Chem JUJ K1 K2 K3 Skema Jawapan SET 2

SKEMA PRAKTIS BESTARI JUJ
KIMIA SET 2 KERTAS 1, 2 & 3

SKEMA JAWAPAN KERTAS 1
JUJ KIMIA SET 2 - 2017

1

D

11

C

21

A

31

D


41

C

2

C

12

B

22

D

32

C


42

A

3

C

13

B

23

C

33

A


43

B

4

C

14

B

24

D

34

A


44

B

5

A

15

C

25

A

35

A


45

A

6

B

16

C

26

C

36

B


46

D

7

B

17

C

27

C

37

A


47

A

8

C

18

A

28

B

38

D


48

B

9

C

19

D

29

D

39

B


49

B

10

B

20

B

30

B

40

C


50

C

4541 Set 2 © Hak Cipta JUJ Pahang 2017

1

SKEMA PRAKTIS BESTARI JUJ
KIMIA SET 2 KERTAS 1, 2 & 3

MARKING SCHEME PAPER 2 SET 2 JUJ CHEMISTRY 2017
Sub
Mark
1
1

Mark


electron

1

1

1. One similarity
2. one different
Sample answer :
1. Same number of proton /proton number // same number of
electron
2. Different number of neutron / nucleon number
70 / 70oC

1
1

2

1

1

1. Heat energy absorbed
2. is used to overcome the forces of attraction between particles
Correct arrangement (at least 3x3 with same size & do not
overlapping each other)

1
1

2

1

1

Question No

Mark Scheme

1 (a)

(i)
(ii)

smallest neutral particles

(iii)
(iv)

(b)

(i)
(ii)
(iii)

1
1

Total marks
Question No
2 (a)

(i)
(ii)

(b)

(c)

(i)
(ii)
(iii)
(iv)

Sub
Mark
1

Mark Scheme

The chemical formula that shows the simplest ratio of atoms of each
element in the compound
C2H4O
1
1. value of n
1
2. Molecular formula
1
Sample answer :
(CH2) n = 42 // (12+ 2(1))n = 42 // 14n = 42 // n = 3
Molecular formula = C3H6
Mass
1
64 + 2(14)+ 6(16) // 188
1
Correct value with unit
1
Answer : 1.2 X 188 g // 225.6 g
1. Correct formula of reactants and product
1
2. balanced
1
Answer : 2Cu(NO3)2
 2CuO + 4NO2 + O2
Total marks

4541 Set 2 © Hak Cipta JUJ Pahang 2017

2

9
Mark
1
1
2

1
1
1

2
9

SKEMA PRAKTIS BESTARI JUJ
KIMIA SET 2 KERTAS 1, 2 & 3

Question No
3 (a)

(b)

(c)

(i)
(ii)
(iii)
(i)
(ii)
(i)
(ii)

Mark scheme

Sub
mark
1
1
1
1
1

1
1
1
1
1

1

1

1.Correct number of ion and nucleus is labelled
2.Correct electron arrangement and charged

1
1

2

1. Soluble in water//
2. High melting and boiling point//
3. Conduct electricity in aqueous and molten state

1+1

2

Chlorine/Cl
Aluminium
Argon atom has achieved stable octet electron arrangement
Cl
The forces of attraction between nucleus and electron in Cl
atoms is stronger than Na atom.
Ionic bond

-

+
Cl

Na

(iii)



mark

Any two

Total marks 10
Question No
4 (a)

(b)

(i)
(ii)
(iii)
(iv)
(i)

(ii)

Mark scheme
Silicon dioxide / silica
stabiliser /emulsifier
Flavouring agent//thickening agent//colouring agent
Analgesic // paracetamol
N2+3H2  2NH3
1. Correct formula of reactants and products
2. Balanced equation
1. Type of fertilizer
2. % of N in urea
3. % of N in ammonium sulphate
4. Conclusion
Answer:
Urea.

