Percubaan SPM Matematik Tambahan Kedah 2017 - Sumber Pendidikan add math kedah k1

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Additional
Mathematics
Paper 1
August, 2017

PROGRAM PEMANTAPAN PRESTASI TINGKATAN 5
SPM 2017
ANJURAN
MAJLIS PENGETUA SEKOLAH MALAYSIA (KEDAH)

ADDITIONAL MATHEMATICS
MARKING SCHEME
Paper 1

MODULE 1

.

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Additional Mathematics Paper 1

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PROGRAM PEMANTAPAN PRESTASI TINGKATAN 5 SPM 2017
Marking Scheme
Additional Mathematics Paper 1

MODUL 1
Question
1
(b) B1 :

(b) B1 :

4

5

f  t   64

Answer

(a )

(b ) t  4

(a )

2

3

f  t   36  7t

Solution/ Marking Scheme

q( x  2)

B2: m  3 or k  10
3
2a  k
1
B1:
 x or

2a  k
3

x

1

(b) 3x  14

2

m  3 and k  10

3

B2: 3  2(2)
B1 :     3   2 or (   )2  2
2

5

B2:  2h  3  4 1  h 2  1  

3

2

B1:  2h  3  4 1  h 2  1

B2 :

h

( x  4)( x  3)  0

6
B1 :

5
12

x2  x  12  0

( x  4)( x  3)

(a ) B1 : 23 y
(b) B1:

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2

1

2

7

Marks
1

3

3

(a ) 27

4y
or 2 2 y
4

(b )

1
4

3

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B3:

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4 log m 2  log m 3
log m 2 _ log m 3

4x  y
x y

B2: log m 24  log m 3 or log m 2  log m 3
B1:

9

kog m 48
log m 6

(a ) B1 : 2sin  cos 
(b) B1: cos 2 

10

(a )

7
25

2

24
or cos 2  2 cos2  1
25

(b )

B2: 180 000   n  116 200 

20
20
, or d 
7
7

B2:

a

B1:

T1  T3  T5  T7  T9  T11  T13  140 or

49
50

2

n  13

B1: a 180 000 or d  16 200

11

4

3

a

s14 ( T1  T3  T5  T7  T9  T11  T13 )  160

20
,
7
20
d 
7
(both)

3

2k
k 1

3

12
B2:

2

1

1
k

B1: r 

1
k

(a )
13
(b) B2:
B1:
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k  5 or

p 

5
2

5 p  2 p2  0

y
 k  2x
x

(b ) k  5 , p 

1

5
2

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B2: mBC  1 or y  5  1( x  0)
y  x  5

B1: B(0,5) or mAB  1

(a )
(b) B1 : 48h  96  6h 2  0 or (h  4)(h  4)  0

16

straight line

(b ) 4

Share R
AND
Largest Dispersion

B1: Share R

3

3

2

17
3

B2: Draw vector 3a and  2b correctly
B1: Draw vector 3a or  2b correctly

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

18
(a )

3
1
(b) ) B2: P T = P R or RT = RP
4
4

PS

 5y

(b )  9 x 

5
y
4

1

3

B1: QT = QP + P T or QT = QR + RT

19

20

B1:

1:2

1
B2 : (3  7)  3  11
2

B1:

21

1
1 2
1
r   s 2 or sr  s 2 or r  s
2
2
2

4

3

4

3

(a) 6h 2

2

(b) 9h

2

1
(3  7)  3
2

B2: k(3)  12  0
B1: kt  12  0

(a ) B1:

1
 3h  8h  sin 30
2

(b) B1:

dA dA dh
dA
 12h or


dt dh dt
dh

22

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(a ) B1:

1 1

2 2

1 1
(b) B1:   
2 2
24



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(a )

1
4

2

(b)

1
2

2



B2: (4P3  2) (3P2  2)  2
120

3

87.746

4

B1: 4 P 3 or 3 P2

25

B3:

x  86
 0.4364
4

B2: P(Z  x)  p ( Z 
B1 : P(Z  x) 

x  86
)  0.4364
4

4
25

END OF MARKING SCHEME

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