37
Student 4 81
Student 5 80
Student 6 71
Student 7 74
Student 8 76
Student 9 80
Student 10 79
Student 11 75
Student 12 75
Student 13 64
Student 14 73
Student 15 74
Student 16 78
Student 17 77
Student 18 79
Student 19 79
Student 20 69
Student 21 76
Student 22 78
Student 23 76
Student 24 75
Student 25 73
Student 26 80
Student 27 72
38
Student 28 70
Student 29 72
Student 30 69
From the scores that were collected above, the researcher counted the statistical scores using SPSS, such as bellow:
Table 4.4 Statistical Scores of Writing
Statistics
Writing Scores N
Valid 30
Missing Mean
75.3000 Median
76.0000 Mode
80.00 Std. Deviation
4.05267 Variance
16.424 Minimum
64.00 Maximum
81.00
From the statistic table, the mean of writing score is 75.3. Median 76, and mode 80. The highest score of writing is 81.00 and the lowest one
is 64.00. The standard deviation is 4.05 with variance 16.424.
39
B. Data Analysis
Table 4.5 Data Analysis Table
Participants X
Y XY
X
2
Y
2
Student 1 63
77 4851
3969 5929
Student 2 57
80 4560
3249 6400
Student 3 60
77 4620
3600 5929
Student 4 73
81 5913
5329 6561
Student 5 60
80 4800
3600 6400
Student 6 73
71 5183
5329 5041
Student 7 57
74 4218
3249 5476
Student 8 60
76 4560
3600 5776
Student 9 63
80 5040
3969 6400
Student 10 53
79 4187
2809 6241
Student 11 50
75 3750
2500 5625
Student 12 80
75 6000
6400 5625
Student 13 47
64 3008
2209 4096
Student 14 67
73 4891
4489 5329
Student 15 60
74 4440
3600 5476
Student 16 70
78 5460
4900 6084
Student 17 73
77 5621
5329 5929
Student 18 70
79 5530
4900 6241
Student 19 50
79 3950
2500 6241
Student 20 53
69 3657
2809 4761
40
Student 21 60
76 4560
3600 5776
Student 22 63
78 4914
3969 6084
Student 23 53
76 4028
2809 5776
Student 24 60
75 4500
3600 5625
Student 25 63
73 4599
3969 5329
Student 26 67
80 5360
4489 6400
Student 27 60
72 4320
3600 5184
Student 28 70
70 4900
4900 4900
Student 29 77
72 5544
5929 5184
Student 30 57
69 3933
3249 4761
N = 30 X=1869 Y=2259 XY=140897 X
2
=118453 Y
2
=170579 N
= 30 X
= 1869 Y
= 2259 XY = 140897
X
2
= 118453 Y
2
= 170579
r
xy
=
=
=
=
41
= =
= 0.165
To make sure the result of the calculation above, the researcher used SPSS program. The using of SPSS is to know whether the calculation that
the researcher did manually was correct and to make sure that there is no mismatching calculation between scores that the researcher counted. The
calculation of SPSS was described such as follow:
Table 4.6 SPSS Correlation Table
Correlations
Grammar Scores Writing Scores
Nilai grammar Pearson Correlation
1 .165
Sig. 2-tailed .385
N 30
30 Nilai writing
Pearson Correlation .165
1 Sig. 2-tailed
.385 N
30 30
The results of those two calculations manual calculation and SPSS calculation are same, in which show the value of r
xy
0.165. It means that there is no mismatch in the process of calculating the data.
From the calculation above, it is found that r
xy
is 0.165. The next step is to find the significance of variables by calculating r
xy
is tested by significance test formula:
t
count
=
42
In which: t
count
= t value R
= 0.165 n
= 30 Therefore, it is calculated that:
t
count
= =
= =
=
= 0.89
Before testing the t
count
, the writer made two hypotheses of significance; they are:
Ha : There is a significant correlation between two variables
Ho : There is no significant correlation between two variables
The formulation of test: 1.
If t
count
t
table
, it means that the null hypothesis is rejected and there is a significant correlation.
2. If t
count
t
table
, the null hypothesis is accepted and there is no significant correlation.
Based on the calculation above, the result is compared by t
table
in the significant of 5 and 1 and n=30, the writer found the Degree of
Freedom Df with the formula: Df = N
– nr = 30 - 2
= 28 From Df = , it is obtained t
table
of 5 = 2.05 and 1 = 2.77. It means that t
count
is lower than t
table
0.89 2.05 and 0.89 2.77. Therefore, the
