Research Findings

B. Research Findings

1. Testing Assumptions

a) Testing Normality

Table 4.12. Testing Normality

One-Sample Kolmogorov-Smirnov Test

Extroversion_X Speaking_Y

N 82 82

Normal Parameters a,b Mean

6,13278 Most Extreme Differences

Std. Deviation

-,109 Kolmogorov-Smirnov Z

Negative

,989 Asymp. Sig. (2-tailed)

,282 a. Test distribution is Normal.

b. Calculated from data.

Based on the calculation using SPSS 18.0, the asymptotic significance normality of Extroversion was 0.423. Then, the normality was consulted with the table of Kolmogorov-Smirnov with the level significance of Extroversion = 0.423

< α= 0.05 it could be concluded that the data was normal distribution. And the asymptotic significance normality of Speaking Ability was 0.282. Then, the normality was consulted with the table of Kolmogorov-Smirnov with the level significance of Speaking Ability = 0.282 ≥ α= 0.05 it could be concluded that the data was normal distribution.

b) Homogenity Test

Table 4.13 Test of Homogeneity of Variances

Speaking_Y Levene Statistic

Based on the output of SPSS above it is known that the value of variable significance of Speaking Ability (Y) based on the variable Extroversion (X) = 0.123>0.05, means that the variable data Speaking Ability (Y) based on the variable Extroversion (X) has homogenity.

Figure 4.4 The Chart of Scatterplot

2. Testing Hypotheses

To measure the difference between extrovert and introvert students‟ speaking score the independent sample t test was applied in manual calculation. After all the collected data have been processed, the researcher analysis them by using independent sample t test.

1. Based on the result of the students‟ speaking score (see appendix), the researcher calculates the mean of each group of students.

M=

X 1=

X 1 = Means score of extrovert students ability in speaking.

X 2 = Means score of introvert students ability in speaking.

2. The researcher count standard deviation of every students by using formula:

SDX 1 = √

SDX 2 = √

SDX 1 = Standard Deviation of extrovert students ability in speaking. SDX 2 = Standard Deviation of introvert students ability in speaking.

3. The researcher counts standard error of mean from every students by using formula:

SE M X 1 = Standard Error of mean from extrovert students ability in speaking.

SE M X 2 = Standard Error of mean from introvert students ability in speaking.

4. The researcher counts standard error from both sample by using formula: SE

M M 2 = √ M M = √( ) ( ) = √( ) ( )

5. The researcher counts t-test by using formula:

t count =

Based on the manual calculation above it can be explained that the mean of English speaking score of extrovert students was 80.2, with the standard deviation was 3.76233 and the standard error of mean was 0.57375. Meanwhile the mean of English speaking score of Introvert students was 71.6, with the standard deviation was 4.84941 and the standard error of mean was 0.77653. from these calculation it can be seen that the t observed was 8.925. The t-table for degree of significant of 5% was 1.99 and the degree of significant of 1% was 2.64.

1.99 and 2.64, the data calculated with manual and statistical result shows that t o was higher than t- table . So, the alternative hypothesis was accepted (Ha) and null hypothesis (Ho) was rejected. It means there significant difference between extrovert and introvert students in speaking ability.

By comparing the values of t o =8.925 and t table

In addition, the research also calculated using statistical calculation Spps

18.0 program as described in the table 4.14.

Table 4.14 Independent Samples Test

Levene's Test for Equality of

Variances

t-test for Equality of Means

Std.

95% Confidence

Error Interval of the Sig. (2- Differen Differen

Mean

Difference

ce ce Lower Upper EI Equal variances

F Sig.

Df tailed)

Equal variances

,96550 6,69224 10,5420 not assumed

8,925 71,52

,000 8,61714

Based on statistical calculation SPSS 18.0 program it can be seen that t obsered was 8.925 and sig. 2 tailed was 0,000.

3. Interpretation of The Result

Based on the manual and statistical calculation, the t observed was 8.925 it was greater than t table 5% (1.99) and 1% (2.64) it can be clarified that there is significant difference between extrovert and introvert students in speaking ability. So, the alternative hypothesis (Ha) was accepted and null hypothesis (Ho) was rejected. To make it clearly the researcher giving interpretation for “t observed ” with consulting t table.

df/db

= (43+39) – 2 = 80  Consulting score of “db/df” with “t table”  In significant degrees t-table 5% = 1.99  In significant degrees t-table 1% = 2.64

The alternative hypothesis of this research is there is any significant different between extrovert and introvert students in speaking ability of English Department at IAIN Palangka Raya academic year 2014-2016. And the null hypothesis of this research is there is no significant different between extrovert and introvert students in speaking ability of English Department at IAIN Palngka Raya academic year 2014-2016. Based on the analysis using independent sample test it found that alternative hypothesis was accepted. The t-observed of this research was (8.925) > t-table 5% (0.220) > t-table 1% (0.286). It meant t-table is greater than t-observed. It can be interpreted that Alternative Hypothesis (Ha) was accepted and Null Hypothesis (Ho) was rejected. In conclusion there is significant difference between extrovert and introvert students in speaking ability of English Department at IAIN Palangka Raya.