38
4 S-19
3 3
4 4
3 17
289 5
S-30 4
3 4
3 2
16 256
6 S-10
4 3
4 2
2 15
225 7
S-20 3
2 4
3 3
15 225
8 S-28
3 3
3 3
3 15
225 9
S-7 3
3 2
3 3
14 196
10 S-25
3 3
4 2
2 14
196 11
S-27 3
3 3
2 3
14 196
12 S-32
3 3
2 3
3 14
196 13
S-1 3
3 2
2 3
13 169
14 S-6
2 2
4 3
2 13
169 15
S-11 3
3 2
3 2
13 169
16 S-16
2 3
2 3
3 13
169 17
S-23 3
3 2
2 3
13 169
18 S-33
2 3
3 2
3 13
169 19
S-34 2
3 2
3 3
13 169
20 S-2
2 2
3 2
3 12
144 21
S-3 3
3 2
2 2
12 144
22 S-4
2 3
2 2
3 12
144 23
S-8 2
3 2
2 3
12 144
24 S-9
2 3
2 3
2 12
144 25
S-12 2
3 2
2 3
12 144
26 S-14
2 2
3 3
2 12
144 27
S-17 2
3 2
2 3
12 144
28 S-24
2 3
2 2
3 12
144 29
S-26 2
3 2
2 3
12 144
30 S-29
2 3
2 2
3 12
144 31
S-31 2
3 2
2 3
12 144
32 S-18
2 3
2 2
2 11
121 33
S-21 2
3 2
2 2
11 121
34 S-22
2 3
2 2
2 11
121 88
99 91
86 92
456 6252
4.4.1 The Computation of the Test Item Validity
“Test validity is defined as the degree to which a test measures what it claims to be measuring.” Brown: 1988: 100. A valid instrument has high level of validity.
39
The validity of the instrument was measured by applying the Pearson’s Product-Moment Coefficient of Correlation. The formula is as follows:
= ∑ − ∑ ∑
∑ ∑ ∑
− ∑ Best, 1981:248
In which: = correlation coefficient,
= number of paired scores, ∑ = sum of the products of paired X and Y scores,
∑ = the sum of the X scores, ∑ = the sum of the Y scores,
∑ = sum of the squared X scores, and ∑ = sum of the squared Y scores.
Criteria: The item test is valid if r
xy
r
table
The following is the example of counting the validity of aspect number 1 which is accent aspect, for the other items will use the same formula.
By using the formula, I obtained that: =
∑ − ∑ ∑
∑ ∑ ∑
− ∑ =
34 1218 − 88456 34 244 − 88 34 6252 − 456
= 41412 − 40128
8296 − 7744212568 − 207936
40
= 1284
5524632 =
1284 √2556864
= 1284
1599 = 0.80
On α = 5 with N = 34, it is obtained = 0.339 Because of
01
, so the item number 1 is valid. It means that the test items which include ascent aspects can be said as the valid test items. The
validity of the test items is 0.80 whereas the validity of the table is only 0.339. The entire results of test item validity analysis can be found in the appendix 6.
4.4.2 The Reliability of the Test
Test reliability refers to the consistency of the examination scores. It might be assessed in many ways. In this research, to find out the reliability of the research,
Alpha formula stated by Arikunto 2006: 196 was applied, as the following: = − 1 1 −
∑
Total Variance: =
∑ − ∑
= 6252 − 456
34 34
= 4
41
The Item Variance:
= ∑
− ∑ 2
31 = 244 − 88
34 34
= 0.47
32 = 293 − 99
34 34
= 0.15
35 = 258 − 92
34 34
= 0.26 4 3 = 2.08
the entire result of item variance can be seen in appendix 7 The computation of reliability test with alpha formula is as follows:
= 5 5
5 − 16 51 − 2.08
4 6 = 0.6 For α = 5 and number of students
= 34,
01
= 0.339 From the computation above, it can be concluded that the reliability of
the test is 0.6, whereas the reliability of the table is 0.339. Because
01
, then instrument is reliable.
4.4.3 Discriminating Power
