Data analysis Findings Spreading Activation Network Model as a Tactic in Writing Task for 10th grade Students of Don Bosco Senior High School, Semarang - Diponegoro University | Institutional Repository (UNDIP-IR)

using the Spreading Activation Network Model, for class B, they did the post- test based on what they know. After they have finished doing it, he gave the scores, and made comparison from these two classes’ score to find which one was better, the one using the spreading activation network model or not

3.6 Data analysis

For the students in Don Bosco Senior High School, Semarang, most of the students feels that writing is one of the problems. They think it is hard to create the idea of the title, and also deliberate it into the form of writing. It happens because they think it is hard to find the correct theme that connects perfectly with the title. To complete this article, the researcher compared two classes, one class used the spreading activation network model, and the other one did not. After that the researcher teaches about the spreading activation network for the class which used it in their writing task. In the end, the researcher received two results of their writing test. With these two results, from the class who used the spreading activation network model and the class who did not use it, the researcher compared the scores, to find out which one has the better mean score. For this part, the researcher used Scoring rubrics by Brown and t-Test. Scoring rubric is used to scoring the students’ writing result of the pre-test and post test for each class, meanwhile T-test is to calculate the mean score of each class, which class is 54 better. Based on Mustafid’s book 2003, “statistika elementer” page 83, T- test formula is: Before we use the T-test, we have to find the v first. V formula is: t is used to find which class who has the best mean point, before we do that we must find the v. 55 CHAPTER 4 FINDINGS AND DISCUSSION This chapter the results of pretest and post-test, the analysis and the calculation result of the comparison between class A and class B pretest and post- test result, to find the mean score, which class is better

