Pembahasan Mtk UN 2013 Paket 01
SMPN 3 KALIBAGOR
PAKET 1
Alfa Kristanti
1
SMPN 3 KALIBAGOR
Muhammad Ridho.M.Pd
2
SMPN 3 KALIBAGOR
Muhammad Ridho.MPd
Al4-kristanty.blogspot.com
2−3 + 4−3 =
2 8 ×
1
1
1
1
8
1
9
+ 3= +
=
+
=
3
2
4
8 64
64 64
64
3 = 2 8 × 3 = 2 24 = 2 4 × 6 = 2 2 6 = 4 6
1
2
1
1 20 5
1 20
2
4 + 6 ∶2 = 4 +
∶ = 4 +
×
4
3
2
4
3 2
4
3
5
1
8
4
83
3
=4 +
=
5−3
12
= 6
17
=
4
8
51
3
12
+ =
+
32
12
11
12
Selisih = 5 + 3 × 64.000 =
2
8
9
Bunga 9 bln = 12 × 12% ×
× 64.000 = 16.000
= 9%
Tabungan setelah 9 bln = 100% T + 9% T = 109% T
109% T = 3.815.000 T =
3.815.000
109%
=
3.815.000
= 3.815.000 ×
109
100
100
109
= 3.500.000
Alfa Kristanti
3
SMPN 3 KALIBAGOR
b=
5−
5−2
2
=
31−19
3
=
12
3
Sn = 2 ( 2a + (n – 1)b )
=4
S24 =
U2 = a + b 19 = a + 4
a = 19 – 4
a = 15
24
2
( 2(15) + (24 – 1) 4 ) = 12 (30 + (23)4 ) = 12 (30 + 92)
= 12 (122) = 1.4.64
a = U1 = 7
Un = a + (n – 1)b
b = U2 – U1 = 15 – 7 = 8
U50 = 7 + (50 – 1)8 = 7 + (49) 8 = 7 + 392 = 399
r=
2
1
=
3
9
=
1
3
Un = a × r n – 1 = 9 ×
Un = 32 × 3−
a = U1 = 9
+1
1
3
= 32 −
−1
= 32 × 3−1
+1
= 33−
−1
5x – 5 ≤ 1 + 2x
5x – 2x ≤ 1 + 5
3x ≤ 6
x≤2
I. 4x2 – 9 = (2x)2 – 32 = (2x + 3)(2x – 3)
II. 2x2 + x – 3 = (2x + 3)(x – 1)
III. x2 + x – 6 = (x + 3)(x – 2)
IV. x2 + 4x – 5 = (x + 5)(x – 1)
×
×
m=
2− 1
2− 1
=
−2 − 1
2− −3
=
y – y1 = m (x – x1)
y–1=
y–1=
−3
5
−3
5
(x – (–3))
5y – 5 = –3x – 9
(x + 3)
5y + 3x = – 9 + 5
5(y – 1) = –3(x + 3)
Alfa Kristanti
−3
5
3x + 5y = – 4
4
SMPN 3 KALIBAGOR
ax + by + c = 0
a=2;b=4
m=
−
=
−2
−4
=
1
2
Jumlah bilangan terbesar dan terkecil
2
= 3 × jml ketiga bilangan
2
= 3 × 96 = 64
M = { 3, 5, 7 }
N = { 4, 6, 8 }
M N = { 3, 4, 5, 6, 7, 8 }
g(2) = 7
2q + r = 7
g(5) = 7
5q + r = 7
2p + 3q = 18.000
2(3000) + 3q = 18.000
6.000 + 3q = 18.000
3q = 12.000
q = 4.000
4p + 2q = 4(3000)+2(4000)
= 12.000 + 8.000
= 20.000
D
10
A
6
6
C
E
10
10
Misal :
Harga gunting = p
Harga spidol = q
S=
10
2q + r = 7
2( 2) + r = 7
4 + r = 7
r = 7 + 4
r =3
2q + r = 7
5q + r = 7
7q = 14
q=2
4
=
40
4
g(4) = 2(4) + ( 3)
=83
= 11
2p + 3q = 18.000 × 5 10p + 15q = 90.000
3p + 5q = 29.000 × 3 9p + 15q = 87.000
p
= 3.000
