SOAL UKK MATEMATIKA IPS SMA KELAS 11

  LATIHAN ULANGAN UMUM SEMESTER 2

  2

  2 @ QI ( I(

  II T

  6

6 B , B >

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f x ( y ) f x ( ) f y ( )

  2 $ =

• ¡ )

  2

  2

  2 t f t ( ) t

• f t ( ) t

  1 = + = +

  B = + f t ( )

  2 t

  4 K f t ( ) = 3 t

  2 f t ( )

  3 t

  8 = ₂

• f x ( ) = +

  3 16 − x { x | 4 x 4} { x | x 4}

• -

  ¡

  ∈ ¡ − ≤ ≤ ∈ ≥

  { x | 0 x 4} { x | 3 x 7}

  B ∈ ¡ ≤ ≤ K ∈ ¡ ≤ ≤

  { x | 2 x 2}

  8 ∈ ¡ − ≤ ≤ 2 $ )

  2 ³ + + x

  3 x

  x

  3 x ₃

-

  2 x

  2 x

  8

  x

  2 x 8 − − _{3 2}

• 4

  3 x x + x 3 x

  B K

  x

  2 x 8 x

  8 ⁴ − ^{2 3} 3 x

  8

• x

  8

  3

  f x ( ) 1 = $ ₂

  2 x

  8 −

  { x | x 2} { x | x 2, x 2} ∈ ¡ ≥ ∈ ¡ ≠ − ≠ -

  { x | x 2} { x | 0 x 2}

  B ∈ ¡ ≤ − K ∈ ¡ ≤ < 8 { x ∈ | 2 − < ≤ x 2}

  ¡

  

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  8

  2 ₁ − f x ( )

  o

  6 = g x ( ) = x x ≥ ( f g ) ( ) x

  2 { x ∈ | x ≤ 4} { x ∈ - | 0 < < x 4}

• x

  ¡ ¡ { x | 0 x 4} { x | 0 x 4}

  B ∈ ¡ ≤ ≤ K ∈ ¡ ≤ <

  { x | 0 x 4}

  8 ∈ ¡ < ≤ 6 f x ( ) =

  4 x + ! 2 g x ( ) = 3 ( g f )(0) = o

• ! B K

  8

  f x ( ) = x

• 2

  1 g x ( ) x 1 ( g f )( ) x

  ? 6 = − o =

• ;

  B ; K x

  1 8 < x

• 2

  = 6 ( g f )( ) x = − +

  1 g x ( ) = 4 x f x ( ) = o ₁

  2 ₁ ( x 2) ( x 1) _{1 8}

  − + − _{1 4}

• -

  B ( − − x 2) K ( − + x 2)
_{1 8 4}

  ( x 2)

  8 − ₈

  6 ( g f )( ) x =

• 2
• ²

  2 x 4 x 7 f x ( ) x 2 x 1 ( ) = o = −

• g x

  1 - 2 x

• 2 x −

  9 B K 2 x

  3 2 x

  9 − −

• 8 2 x

  3 ₂

  1 ²

  ( )

  1

  6 f x = x ( f g x )( ) x

  4 x 5 g x ( − = 3) o = − ^K

  x −

  2

• 1 ( x − 5) 1 ( x − 3)

  −

• B 1 ( x 1) K 1 ( x 3)

  8

• 1 ( x 1)

  2 x

  5 − −

  1 f (1)

  6 f x ( ) = =

  3 x

  2 −

• ;? B H K ; 8 ;

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  −

  ( g f )(2 x 3) 3 x 6 g x ( ) x

  4

  6 o = − = + f (8)

• 1

  =

• B K

  8 _{1 1 1 1} − −

¹

−

  ( 6 f ( ) x = x − 1) g ( ) x (3 x ) _{5 = − ( f g ) (6) = 2 o}

• ; B K ;

  8

  3 ^{1 1} − −

  6 f x ( )

  2 x 3 g x ( ) = x 1 ( g f )( ) a 2 a = o = =

• B = K

  8

• x

  1

  6 f x ( ) = , x ≠ $ $ ₁ x − f ( ) p

  =

• H B K H

8 H

  _{2 2} 

  2 x − 8 x − 2 x 

  ! lim − = ₂   x

  → x

  2 2 x

  4 − −

   

• B ! K

  ∞ 8 = ₂ x (3 a x )

  3 a

• − − ? lim ...

  =

  x → a x a

  −

• < B < K < 8 <

  1

• 2 x

  = lim =

  →−

  2 4 x

• x

  6 ^{1 2} −

• ; B K ;

  8 __________________________________________________________ WWW.TERSATU.COM

  2 x + − −

  3 x

  1 lim = _{1 2}

  x →

  1 x −

  ; H - H B ; H K H

  8 ₃

  3 x 5 x − lim ₃ =

  4 x 6 x

• x →∞

  ; H - H! B H K H 8 ; H! ₂

  2 9 x 2 x

  5 − − − =

• lim 3 x

  x →∞ )

  (

  ; H! - ?H B ;?H K H! 8 ; H f x ( ) − f (3)

  2 6 f x ( ) x lim ... =

  = ₃

  x → x

  3 −

  ; H - H B K ∞

  8 H

  6 x 7 f '(3)

