ≤ 9 ,

  • 3 xy

  5 ≥ − 15 , x ≥ , y ≥ '

  %

  1 ) /

  • ! # $ % # ) 8 8 8 #

  6 $1 / ) )

  $/ $& 9

  • , ! # # #

  6 /9 /9 )9 $9 ) &9

  1

  • x y x a

  1 x b -

  8 # A = , B =

  2 , C = , =

  • 1 x-y b a

  − 2 y

  3

  1 /

  3 - - 2 x a

  5 3 a

  2

  $ = = " 8 ! #

  1 1 y b 4 - 2 b

  8

  $ ) %

) , , + α , β ,

  ∆ ABCBAC = ∠ABC =

  3

  • sin( α β ) = # ) #

  5

  % & 1 )

  • , ' + + '

  −

  : $ :

  1

  2

  3 ) (

  − =

  x x f

  1

  3

  3 ) )( o (

  x x x g f = − )

  1

  1 (x g

  x x

  1 + 1 + x

  x

  1 + −

  x x

  1 −

  x x x x

  1 −

  3 ' : ) : ) :

  6

  www.onlineschools.name

  2

  % θ ' θ θ

  2 sin

  2 2 cos

  1 2 = + = θ tan

  3

  3

  1

  3

  3

  

/ ! ! + + + + ! + + % / &

' ) ) $ %

  8

  $ & + + ,+ + + + ,+ -

  8

  1

  8

  2

  8

  3

  8

  4

  • ( ! 3 ' ' - ' + - ( ! 3 )
    • ' + + - ( ! 3 3 - ' + - ' ! 3
      • =

  www.onlineschools.name

  3 x

  2

  2 − − lim x 2 = 2 x

  4

  3

  8

  3

  4

  1

  1

  2

  2

  f ( x ) = ; + ; $ ' < $ # 3 2 2

  ( x 2 x ) −

  1

  4

  1

  12

  1

  24

  1 −

  2

  1 −

  4

  1 3

  1 2

  • ) ! # " 8 = f ( x ) = x xx + 1 , + ++

  2

  2

  8 # > >

  1

  5 sin π cos π 2 3 4

  d d d d

  6

  6

  $ d = + + + + det

  ... =

  7

  5

  5 25 125 625 π π cos sin

  6

  6

  1 −

  2

  1 −

  9

  1 −

  11

  1

  3

  1

  2

  www.onlineschools.name

  3 2 2

  2 x + - 3 x

  = = 1 2 2 x

  • ) " " ' ( det x x
  • 5 2x

  7

  1

  10

  4

  1

  14

  4

  1

  18

  4

  1

  24

  4

  1

  28

  4