= 10
2−
2 =
DE =
102 − 62 = 100 − 36 = 64 = 8
BD = 2 × DE = 2 × 8 = 16
1
1
1
Lbelahketupat ABCD = × d1 × d2 = × AC × BD = = × 12 × 16 = 96
2
2
2
B
Alfa Kristanti
5
SMPN 3 KALIBAGOR
P
B
80o
65
C
Pada gambar di samping:
ABC PQR maka
AB = PQ, BC = PR,
AC = QR
80o
o
A
65o
R
Q
Q
16
P
L
8
28
R
=
6
12
21
K
KL =
=
12
16
3
=4 ,
=
21
28
3
=4 ,
=
6
8
3
=4
M
4 × 27 + 2 × 12
4+2
108 + 24
6
=
132
6
= 22
L daerah tdk diarsir = LKLMN + LPQRS – 2 × L daerah diarsir
= 16 × 12 + 82 – 2 × 40
= 192 + 64 – 80
= 176
Banyak lampu =
�
�
�
=
4 × 30
6
= 20
F
D
Alfa Kristanti
E
6
SMPN 3 KALIBAGOR
(6x + 4) + (5x + 9) = 90
11x + 13 = 90
11x = 90 – 13
11x = 77
x=7
Penyiku AOC = COB = 5x + 9 = 5(7) + 9 = 35 + 9 = 44
Sudut keliling menghdp
busur yg sama maka
ABE = ACE = ADE
96
ABE = = 32
3
AOE = 2 × ABE
= 2 × 32
= 64
luar = 262 − 13 − 3
676 − 100 =
=
LORS =
2
=
676 − 102
576 = 24
×
75
105
× 21
=
= 15
Panjang rusuk balok = 4 (p + l + t) = 4 (30 + 12 + 18)
= 4 (60) = 240 cm
Kawat untuk kerangka 2 balok = 2 × 240 = 480 cm
Sisa kawat = 5 m – 480 cm = 500 cm – 480 cm = 20 cm
Alfa Kristanti
7
SMPN 3 KALIBAGOR
BC =
4
72
4
=
t = 152 − 92 =
t = 144 = 12
= 18
1
225 − 81
t
9
1
Vlimas = 3 La × t = 3 × 182 × 12 = 324 × 4 = 1.296
dbola = rusuk kubus
dbola = 12, maka :
12
r= =6
4
15
4
4
Vbola = π r3 = π × 63 = π × 216
3
3
3
= 4 π × 72 = 288 π
2
Ldinding = 2 (pt + lt) = 2(6 × 5 + 10 × 5)
= 2(30 + 50) = 2(80) = 160
Biaya = 160 × Rp 40.000,- = Rp 6.400.000,-
4
s
s
Lkubus = 6 s2
s 2 + s 2 = 42
2 s2 = 16
s2 = 8
s= 8= 4 ×2=2 2
=6× 2 2
=6×8
= 48
2
d = 14 r = 7
22
Ltabung = 2πr (r + t) = 2 × × 7 (7 + 34)
7
= 44 (41) = 1.804
Siswa dgn nilai 72 = 40 – 28 = 12 anak
Jml nilai siswa = 28 × 80 + 12 × 72 = 2.240 + 864 = 3.104
Rata-rata nilai =
Alfa Kristanti
=
3.104
40
= 77,6
8
SMPN 3 KALIBAGOR
Data
5 6 7 8 9
frekuensi 2 3 2 4 1
Modus
32
30
Jumlah hasil panen 2010 dan 2011 = 3 + 4 = 7
Alfa Kristanti
9
SMPN 3 KALIBAGOR
n(S) = 2 × 2 × 2 = 8
2 angka 1 gambar = AAG, AGA, GAA
3
P (2 angka 1 gambar) = 8
6
5
5
4
3
3
2
2
Banyak kelereng = 6 + 5 + 3 + 3 + 2 + 4 + 2 + 5 = 30
Kelereng merah = 6
6
P ( 1 merah) = 30 × 100 % = 20 %
