34 −
Teacher check students works by asking some of them to read out their answer. Now, Anita what is your answer for number one? Are you
sure? Class, do you agree with Anitas answer? Etc. f.
Closure −
Teacher concludes the lesson. Teacher may say, So, what do you get from our lesson today? Do you enjoy your reading today? Etc.
− Teacher closes the lesson. Teacher may say, I think time is up, see
you next Tuesday, bye.
B. Findings of the Research
1. Description of the Data
+
, - -
. -
+ .
. .
. 0 . +
. .
Table 4.1
1
35
1
1 1
2
1 1
1 2
1
1. Determining Mean of Pre-test Score of Experiment Class:
M
x
1
= x N
= 1.290 20
= 64.5
2. Determining Mean of Post-test Score of Experiment Class:
M
y
l
= y N
= 1.495
36 20
= 74.75
Table 4.2 The Test Score of the Controlled Class
Students Pre-test x
Post-test y
1 50
60 2
60 70
3 50
60 4
65 75
5 75
85 6
65 60
7 70
80 8
65 70
9 65
75 10
70 60
11 70
65 12
65 75
13 55
65 14
60 70
15 60
70 16
70 75
17 55
70 18
50 60
19 55
70 20
55 65
1. Determining Mean of Pre-test Score of Controlled Class:
37 M
x2
= x N
= 1.230 20
= 63.25 2.
Determining Mean of Post-test Score of Controlled Class: M
y2
= y N
= 1.380 20
= 69
Table 4.3 The Calculation of the Test Score of the Experiment Class
Students Pre-test x
Post-test y D = x-y
D2 = x-y
2
1
1
−10 100
2 −15
225 3
−10 100
4 −10
100 5
1
−5 25
6 −15
225 7
1
−20 400
8 −5
25 9
10 −15
225 11
−15 225
12 −10
100 13
1
−10 100
14
1
−20 400
15 −20
400
38 16
−15 225
17 −5
25 18
−10 100
19
1
−10 100
20 −5
25 = −215
D
2
= 3.125
Table 4.4 The Calculation 0f the Test Score of the Controlled Class
Students Pre-test x
Post-test y D = x-y
D2 = x-y
2
1 50
60 −10
100 2
60 70
−10 100
3 50
60 −10
100 4
65 75
−10 100
5 75
85 −10
100 6
65 60
5 25
7 70
80 −10
100 8
65 70
−5 25
9 65
75 −10
100 10
70 60
10 100
11 70
65 5
25 12
65 75
−10 100
13 55
65 −10
100 14
60 70
−10 100
15 60
70 −10
100 16
70 75
−5 25
17 55
70 −15
225 18
50 60
−10 100
19 55
70 −15
225
39 20
55 65
−10 100
= −150 D
2
= 1.950
2. Analysis of the Data
From the data description above, the writer analyzed the score from the experiment and controlled class by integrating the results into the formula as follows:
a. Determining Mean of Difference of Experiment Class:
M
D1
=
D
N = −215
20 = −10.75
b. Determining Mean of Difference of Controlled Class:
M
D 2
=
D
N = −150
20 = −7.5
c. Determining Deviation Standard of Difference of Experiment Class:
SD
D 1
=
D
2
− D
2
N N =
3.125 − −215 20
20 =
156.25 − −2.31 =
156.25 + 2.31 =
158.56 = 12.6
d. Determining Deviation Standard of Difference of Controlled Class:
SD
D 2
=
D
2
− D
2
N N
40 =
1.950 − −150
2
20 20 =
97.5 − −1.125 =
98.625 = 9.93
e. Determining Standard Error from Mean of Difference of Experiment Class:
SE
M
D1
= SD
D1
N − 1 = 12.6
20 − 1 = 12.6
19 = 12.6
4.3
= 2.9 f.
Determining Standard Error from Mean of Difference of Controlled Class: SE
M
D2
= SD
D2
N − 1 = 9.93
20 − 1 = 9.93
19 = 9.93
4.3
= 2.31 g.
Determining t-observation t
o
: t
o
=
M
D1
–
M
D2
41
SE
MD1
– SE
MD2
= - 10.75 – -7.5 2.9 – 2.31
= -10.75 + 7.5 2.9 – 2.31
= -3.25 0.59
= -5.5 Note: Tanda – minus di sini bukanlah tanda aljabar; karena itu dengan t
o
sebesar −5.5 itu dapat kita baca: ada selisih derajat perbedaan sebesar 5.5.
35
h. Determining t-table t
t
in significance level 5 and 1 with degree of freedom df df = N1 + N2 – 2
= 20 + 20 – 2 = 40 – 2
= 38 See the table of t values of degree of freedom df = 38 at significance level 5
and 1 t
table
t
t
at significance level 5 = 2.02 t
table
t
t
at significance level 1 = 2.71 5 = t
o
t
t
= -5.5 2.02 1 = t
o
t
t
= -5.5 2.71
3. Test of Hypothesis