PENYERAPAN KADMIUM (Cd) OLEH FRAKSI TERLARUT DAN FRAKSI TIDAK TERLARUT PADA KETAN HITAM (Oryza Sativa, L Forma Glutinosa) : PENGARUH UKURAN PARTIKEL DAN KONSENTRASI ADSORBEN - Unika Repository

7. LAMPIRAN Lampiran 1. Hasil Uji Beda

  

1.1. Hasil Uji Beda Penyerapan Cd oleh Fraksi Terlarut (Soluble) Antar Konsentrasi

Padatan Ketan Hitam soluble a,b

  Duncan Subset konsentrasi N

  1

  2

  3 20% 15 8,4393 15% 15 28,6962 10% 15 32,3896 Sig. 1,000 1,000 1,000 Means for groups in homogeneous subsets are displayed.

  Based on Type III Sum of Squares The error term is Mean Square(Error) = 13,522.

  a.

  Uses Harmonic Mean Sample Size = 15,000.

  b.

  Alpha = ,05.

  

1.2. Hasil Uji Beda Penyerapan Cd Fraksi Terlarut (Soluble) Antar Ukuran Partikel (Mesh)

Ketan Hitam soluble a,b

  Duncan Subset mesh N

  1

  2

  3 100 15 16,5239

  80 15 24,8798 40 15 28,1215 Sig. 1,000 1,000 1,000 Means for groups in homogeneous subsets are displayed.

  Based on Type III Sum of Squares The error term is Mean Square(Error) = 13,522.

  a.

  Uses Harmonic Mean Sample Size = 15,000.

  b.

  Alpha = ,05.

  

1.3. Hasil Uji Beda Penyerapan Cd Fraksi Tidak Terlarut (Insoluble) Antar Konsentrasi

Padatan Ketan Hitam

  Duncan

  Alpha = ,05.

  a.

  Uses Harmonic Mean Sample Size = 15,000.

  Based on Type III Sum of Squares The error term is Mean Square(Error) = 18,857.

  3 Subset Means for groups in homogeneous subsets are displayed.

  2

  1

  N

  80 100 Sig.

  40

  1,000 1,000 1,000 mesh

  15 54,0223 15 61,7000 15 71,5966

  a,b

  insoluble

  

1.4. Hasil Uji Beda Penyerapan Cd oleh Fraksi Tidak Terlarut (Insoluble) Antar Ukuran

Partikel (Mesh) Ketan Hitam insoluble

  b.

  Alpha = ,05.

  a.

  Uses Harmonic Mean Sample Size = 15,000.

  Based on Type III Sum of Squares The error term is Mean Square(Error) = 18,857.

  3 Subset Means for groups in homogeneous subsets are displayed.

  2

  1

  N

  1,000 1,000 1,000 konsentrasi 10% 15% 20% Sig.

  15 38,6488 15 61,7170 15 86,9532

  a,b

  Duncan

  b.

  

1.5. Hasil Uji Beda Total Penyerapan Cd oleh Fraksi Terlarut (Soluble) dan Tidak Tidak

Terlarut (Insoluble) Antar Konsentrasi Padatan Ketan Hitam total a,b

  Duncan Subset konsentrasi N

  1

  2

  3 10% 15 71,0384 15% 15 90,4133 20% 15 95,3925 Sig.

  1,000 1,000 1,000 Means for groups in homogeneous subsets are displayed. Based on Type III Sum of Squares The error term is Mean Square(Error) = 21,824.

  a.

  Uses Harmonic Mean Sample Size = 15,000.

  b.

  Alpha = ,05.

  

1.6. Hasil Uji Beda Total Penyerapan Cd oleh Fraksi Terlarut (Soluble) dan Tidak Tidak

Terlarut (Insoluble) Antar Ukuran Partikel (Mesh) Ketan Hitam total a,b

  Duncan Subset mesh N

  1

  2

  40 15 82,1439 80 15 86,5798 100 15 88,1205 Sig. 1,000 ,372 Means for groups in homogeneous subsets are displayed.

  Based on Type III Sum of Squares The error term is Mean Square(Error) = 21,824.

  a.

  Uses Harmonic Mean Sample Size = 15,000.

  b.

  Alpha = ,05.

1.7. Hasil Uji Beda Penyerapan Cd oleh Kontrol soluble

  a

  Duncan Subset for alpha = .05

  Konsentrasi N

  1

  2

  3 20% 5 7,76720 15% 5 13,23500 10% 5 37,03900 Sig.

  1,000 1,000 1,000 Means for groups in homogeneous subsets are displayed.

  a.

  Uses Harmonic Mean Sample Size = 5,000.

  insoluble a

  Duncan Subset for alpha = .05

  Konsentrasi N

  1

  2

  3 10% 5 32,38040 15% 5 57,93600 20% 5 79,01360 Sig.

  1,000 1,000 1,000 Means for groups in homogeneous subsets are displayed.

  a.

  Uses Harmonic Mean Sample Size = 5,000.

  total a

  Duncan Subset for alpha = .05

  Konsentrasi N

  1

  2 10% 5 69,41960 15% 5 71,17072 20% 5 86,78049 Sig.

  ,191 1,000 Means for groups in homogeneous subsets are displayed.

  a.

  Uses Harmonic Mean Sample Size = 5,000.

  Lampiran 2. Hasil Normalitas Data

  2.1. Tabel Normalitas Data Ketan Hitam Tests of Normality a

  Kolmogorov-Smirnov Shapiro-Wilk konsentrasi Statistic df Sig. Statistic df Sig. soluble 10%

  ,143 15 ,200* ,936 15 ,335 15% ,115 15 ,200* ,961 15 ,712 20%

  ,112 15 ,200* ,970 15 ,856 insoluble 10% ,168 15 ,200* ,910 15 ,136

  15% ,176 15 ,200* ,902 15 ,103 20%

  ,156 15 ,200* ,957 15 ,641 total 10% ,246 15 ,015 ,915 15 ,164

  15% ,145 15 ,200* ,951 15 ,536 20%

  ,212 15 ,068 ,896 15 ,084 *. This is a lower bound of the true significance.

  a.

  Lilliefors Significance Correction

  Tests of Normality

a

  Kolmogorov-Smirnov Shapiro-Wilk mesh Statistic df Sig. Statistic df Sig. soluble

  40 ,144 15 ,200* ,937 15 ,342

  80 ,211 15 ,070 ,869 15 ,033

  100 ,221 15 ,047 ,894 15 ,078 insoluble

  40 ,165 15 ,200* ,891 15 ,069 80 ,203

  15 ,099 ,871 15 ,035 100

  ,173 15 ,200* ,914 15 ,157 total

  40 ,166 15 ,200* ,929 15 ,266 80 ,251

  15 ,012 ,861 15 ,025 100

  ,234 15 ,027 ,849 15 ,017 *. This is a lower bound of the true significance.

  a.