Sub
mark
1
1
1
1

mark
1
1
1
1

1
1

2

1
4

% of N in urea
=(28/60) x100%
=46.67%

%of N in ammonium sulphate
=(28/132) x 100%
= 21.21%

% of nitrogen atom by mass for urea is higher than
ammonium sulphate

1+1

1
Total marks

4541 Set 2 © Hak Cipta JUJ Pahang 2017

3

10

SKEMA PRAKTIS BESTARI JUJ
KIMIA SET 2 KERTAS 1, 2 & 3

Question No
5 (a)

(i)

(b)

(i)

(ii)

(c)

(iii)
(i)

Sub
Mark

Mark Scheme

Mark

Increase of hydrogen gas per unit time // decrease of mass of
zinc per unit time
1. draw the triangle
2. calculation

1

1

43.5-29 cm3 // 14.5 cm3 // 0.242 cm3 s-1
120-60 s
60 s
41-26 cm3 s-1 // 15 cm3 s-1 // 0.25 cm3 s-1
120-60
60
Because the concentration of acid decrease with time
Volume of gas / cm3

1

2

1

1

1

1

1

1

1

Set II
Set I

(ii)
(d)

(i)
(ii)

Time / s
1. size of zinc is smaller
1
2
2. remain the volume and concentration of hydrochloric acid.
1
Put 5 g/a packet of fine sugar in hot water and cold water in two 1
1
cups. Sugar in hot water dissolve faster.
1. temperature higher in hot water
1
2
2. water particles has higher kinetic energy
1
Total Marks
11

Question No
6(a) (i)
(ii)
(iii)
(iv)

Mark Scheme
Na+ , NO3- , H+ , OH- (accept name of ions)
1. hydrogen ions
1. put glowing wooden splinter into a test tube
2. The wooden splinter lights up
1. Suggest the suitable electrode (can infer from diagram)
2. functional diagram
3. correct label :
Anode : silver electrode ; Cathode : iron spoon
Electrolyte : silver nitrate solution

silver

Iron
spoon

4541 Set 2 © Hak Cipta JUJ Pahang 2017

Silver nitrate
solution
4

Sub
Mark
1
1
1
1
1
1
1

Mark
1
1
2
3

SKEMA PRAKTIS BESTARI JUJ
KIMIA SET 2 KERTAS 1, 2 & 3

Question No
(b)

(i)

(iii)

1. Anode : Zn  Zn2+ + 2e
2. Cathode : Cu2+ + 2e  Cu

1. Change copper electrode to silver electrode // change zinc
electrode to magnesium electrode// any suitaible pair of
electrodes
2. Reason :
Distance between Ag and Zinc / Mg and Cu in
electrochemical series is further
Total Marks

Question No
7 (a)

(i)

Sub
Mark
1
1

Mark Scheme

Mark
2

1

2
1
11
Sub
Mark

Mark Scheme

Mark

1. structural formula
2. name

1+1
1+1
Butan -2-ol

2-methylpropan-2-ol

*

(ii)

*Any two isomer
1. Reaction I = esterification
Functional
group
X

//

2-methylpropan-1-ol

4
1

Homologous
series
Alkene

name

Carboxylic acid

Butanoic acid

ester

Butyl
etanoate

But-1-ene

1+1+1

Carbon-carbon
double bond
Y
//

1+1+1

Carboxyl group
z

1+1+1

//

carboxylate
group
4541 Set 2 © Hak Cipta JUJ Pahang 2017

10
5

SKEMA PRAKTIS BESTARI JUJ
KIMIA SET 2 KERTAS 1, 2 & 3

Question No
(b)

Sub
Mark

Mark Scheme
1. Correct formula of reactants and product
2. balanced
C3H8 + 5O2

Mark

1
1

3CO2 + 4H2O

3 & 4. Calculation

% of carbon

Propene
3(12) x 100
42
= 85.71%

Propane
3(12) x 100
44
= 81.81%

1+1

5. % of carbon atom by mass in propene is higher than
propane.
6. Propene produces more soot than propane

1
1

6

Total Marks 20
Question No
8 (a)

(b)

