soal matematika dasar snmptn 2009 kode 185 jogjastudent.com
www.onlineschools.name
!
""
() (
# $% #'
$
-
1−
4 4
+
=0
x x2
*
"( *
(*
+
"* ,("( *
.% "
+ %*
2
x2
1
2
2
1
2
1
4
y = −1
y =1
1
f (x ) = 1 −
x
1
f (x ) = x −
x
1
f (x ) = 2
x +1
1
f (x ) = 2
x
1
f (x ) =
x
!
%
%
1
5
3
10
2
5
5
10
3
5
"
$"
#
! $"
#
#
$"
$"
"
$ $ &
$
$
www.onlineschools.name
"
#
#
#"
"
%
%
$
$
$
#
%
(
$
$
' $
"
%
#
%
%
$
*
%
#
#
)
$
#
$
)
*)
+
+*
,
*
-
(
#
..
#
(
#
#
$
#
#
(
$
#
(
$
#
)
).
*)
*.
,
)
/
A=
2 0
0 3
$
1
0
1
!
"
#
3b
2
2b
3
+
#
"
#
2
&
#
!
#
#
%
#
#
#
&
*).
* .
* .
*..
,.
,
3
2
$ %
" #" $
*)
$
$
" #"
!.
.
,
!+ *
$
2
$
$
!)
!+
#
www.onlineschools.name
4
$
#
2
5
x ≥0
$
$
#5
6 #
2#
$
$
#
5
$
#
#
#
x2 ≥ 0
x2 > 0
x>0
x2 < 0
x≠0
. $
#
"
"
(
%
(
$ % "S n = n 2 +
$ 7
"
#
$
$
#
( & $ "
$
$
8
8
!
#
f (x ) = x 2
g (x ) = x 3
f (x ) = x 3
g (x ) =
f ( x ) = cos(πx )
1
# x ∈ [0,1]
f ( x) ≤ g (x )
$
$
x
g (x ) = sin (πx )
f (x ) = x
g (x ) = x 2
f (x ) = x 2
g (x ) = x
#
...
..,
#
$
#
$
"" $
..,
%
$
"" #
$
$
%
""
..
#
#
...
P + 3Q
4
3P + Q
4
2 P + 2Q
4
P P PQ
Q PQ
!
4x − 5 < 5
9
4 x < 10
4x − 5 < 5
4x − 5 > 5
0 < 5 − 4x < 5
0 < 4 x < 10
!
www.onlineschools.name
(x, y ) = (2,1)
ax + by = 1
cx + dy = 2
#
$
2a + 4b = 2c + d
a+b = c+d
4a + 2b = 2c + d
2a + 4b = c + 2d
4a + 2b = c + d
* -
(
"
"
( & $
(
*
*
!.
!
!*
&
(
* "
#
#
, "
$
. "
%
&
!
""
() (
# $% #'
$
-
1−
4 4
+
=0
x x2
*
"( *
(*
+
"* ,("( *
.% "
+ %*
2
x2
1
2
2
1
2
1
4
y = −1
y =1
1
f (x ) = 1 −
x
1
f (x ) = x −
x
1
f (x ) = 2
x +1
1
f (x ) = 2
x
1
f (x ) =
x
!
%
%
1
5
3
10
2
5
5
10
3
5
"
$"
#
! $"
#
#
$"
$"
"
$ $ &
$
$
www.onlineschools.name
"
#
#
#"
"
%
%
$
$
$
#
%
(
$
$
' $
"
%
#
%
%
$
*
%
#
#
)
$
#
$
)
*)
+
+*
,
*
-
(
#
..
#
(
#
#
$
#
#
(
$
#
(
$
#
)
).
*)
*.
,
)
/
A=
2 0
0 3
$
1
0
1
!
"
#
3b
2
2b
3
+
#
"
#
2
&
#
!
#
#
%
#
#
#
&
*).
* .
* .
*..
,.
,
3
2
$ %
" #" $
*)
$
$
" #"
!.
.
,
!+ *
$
2
$
$
!)
!+
#
www.onlineschools.name
4
$
#
2
5
x ≥0
$
$
#5
6 #
2#
$
$
#
5
$
#
#
#
x2 ≥ 0
x2 > 0
x>0
x2 < 0
x≠0
. $
#
"
"
(
%
(
$ % "S n = n 2 +
$ 7
"
#
$
$
#
( & $ "
$
$
8
8
!
#
f (x ) = x 2
g (x ) = x 3
f (x ) = x 3
g (x ) =
f ( x ) = cos(πx )
1
# x ∈ [0,1]
f ( x) ≤ g (x )
$
$
x
g (x ) = sin (πx )
f (x ) = x
g (x ) = x 2
f (x ) = x 2
g (x ) = x
#
...
..,
#
$
#
$
"" $
..,
%
$
"" #
$
$
%
""
..
#
#
...
P + 3Q
4
3P + Q
4
2 P + 2Q
4
P P PQ
Q PQ
!
4x − 5 < 5
9
4 x < 10
4x − 5 < 5
4x − 5 > 5
0 < 5 − 4x < 5
0 < 4 x < 10
!
www.onlineschools.name
(x, y ) = (2,1)
ax + by = 1
cx + dy = 2
#
$
2a + 4b = 2c + d
a+b = c+d
4a + 2b = 2c + d
2a + 4b = c + 2d
4a + 2b = c + d
* -
(
"
"
( & $
(
*
*
!.
!
!*
&
(
* "
#
#
, "
$
. "
%
&