  Lilliefors Significance Correction

• .

  10% 15% 20% Total

  Shapiro-Wilk This is a lower bound of the true significance.

  a

  Kolmogorov-Smirnov

  Statistic df Sig. Statistic df Sig.

  Konsentrasi 10% 15% 20% 10% 15% 20% 10% 15% 20% soluble insoluble total

  ,227 5 ,200* ,916 5 ,507 ,315 5 ,119 ,828 5 ,134 ,190 5 ,200* ,947 5 ,717 ,199 5 ,200* ,970 5 ,875 ,240 5 ,200* ,922 5 ,543 ,194 5 ,200* ,972 5 ,889 ,286 5 ,200* ,792 5 ,070 ,255 5 ,200* ,883 5 ,324 ,206 5 ,200* ,917 5 ,510

  Tests of Normality

  

3.1. Tabel Deskriptif Statistik Penyerapan Cd oleh Fraksi Terlarut (Soluble) antar

Konsentrasi Padatan dan Ukuran Partikel Ketan Hitam                

  2.1. Tabel Normalitas Data Selulosa (Kontrol) Lampiran 3. Tabel Deskriptif Statistik

  Mean Std. Deviation N

  80 100 Total konsentrasi

  Descriptive Statistics Dependent Variable: soluble 44,2119 4,96733

  40

  80 100 Total

  40

  80 100 Total

  40

  80 100 Total

  40

  15 28,1215 14,10826 15 24,8798 12,79755 15 16,5239 9,25622 15 23,1751 12,92737 45 mesh

  15 11,9491 3,41851 5 8,6278 1,85812 5 4,7411 2,03029 5 8,4393 3,84707

  15 28,2036 3,11844 5 36,8585 3,83461 5 21,0266 3,60177 5 28,6962 7,45488

  5 29,1530 4,76598 5 23,8040 4,20031 5 32,3896 9,92795

  Lilliefors Significance Correction a.

  

Descriptive Statistics

  15 54,0223 24,13515 15 mesh

  40

  80 100 Total konsentrasi

  10% 15% 20% Total

  Mean Std. Deviation N

  Descriptive Statistics Dependent Variable: insoluble 25,4848 4,08332

  5 41,8625 3,40601 5 48,5991 4,21814 5 38,6488 10,68177

  15 54,7570 4,63207 5 56,5428 4,03123 5 73,8513 5,80462 5 61,7170 9,99242

  15 81,8253 3,96492 5 86,6949 4,46887 5 92,3394 4,06851 5 86,9532 5,89093

  40

  40

  80 100 Total

  40

  80 100 Total

  40

  80 100 Total

  40 konsentrasi 10% 15% 20% Total

  Mean Std. Deviation N  

  

3.2. Tabel Deskriptif Statistik Penyerapan Cd oleh Fraksi Tidak Terlarut (Insoluble)

antar Konsentrasi Padatan dan Ukuran Partikel Ketan Hitam

  80 100 Total

  80 100 Total

  Dependent Variable: total 69,6966 1,82865

  5 95,3226 4,33051

  5 71,0155 3,65920

  5 72,4030 8,00592

  5 71,0384 4,93985

  15 82,9606 2,75512

  5 93,4013 4,90567

  5 94,8778 3,63580

  5 90,4133 6,55480

  15 93,7744 6,00412

  5 97,0805 3,98819

  40

  5 95,3925 4,70710

  15 82,1439 10,83080

  15 86,5798 12,10350

  15 88,1205 12,64287

  15 85,6147 11,88950

  45 mesh

  40

  80 100 Total

  

3.3. Tabel Deskriptif Statistik Penyerapan Total Cd oleh Fraksi Terlarut (Soluble)

dan Fraksi Tidak Terlarut (Insoluble) antar Konsentrasi Padatan dan Ukuran

Partikel.

• mesh a.

  R Squared = ,934 (Adjusted R Squared = ,919) a.

  8 36 ,316 F df1 df2 Sig. Tests the null hypothesis that the error variance of the dependent variable is equal across groups.

  Dependent Variable: soluble 1,218

  Levene's Test of Equality of Error Variances a

  95% Confidence Interval for Mean Minimum Maximum

  10% 15% 20% Total 10% 15% 20% Total 10% 15% 20% Total soluble insoluble total N Mean Std. Deviation Std. Error Lower Bound Upper Bound

  5 37,03900 ,913540 ,408548 35,90469 38,17331 35,832 38,002 5 13,23500 1,566150 ,700404 11,29037 15,17963 10,564 14,574 5 7,76720 1,019355 ,455869 6,50150 9,03290 6,334 8,820 15 19,34707 13,200600 3,408380 12,03682 26,65732 6,334 38,002 5 32,38040 ,662887 ,296452 31,55732 33,20348 31,425 33,224 5 57,93600 1,726478 ,772105 55,79229 60,07971 56,232 60,400 5 79,01360 1,900449 ,849907 76,65388 81,37332 76,463 81,410 15 56,44333 19,787218 5,109038 45,48554 67,40113 31,425 81,410 5 69,41960 1,305491 ,583833 67,79862 71,04058 67,957 70,584 5 71,17072 1,773597 ,793177 68,96851 73,37293 69,560 74,088 5 86,78049 2,670492 1,194280 83,46463 90,09634 82,797 89,289 15 75,79027 8,287161 2,139736 71,20099 80,37954 67,957 89,289

  

4.1. Tabel Anova Penyerapan Cd oleh Fraksi Terlarut (Soluble) antar Konsentrasi

Padatan dan Ukuran Partikel Descriptives

  3.4. Tabel Deskriptif Statistik Penyerapan Cd oleh Kontrol (Selulosa) Lampiran 4. Tabel Anova

  Type III Sum of Squares df Mean Square F Sig.

  Tests of Between-Subjects Effects

  44 Source Corrected Model Intercept konsentrasi mesh konsentrasi * mesh Error Total Corrected Total

  45 7353,146

  31521,906

  804,198 4 201,050 14,869 ,000 486,777 36 13,522

  4987,995 2 2493,997 184,446 ,000 1074,176 2 537,088 39,721 ,000

  8 858,296 63,476 ,000 24168,761 1 24168,761 1787,422 ,000

  a

  Dependent Variable: soluble 6866,369

  Design: Intercept+konsentrasi+mesh+konsentrasi

  

4.2. Tabel Anova Penyerapan Cd oleh Fraksi Tidak Terlarut (Insoluble) antar

Konsentrasi Padatan dan Ukuran Partikel a Levene's Test of Equality of Error Variances

  Dependent Variable: insoluble F df1 df2 Sig.

