Decibel | Dokumen 471 DECIBEL
Pengertian Gain, Attenuasi dan
Decibels
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telkomd.pnj@gmail.com
telkom14pnj@gmail.com
Gain, attenuation, dan
Decibel
• Gain = penguatan, atau dikatakan
sebagai perbandingan output dan input
dimana output lebih besar daripada input.
• Attenuation = redaman, dikatakan
sebagai perbandingan output dan input
dimana output lebih kecil daripada input.
• Decibel (dB): satuan ukuran yang dipakai
untuk menyatakan Gain dan Attenuation.
Gain = amplification
output Vout
Av
input
Vin
Vout
A gain
Vin
output Pout
Ap
input
Pin
Contoh soal
1. Berapa penguatan tegangan sebuah penguat yang menghasilkan
tegangan keluaran 750 mV dari sumber masukan 30 V ?
Vout 750 10 3
Av
25.000
6
Vin
30 10
2. The power output of an amplifier is 6 watts (W). The power gain is 80.
What is the input power?
Pout
Ap
Pin
therefore
Pout
Pin
Ap
6
Pin 0.075 W 75 mW
80
Contoh soal
3. Three cascaded amplifiers have power gain of 5, 2, and 17.
The input power is 40 mW. What is the output power?
Ap A1 A2 A3 5 2 17 170
Pout
Ap
Pin
therefore
Pout Ap Pin
Pout 170(40 10 3 ) 6.8 W
4. A two stage amplifier has an input power of 25 W and an output
power of 1.5 mW. One stage has a gain of 3. What is the gain of
the second stage?
Pout 1.5 10 3
Ap
60
6
Pin 25 10
Ap A1 A2
if A1 3, then 60 3 A2 and A2 60 / 3 20
Attenuation = redaman
Vin
output Vout
attenuation A
input
Vin
R1=200
R2=100
Vin
Vout
R2
Vin
R1 R2
R2 100
A
0.3333
R1 R2 300
Loss
stage
Loss
circuit
Loss
component
A1=0,2
A2=0,9
A3=0,06
AT= A1 x A2 x A3 = 0.2 X 0.9 x 0.06 = 0.0108
Vout = AT Vin= 0.0324 = 32.4 mV
Vout
Redaman
Vin
R1=750
Vout = Vin
R2=250
Vin = 1.5 V
250
(750 250)
250
A1
0,25
1000
A1
A2 = 4
Loss 0.15V
stage
A1= 0.1
A2= 10
1.5V
AT A1 A2 0,25(4) 1
Vout = 6.75 V
Loss 0.45V
stage
A3= 0.3
A4= 15
AT = A1 A2 A3 A4 = (0.1)(10)(0.3)(15) = 4.5
Contoh soal
A voltage divider like that shown in Fig. 2-5 has values of R1 = 10 k and
R2 = 470 .
a. What is the attenuation?
A1
R2
470
R1 R2 10,470
A1 0.045
b. What amplifier gain would you need to offset the loss for an overall
gain of 1 ?
AT = A1A2
where A1 is attenuation and A2 is the amplifier gain
1 0.045 A2
1
A2
22.3
0.045
Note:
To find the gain that will offset the loss for unity gain, just take
the reciprocal of attenuation: A2 = 1/A1
Contoh soal
An amplifier has a gain of 45,000, which is too
much for the application. With an input voltage of
20V, what attenuation factor is needed to keep
the output voltage from exceeding 100 mV?
Let A1 = amplifier gain = 45,000; A2 =
attenuation factor; AT = total gain.
Vout 100 10 3
AT
5,000
6
Vin
20 10
AT A1 A2
therefore
AT
5,000
A2
0.1111
A1 45,000
Decibel (dB)
Vout
dB 20 log
Vin
(1)
I out
dB 20 log
I in
( 2)
Pout
dB 10 log
Pin
(3)
It is common for electronic circuits
and systems to have extremely
high gains or attenuations, often
in excess of 1 million.
Dengan mengubah angka di atas
menjadi decibel (dB) akan
membuatnya terkesan menjadi
lebih kecil dan mudah digunakan.
Formula (1) untuk menyatakan penguatan (gain) atau
redaman (attenuation) tegangan dari suatu rangkaian.