4.1 Findings

In a way to know the score for each student, the researcher used two tests, the pre-test and the post test. The subjects were divided into two classes, the class that used the spreading activation network model and the class that did not use the spreading activation network model. In doing the research, the researcher had a role as a teacher too, he also gave help to the students who did not understand, for example, translated the 56 Indonesian word into English. The researcher gave a task for all of the students, a writing task. In doing the task, he gave the students 15 minutes to finish the task; he also gave no boundaries for the students to choose their ideas. The sum of meeting for each class was same, for class that used the spreading activation network model, which was class A, contains 3 meetings. Meanwhile for the class that did not use the spreading activation network, which is class B, contain 3 meetings also. The difference was only in the second meeting. For class A, he explained their mistakes in the pretest and taught the Spreading Activation Network Model, for class B, he only explained their mistakes. After he had the tests from every class, the researcher gave score based on the rubric scoring by Douglas Brown. In Douglas Brown’s scoring rubric the score is between 1-20, because the KTSP’s scoring standard maximum is 10, so he divided the Douglas Brown’s scoring rubric into two. For example: if the student gets 18 in Douglas Brown’s rubric scoring, the score he uses will be 9. a First meeting: Pretest result The researcher gave the pre test to know how far the students of both classes knew about writing and their writing skill. In this first meeting, most of the students had problems in writing, especially to find the right vocabularies. The students who had 5 and 6 dominated the students’ score list 57 b Second Meeting For this meeting, the researcher differentiated for each class. For class A, The researcher explained their mistakes in pretest, and also taught the Spreading Activation Network Model. The first model that was used by the researcher was the Spreading Activation Network Model made by Collins and Loftus 1975 Diagram 1: 58 Animal Bird Insect Airplane Can fly Has engine Breathe s Aardvark Canary The researcher explained the model. Animal node is divided into several nodes; they are insect, canary, bird, aardvark, and canary. Animal also breathes, that’s why there is node of breath. Canary and bird is related, because canary is one of kinds of bird, that’s why node canary and bird is connected. Bird also breathes same like animal. Airplane model is made based on bird body, which is why they are connected. Airplane can fly, so can bird, their nodes are connected. In order to fly, an airplane has to have an engine, their nodes are connected. The researcher also give another model, because, he taught the model made by Collins and Loftus was hard for them. Diagram 2: ────────── Teacher ↑ Don Bosco Father ↑ ↑ Student Me Family→Mother→Lecturer ↓ Brother ↓ College Boy UNDIP ↓ English Faculty ────── By making a simpler model, the researcher had helped the students to understand how to use the Spreading Activation Network Model. The researcher explained the model. There is a family of 4, father mother, brother and me. Father works as a teacher. He teaches in Don Bosco 59 Senior High School. Mother works as a lecturer. He lectures in UNDIP. Brother is a college boy, he studies in English Faculty of UNDIP. Me, is a student. He studies in Don Bosco Senior High School. Meanwhile, for class B, the researcher only explained their mistakes they had made in the pretest. He emphasized that in making writing task, from first paragraph until the last paragraph must be connected. c Third meeting: Post-test result The researcher gave the post-test to know were there any improvement from both classes. For class A, they did the writing task with full of confident. They did not ask. Most of them finished it before the time was up. They managed to make their own model, although still a simple form. Their writing result also showed an improvement, they have made a good writing result. For class B, they finished the writing task in a nick of time. They still have a hard time in finishing the task. Below are the lists of scores for class A and class B 60 Table 1: Class that used Spreading Activation Network Model Name Score Pre-Test Final Test 1. Bella C. 2. Cahya 3. Ryan 4. Doma 5. Bagus 6. Rebecca 7. Anastasia 8. Bella B. 9. Margaretha 10. Apfel 11. Adamas 12. Ralisna 13. Nidya 14. Mega 15. Nyoman 16. Igansius 17. Stefi 18. Mitza 19. Florentina 20. Fernando 21. Silvia 22. Andreas 23. Fx. Enrico 24. Yudha 25. Gresilia 26. M. Bagie 27. Sangwiku 28. Bastian 29. Desy 6 5 5 5 6 6 6.5 6 6 6 6 6 7 7 7 6.5 6 5 5 5 6 6 6 6 5.5 5 6 6 6 6.5 5 4.5 6 5 7 7 6.5 6.5 6 6.5 6.5 7.5 7.5 7.5 7 6.5 6 5 6 6.5 6.5 4.5 3 6.5 5 6 7 6.5 61 30. Yulianto 5 6.5 TOTAL 175.5 184 The tabel above was the table for class A, experimental class. In the pre-test, Nidya, Mega and Nyoman’s score was the highest. They got 7 for the pre-test. Meanwhile for the final test, Nidya, Mega and Nyoman’s score was also the highest. They improved their score by 0.5. The total score for pre-test was 175.5. By adding all of the score from the students, the researcher got the total score. The total score for final test was 184. 