  ,405

  8 36 ,910 Tests the null hypothesis that the error variance of the dependent variable is equal across groups.

  a.

  Design: Intercept+konsentrasi+mesh+konsentrasi

• mesh

  Tests of Between-Subjects Effects

  Dependent Variable: insoluble Type III Sum Source of Squares df Mean Square F Sig.

  a

  Corrected Model 20313,892 8 2539,237 134,659 ,000 Intercept

  175441,962 1 175441,962 9303,881 ,000 konsentrasi 17511,615 2 8755,808 464,330 ,000 mesh 2328,710

  2 1164,355 61,747 ,000 konsentrasi * mesh 473,567 4 118,392 6,278 ,001

  Error 678,847 36 18,857

  Total 196434,702

  45 Corrected Total 20992,739

  44 a. R Squared = ,968 (Adjusted R Squared = ,960)

  

4.3. Tabel Anova Penyerapan Total Cd oleh Fraksi Terlarut (Soluble) dan Fraksi

Tidak Terlarut (Insoluble) antar Konsentrasi Padatan dan Ukuran Partikel. a Levene's Test of Equality of Error Variances

  Dependent Variable: total F df1 df2 Sig.

  1,858

  8 36 ,098 Tests the null hypothesis that the error variance of the dependent variable is equal across groups.

  a.

  Design: Intercept+konsentrasi+mesh+konsentrasi

• mesh

  Tests of Between-Subjects Effects

  Dependent Variable: total Type III Sum Source of Squares df Mean Square F Sig.

  a

  Corrected Model 5434,204 8 679,276 31,126 ,000

  Intercept 329844,544 1 329844,544 15114,143 ,000 konsentrasi 4966,514 2 2483,257 113,788 ,000 mesh

  288,850 2 144,425 6,618 ,004 konsentrasi * mesh 178,840 4 44,710 2,049 ,108

  Error 785,648 36 21,824

  Total 336064,397

  45 Corrected Total 6219,853

  44 a. R Squared = ,874 (Adjusted R Squared = ,846)

  4.4. Tabel Anova Penyerapan Cd oleh Kontrol (Selulosa) ANOVA Sum of Squares df Mean Square F Sig. soluble Between Groups 2422,276 2 1211,138 839,811 ,000 Within Groups

  17,306 12 1,442 Total 2439,582

  14 insoluble Between Groups 5453,349 2 2726,674 1163,281 ,000 Within Groups

  28,127 12 2,344 Total 5481,476

  14 total Between Groups 913,553 2 456,776 114,371 ,000 Within Groups 47,926

  12 3,994 Total 961,479

  14

  Lampiran 5

  5.1. Kurva Standar Kadmium

  12 y  = 0,792x + 1,688 10  = 0,956 R²

  8,95

  8 7,85 8,825 7,1

  6 Series1 4,95 Linear  (Series1)

  4

  2 1,775

  2

  4

  6

  8

  10

  12

  5.2. Perhitungan Fraksi Terlarut dan Tidak Terlarut pada Ketan Hitam

5.2.1. Konsentrasi 10% Ukuran Partikel 40 mesh

• Fraksi Terlarut

  Keterangan : A : Berat Tabung Kosong B : Berat Tabung + Isi C : Berat Basah (B-A) D : Berat Soluble (D-C) E : Pembacaan AAS

  Persamaan Kurva Standar : y = 0,8673x + 1,4165; dimana y merupakan nilai dari pembacaan AAS

  1. A= 5,646; B= 15,658; C=8,083 ; D=7,575 ;E= 7,1 Nilai x = ( y – 1,4165)/ 0,8673 = (7,1 – 1,4165)/0,8673 = 6,55

  Jumlah Cd= Nilai x * D = 6,55 * 7,575= 49,64 μg

  2. A= 5,606; B= 16,199; C=8,192 ; D= 8,007 ;E= 5,8 Nilai x= ( y – 1,4165)/ 0,8673 = (5,8– 1,4165)/0,8673 = 5,05 Jumlah Cd= Nilai x * D = 5,05 * 8,007= 40,47

  μg

  3. A= 5,601 ; B= 15,934; C=8,064 ; D= 7,87 ;E= 6,7 Nilai x = ( y – 1,4165)/ 0,8673 = (6,7– 1,4165)/0,8673 = 6,09 Jumlah Cd= Nilai x * D = 6,09 * 7,87= 47,94 μg

  4. A= 5,555; B= 16,856; C=8,402 ; D=8,454 ;E= 5,3 Nilai x = ( y – 1,4165)/ 0,8673 = (5,3– 1,4165)/0,8673 = 4,48 Jumlah Cd= Nilai x * D = 4,48 * 8,454= 37,85 μg

  5. A= 5,579; B= 15,575; C=8,02 ; D=7,555 ;E=6,6 Nilai x = ( y – 1,4165)/ 0,8673 = (6,6– 1,4165)/0,8673 = 5,98 Jumlah Cd= Nilai x * D = 5,98 * 7,555 = 45,15 μg

• Fraksi Tidak Terlarut

  A : Berat Cawan Kosong B : Berat Cawan + Berat Kering C : Berat Insoluble (B-A) D : Pembacaan AAS Fp: Faktor Pengenceran = 10

  Persamaan Kurva Standar : y = 0,8673x + 1,4165; dimana y merupakan nilai dari pembacaan AAS

  1. A= 20,398 ; B= 21,236; C= 0,838 ; D= 3,7 Nilai x = ( y – 1,4165)/ 0,8673 = (3,7 – 1,4165)/0,8673 = 2,63 Jumlah Cd= Nilai x * C* Fp = 2,63 * 0,838* 10 = 22,06 μg

  Nilai x = ( y – 1,4165)/ 0,8673 = (3,7 – 1,4165)/0,8673 = 3,44 Jumlah Cd= Nilai x * C* Fp = 3,44 * 0,838* 10 = 28,83 μg

  3.A= 25,881 ; B= 26,734; C= 0,853 ; D= 3,8 Nilai x = ( y – 1,4165)/ 0,8673 = (3,7 – 1,4165)/0,8673 = 2,75 Jumlah Cd= Nilai x * C* Fp = 2,75 * 0,853* 10 = 23,44 μg

  4. A= 17,058 ; B= 17,899; C= 0,841 ; D= 4,6 Nilai x = ( y – 1,4165)/ 0,8673 = (3,7 – 1,4165)/0,8673 = 3,67 Jumlah Cd= Nilai x * C* Fp = 3,67 * 0,841* 10 = 30,87 μg

  5. A= 22,059 ; B= 22,903; C= 0,844 ; D= 3,7 Nilai x = ( y – 1,4165)/ 0,8673 = (3,7 – 1,4165)/0,8673 = 2,63 Jumlah Cd= Nilai x * C* Fp = 2,63 * 0,844* 10 = 22,22