Mark scheme
1. V = sodium carbonate
2. W= copper(II) sulphate
3. X = nitric acid
4. Y = copper(II) oxide
5. Z= Carbon dioxide
6. Double decomposition reaction // precipitation reaction
Correct formula of reactants
7 & 8. Reaction I : Na2CO3 + CuSO4  CuCO3 + Na2SO4
9& 10. Reaction II : CuCO3 + HNO3  Cu(NO3)2 + CO2 +H2O
Compare and contrast :
Similarities :
1. Both experiment produce black residue
2. Both experiment released gas when heated
Differences:
3. Exp I produced colourless gas and Exp II produced brown gas
4. Exp 1 turns the limewater chalky and Exp II turns moist blue
litmus paper to red
* Choose any 3
4. mole
5. ratio mole
6. correct answer with unit
Answer :
Mol = 6.2/124 // 0.05
Ratio : 1 mol CuCO3 : 1 mol CO2
0.05 mol CuCO3 : 0.05 mol CO2
Answer : 0.05 x 24 dm3 // 1.2 dm3

Sub
mark
1
1
1
1
1
1
2+2

mark

10

1+1+1

1
1
1
6

4541 Set 2 © Hak Cipta JUJ Pahang 2017

6

SKEMA PRAKTIS BESTARI JUJ
KIMIA SET 2 KERTAS 1, 2 & 3

Question No
(c)

Mark scheme

Sub
mark
1
1
1
1

1.Egg shells contain calcium carbonate
2. Calcium carbonate can react with acid
3. Calcium carbonate can dissolved in acid
4. Egg shell becomes soft//easier to insert in the bottle

mark

4

Total Marks 20
Question
No
9
(a)

Mark scheme

Types
of
reaction
Energy
profile
diagram

(b) (i)

Elephant Toothpaste
Exothermic

Sub
mark
Cold Pack
Endothermic
1+1

-Correct level and label
-Correct level and label
energy
energy
-correct equation & H
-correct equation & H
Total
Total energy content of the Total energy content of
energy
reactants is higher than
the products is higher
content products
than reactants
1. State solution A,
2. solution B
3. precipitate D (can infer from procedure)
4-9. procedure
10. data
11-12. calculation
Sample answer :
1. Solution A = sodium chloride solution
2. solution B silver nitrate solution,
3. Precipitate D = silver chloride
Procedure :
4. Measure [20 – 100 cm3] of sodium chloride [any suitable
solution] [0.5 – 2.0 moldm-3] solution and pour the solution into a
plastic/polystryrene cup
5.Measure [20 – 100 cm3] of silver nitrate [any suitable solution]
[0.5 – 2.0 moldm-3] solution and pour the solution into another
plastic/polystryrene cup
6. record initial temperature for both solutions

4541 Set 2 © Hak Cipta JUJ Pahang 2017

mark

7

1+1
1+1
1+1
8

1
1
1

1

1

1

SKEMA PRAKTIS BESTARI JUJ
KIMIA SET 2 KERTAS 1, 2 & 3

Question
No

Mark scheme

Sub
mark
1

7. pour sodium chloride solution quickly into the silver nitrate
solution
8.stir the mixture
9. record the highest temperature reached

mark

1
1

10. Initial temperature of sodium chloride solution = T1oC
Initial temperature of silver nitrate solution = T2 oC
Average Initial temperature = (T1+ T2)/2 = Ta oC
Highest temperature = Tb oC

1

11. heat given out = mc = 200 x 4.2 x (Tb – Ta)
1000
= w kJ

1

1
12. number of mol = 50 x 1 /1000 = 0.05
13. Heat of precipitation = - w/0.05 = -X kJmol-1

1
Total Marks

Question
10 (a)(i)

Answer

Sub
mark
1

1. suitable metal R : Zn/Mg

Types of
reaction
Half
equation

Zn/Mg
2. oxidation

CuSO4
3. reduction

4. Zn  Zn2+ + 2e

5. Cu2+ + 2e  Cu

6. Name the ion present in the colourless solution = copper(II) ions

max12
20
marks

1+1

1+1
1

6

(a)(ii)
Change in
oxidation
number
Role
(b)