Formula (2) untuk penguatan atau redaman arus
Formula (3) untuk penguatan atau redaman daya
Contoh
a. An amplifier has an input of 3 mV and an output of 5 V. What is
the gain in decibels?
dB 20 log
5
20 log 1666.67 20(3.22) 64.4
0.003
b. A filter has a power input of 50 mW and an output of 2 mW.
What is the gain or attenuation?
2
dB 10 log 10 log 0.04 10( 1.398) 13.98
50
Note that when the circuit has gain, the decibel figure
is positive. If the gain is less than 1, which means that
there is an attenuation, the decibel figure is negative.
dB (decibel)
Adalah satuan factor penguatan jika nilainya positif, dan
pelemahan/redaman/loss jika nilainya negative.
Jika input = 1 watt, output = 100 watt maka terjadi
penguatan (G) 100 kali, maka G = 10 log 100/1 = 20 dB
Jika input = 100 watt, output = 50 watt maka terjadi
redaman/loss daya (G), maka G = 10 log 50/100 = -3 dB
( maka disebut redaman / loss 3 dB)
• dBW (Decibel Watt ) dan dBm adalah satuan level
daya
• dBW :adalah satuan level daya dengan
referensi daya 1 watt P(dBW) = 10 Log P(watt)/1
watt
dBm:adalah satuan level daya dengan referensi
daya 1 mW = 10-3 watt
• P (dBm) = 10 Log P(watt)/10-3 watt
• 10 Watt = P (dBW) = 10 Log 10 Watt/1 Watt (= 10 Log
10 = 10 dBW)
• 1000 Watt = P (dBW) = 10 Log 1000 Watt /1 Watt (=
10 Log 1000 = 30 dBW)
• 10 Watt = P(dBm) = 10 Log 10/10-3 = 10 Log 104 =
10*4 = 40 dBm
• 100 Watt = P(dBm) = 10 Log 100/10-3 = 10 Log 105
= 10*5 = 50 dBm
• 1000 Watt = P(dBm) = 10 Log 1000/10-3 = 10 Log
106 = 10*6 = 60 dBm
• Terlihat bahwa dari dBw ke dBm terdapat selisih 30 dB
sehingga dapat dirumuskan :
P (dBm) = P (dBW) + 30 atau, P (dBW) = P (dBm) – 30
Contoh :
1. Sebuah Amplifier mempunyai gain = 20 dB, jika
diberi input 10 dBm berapa output amplifier
tersebut? Jawab : Pout (dBm) = Pin(dBm) + G =
10 + 20 = 30 dBm.
2. Sebuah Amplifier dengan gain 30 dB, jika
outputnya sebesar 45 dBm berapa level
inputnya? Jawab : Pout(dBm) = Pin (dBm) + G =?
Pin = Pout G = 45 - 30 = 15 dBm
3. Output amplifier sebesar 30 dBm akan dilewatkan
kabel dengan redaman / loss 2 dB. Berapa level
sinyal setelah melewati kabel?
Jawab : Pout = Pin L = 30 - 2 = 28 dBm
gain (redaman) total:
A1=15dB
A2= - 20dB
A3= 35dB
Loss
stage
AT = A1 + A2 + A3
AT = 15 – 20 + 35 = 30 dB
Antilog:
Contoh soal
1. A power amplifier with a 40 dB gain has an output power of 100 W.
What is the input power?
Pout
dB 10 log
Pin
Pout
40
log
10
Pin
Pout
10 4
Pin
Pout
anti log 4
Pin
Pout
dB
log
10
Pin
P
100
Pin out
10 mW
10,000 10,000
2. A power amplifier has a gain of 60 dB. If the input voltage is 50V,
what is the output voltage?
dB 20 log
Vout
3 log
Vin
Vout
Vin
Vout 1000 Vin
V
dB
log out
20
Vin
Vout
103 1000
Vin
Vout 1000(5 10 6 ) 50 mV
dBm dan dB
dBm adalah ratio logaritmik dengan acuan 1 mW untuk daya
dB adalah ratio logaritmik dengan acuan 1 Volt untuk
tegangan
Px
dBm 10 log
1 mW
Vx
dan dB 20 log
1 V
Contoh:
1. Nyatakan 20 dBm dalam watt.
Daya = 100 mW
2. Nyatakan 40 dB dalam volt.
Tegangan = 100 V
Contoh:
A1= 30dB
1mW
A2= - 10dB
Loss
stage
A3= 3dB
???