  μg

  Ukuran Partikel 80 mesh

• Fraksi Terlarut

  Keterangan : A : Berat Tabung Kosong B : Berat Tabung + Isi C : Berat Basah (B-A) D : Berat Soluble (D-C) E : Pembacaan AAS Fp : 10

  Persamaan Kurva Standar : y = 0,8673x + 1,4165; dimana y merupakan nilai dari pembacaan AAS

  1. A= 5,66 ; B= 16,894; C=9,263 ; D=7,631 ;E= 4 Nilai x = ( y – 1,4165)/ 0,8673 = (4 – 1,4165)/0,8673 = 2,98

  2. A= 5,552; B=16,495 ; C=9,482 ; D=7,013 ; E=5,7 Nilai x= Nilai x = ( y – 1,4165)/ 0,8673 = (5,7– 1,4165)/0,8673 = 4,94 Jumlah Cd= Nilai x * D = 4,94 * 7,013= 34,64

  μg

  3. A= 5,546; B=17,306 ; C= 9,51; D=7,796 ; E=4,3 Nilai x = ( y – 1,4165)/ 0,8673 = (4,3– 1,4165)/0,8673 = 3,32 Jumlah Cd= Nilai x * D = 3,32 * 7,796= 25,93 μg

  4. A= 5,613; B=16,227 ; C=9,842 ; D=6,385 ; E=5,6 Nilai x = ( y – 1,4165)/ 0,8673 = (5,6– 1,4165)/0,8673 = 4,82 Jumlah Cd= Nilai x * D = 4,82 * 6,385 = 30,80 μg

  5. A= 5,573; B=16,758 ; C=9,496 ; D=7,262 ; E=5,2 Nilai x = ( y – 1,4165)/ 0,8673 = (5,2– 1,4165)/0,8673 = 4,36 Jumlah Cd= Nilai x * D = 4,36 * 7,262 = 31,68

  μg

• Fraksi Tidak Terlarut

  A : Berat Cawan Kosong B : Berat Cawan + Berat Kering C : Berat Insoluble (B-A) D : Pembacaan AAS Fp: Faktor Pengenceran = 10

  Persamaan Kurva Standar : y = 0,8673x + 1,4165; dimana y merupakan nilai dari pembacaan AAS

  1. A= 28,413 ; B= 29,178; C= 0,765 ; D= 6,8 Nilai x = ( y – 1,4165)/ 0,8673 = (6,8 – 1,4165)/0,8673 = 6,21 Jumlah Cd= Nilai x * C* Fp = 6,21 * 0,765* 10 = 47,49 μg

  2.A= 20,492 ; B= 21,256; C=0,764 ; D= 6,2

  Jumlah Cd= Nilai x * C* Fp = 5,52 * 0,764* 10 = 42,14 μg

  3.A= 18,985 ; B= 19,756; C= 0,771 ; D= 6 Nilai x = ( y – 1,4165)/ 0,8673 = (6 – 1,4165)/0,8673 = 5,28 Jumlah Cd= Nilai x * C* Fp = 5,28 * 0,771* 10 = 40,75

  μg

  4. A= 22,091 ; B= 22,857; C= 0,766 ; D= 6 Nilai x = ( y – 1,4165)/ 0,8673 = (6– 1,4165)/0,8673 = 5,28 Jumlah Cd= Nilai x * C* Fp = 5,28 * 0,766* 10 = 40,48 μg

  5. A= 26,1 ; B= 26,861; C= 0,761 ; D= 5,8 Nilai x = ( y – 1,4165)/ 0,8673 = (5,8 – 1,4165)/0,8673 = 5,05 Jumlah Cd= Nilai x * C* Fp = 5,05* 0,761* 10 = 38,46 μg

  Ukuran Partikel 100 mesh

• Fraksi Tidak Terlarut

  Keterangan : A : Berat Tabung Kosong B : Berat Tabung + Isi C : Berat Basah (B-A) D : Berat Soluble (D-C) E : Pembacaan AAS Fp : 10

  Persamaan Kurva Standar : y = 0,8673x + 1,4165; dimana y merupakan nilai dari pembacaan AAS

  1. A= 5,552 ; B= 16,402; C=8,035 ; D=8,367 ;E= 4 Nilai x = ( y – 1,4165)/ 0,8673 = (4 – 1,4165)/0,8673 = 2,98

  2. A=5,578 ; B= 16,289; C=8,104 ; D=8,185 ;E=4,6 Nilai x= Nilai x = ( y – 1,4165)/ 0,8673 = (4,6– 1,4165)/0,8673 = 3,67 Jumlah Cd= Nilai x * D = 3,67 * 8,185= 30,04

  μg

  3. A=5,519 ; B= 15,903; C=8,001 ; D=7,902 ;E=3,5 Nilai x = ( y – 1,4165)/ 0,8673 = (3,5– 1,4165)/0,8673 = 2,40 Jumlah Cd= Nilai x * D = 2,40 * 7,902= 18,98 μg

  4. A=5,56 ; B= 16,959; C=8,161 ; D=8,798 ;E=3,5 Nilai x = ( y – 1,4165)/ 0,8673 = (3,5– 1,4165)/0,8673 = 2,40 Jumlah Cd= Nilai x * D = 2,40 * 8,798= 21,14 μg

  5. A= 5,582; B= 15,467; C=7,432 ; D=8,035 ;E=4 Nilai x = ( y – 1,4165)/ 0,8673 = (4– 1,4165)/0,8673 = 2,98 Jumlah Cd= Nilai x * D = 2,98 * 8,035= 23,93

  μg

• Fraksi Tidak Terlarut

  A : Berat Cawan Kosong B : Berat Cawan + Berat Kering C : Berat Insoluble (B-A) D : Pembacaan AAS Fp: Faktor Pengenceran = 10

  Persamaan Kurva Standar : y = 0,8673x + 1,4165; dimana y merupakan nilai dari pembacaan AAS

  1. A= 24,467 ; B= 25,264; C= 0,797 ; D= 7,1 Nilai x = ( y – 1,4165)/ 0,8673 = (7,1 – 1,4165)/0,8673 = 6,55 Jumlah Cd= Nilai x * C* Fp = 6,55 * 0,797* 10 = 52,23 μg

  2.A= 19,895 ; B= 20,699; C=0,804 ; D= 7,1

  Jumlah Cd= Nilai x * C* Fp = 6,55 * 0,804* 10 = 52,69 μg

  3.A= 24,952 ; B= 25,757; C= 0,805 ; D=6 Nilai x = ( y – 1,4165)/ 0,8673 = (6 – 1,4165)/0,8673 = 5,28 Jumlah Cd= Nilai x * C* Fp = 5,28 * 0,805* 10 = 42,54

