CHAPTER IV RESEARCH FINDING
A. Description of Data
As it has been mentioned, the writer conducted the filed research. Having finished doing the research about technique in teaching reading through pre-reading activities. the
Experiment class is XI-IPA 1 and the controlled class XI-IPA 2. From each class there are 30 students as the sample.
The data from the score of experiment class have been obtained as in the following: Table 1
The Test Score of Experiment Class Students N
X 1 85
2 85 3 85
4 80 5 80
6 80 7 80
8 80 9 80
10 80 11 75
12 75 13 75
14 75 15 75
16 75 17 75
18 75 19 75
20 75 21 70
22 70 23 70
24 70 25 70
26 65 27 65
28 65 29 60
30 60
N = 30 2230
The highest score for experiment class is 85; there are three students who got the highest score. The lowest score for the experiment class is 60; there are two students who have
the lowest score. The total of the experiment class score is 2230.
Table 2 The Test Score of Control Class
Students N Y
1 80 2 80
3 80 4 75
5 75 6 70
7 70 8 70
9 65
10 65 11 65
12 65 13 65
14 65 15 65
16 65 17 65
18 65 19 60
20 60 21 60
22 60 23 60
24 60 25 50
26 50 27 50
28 45 29 45
30 45
N = 30 1895
The highest score for controlled class is 80; there are three students who got the highest score. The lowest score for the controlled class is 45; there are three students who have
the lowest score. The total of the controlled class score is 1895. The differentiate result of the experiment class and the controlled class is 335.
To know the result of the test, the writer makes table of students score for each class,
both experiment class and controlled class.
Table 3 The Calculation of Both Experiment Class And
Control Class Test Students
N X Y X y x
2
y
2
1 85 80
10.7 16.8
114.49 282.24
2 85 80
10.7 16.8
114.49 282.24
3 85 80
10.7 16.8
114.49 282.24
4 80 75
5.7 11.8
32.49 139.24
5 80 75
5.7 11.8
32.49 139.24
6 80 70
5.7 6.8
32.49 139.24
M
x
= M
y
= M
x
=
SD
x
= SD
y
= =
= 7 80
70 5.7
6.8 32.49
139.24 8 80
70 5.7
6.8 32.49
139.24 9 80
65 5.7
1.8 32.49
3.24 10 80 65
5.7 1.8
32.49 3.24
11 75 65 0.7
1.8 0.49
3.24 12 75 65
0.7 1.8
0.49 3.24
13 75 65 0.7
1.8 0.49
3.24 14 75 65
0.7 1.8
0.49 3.24
15 75 65 0.7
1.8 0.49
3.24 16 75 65
0.7 1.8
0.49 3.24
17 75 65 0.7
1.8 0.49
3.24 18 75 65
0.7 1.8
0.49 3.24
19 75 60 0.7
-3.2 0.49
10.24 20 75 60
0.7 -3.2
0.49 10.24
21 70 60 -4.3
-3.2 18.49
10.24 22 70 60
-4.3 -3.2
18.49 10.24
23 70 60 -4.3
-3.2 18.49
10.24 24 70 60
-4.3 -3.2
18.49 10.24
25 70 50 -4.3
-13.2 18.49
174.24 26 65 50
-9.3 -13.2
86.49 174.24
27 65 50 -9.3
-13.2 86.49
174.24 28 65 45
-9.3 -18.2
86.49 331.24
29 60 45 -14.3
-18.2 204.49
331.24 30 60 45
-14.3 -18.2
204.49 331.24
2230 1895
1336.7 2874.2
Based on the data in table 3, it has been calculated the result of
ΣX = 2230 and ΣY =
1895. Then the writer tries to find out the mean variable X variable Y with formula:
Σ
X
Σ
Y N
N 2230
1895 30
30 = 74.3
= 63.2 Based on the table 3, it has been known the result of
Σ
x 2
= 1336.7 and
Σ
y 2
= 2874.2, the values of definitions standard variable X and variable Y are calculated by using this
formula:
Σ
X
2
Σ
Y
2
N N
=
SE
Mx
= SE
My
= =
=
=
= =
= =
= =
1336.7 2874.2
30 30
=
√
44.56 =
√
95.81 = 6.68
= 9.79 The next procedure of calculation is determining standard error mean variable X and
variable Y with this formula:
Σ
SD
x
Σ
SD
y
√ N -1 √ N -1
6.68 9.79
√30 –
1 √30 – 1
6.68 9.79
√ 29
√ 29 6.68
9.79 5.39
5.39 1.24
1.82
After the values of standard error mean of variable X and variable Y have been taken, the writer will use them to calculate the difference of mean variable X and variable Y with this
formula:
SE
Mx
– M
y
=
√
SE
Mx 2
+ SE
My 2
T
o
= T
o
=
= =
SE
Mx
– M
y
=
√1.24
2
+ 1.82
2
=
√1.5376 + 3.3124 =
√4.85 =
2.2
And the last calculation of this research is determining the value of t
o
t observation with formula:
M
x
- M
y
SE
Mx –
SE
M y
74.3 – 63.2 2.2
11.1 2.2
5.05
B. Test of Hypothesis
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