Alfa Kristanti
10
PAKET 1
Alfa Kristanti
1
SMPN 3 KALIBAGOR
Muhammad Ridho.M.Pd
2
SMPN 3 KALIBAGOR
Muhammad Ridho.MPd
Al4-kristanty.blogspot.com
2−3 + 4−3 =
2 8 ×
1
1
1
1
8
1
9
+ 3= +
=
+
=
3
2
4
8 64
64 64
64
3 = 2 8 × 3 = 2 24 = 2 4 × 6 = 2 2 6 = 4 6
1
2
1
1 20 5
1 20
2
4 + 6 ∶2 = 4 +
∶ = 4 +
×
4
3
2
4
3 2
4
3
5
1
8
4
83
3
=4 +
=
5−3
12
= 6
17
=
4
8
51
3
12
+ =
+
32
12
11
12
Selisih = 5 + 3 × 64.000 =
2
8
9
Bunga 9 bln = 12 × 12% ×
× 64.000 = 16.000
= 9%
Tabungan setelah 9 bln = 100% T + 9% T = 109% T
109% T = 3.815.000 T =
3.815.000
109%
=
3.815.000
= 3.815.000 ×
109
100
100
109
= 3.500.000
Alfa Kristanti
3
SMPN 3 KALIBAGOR
b=
5−
5−2
2
=
31−19
3
=
12
3
Sn = 2 ( 2a + (n – 1)b )
=4
S24 =
U2 = a + b 19 = a + 4
a = 19 – 4
a = 15
24
2
( 2(15) + (24 – 1) 4 ) = 12 (30 + (23)4 ) = 12 (30 + 92)
= 12 (122) = 1.4.64
a = U1 = 7
Un = a + (n – 1)b
b = U2 – U1 = 15 – 7 = 8
U50 = 7 + (50 – 1)8 = 7 + (49) 8 = 7 + 392 = 399
r=
2
1
=
3
9
=
1
3
Un = a × r n – 1 = 9 ×
Un = 32 × 3−
a = U1 = 9
+1
1
3
= 32 −
−1
= 32 × 3−1
+1
= 33−
−1
5x – 5 ≤ 1 + 2x
5x – 2x ≤ 1 + 5
3x ≤ 6
x≤2
I. 4x2 – 9 = (2x)2 – 32 = (2x + 3)(2x – 3)
II. 2x2 + x – 3 = (2x + 3)(x – 1)
III. x2 + x – 6 = (x + 3)(x – 2)
IV. x2 + 4x – 5 = (x + 5)(x – 1)
×
×
m=
2− 1
2− 1
=
−2 − 1
2− −3
=
y – y1 = m (x – x1)
y–1=
y–1=
−3
5
−3
5
(x – (–3))
5y – 5 = –3x – 9
(x + 3)
5y + 3x = – 9 + 5
5(y – 1) = –3(x + 3)
Alfa Kristanti
−3
5
3x + 5y = – 4
4
SMPN 3 KALIBAGOR
ax + by + c = 0
a=2;b=4
m=
−
=
−2
−4
=
1
2
Jumlah bilangan terbesar dan terkecil
2
= 3 × jml ketiga bilangan
2
= 3 × 96 = 64
M = { 3, 5, 7 }
N = { 4, 6, 8 }
M N = { 3, 4, 5, 6, 7, 8 }
g(2) = 7
2q + r = 7
g(5) = 7
5q + r = 7
2p + 3q = 18.000
2(3000) + 3q = 18.000
6.000 + 3q = 18.000
3q = 12.000
q = 4.000
4p + 2q = 4(3000)+2(4000)
= 12.000 + 8.000
= 20.000
D
10
A
6
6
C
E
10
10
Misal :
Harga gunting = p
Harga spidol = q
S=
10
2q + r = 7
2( 2) + r = 7
4 + r = 7
r = 7 + 4
r =3
2q + r = 7
5q + r = 7
7q = 14
q=2
4
=
40
4
g(4) = 2(4) + ( 3)
=83
= 11
2p + 3q = 18.000 × 5 10p + 15q = 90.000
3p + 5q = 29.000 × 3 9p + 15q = 87.000
p
= 3.000
= 10
2−
2 =
DE =