  μg

  4. A= 22,718 ; B= 23,523; C= 0,805 ; D= 6,7 Nilai x = ( y – 1,4165)/ 0,8673 = (6,7– 1,4165)/0,8673 = 6,09 Jumlah Cd= Nilai x * C* Fp = 6,09 * 0,805* 10 = 49,04 μg

  5. A= 18,838 ; B= 19,616; C= 0,778 ; D= 6,6 Nilai x = ( y – 1,4165)/ 0,8673 = (6,6– 1,4165)/0,8673 = 5,98 Jumlah Cd= Nilai x * C* Fp = 5,98* 0,778* 10 = 46,50 μg

5.2.2. Konsentrasi 15% Ukuran Partikel 40 mesh

• Fraksi terlarut

  Keterangan : A : Berat Tabung Kosong B : Berat Tabung + Isi C : Berat Basah (B-A) D : Berat Soluble (D-C) E : Pembacaan AAS

  Persamaan Kurva Standar : y = 0,8673x + 1,4165; dimana y merupakan nilai dari pembacaan AAS

  1. A= 5,609 ; B= 15,823; C= 9,33 ; D= 6,493 ;E= 5,8 Nilai x = ( y – 1,4165)/ 0,8673 = (5,8 – 1,4165)/0,8673 = 5,05

  2. A= 5,609 ; B=15,068 ; C= 9,061 ; D= 6,007 ; E= 5 Nilai x= Nilai x = ( y – 1,4165)/ 0,8673 = (5– 1,4165)/0,8673 = 4,13 Jumlah Cd= Nilai x * D = 4,13 * 6,01= 24,82

  μg

  3. A= 5,622 ;B= 15,626 ; C= 9,187 ;D= 6,439 ; E= 5,3 Nilai x = ( y – 1,4165)/ 0,8673 = (5,3– 1,4165)/0,8673 = 4,48 Jumlah Cd= Nilai x * D = 4,48 * 6,44 = 28,83 μg

  4. A=5,525 ;B= 15,399 ;C= 9,142 ;D= 6,257 ;E= 5 Nilai x = ( y – 1,4165)/ 0,8673 = (5– 1,4165)/0,8673 = 4,13 Jumlah Cd= Nilai x * D = 4,13 * 6,26 = 25,85 μg

  5. A= 5,604 ;B= 15,042 ;C= 8,947 ;D= 6,095 ;E= 5,5 Nilai x = ( y – 1,4165)/ 0,8673 = (5,5– 1,4165)/0,8673 = 4,71 Jumlah Cd= Nilai x * D = 4,71 * 6,10 = 28,70

  μg

• Fraksi Tidak Terlarut

  A : Berat Cawan Kosong B : Berat Cawan + Berat Kering C : Berat Insoluble (B-A) D : Pembacaan AAS Fp: Faktor Pengenceran = 10

  Persamaan Kurva Standar : y = 0,8673x + 1,4165; dimana y merupakan nilai dari pembacaan AAS

  1. A= 20,934 ; B= 22,181; C= 1,247 ; D= 5 Nilai x = ( y – 1,4165)/ 0,8673 = (5 – 1,4165)/0,8673 = 4,13 Jumlah Cd= Nilai x * C* Fp = 4,13 * 1,247* 10 = 51,52 μg

  2.A= 21,071 ; B= 22,311; C= 1,24 ; D= 5,6

  Jumlah Cd= Nilai x * C* Fp = 4,82 * 1,24* 10 = 59,81

  3.A= 20,913 ; B= 22,152 ; C= 1,239 ; D= 5,1 Nilai x = ( y – 1,4165)/ 0,8673 = (5,1 – 1,4165)/0,8673 = 4,25 Jumlah Cd= Nilai x * C* Fp = 4,25 * 1,239* 10 = 52,62 μg

  4. A= 19,666 ; B=17,899; C= 1,237 ; D= 5,6 Nilai x = ( y – 1,4165)/ 0,8673 = (5,6– 1,4165)/0,8673 = 4,82 Jumlah Cd= Nilai x * C* Fp = 4,82* 1,237* 10 = 59,67 μg

  5. A= 23,443 ; B= 24,657; C= 1,214 ; D= 5 Nilai x = ( y – 1,4165)/ 0,8673 = (5 – 1,4165)/0,8673 = 4,13 Jumlah Cd= Nilai x * C* Fp = 4,13 * 1,214* 10 = 50,16 μg

  Ukuran Partikel 80 mesh

• Fraksi Terlarut

  Keterangan : A : Berat Tabung Kosong B : Berat Tabung + Isi C : Berat Basah (B-A) D : Berat Soluble (D-C) E : Pembacaan AAS Fp : 10

  Persamaan Kurva Standar : y = 0,8673x + 1,4165; dimana y merupakan nilai dari pembacaan AAS

  1. A=5,709 ; B= 16,003; C=9,263 ; D=6,74 ;E= 7 Nilai x = ( y – 1,4165)/ 0,8673 = (7 – 1,4165)/0,8673 = 6,44

  2. A=5,535 ; B= 15,99; C=9,482 ; D=6,508 ;E= 6,3 Nilai x= Nilai x = ( y – 1,4165)/ 0,8673 = (6,3– 1,4165)/0,8673 = 5,63 Jumlah Cd= Nilai x * D = 5,63 * 6,508= 34,64

  μg

  3. A= 5,577; B= 16,049; C=9,51 ; D=6,539 ;E=6,2 Nilai x = ( y – 1,4165)/ 0,8673 = (6,2– 1,4165)/0,8673 = 5,52 Jumlah Cd= Nilai x * D = 5,52 * 6,539= 36,07 μg

  4. A=5,595 ; B= 16,355; C=9,842 ; D=6,513 ;E= 6 Nilai x = ( y – 1,4165)/ 0,8673 = (6– 1,4165)/0,8673 = 5,28 Jumlah Cd= Nilai x * D = 5,28 * 6,513= 34,42 μg

  5. A=v ; B= 16,029; C=9,496 ; D=6,533 ;E=5,9 Nilai x = ( y – 1,4165)/ 0,8673 = (5,9– 1,4165)/0,8673 = 5,17 Jumlah Cd= Nilai x * D = 5,17 * 6,533= 33,77

  μg

• Fraksi Tidak Terlarut

  A : Berat Cawan Kosong B : Berat Cawan + Berat Kering C : Berat Insoluble (B-A) D : Pembacaan AAS Fp: Faktor Pengenceran = 10

  Persamaan Kurva Standar : y = 0,8673x + 1,4165; dimana y merupakan nilai dari pembacaan AAS