62 Table 2: Class that did not use Spreading Activation Network Model Name Score Pre-Test Final Test 1. Gemma 2. Febrina 3. Boby 4. Felicitas 5. Ayub 6. Dominicus 7. Gregorius 8. Dita 9. Julius 10. Cozmos 11. Vinsensius 12. Anastasya 13. Bondan 14. Laurensius 15. Eduardus 16. Alpinta 17. Stefanus 18. Dersyanto 19. Dwiki 20. Heronimus 21. Damanika 22. Maria 23. Valentina 24. Hayyu 25. Della 26. Sondhy 27. Christine 28. Andreas 29. Dionisius 6.5 6 6.5 6 6.5 6 6 6 5.5 5.5 5.5 6 6 5.5 5.5 6 6 5.5 5 6 6 6 6.5 6 6 6.5 7.5 7.5 6 6.5 6 6.5 6 6.5 6.5 6 6 6 6 5.5 5.5 4.5 6 6 5 6 6 6 6 6 6 6.5 6.5 6 6.5 7.5 7.5 6 63 TOTAL 175.5 177 The tabel above was the table score list for class B, controlled class. In the pre-test, Christine and Andreas’ score was the highest. They got 7.5 for the pre-test. Meanwhile for the final test, By adding all of the score from the students, the researcher got the total score. The total score for final test was 177. Again, by adding all of the score from the students, the researcher got the total score. Christine and Andreas’ score was also the highest. But they did not improve at all, the score was still 7.5. Based on the pretest score from both classes, it can be stated that they still had difficulties in doing the writing task. The researcher still found most of them did not finish the writing. It happened because they still confused on the vocabularies, what were the right words that related with their ideas. From the post –test result from class A, there were a significant improvement with the scores. With the help of the Spreading Activation Network Model, they could finish their writing and gained a better score, although there were still a few students who did not make an improvement. Based on the researcher’s point of view, this happened because, these students were too confident with their writing, they did not check their writing result again when there was still more time. For class B, they did not make any improvement; most of the students’ scores were decreasing. This happened because they still had a hard time to finish their writing. 64 By using these scores, he used t-test in finding which class that has the bigger mean score. But before that, he has to find the change from the pre test’s score to the post test’s score for each class. Table 3: Case Processing Summary 29 100,0 ,0 29 100,0 30 100,0 ,0 30 100,0 kategori WITHOUT SANM WITH SANM perubahan N Percent N Percent N Percent Valid Missing Total Cases Based on the table, the sum of the sample N for class B without SANM was 29, there was no missing score. So was for class A with SANM, the sum of the sample N was 30, there was no missing score. Missing score means that all of the students have their scores for pretest and post-test. Table 4: 65 Descriptives ,2586 ,07286 ,1094 ,4079 ,2126 ,0000 ,154 ,39235 ,00 1,50 1,50 ,50 1,606 ,434 2,415 ,845 ,6833 ,10850 ,4614 ,9052 ,6204 ,5000 ,353 ,59427 ,00 3,00 3,00 ,50 2,123 ,427 7,162 ,833 Mean Lower Bound Upper Bound 95 Confidence Interval for Mean 5 Trimmed Mean Median Variance Std. Deviation Minimum Maximum Range Interquartile Range Skewness Kurtosis Mean Lower Bound Upper Bound 95 Confidence Interval for Mean 5 Trimmed Mean Median Variance Std. Deviation Minimum Maximum Range Interquartile Range Skewness Kurtosis kategori WITHOUT SANM WITH SANM perubahan Statistic Std. Error Based on the data’s description, mean score for class B without SANM was 0.258, the median score was 0.000, the minimum score was 0.00 and the maximum score was 1.50. Meanwhile, the mean score for class A with SANM was 0.6833, the median score was 0.500, the minimum score was 0.00, and the maximum score was 3.00. It can be concluded that the data 66 for class A with SANM had a higher mean score than the data for class B without SANM. Table 5: Tests of Normality ,366 29 ,000 ,690 29 ,000 ,288 30 ,000 ,761 30 ,000 kategori WITHOUT SANM WITH SANM perubahan Statistic df Sig. Statistic df Sig. Kolmogorov-Smirnov a Shapiro-Wilk Lilliefors Significance Correction a. The table above was the normality test for knowing the data distribution, the result for the sig. point for class B without SANM was 0.000 0.05 5 and the sig point for class A with SANM was 0.000 0.05 5. It can be concluded that the data distribution for class B without SANM and class A with SANM was not normal because the sig point was smaller than 0.05 Table 6: 67 kategori WITH SANM WITHOUT SANM p er u b ah an 3.00 2.50 2.00 1.50 1.00 0.50 0.00 53 13 The graph above was boxplot for normality test. From the picture we saw that there was a score outside the boxplot, 13 for class B without SANM and 53 for class A with SANM. It showed that the data had an abnormal distribution to support the previous test. The statistic test for an abnormal distribution data which the sample was free and only two categories, the researcher used Mann Whitney test. NPar Tests 68 Mann-Whitney Test Table 7: Ranks 29 22,59 655,00 30 37,17 1115,00 59 kategori WITHOUT SANM WITH SANM Total perubahan N Mean Rank Sum of Ranks Based on the data above, the mean rank for class A data with SANM was 37.17. Meanwhile, for class B data without SANM was 22.59. The mean rank for class A data was higher than the mean rank for class B. Table 8: Test Statistics a 220,000 655,000 -3,479 ,001 Mann-Whitney U Wilcoxon W Z Asymp. Sig. 2-tailed perubahan Grouping Variable: kategori a.

4.2 Discussion