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140
Tugas A khir
140 Perencanaan Struktur Factory Outlet dan Resto 2 Lantai
Bab 5 Plat Lantai
5.6. Penulangan lapangan arah y
Mu = 225,09 kgm = 2,2509.10
6
Nmm
Mn = φ
Mu =
6 6
10 .
813 ,
2 8
, 10
. 2509
, 2
= Nmm
Rn =
=
2
.d b
Mn =
2 6
85 .
1000 10
. 813
, 2
0,389 Nmm
2
m = 29
, 11
25 .
85 ,
240 .
85 ,
= =
c f
fy
i
ρ
perlu
=
⎟ ⎟
⎠ ⎞
⎜ ⎜
⎝ ⎛
− −
× fy
Rn m
m .
. 2
1 1
1
= .
294 ,
11 1
⎟⎟ ⎠
⎞ ⎜⎜
⎝ ⎛
− −
240 389
, .
294 ,
11 .
2 1
1 = 0,0016
ρ ρ
max
ρ ρ
min
, di pakai ρ
min
= 0,0025 As =
ρ
min
b . d = 0,0025 . 1000 . 85
= 212,51 mm
2
Digunakan tulangan ∅ 10
= ¼ . π . 10
2
= 78,5 mm
2
Jumlah tulangan =
71 ,
2 5
, 78
5 ,
212 =
~ 4 buah. Jarak tulangan dalam 1 m
1
= 250
4 1000 =
mm ~ 240 mm. Jarak maksimum
= 2 x h = 2 x 120 = 240 mm As yang timbul
= 4. ¼. π.10
2
= 314 212,51 As….OK
Dipakai tulangan D 10 – 240 mm
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141
Tugas A khir
141 Perencanaan Struktur Factory Outlet dan Resto 2 Lantai
Bab 5 Plat Lantai
5.7. Penulangan tumpuan arah x
Mu = 739,56 kgm = 7,39.10
6
Nmm
Mn = φ
Mu =
= 8
, 10
. 39
, 7
6
9,23.10
6
Nmm Rn
= =
2
.d b
Mn =
2 6
85 .
1000 10
. 23
, 9
1,27 Nmm
2
m = 29
, 11
25 .
85 ,
240 .
85 ,
= =
c f
fy
ρ
perlu
= ⎟⎟
⎠ ⎞
⎜⎜ ⎝
⎛ −
− fy
Rn .
m 2
1 1
. m
1
= .
29 ,
11 1
⎟⎟ ⎠
⎞ ⎜⎜
⎝ ⎛
− −
240 27
, 1
. 29
, 11
. 2
1 1
= 0,005 ρ ρ
max
ρ ρ
min
, di pakai ρ
perlu
= 0,005 As
= ρ
perlu
. b . d = 0,005 . 1000 . 85
= 425 mm
2
Digunakan tulangan D 10 = ¼ .
π . 10
2
= 78,5 mm
2
Jumlah tulangan =
41 ,
5 5
, 78
425 = ~ 6 buah.
Jarak tulangan dalam 1 m
1
= 66
, 166
6 1000 =
mm ~ 120 mm Jarak maksimum
= 2 x h = 2 x 120 = 240 mm As yang timbul
= 6. ¼. π.10
2
= 471 425 As ….OK
Dipakai tulangan D 10 – 120 mm
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Tugas A khir
142 Perencanaan Struktur Factory Outlet dan Resto 2 Lantai
Bab 5 Plat Lantai
5.8. Penulangan tumpuan arah y
Mu = 578,80 kgm = 5,78.10
6
Nmm
Mn = φ
Mu =
= 8
, 10
. 78
, 5
6
7,22.10
6
Nmm Rn
= =
2
.d b
Mn =
2 6
95 .
1000 10
. 22
, 7
0,80 Nmm
2
M =
29 ,
11 25
. 85
, 240
. 85
, =
= c
f fy
ρ
perlu
= ⎟⎟
⎠ ⎞
⎜⎜ ⎝
⎛ −
− fy
Rn .
m 2
1 1
. m
1
= .
29 ,
11 1
⎟⎟ ⎠
⎞ ⎜⎜
⎝ ⎛
− −
240 80
, .
29 ,
11 .
2 1
1 = 0,0034
ρ ρ
max
ρ ρ
min
, di pakai ρ
perlu
= 0,0034 As
= ρ
perlu
. b . d = 0,0034 . 1000 . 95
= 323 mm
2
Digunakan tulangan ∅ 10
= ¼ . π . 10
2
= 78,5 mm
2
Jumlah tulangan =
12 ,
4 5
, 78
323 = ~ 5 buah.
Jarak tulangan dalam 1 m
1
= 200
5 1000 =
mm ~ 120 mm. Jarak maksimum
= 2 x h = 2 x 120 = 240 mm As yang timbul
= 5. ¼. π.10
2
= 392,5 323 As ….OK
Dipakai tulangan D 10 – 120 mm
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Tugas A khir
143 Perencanaan Struktur Factory Outlet dan Resto 2 Lantai
Bab 5 Plat Lantai
5.9. Rekapitulasi Tulangan
