jawapan add math sbp k1

1

SULIT
3472/1
Additional
Mathematics
Kertas 1
Ogos
2017

BAHAGIAN PENGURUSAN
SEKOLAH BERASRAMA PENUH
DAN SEKOLAH KECEMERLANGAN
KEMENTERIAN PELAJARAN MALAYSIA

PEPERIKSAAN PERCUBAAN SPM
TINGKATAN 5
2017

ADDITIONAL MATHEMATICS
Paper 1

MARKING SCHEME

This marking scheme consists of 6 printed pages

2

MARKING SCHEME
Number

Sub

Solution and Mark Scheme

Marks Marks

9x2 + 12x + 4 = 0

1

2

(3x + 2)(3x + 2) = 0
SOR = 

OR

2  2
4
+   = 
3  3
3

Total

2

B1

or

 2  2 4
POR =       =
 3  3 9
2

(a)

0  22  122  q

16

2

(b)

x2 , x4

tan  

3

or

2

2 q  6

B1
1
2

2
3

cos   sin   2sin   cos 

4

(a)

3

2

B1

205 , 209.1 , 213.282

1

3

Nota:
Kalau calon senaraikan lebih daripada tiga, semua kena betul

(b)

17,338.78 seconds or
4 hours 49 minutes

205(1.02  1)
1.02  1
r  20cm

288.98 minutes
Nota:

50

5

(a)
(b)

r 

q
40

r

1

q 2  * 20 

dA
 2r
dr

Terima

or 4.82 hours

(3'25'')(1.0250  1)
1.02  1

or

2

B1

1
3

B2

B1

4

3

V  322.5

6

V

3

3t 2
 5t + c
2

B2

dV
 3t  5 atau V   3t  5 dt atau c  4
dt
p  2, p  

7

B1

p  1

2

24  3  5

(a)

(b)

3

B2

1
x2
 3 f xdx  x  1

9

B1
3

2
3

3p2
4
p 1

8

3

2

B1

570

3

2020

3

2
6 tahun atau senarai:

B1

2015: 300,
2016: 330,
2017: 360,
2018: 390,
2019: 420,
2020: 450

10

(a)

q  3, p  6 (BOTH)

q  3 OR p  6

p  2q OR 16  q 2  7

(b)

3

( -3, 16 )

B2
OR

p2
 7  16
4

B1

1

4

4

11

(a)

p = 4 and

q

p = 4 or q  

(b)

30
6

0.9134 @
4 y2  

12

4
3 4

4

B1

(b)

30

1

(c)

4530

2

(a)

(b)

2

3

B1

C 2 3 C 3

144

(a)

B1

1
216
1 1 1
x x
6 6 6

(b)

2

4

B1
2

25
7776

x  59.29

120

4

2

4 ! 3 !

x  56

4

B1

3

5 1 1 1 1
   
6 6 6 6 6

15

2

1

(a)

4

B1

150

(b)

14

2

(a)

2
x
 30 2  6
5

13

4
3

4
3

 0.3

26.14%

P ( z  0.639 )

B1

2
B1

2
B1

4

5

16

(a)

2.095 rad

1

(b)

565.65 m2
1
24 2 2.095   1 62 2.095 
2
2
24 seen

3

17

4 sin x cos y  cos x sin y

sin 2 x sin 2 y  2 sin x cos x2 sin y cos y
x = 120o , 240o , 180o

18

(2 cos x + 1) (cos x + 1) = 0

2 ( 1 – cos2 x )  3 cos x  3 = 0
19

20

21

B2
B1
3

4 pq

B1
3

3

B2
B1
3

B2
B1

(a)

2.579

1

(b)

8

2

log a 8  log a x
x

3

B2

3

a 3b
625
a b(a 2 )
54
(5  7) x or 5 2 ( x 2 )

4

3

B1
3

1
4

(3  x 2 ) 2  (2  x)

3

1

B2

log 2 (2  x)
log 2

22

B1

x

 5,  4

x3
 1
2

 1, 0

or

4 y
0
2

3
B2
B1

3

6

23

(a)
(b)

3

3 y  x  16  0
y6 

24

1
x  2
3

1
or equivalent

a  10 and b  3 10
a  10 OR b  3 10



or equivalent

3

or equivalent

B2

AC  2i  6 j

A3,  4

or

or

CD  i  3 j

1
 
 3

B2

B1

END OF MARKING SCHEME

3

B1
3

2
3

 2
*accept  
 6

2

B1

3a  b OR a 2  b 2  100

25

3

3