  1. A= 17,058 ; B= 18,286; C= 1,228 ; D= 5,4 Nilai x = ( y – 1,4165)/ 0,8673 = (5,4 – 1,4165)/0,8673 = 4,59 Jumlah Cd= Nilai x * C* Fp = 4,59 * 1,228* 10 = 56,40

  μg

  2.A= 28,405 ; B= 29,631; C=1,226 ; D=5,2 Nilai x = ( y – 1,4165)/ 0,8673 = (5,2 – 1,4165)/0,8673 = 4,36

  3.A= 19,893 ; B= 21,11; C= 1,217 ; D= 5,2 Nilai x = ( y – 1,4165)/ 0,8673 = (5,2 – 1,4165)/0,8673 = 4,36 Jumlah Cd= Nilai x * C* Fp = 4,36 * 1,217* 10 = 53,09

  μg

  4. A= 25,971 ; B= 27,166; C= 1,195 ; D= 6 Nilai x = ( y – 1,4165)/ 0,8673 = (6– 1,4165)/0,8673 = 5,28 Jumlah Cd= Nilai x * C* Fp = 5,28 * 1,195* 10 = 63,15 μg

  5. A= 23,11 ; B= 24,342; C= 1,232 ; D= 5,4 Nilai x = ( y – 1,4165)/ 0,8673 = (5,4 – 1,4165)/0,8673 = 4,59 Jumlah Cd= Nilai x * C* Fp = 4,59* 1,232* 10 = 56,59 μg

  Ukuran Partikel 100 mesh

• Fraksi Terlarut

  Keterangan : A : Berat Tabung Kosong B : Berat Tabung + Isi C : Berat Basah (B-A) D : Berat Soluble (D-C) E : Pembacaan AAS Fp : 10

  Persamaan Kurva Standar : y = 0,8673x + 1,4165; dimana y merupakan nilai dari pembacaan AAS

  1. A= 5,575; B=16,882 ; C=9,171 ; D=7,711 ;E= 3,6 Nilai x = ( y – 1,4165)/ 0,8673 = (3,6 – 1,4165)/0,8673 = 2,52 Jumlah Cd= Nilai x * D = 2,52 * 7,711= 22,73 = 19,41

  μg

  2. A=5,529 ; B= 16,729; C=9,185 ; D=7,544 ;E=4,2

  Jumlah Cd= Nilai x * D = 3,21 * 7,544= 24,21 μg

  3. A=5,612 ; B= 17,19; C=9,245 ; D=7,945 ;E=3,4 Nilai x = ( y – 1,4165)/ 0,8673 = (3,4– 1,4165)/0,8673 = 2,29 Jumlah Cd= Nilai x * D = 2,29 * 7,945= 18,17

  μg

  4. A=5,581 ; B= 16,13; C=8,702 ; D=7,428 ;E=4,4 Nilai x = ( y – 1,4165)/ 0,8673 = (4,4– 1,4165)/0,8673 = 3,44 Jumlah Cd= Nilai x * D = 3,44 * 7,428= 25,55 μg

  5. A=5,594 ; B= 16,924; C=9,147 ; D=7,777 ;E=3,4 Nilai x = ( y – 1,4165)/ 0,8673 = (3,4– 1,4165)/0,8673 = 2,29 Jumlah Cd= Nilai x * D = 2,29 * 7,777= 17,79 μg

• Fraksi Tidak Terlarut

  A : Berat Cawan Kosong B : Berat Cawan + Berat Kering C : Berat Insoluble (B-A) D : Pembacaan AAS Fp: Faktor Pengenceran = 10

  Persamaan Kurva Standar : y = 0,8673x + 1,4165; dimana y merupakan nilai dari pembacaan AAS

  1. A= 22,058 ; B= 23,23; C= 1,172 ; D= 7,1 Nilai x = ( y – 1,4165)/ 0,8673 = (7,1 – 1,4165)/0,8673 = 6,55 Jumlah Cd= Nilai x * C* Fp = 6,55 * 0,797* 10 = 76,80 μg

  2.A= 26,114 ; B= 27,237; C=1,123 ; D= 7 Nilai x = ( y – 1,4165)/ 0,8673 = (7, – 1,4165)/0,8673 = 6,44 Jumlah Cd= Nilai x * C* Fp = 6,44 * 1,123* 10 = 72,30 μg

  Nilai x = ( y – 1,4165)/ 0,8673 = (7,5 – 1,4165)/0,8673 = 7,01 Jumlah Cd= Nilai x * C* Fp = 7,01* 1,158* 10 = 81,23 μg

  4. A= 19,895 ; B= 21,059; C= 1,164 ; D= 6,3 Nilai x = ( y – 1,4165)/ 0,8673 = (6,3– 1,4165)/0,8673 = 5,63 Jumlah Cd= Nilai x * C* Fp = 5,63 * 1,164* 10 = 65,54 μg

  5. A= 22,291 ; B= 23,431; C= 1,14 ; D= 7 Nilai x = ( y – 1,4165)/ 0,8673 = (7– 1,4165)/0,8673 = 6,44 Jumlah Cd= Nilai x * C* Fp = 6,44* 1,14* 10 = 73,39 μg

5.2.3. Konsentrasi 20% Ukuran Partikel 40 mesh

• Fraksi Terlarut\

  Keterangan : A : Berat Tabung Kosong B : Berat Tabung + Isi C : Berat Basah (B-A) D : Berat Soluble (D-C) E : Pembacaan AAS Fp : 10

  Persamaan Kurva Standar : y = 0,8673x + 1,4165; dimana y merupakan nilai dari pembacaan AAS

  1. A=5,562 ; B= 15,992; C=10,243 ; D=5,749 ;E= 3,7 Nilai x = ( y – 1,4165)/ 0,8673 = (3,7 – 1,4165)/0,8673 = 2,63 Jumlah Cd= Nilai x * D = 2,63* 5,749= 22,73 = 15,14 μg

  2. A=5,554 ; B= 16,584; C=10,236 ; D=6,348 ;E=2,6

  Nilai x= Nilai x = ( y – 1,4165)/ 0,8673 = (2,6– 1,4165)/0,8673 = 1,36 Jumlah Cd= Nilai x * D = 1,36 * 6,348= 8,66 μg

  3. A=5,583 ; B=16,327; C=10,365 ; D=5,962 ;E=3,7 Nilai x = ( y – 1,4165)/ 0,8673 = (3,7– 1,4165)/0,8673 = 2,63 Jumlah Cd= Nilai x * D = 2,63 * 5,962= 15,70 μg

  4. A=5,542 ; B=16,356; C=10,319 ; D=6,037 ;E=3,1 Nilai x = ( y – 1,4165)/ 0,8673 = (3,1– 1,4165)/0,8673 = 1,94 Jumlah Cd= Nilai x * D = 1,94 * 6,037= 11,72 μg