102 − 62 = 100 − 36 = 64 = 8
BD = 2 × DE = 2 × 8 = 16
1
1
1
Lbelahketupat ABCD = × d1 × d2 = × AC × BD = = × 12 × 16 = 96
2
2
2
B
Alfa Kristanti
5
SMPN 3 KALIBAGOR
P
B
80o
65
C
Pada gambar di samping:
ABC PQR maka
AB = PQ, BC = PR,
AC = QR
80o
o
A
65o
R
Q
Q
16
P
L
8
28
R
=
6
12
21
K
KL =
=
12
16
3
=4 ,
=
21
28
3
=4 ,
=
6
8
3
=4
M
4 × 27 + 2 × 12
4+2
108 + 24
6
=
132
6
= 22
L daerah tdk diarsir = LKLMN + LPQRS – 2 × L daerah diarsir
= 16 × 12 + 82 – 2 × 40
= 192 + 64 – 80
= 176
Banyak lampu =
�
�
�
=
4 × 30
6
= 20
F
D
Alfa Kristanti
E
6
SMPN 3 KALIBAGOR
(6x + 4) + (5x + 9) = 90
11x + 13 = 90
11x = 90 – 13
11x = 77
x=7
Penyiku AOC = COB = 5x + 9 = 5(7) + 9 = 35 + 9 = 44
Sudut keliling menghdp
busur yg sama maka
ABE = ACE = ADE
96
ABE = = 32
3
AOE = 2 × ABE
= 2 × 32
= 64
luar = 262 − 13 − 3
676 − 100 =
=
LORS =
2
=
676 − 102
576 = 24
×
75
105
× 21
=
= 15
Panjang rusuk balok = 4 (p + l + t) = 4 (30 + 12 + 18)
= 4 (60) = 240 cm
Kawat untuk kerangka 2 balok = 2 × 240 = 480 cm
Sisa kawat = 5 m – 480 cm = 500 cm – 480 cm = 20 cm
Alfa Kristanti
7
SMPN 3 KALIBAGOR
BC =
4
72
4
=
t = 152 − 92 =
t = 144 = 12
= 18
1
225 − 81
t
9
1
Vlimas = 3 La × t = 3 × 182 × 12 = 324 × 4 = 1.296
dbola = rusuk kubus
dbola = 12, maka :
12
r= =6
4
15
4
4
Vbola = π r3 = π × 63 = π × 216
3
3
3
= 4 π × 72 = 288 π
2
Ldinding = 2 (pt + lt) = 2(6 × 5 + 10 × 5)
= 2(30 + 50) = 2(80) = 160
Biaya = 160 × Rp 40.000,- = Rp 6.400.000,-
4
s
s
Lkubus = 6 s2
s 2 + s 2 = 42
2 s2 = 16
s2 = 8
s= 8= 4 ×2=2 2
=6× 2 2
=6×8
= 48
2
d = 14 r = 7
22
Ltabung = 2πr (r + t) = 2 × × 7 (7 + 34)
7
= 44 (41) = 1.804
Siswa dgn nilai 72 = 40 – 28 = 12 anak
Jml nilai siswa = 28 × 80 + 12 × 72 = 2.240 + 864 = 3.104
Rata-rata nilai =
Alfa Kristanti
=
3.104
40
= 77,6
8
SMPN 3 KALIBAGOR
Data
5 6 7 8 9
frekuensi 2 3 2 4 1
Modus
32
30
Jumlah hasil panen 2010 dan 2011 = 3 + 4 = 7
Alfa Kristanti
9
SMPN 3 KALIBAGOR
n(S) = 2 × 2 × 2 = 8
2 angka 1 gambar = AAG, AGA, GAA
3
P (2 angka 1 gambar) = 8
6
5
5
4
3
3
2
2
Banyak kelereng = 6 + 5 + 3 + 3 + 2 + 4 + 2 + 5 = 30
Kelereng merah = 6
6
P ( 1 merah) = 30 × 100 % = 20 %
Alfa Kristanti
10