Zn/Mg
1. 0  +2

CuSO4
2. +2  0

3. Reducing agent

4. Oxidizing agent

Sample answer :
1. Metal : Zn/Al

1+1
1

Procedure :
2. Clean Zn/Al strip and iron nail with sand paper
3. Coil Zn/Al strip around the iron nail and put in a test tube
4. Put the iron nail only into another test tube.
5. Pour the hot agar-agar/jelly solution that has been mixed with
potassium hexacyanoferrate(III) and phenolphthalein indicator until
the iron nail immersed into both test tube.
4541 Set 2 © Hak Cipta JUJ Pahang 2017

1+1

8

1
1
1
1

4

SKEMA PRAKTIS BESTARI JUJ
KIMIA SET 2 KERTAS 1, 2 & 3

Question

Answer

Sub
mark
1

6. Leave the test tubes aside for a few days.
7. Observation
Pair of metal
Zn/Al and iron nail
Iron nail

1

Observation
pink spot form
Blue spot form

Half equation for oxidation of metals
8. Test tube I : Zn  Zn2+ + 2e
9. Test Tube II : Fe  Fe2+ + 2e

1
1

10. Conclusion
When a more electropositive metal is in contact with iron, the metal
inhibits rusting //
iron does not rust when in contact with a more electropositive metal
Total marks

END OF MARKING SCHEME PAPER 2

4541 Set 2 © Hak Cipta JUJ Pahang 2017

9

marks

1
10

20

SKEMA PRAKTIS BESTARI JUJ
KIMIA SET 2 KERTAS 1, 2 & 3

PERATURAN PEMARKAHAN KIMIA KERTAS 3 JUJ SET 2 2017
Question

Rubric
Able to state the colour change correctly

Score

3

Answer:
Pink colour change to colourless
Able to state the colour change less correctly

1(a)
2

Sample answer:
Purple to colourless
Able to state an idea of colour

1
Sample Answer:
Pink // Colourless// Purple
0

No response or wrong response

Question

Rubric
Able to record all burette readings accurately to 2 decimal
places

Score
3

Answer:

1(b)

Titration
I
II
III

Initial reading (cm3)
0.00
0.50
5.50

Final reading (cm3)
26.00
24.50
30.50

Able to record all the burette readings correctly to 1 decimal
places or able to record at least 4 reading correctly // uniform
decimal places
Able to record at least 2 burette reading correctly without
decimal places
No response or wrong response

4541 Set 2 © Hak Cipta JUJ Pahang 2017

10

2

1
0

SKEMA PRAKTIS BESTARI JUJ
KIMIA SET 2 KERTAS 1, 2 & 3

Question

Rubric
Able to consruct a table that contains the following information.

Score

1. Hading in the table : Set, Initil reading/cm3, Final reading/cm3,
Volume of acid/cm3
2. Transfer all the burette readings from 1(b) correctly

3. With unit at the heading
Sample answer:

1(c)

3

Titration Initil reading/cm3
Bacaan awal/cm3

Final
reading/cm3
Bacaan
akhir/cm3
26.00

Volume of
acid/cm3
Isipadu asid/cm3
26.00

I

0.00

II

0.50

24.50

24.00

III

5.50

30.50

25.00

Able to construct a table less correctly

2
Able to construct a table that contains the following information

1. Headings in the table : suitable heading
1
2. 2 column with heading without data/
2 column only
Sample answer:
Initial reading

Final reading

0

No response or wrong response

4541 Set 2 © Hak Cipta JUJ Pahang 2017

11

SKEMA PRAKTIS BESTARI JUJ
KIMIA SET 2 KERTAS 1, 2 & 3

Question

Rubric
Able to calculate the average volume and concentration of
hydrochloric acid with unit correctly
Answer:
Average volume of hydrochloric acid
= 26.00 + 24.00 + 25.00
---------------------------- = 25.00 cm3
3

Score

--- p1
3

1(d)
Concentration of hydrochloric acid
MHCl VHCl
= 1
MNaOH VNaOH
1
MHCl X 25.00 = 1
1.0 X 50.00
1

---- p2

// 25.00 MHCl = 50.00
MHCl = 50.00
25.00
= 2.0 mol dm-3

---- p3

Able to calculate the average volume and concentration of
hydrochloric acid correctly without unit
Able to calculate volume of acid OR concentration of acid
correctly
No response or wrong response