  5. A=5,584 ; B= 16,479; C=10,227 ; D=6,252 ;E=2,6 Nilai x = ( y – 1,4165)/ 0,8673 = (2,6– 1,4165)/0,8673 = 1,36 Jumlah Cd= Nilai x * D = 1,36 * 6,252= 8,53

  μg

• Fraksi Tidak Terlarut

  A : Berat Cawan Kosong B : Berat Cawan + Berat Kering C : Berat Insoluble (B-A) D : Pembacaan AAS Fp: Faktor Pengenceran = 10

  Persamaan Kurva Standar : y = 0,8673x + 1,4165; dimana y merupakan nilai dari pembacaan AAS

  1. A= 20,398 ; B= 22,071; C= 1,673 ; D= 5,8 Nilai x = ( y – 1,4165)/ 0,8673 = (5,8 – 1,4165)/0,8673 = 5,05 Jumlah Cd= Nilai x * C* Fp = 5,05 * 1,673* 10 = 84,56 μg

  2.A= 21,087 ; B= 22,753; C= 1,666 ; D= 5,9 Nilai x = ( y – 1,4165)/ 0,8673 = (5,9 – 1,4165)/0,8673 = 5,17

  3.A= 25,881 ; B= 27,559 ; C= 1,678 ; D= 5,7 Nilai x = ( y – 1,4165)/ 0,8673 = (5,1 – 1,4165)/0,8673 = 4,94 Jumlah Cd= Nilai x * C* Fp = 4,94 * 1,678* 10 = 82,87

  μg

  4. A= 17,058 ; B=18,737; C= 1,679 ; D= 5,5 Nilai x = ( y – 1,4165)/ 0,8673 = (5,5– 1,4165)/0,8673 = 4,71 Jumlah Cd= Nilai x * C* Fp = 4,71* 1,679* 10 = 79,05 μg

  5. A= 22,059 ; B= 23,725; C= 1,666 ; D=5,4 Nilai x = ( y – 1,4165)/ 0,8673 = (5,4 – 1,4165)/0,8673 = 4,59 Jumlah Cd= Nilai x * C* Fp = 4,59 * 1,666* 10 = 76,52 μg

  Ukuran Partikel 80 mesh

• Fraksi Terlarut

  Keterangan : A : Berat Tabung Kosong B : Berat Tabung + Isi C : Berat Basah (B-A) D : Berat Soluble (D-C) E : Pembacaan AAS Fp : 10

  Persamaan Kurva Standar : y = 0,8673x + 1,4165; dimana y merupakan nilai dari pembacaan AAS

  1. A=5,555 ; B=16,438; C=10,634 ; D=5,804 ;E= 2,9 Nilai x = ( y – 1,4165)/ 0,8673 = (2,9 – 1,4165)/0,8673 = 1,71 Jumlah Cd= Nilai x * D = 1,71 * 5,804= 22,73 = 9,93 μg

  2. A=5,578 ; B=16,733; C=10,559 ; D=6,174 ;E=2,4

  Jumlah Cd= Nilai x * D = 1,13 * 6,174= 7,00 μg

  3. A=5,557 ; B=16,704; C=10,608 ; D=6,096 ;E=2,9 Nilai x = ( y – 1,4165)/ 0,8673 = (2,9– 1,4165)/0,8673 = 1,71 Jumlah Cd= Nilai x * D = 1,71 * 6,096= 10,43

  μg

  4. A=5,613 ; B=16,857; C=10,686 ; D=6,171 ;E=2,3 Nilai x = ( y – 1,4165)/ 0,8673 = (2,3– 1,4165)/0,8673 = 1,02 Jumlah Cd= Nilai x * D = 1,02 * 6,171= 6,29 μg

  5. A=5,573 ; B=16,102; C=10,550 ; D=5,552 ;E=2,9 Nilai x = ( y – 1,4165)/ 0,8673 = (2,9– 1,4165)/0,8673 = 1,71 Jumlah Cd= Nilai x * D = 1,71 * 5,552= 9,50 μg

• Fraksi Tidak Terlarut

  A : Berat Cawan Kosong B : Berat Cawan + Berat Kering C : Berat Insoluble (B-A) D : Pembacaan AAS Fp: Faktor Pengenceran = 10

  Persamaan Kurva Standar : y = 0,8673x + 1,4165; dimana y merupakan nilai dari pembacaan AAS

  1. A= 28,413 ; B= 30,062 ; C= 1,649 ; D=5,8 Nilai x = ( y – 1,4165)/ 0,8673 = (5,4 – 1,4165)/0,8673 = 5,05 Jumlah Cd= Nilai x * C* Fp = 5,05 * 1,649* 10 = 83,34 μg

  2.A= 20,492 ; B= 22,128; C=1,636 ; D=6,3 Nilai x = ( y – 1,4165)/ 0,8673 = (6,3 – 1,4165)/0,8673 = 5,63 Jumlah Cd= Nilai x * C* Fp = 5,63 * 1,636* 10 = 92,12 μg

  Nilai x = ( y – 1,4165)/ 0,8673 = (6,3 – 1,4165)/0,8673 = 5,63 Jumlah Cd= Nilai x * C* Fp = 5,63 * 1,476* 10 = 83,11 μg

  4. A= 22,091 ; B= 23,751; C= 1,66 ; D= 5,8 Nilai x = ( y – 1,4165)/ 0,8673 = (5,8– 1,4165)/0,8673 = 5,05 Jumlah Cd= Nilai x * C* Fp = 5,05 * 1,66* 10 = 83,90 μg

  5. A= 26,1 ; B= 27,75; C= 1,65 ; D= 6,2 Nilai x = ( y – 1,4165)/ 0,8673 = (6,2 – 1,4165)/0,8673 = 5,52 Jumlah Cd= Nilai x * C* Fp = 5,52* 1,65* 10 = 91,00 μg

  Ukuran Partikel 100 mesh

• Fraksi Terlarut

  Keterangan : A : Berat Tabung Kosong B : Berat Tabung + Isi C : Berat Basah (B-A) D : Berat Soluble (D-C) E : Pembacaan AAS Fp : 10

  Persamaan Kurva Standar : y = 0,8673x + 1,4165; dimana y merupakan nilai dari pembacaan AAS

  1. A=5,552 ; B= 17,678; C=10,113 ; D=7,565 ;E= 1,60 Nilai x = ( y – 1,4165)/ 0,8673 = (1,6 – 1,4165)/0,8673 = 0,21 Jumlah Cd= Nilai x * D = 0,21 * 7,565= 22,73 = 1,60 μg