Decibels
bangtelkom2014@gmail.com
telkomd.pnj@gmail.com
telkom14pnj@gmail.com
Gain, attenuation, dan
Decibel
• Gain = penguatan, atau dikatakan
sebagai perbandingan output dan input
dimana output lebih besar daripada input.
• Attenuation = redaman, dikatakan
sebagai perbandingan output dan input
dimana output lebih kecil daripada input.
• Decibel (dB): satuan ukuran yang dipakai
untuk menyatakan Gain dan Attenuation.
Gain = amplification
output Vout
Av
input
Vin
Vout
A gain
Vin
output Pout
Ap
input
Pin
Contoh soal
1. Berapa penguatan tegangan sebuah penguat yang menghasilkan
tegangan keluaran 750 mV dari sumber masukan 30 V ?
Vout 750 10 3
Av
25.000
6
Vin
30 10
2. The power output of an amplifier is 6 watts (W). The power gain is 80.
What is the input power?
Pout
Ap
Pin
therefore
Pout
Pin
Ap
6
Pin 0.075 W 75 mW
80
Contoh soal
3. Three cascaded amplifiers have power gain of 5, 2, and 17.
The input power is 40 mW. What is the output power?
Ap A1 A2 A3 5 2 17 170
Pout
Ap
Pin
therefore
Pout Ap Pin
Pout 170(40 10 3 ) 6.8 W
4. A two stage amplifier has an input power of 25 W and an output
power of 1.5 mW. One stage has a gain of 3. What is the gain of
the second stage?
Pout 1.5 10 3
Ap
60
6
Pin 25 10
Ap A1 A2
if A1 3, then 60 3 A2 and A2 60 / 3 20
Attenuation = redaman
Vin
output Vout
attenuation A
input
Vin
R1=200
R2=100
Vin
Vout
R2
Vin
R1 R2
R2 100
A
0.3333
R1 R2 300
Loss
stage
Loss
circuit
Loss
component
A1=0,2
A2=0,9
A3=0,06
AT= A1 x A2 x A3 = 0.2 X 0.9 x 0.06 = 0.0108
Vout = AT Vin= 0.0324 = 32.4 mV
Vout
Redaman
Vin
R1=750
Vout = Vin
R2=250
Vin = 1.5 V
250
(750 250)
250
A1
0,25
1000
A1
A2 = 4
Loss 0.15V
stage
A1= 0.1
A2= 10
1.5V
AT A1 A2 0,25(4) 1
Vout = 6.75 V
Loss 0.45V
stage
A3= 0.3
A4= 15
AT = A1 A2 A3 A4 = (0.1)(10)(0.3)(15) = 4.5
Contoh soal
A voltage divider like that shown in Fig. 2-5 has values of R1 = 10 k and
R2 = 470 .
a. What is the attenuation?
A1
R2
470
R1 R2 10,470
A1 0.045
b. What amplifier gain would you need to offset the loss for an overall
gain of 1 ?
AT = A1A2
where A1 is attenuation and A2 is the amplifier gain
1 0.045 A2
1
A2
22.3
0.045
Note:
To find the gain that will offset the loss for unity gain, just take
the reciprocal of attenuation: A2 = 1/A1
Contoh soal
An amplifier has a gain of 45,000, which is too
much for the application. With an input voltage of
20V, what attenuation factor is needed to keep
the output voltage from exceeding 100 mV?
Let A1 = amplifier gain = 45,000; A2 =
attenuation factor; AT = total gain.
Vout 100 10 3
AT
5,000
6
Vin
20 10
AT A1 A2
therefore
AT
5,000
A2
0.1111
A1 45,000
Decibel (dB)
Vout
dB 20 log
Vin
(1)
I out
dB 20 log
I in
( 2)
Pout
dB 10 log
Pin
(3)
It is common for electronic circuits
and systems to have extremely
high gains or attenuations, often
in excess of 1 million.
Dengan mengubah angka di atas
menjadi decibel (dB) akan
membuatnya terkesan menjadi
lebih kecil dan mudah digunakan.
Formula (1) untuk menyatakan penguatan (gain) atau
redaman (attenuation) tegangan dari suatu rangkaian.