  6 = H - ?H B H K H

• f x ( )

  8 H? ₂

  2

  1

  x − 6 f x ( ) f '( ) x

  = =

  x

  2 x x

• 3 x

  5 x −

• -

  2 x x

  x x

  5 x − 3 x −

  B K

  2

  2 x

  2 2 x

  8

• 3 x

  2 x _{3 3}

• 2(5 h ) 2(5)

  − lim ... =

  h → h

• B K

  8

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  2

  3

  2 x 1) = −

• ! f x ( ) 5( x

  2

  2

• x x x x
• 2

  15(2 2) 30( 1)( + + 2 − 1)

  2

  2

  2

  2

  B x x K x x x

  15( 2 − + + 1) 15(2 2) ( 2 − 1)

• 2

  2

  2 8 x x x

  10( 1)( + + 2 − 1)

  2

  3

  ? 6 = = ₄

• f x ( ) f '( ) x

  x

  1 x ₃ − 8 x 3 − 8 x

• ₃

  3

• -

  ⁴
^{2 4 2 2}

  ( x 1) x ( x 1) x + + _{3 3} 8 x 3 8 x

  3 −

  − +

  B

  ( x 1) x ( x 1) x ₃ ^{4 2 K 4 2 2} 8 x

  3 −

  8 ^{4 2 2}

• ( x 1) x
2<

• = ( " y = 1 ( x 4) % H &amp;

  2 x 25 y

  7 25 x 2 y

  7 − = + = + + - 2 x

  25 y

  7 25 x 2 y

• 7 B + = K − =

  x y

  8

  2 − 25 − =

  7 ₂

  2

  ( " y = x − x % ; &amp; ; ; / - &lt; ; / B ; ; / K ; ; / 8 &lt; ; / ₂

  4 x 5 $ = −

• ( " y x

  / &lt; ; ; / - ; % = / B ; &lt; ! / K ; &lt; / 8 ; % /

  ( " − ≤ ≤

  1 2 $

  f x ( ) = x −

  3 x

• x

  3 P

  ;! - ! B ; K =

  8 _{1 3 2} f x ( ) x

  3 x

  A = − $ ₆

  1 x 6 x &lt; x &gt;

  12 &lt; &lt; -

  x

  1 x

  12 K &lt; &gt; &lt; &lt; 6 x

  6 B 1 x

  6

  8 − &lt; &lt;

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  2 x − 5 x 20 * % ( #&amp;

• 5
⁴ 6 " y =

  /

• ; B K

  8

  2 ²

• 2

  x x

• 6 . x kx + = k x x

  1

  2

  1

  2

• /
• ; B K

8 H

  ₃

  6 = − x

• f x ( ) (1 2 ) x

  &lt; &lt; - 1/ 2

  x 1/ 2

  &lt;

  x x B &gt; 1/ 2 K &gt; x

  8 &lt; _{1 3 2 3} −

  ! 6 = dy dx = ... x

• y x ( x 4)

  4 −

• x ( x 4)
^{1 − − 2 3 5 3} 3<
• _{2 3 5 3}
• 3 x ( x 4) 4 x

  − _{5 2 3 5 3}

  − −

  B K

• x ( x 4)

  3 x ( x 4) ⁹

• 2 3 5 3

  x

  −

  2

  8 2 3 5 3

• 3 x ( x 4)
_{3 2}

  ? y = + + + + x

  6 x 9 x

  7 P

  %; &amp; - % &amp; B %; ?&amp; K % &amp; 8 %; &amp;

• =
• $ * U /

  1

  1

  1

• a a a

  2

  6

  8

  1

  1 B a K a

  3

  6

  1 8 a

  4

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  6 $

  2

  ( ) = 100 1.200 $

• C n n
• ! B K

  8

• p x ( )

  5 0, 002 x

  $ % &amp; = − C x ( ) 3 1,1 x

  = + + $

  ? - ? B ? K ? 8 ? ii. iSIAN

  6 $ c

  &gt;

  f c '( ) f x ( ) f c ( )

  − lim

  x c → x − c

  2 x − −

• 2 x

  D lim x →

x

• 25 x

  4 B $ % &amp;

  H N B $ ) _{3 2}

  3 x 4 y 3( x x )

• " = − = − $ $
• # % !&amp;
_{3 2} f x ( ) x ax b
• y x

  1 = + + +

  f '(2)

  4 f ''(2)

  1

  

! 2 # % &amp; / = = − '% &amp; /

g '(2) =

  5

  8 d

  3

  [ f ( ) x g ( )] x /

• 2

  dx ______________________________________________________ WWW.TERSATU.COM

  d

  [ ( ) ( )] f x g x

  / dx d

• [ ( ( ))] f g x /

  dx ? $ $ $

   

• − = B $ $ )    

  1 − f x ( ) x

  2 g f

  = 2 = − =

• ' $
• g x '( ) g x f x
• 3$ '( ) '( )

  8 1 2

  &gt; p x ( ) = (182 − x 36) * $ $ $

• , # # , ,, ,0 ,

  , ,

  2

  c f c) '(

• , 00 &amp;!
• 0 F H, F * 99 " , # * *99 0 0 -

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