IEEE 802.16 de Preamble Signal

TELKOMNIKA ISSN: 1693-6930  The Most Possible Scheme of Joint Service Detection for the Next… Hendra Setiawan 157 , , , , … , 6 2 3 where is downlink bandwidth configuration, and is resource block size in the frequency domain. Resource elements k, l for n = −5,−4, · · · ,−1, 62, 63, · · · , 66 are reserved and not used for transmission of the primary synchronization signal. Furthermore, we can derive time domain signal by mapping only primary synchronization signal based on Eq.2 and Eq.3in 2048 point IFFT as shown in Figure2. Figure 1. Primary synchronization signals of LTE in frequency domain P-SCH detection in LTE is not easy because of the frequency domain term. Moreover, the spectrum flexibility in LTE makes P-SCH detection more complex. However, P-SCH is transmitted only in the central part of the overall transmission band of the cell, i.e. the constant bandwidth of 1.25 MHz, regardless of the overall transmission bandwidth of the cell [20]. Therefore, we should focus on some sub carriers around the central of bandwidth to detect P- SCH.

2.2. IEEE 802.16 de Preamble Signal

There are four types of PHY Layer mentioned in IEEE802.16 standard; wireless MAN single carrier, wireless MAN single carrier access, wireless MAN OFDM, and wireless MAN OFDMA [30]. In this paper, we discuss the OFDM and OFDMA schemes only. u = 25 u = 29 u = 34 Real part Imaginary part  ISSN: 1693-6930 TELKOMNIKA Vol. 11, No. 1, March 2013 : 155 – 166 158 Figure 2. Primary synchronization signals of LTE in time domain 2.2.1. OFDM Scheme In this scheme, preamble always exists in the start of a packet. Therefore, preamble becomes the most effective signal in term of service recognition. As mentioned in [21],the frequency domain sequences for all full bandwidth preambles in OFDM mode are derived from the sequence: , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , 4 where A = 1 + j; B = -1 + j; C = -1 –j; D = 1 –j. Preamble in OFDM mode consists of two consecutive OFDM symbols with4 MHz sampling rate. The first symbol in time domain has four repetitions of 64-sample fragment denoted P 4×64 preceded by a cyclic prefix CP. The frequency domain sequence for P 4x64 is defined by: TELK samp The p 2.2.2 define where numb rate. define FFT s boost prope Figu KOMNIKA The Mos The sec plefragment d preamble sig . OFDMA Sc In OFDM ed by allocat e PreambleC ber of the pre Each seg Each of dif ed in[21]. Th schemes wh tedBPSK mo erty [22] i.e. s ure 4. An exa t Possible Sc √ ∙ √ ∙ ond symbol denoted P EVE √ ∙ gnals generat Figure cheme MA scheme, tion of differe CarrierSet n sp eamble carrie gment uses fferentFFT s his means th en performin odulation, th symmetry fo ample of 802 IS cheme of Joi l in time d EN . In frequen ted based on e 3. Preambl there are ent subcarrie pecifies all su er-set indexe one type of sizes has 11 e receiver sh ng preamble erefore, the r I-part and a 2.16 OFDMA SSN: 1693-69 int Service D domain is c ncy domain it n Eq.4, 5, e signal of IE three types ers for each o ubcarriers al ed 0,1,2, and preamble ou 14 different hould consid detection. H output sam anti-symmetr A preamble fo 930 Detection for composed o t is defined b and 6 are EEE 802.16 of preambl one of them a llocated to th d k is a runnin ut of the thre pseudo num der 456 pream However, pre ples satisfy ry for Q-part or index = 43 the Next… of two repet by: given in Figu OFDM le carrier se and express he specific p ng index0,1, ee sets in 22 mber PN s mble pattern ambles are m complex co as shown in 3, IDcell= 13,  Hendra Setia titions of a ure 3. ets[21], thos ed as preamble, n …567. 2.4 MHz sam series patter ns for four dif modulated u njugate sym Figure 4. and segmen awan 159 5 128- 6 se are 7 is the mpling rns as fferent sing a mmetry n = 1 TELK 160

2.3. I