CHAPTER IV RESEARCH FINDINGS
D. Data Description
After doing the research, the writer found the test score of experimental class and controlled class as follows:
Table 1 The Test Scores of the Experimental Class Students
N Pre-test
post- test
gained score 1 64
60 -4
2 48 64
16 3 50
66 16
4 46 56
10 5 62
64 2
6 66 64
-2 7 56
68 12
8 42 67
25 9 66
54 -12
10 64 76
12 11 58
78 20
12 72 78
6 13 78
82 4
14 36 64
28 15 52
62 10
16 58 76
18 17 48
64 16
18 68 67
-1 19 50
50
20 84 98
14 21 70
76 6
22 70 96
26 23 54
54 Sum
222
Table 1 The Test Scores of the controlled class
N Pre-test
Post- test
Gained score 1 80 80
2 84 80 -4 3 76 76
4 80 64 -16 5 76 64 -12
6 32 54 22 7 44 68 24
8 44 72 28 9 49 68 19
10 60 58 -2
11 72 62 -10 12 57 62
5 13 49 58
9 14 62 52 -10
15 72 46 -26 16 46 70
24 17 64 50 -14
18 26 72 46
19 51 68 17
20 42 60 18
21 34 76 42
22 30 64 34
23 48 50 2
Sum 196
Table 2 The Calculation Result of Mean and Standard Deviation
of Experiment Class and controlled class
N X Y x y x2 y2
1 -4 0
-13.652 -8.522
186.382 72.620
2 16 -4
6.348 -12.522
40.295 156.794
3 16 0
6.348 -8.522
40.295 72.620
4 10 -16
0.348 -24.522
0.121 601.316
5 2 -12
-7.652 -20.522
58.556 421.142
6 -2 22
-11.652 13.478
135.773 181.664
7 12 24
2.348 15.478
5.512 239.577
8 25 28
15.348 19.478
235.556 379.403
9 -12 19
-21.652 10.478
468.817 109.794
10 12 -2
2.348 -10.522
5.512 110.707
11 20 -10
10.348 -18.522
107.078 343.055
12 6 5
-3.652 -3.522
13.338 12.403
13 4 9
-5.652 0.478
31.947 0.229
14 28 -10
18.348 -18.522
336.643 343.055
15 10 -26
0.348 -34.522
0.121 1191.750
16 18 24
8.348 15.478
69.686 239.577
17 16 -14
6.348 -22.522
40.295 507.229
18 -1 46
-10.652 37.478
113.469 1404.620
19 0 17
-9.652 8.478
93.164 71.881
20 14 18
4.348 9.478
18.904 89.837
21 6 42
-3.652 33.478
13.338 1120.794
22 26 34
16.348 25.478
267.251 649.142
23 0 2
-9.652 -6.522
93.164 42.533
Sum 222
196 0.000
0.000 2375.217
8361.739
From table 2 and 3, the writer have found that Σ X = 222, Σ Y = 196, Σ x
2
= 2375.217,
Σ y
2
= 8361.739 The formula to seek “t” or t
o
in the condition with small sample N30 is as follows:
If we use the formula to seek “to”, the steps are needed as follows: 1.
Determining Mean variable X with formula:
2. Determining Mean variable Y with formula:
3. Determining of Standard of Deviation of Variable X:
1
1 N
X M
or Mx
Σ =
23 196
= 521
, 8
=
2
2 N
Y M
or My
Σ =
23 222
= 652
, 9
=
1 2
1 N
X SD
or SDx
∑
=
23 217
. 2375
= 270
. 103
=
162 ,
10 1
= SD
or SDx
2 1
2 1
M M
SE M
M to
− −
=
4. Determining of Standard Deviation of Variable Y:
5. Determining of Standard Error of Mean Variable X:
6. Determining of Standard Error of Mean Variable Y:
7. Determining Standard Error Mean Difference of M
1
and M
2
:
8. Determining t
o
with formula:
2 1
2 1
M M
o
SE M
M t
−
− =
23 739
. 8361
= 553
, 363
=
067 ,
19 2
= SD
or SDy
2 2
2
N y
SD or
SDy
∑
=
1
1 1
1
− =
N SD
SE or
SE
M
Mx
1 23
162 .
10 −
= 22
162 .
10 =
690 .
4 162
. 10
=
065 ,
4
2
=
M
SE or
SE
My
1
2 2
2
− =
N SD
SE or
SE
M
My
1 23
067 .
19 −
= 22
067 ,
19 =
690 .
4 067
, 19
= 166
, 2
=
M
SE or
SE
Mx
2 2
2 1
1 M
M M
SE SE
SE or
SE +
=
2 2
065 ,
4 166
, 2
+ =
499 .
16 691
, 4
+ =
19 ,
21 =
603 ,
4
1
= SE
or SE
M
063 ,
4 521
, 8
652 ,
9 −
=
9. Determining t-table in significance level 5 with df or db:
The writer gained t table for df = 44: S.L. 5 = 2,02
10. The Comparison between t-score with t-table:
t-score = -t-table t-score + t-table t-score = -2,02 0,245 2,02
E. Test of Hypothesis
Kategori