Formula (2) untuk penguatan atau redaman arus
Formula (3) untuk penguatan atau redaman daya
Contoh
a. An amplifier has an input of 3 mV and an output of 5 V. What is
the gain in decibels?
dB 20 log
5
20 log 1666.67 20(3.22) 64.4
0.003
b. A filter has a power input of 50 mW and an output of 2 mW.
What is the gain or attenuation?
2
dB 10 log 10 log 0.04 10( 1.398) 13.98
50
Note that when the circuit has gain, the decibel figure
is positive. If the gain is less than 1, which means that
there is an attenuation, the decibel figure is negative.
dB (decibel)
Adalah satuan factor penguatan jika nilainya positif, dan
pelemahan/redaman/loss jika nilainya negative.
Jika input = 1 watt, output = 100 watt maka terjadi
penguatan (G) 100 kali, maka G = 10 log 100/1 = 20 dB
Jika input = 100 watt, output = 50 watt maka terjadi
redaman/loss daya (G), maka G = 10 log 50/100 = -3 dB
( maka disebut redaman / loss 3 dB)
• dBW (Decibel Watt ) dan dBm adalah satuan level
daya
• dBW :adalah satuan level daya dengan
referensi daya 1 watt P(dBW) = 10 Log P(watt)/1
watt
dBm:adalah satuan level daya dengan referensi
daya 1 mW = 10-3 watt
• P (dBm) = 10 Log P(watt)/10-3 watt
• 10 Watt = P (dBW) = 10 Log 10 Watt/1 Watt (= 10 Log
10 = 10 dBW)
• 1000 Watt = P (dBW) = 10 Log 1000 Watt /1 Watt (=
10 Log 1000 = 30 dBW)
• 10 Watt = P(dBm) = 10 Log 10/10-3 = 10 Log 104 =
10*4 = 40 dBm
• 100 Watt = P(dBm) = 10 Log 100/10-3 = 10 Log 105
= 10*5 = 50 dBm
• 1000 Watt = P(dBm) = 10 Log 1000/10-3 = 10 Log
106 = 10*6 = 60 dBm
• Terlihat bahwa dari dBw ke dBm terdapat selisih 30 dB
sehingga dapat dirumuskan :
P (dBm) = P (dBW) + 30 atau, P (dBW) = P (dBm) – 30
Contoh :
1. Sebuah Amplifier mempunyai gain = 20 dB, jika
diberi input 10 dBm berapa output amplifier
tersebut? Jawab : Pout (dBm) = Pin(dBm) + G =
10 + 20 = 30 dBm.
2. Sebuah Amplifier dengan gain 30 dB, jika
outputnya sebesar 45 dBm berapa level
inputnya? Jawab : Pout(dBm) = Pin (dBm) + G =?
Pin = Pout G = 45 - 30 = 15 dBm
3. Output amplifier sebesar 30 dBm akan dilewatkan
kabel dengan redaman / loss 2 dB. Berapa level
sinyal setelah melewati kabel?
Jawab : Pout = Pin L = 30 - 2 = 28 dBm
gain (redaman) total:
A1=15dB
A2= - 20dB
A3= 35dB
Loss
stage
AT = A1 + A2 + A3
AT = 15 – 20 + 35 = 30 dB
Antilog:
Contoh soal
1. A power amplifier with a 40 dB gain has an output power of 100 W.
What is the input power?
Pout
dB 10 log
Pin
Pout
40
log
10
Pin
Pout
10 4
Pin
Pout
anti log 4
Pin
Pout
dB
log
10
Pin
P
100
Pin out
10 mW
10,000 10,000
2. A power amplifier has a gain of 60 dB. If the input voltage is 50V,
what is the output voltage?
dB 20 log
Vout
3 log
Vin
Vout
Vin
Vout 1000 Vin
V
dB
log out
20
Vin
Vout
103 1000
Vin
Vout 1000(5 10 6 ) 50 mV
dBm dan dB
dBm adalah ratio logaritmik dengan acuan 1 mW untuk daya
dB adalah ratio logaritmik dengan acuan 1 Volt untuk
tegangan
Px
dBm 10 log
1 mW
Vx
dan dB 20 log
1 V
Contoh:
1. Nyatakan 20 dBm dalam watt.
Daya = 100 mW
2. Nyatakan 40 dB dalam volt.
Tegangan = 100 V
Contoh:
A1= 30dB
1mW
A2= - 10dB
Loss
stage
A3= 3dB
???