Question

1(e)

Rubric
Able to classify all the acids into strong and weak acid correctly
Strong acids
Asid kuat

Weak acids
Asid lemah

Sulfuric acid
Nitric acid

Citric acid
Ethanoic acid

Able to classify at least 3 acids correctly
Able to classify at least 2 acids correctly/reverse
No response or wrong response

4541 Set 2 © Hak Cipta JUJ Pahang 2017

12

2
1
0

Score

3

2
1
0

SKEMA PRAKTIS BESTARI JUJ
KIMIA SET 2 KERTAS 1, 2 & 3

Question

2(a)

Question

Rubric
Able to state all inferences correctly
Test tube
Inference

A
B
Iron nail
Iron nail
does not
rust // Fe2+
rust //Fe2+ Present /
does not
formed
present
Able to state 3 inferences correctly
Able to state 2 inferences correctly
No response or wrong response

Score

C
Iron nail
does not
rust // Fe2+
does not
present

D
Iron nail
rust // Fe2+
Present /
formed

Rubric
Able to state the relationship between manipulated varible and
responding variable with direction correctly

3

2
1
0

Score

2(b)
Sample answer:
When a more/less electropositive metal / higher/lower than iron
in Electrochemical series is in contact with iron, iron (nail) does
not rust/rust
Able to state the hypothesis less correctly
Sample answer:
The rusting of iron is faster / slower, if a less / more
electropositive metal is in contact with iron/Fe
Able to give an idea of hypothesis
Sample answer:
Iron rust when in contact with other metal // other metal affect
the rusting of iron.
No response or wrong response

Question

2(c)

Rubric
Able to state all the variables correctly
Sample answer:
Manipulated variable : Type / different electropositive metal
Responding variable : Rusting // presence of blue sport
Constant variable
: Type of iron nail // iron //medium in
which the iron are kept
Able to state any two of variables in this experiment correctly
Able to state any two of variables in this experiment correctly
No response or wrong response

4541 Set 2 © Hak Cipta JUJ Pahang 2017

13

3

2

1
0

Score

3

2
1
0

SKEMA PRAKTIS BESTARI JUJ
KIMIA SET 2 KERTAS 1, 2 & 3

Question

Rubric
Able to give one operational definition of the experiment
correctly with the following aspects:

3

i) what you do
ii) what you observe

2(d)

Sample answer:
1. when iron nail is coiled/in contact with a less
electropositive metal (copper)/metal located below iron in
electrochemical series
2. Rusting of iron is the formation of blue spot/colouration
Able to state at least two criteria correctly
Sample answer:
Rusting of iron is the formation of blue spot /colouration
or
when iron nail is coiled/in contact with a less electropositive
metal
Able to state an idea of operational definition
Sample answer:
Blue spot/rusting occur
No response or wrong response

Question

2(e)

Score

1
0

Rubric
Able to predict the observation correctly
Answer:
The intensity of blue spot/colouration is very high//higher than
test tube B.
Able to predict the observation
Sample answer:
The intensity of blue spot/colouration is high
Able to predict the observation
Sample answer:
Blue spot/colour
No response or wrong response

4541 Set 2 © Hak Cipta JUJ Pahang 2017

2

14

Score

3

2
1

0

SKEMA PRAKTIS BESTARI JUJ
KIMIA SET 2 KERTAS 1, 2 & 3

Question

Rubric
Able to state the relationship correctly between the time taken
and the amount of rust form correctly
1. Time taken
2. Formation of rust
3. Comparison

Score

3
Sample answer:

2(f)

The longer the time taken, the bigger/greater/larger the rust form
//the longger the time taken, more rust is form
//the rust form is greater/bigger/larger when the time taken is
longer
//the rust form in one week is more/bigger/greater/larger than one
day
Able to state the relationship between the time taken and the
amount of rust form less correctly
1. Time taken/Formation of rust

2
Sample answer:
The rust form is bigger/greater/larger
//the form is directly proportional to the time taken
Able to state any idea of relationship
Sample answer:

1
The rust is form/change//rust is small/less
No response or wrong response

4541 Set 2 © Hak Cipta JUJ Pahang 2017

0

15

SKEMA PRAKTIS BESTARI JUJ
KIMIA SET 2 KERTAS 1, 2 & 3

Question

Rubric
Able to give the problem statement correctly

Score

Sample answer:
3
How does the effectiveness of cleansing action of two different
types of cleansing agent in hard water?
// What is the difference in effectiveness of cleansing action in
hard water using soap and detergent?
Able to give the problem statement less correctly

Sample answer:
3(a)
How does different type of cleansing agent affect the
effectiveness of cleansing action in hard water?

2

// To investigate the effectiveness of different type of cleansing
agent in hard water.
Able to give an idea of statement of the problem

1

Sample answer:
To study the effectiveness of cleansing action in hard water

0

No response or wrong response

Question

Rubric
Able to state all variables correctly

Score

Sample answer:

3(b)

Manipulated variable :Types of cleansing agent//soap and
detergent
Responding variable : Effectiveness of cleansing agent//ability
to remove the oily stains on cloth
Constant variable
: Hard water//Cloth with oily stains//Size
of cloth

3

Able to state any two variables correctly
Able to state any one variable correctly
No response or wrong response

2
1
0

4541 Set 2 © Hak Cipta JUJ Pahang 2017

16

SKEMA PRAKTIS BESTARI JUJ
KIMIA SET 2 KERTAS 1, 2 & 3

Question

Rubric
Able to state the relationship between the manipulated variable
and the responding variable correctly
Sample answer:
Detergent is more effective than soap in hard water.
// Detergent in hard water can remove the oily stains on cloth
while soap cannot.

Score

3

Able to state the relationship between the manipulated variable
and the responding variable incorrectly

3(c)

Question

3(d)

Sample answer:
Detergent is more effective
// Soap is less effective
// Detergent in hard water can remove the oily stains on
cloth
//soap cannot remove stain on cloth.
Able to state an idea of hypothesis
No response or wrong response

Rubric
Able to give the completely list of the apparatus and materials
Answer:
Apparatus:
Beakers, measuring cylinder, glass rod
Material:
Soap, detergent, [cleansing agent X dan cleansing agent Y],
0.5 - 1 mol dm-3 magnesium sulphate solution/[sea water/hard
water], 2 pieces of cloth with oily stains.

2

1
0

Score

3

Able to give the list of the apparatus and materials correctly but
not completely

Answer:
Apparatus:
Any containers, glass rod
Material:
Cleansing agent, cloth with oily stains.
Able to give two materials and at least one apparatus
Answer :
Material:
Soap solution / detergent, hard water
[any container]
No response or wrong response

2

1

0

4541 Set 2 © Hak Cipta JUJ Pahang 2017

17

SKEMA PRAKTIS BESTARI JUJ
KIMIA SET 2 KERTAS 1, 2 & 3

Question

Rubric
Able to state all procedures correctly

Score

Sample answer :

3(e)

1. Label 2 beakers as A and B respectively
2. Fill all the beakers with [50 - 100 cm3 ]of hard water /
magnesium sulphate solution
3. Add cleansing agent X/detergent in beaker A and
cleansing agent Y/soap in bikar B.
4. Place a piece of cloth with oily stain into each beaker
5. Stir the solution in each beaker using glass rod until no
change can be observed
6. Wash the oily stain on each piece of cloth using the
solution in each beaker
7. Record the observation.
Able to state three steps of procedures correctly
Steps 2, 3, 5, 6,
Able to state two steps of procedures correctly
Steps 2, 3, 6
No response or wrong response

Question

Rubric
Able to exhibit the tabulation of data that includes the following
information.
1. Headings
Sample answer :

3(f)

Beaker
A
B

3

2
1
0

Score

2
Observation

Able to tabulate the data incompletely

1. Titles without unit
Sample answer:

1

Beaker
No response given / wrong response

PERATURAN PEMARKAHAN TAMAT

4541 Set 2 © Hak Cipta JUJ Pahang 2017

18

0