  2. A=5,578 ; B=17,790; C=10,299 ; D=7,491 ;E=1,90 Nilai x= Nilai x = ( y – 1,4165)/ 0,8673 = (1,9– 1,4165)/0,8673 = 0,56

  3. A=5,519 ; B=17,768; C=10,320 ; D=7,448 ;E=2,0 Nilai x = ( y – 1,4165)/ 0,8673 = (2,0– 1,4165)/0,8673 = 0,67 Jumlah Cd= Nilai x * D = 0,67 * 7,448= 5,01

  μg

  4. A= 5,56; B=17,986; C=10,306 ; D=7,68 ;E=2,10 Nilai x = ( y – 1,4165)/ 0,8673 = (2,10– 1,4165)/0,8673 = 0,79 Jumlah Cd= Nilai x * D = 0,79 * 7,68= 6,05 μg

  5. A=5,582 ; B=17,842; C=10,242 ; D=7,6 ;E=2,20 Nilai x = ( y – 1,4165)/ 0,8673 = (2,20– 1,4165)/0,8673 = 0,90 Jumlah Cd= Nilai x * D = 0,90 * 7,6= 6,87 μg

• Fraksi Tidak Terlarut

  A : Berat Cawan Kosong B : Berat Cawan + Berat Kering C : Berat Insoluble (B-A) D : Pembacaan AAS Fp: Faktor Pengenceran = 10

  Persamaan Kurva Standar : y = 0,8673x + 1,4165; dimana y merupakan nilai dari pembacaan AAS

  1. A= 24,467 ; B= 26,061; C= 1,594 ; D= 6,7 Nilai x = ( y – 1,4165)/ 0,8673 = (6,7 – 1,4165)/0,8673 = 6,09 Jumlah Cd= Nilai x * C* Fp = 6,09* 1,594* 10 = 97,10 μg

  2.A= 23,13 ; B= 24,543; C=1,413 ; D= 6,7 Nilai x = ( y – 1,4165)/ 0,8673 = (6,7, – 1,4165)/0,8673 = 6,09 Jumlah Cd= Nilai x * C* Fp = 6,09 * 1,413* 10 = 86,08 μg

  3.A= 24,952 ; B= 26,547; C= 1,595 ; D=6,5

  Jumlah Cd= Nilai x * C* Fp = 5,86* 1,595* 10 = 93,49 μg

  4. A= 22,718 ; B= 24,307; C= 1,589 ; D= 6,4 Nilai x = ( y – 1,4165)/ 0,8673 = (6,3– 1,4165)/0,8673 = 5,75 Jumlah Cd= Nilai x * C* Fp = 5,75 * 1,589* 10 = 91,30

  μg

  5. A= 18,838 ; B= 20,437; C= 1,599 ; D= 6,5 Nilai x = ( y – 1,4165)/ 0,8673 = (6,5 – 1,4165)/0,8673 = 5,86 Jumlah Cd= Nilai x * C* Fp = 5,86* 1,599* 10 = 93,72 μg

5.3. Perhitungan Fraksi Terlarut dan Tidak Terlarut pada Kontrol

5.3.1. Konsentrasi 10%

• Fraksi Terlarut

  Keterangan : A : Berat Tabung Kosong B : Berat Tabung + Isi C : Berat Basah (B-A) D : Berat Soluble (D-C) E : Pembacaan AAS Fp : 10

  Persamaan Kurva Standar : y = 0,8673x + 1,4165; dimana y merupakan nilai dari pembacaan AAS

  1. A= 5,562 ; B= 16,339; C=9,084 ; D=7,255 ;E= 5,2 Nilai x = ( y – 1,4165)/ 0,8673 = (5,2 – 1,4165)/0,8673 = 4,36 Jumlah Cd= Nilai x * D = 4,36 * 7,255= 22,73 = 31,65

  2. A= 5,554; B=16,491 ; C=8,897 ; D=7,594 ; E=4,6 Nilai x= Nilai x = ( y – 1,4165)/ 0,8673 = (4,6– 1,4165)/0,8673 = 3,67

  Jumlah Cd= Nilai x * D = 3,67 * 7,594= 27,87 μg

  3. A= 5,583; B=16,317 ; C= 9,03; D=7,287 ; E=5,2 Nilai x = ( y – 1,4165)/ 0,8673 = (5,2– 1,4165)/0,8673 = 4,36 Jumlah Cd= Nilai x * D = 4,36 * 7,287= 31,79

  μg

  4. A= 5,548; B=16,671 ; C=8,997 ; D=7,674 ; E=4,2 Nilai x = ( y – 1,4165)/ 0,8673 = (4,2– 1,4165)/0,8673 = 3,21 Jumlah Cd= Nilai x * D = 3,21* 7,674= 24,63 μg

  5. A= 5,582; B=16,486 ; C=8,967 ; D=7,519 ; E=5,6 Nilai x = ( y – 1,4165)/ 0,8673 = (5,6– 1,4165)/0,8673 = 4,82 Jumlah Cd= Nilai x * D = 4,82 * 7,519= 36,27 μg

• Fraksi Tidak Terlarut

  A : Berat Cawan Kosong B : Berat Cawan + Berat Kering C : Berat Insoluble (B-A) D : Pembacaan AAS Fp: Faktor Pengenceran = 10

  Persamaan Kurva Standar : y = 0,8673x + 1,4165; dimana y merupakan nilai dari pembacaan AAS

  1. A= 20,398 ; B= 21,314; C= 0,916 ; D= 8,1 Nilai x = ( y – 1,4165)/ 0,8673 = (8,1 – 1,4165)/0,8673 = 7,71 Jumlah Cd= Nilai x * C* Fp = 7,71 * 0,916* 10 = 35,29 μg

  2.A= 21,087 ; B= 21,998; C=0,911 ; D= 7,2 Nilai x = ( y – 1,4165)/ 0,8673 = (7,2 – 1,4165)/0,8673 = 6,67

  3.A= 25,881 ; B= 26,813; C= 0,932 ; D= 6,9 Nilai x = ( y – 1,4165)/ 0,8673 = (6,9 – 1,4165)/0,8673 = 6,32 Jumlah Cd= Nilai x * C* Fp = 6,32 * 0,932* 10 = 29,46

  μg

  4. A= 17,058 ; B= 17,971; C= 0,913 ; D= 7,4 Nilai x = ( y – 1,4165)/ 0,8673 = (7,4– 1,4165)/0,8673 = 6,90 Jumlah Cd= Nilai x * C* Fp = 6,90 * 0,913* 10 = 31,49 μg

  5. A= 22,969 ; B= 23,898; C= 0,929 ; D= 8,8 Nilai x = ( y – 1,4165)/ 0,8673 = (8,8 – 1,4165)/0,8673 = 8,51 Jumlah Cd= Nilai x * C* Fp = 8,51* 0,929* 10 = 39,54 μg

5.3.2. Konsentrasi 15%

• Fraksi Terlarut

  Keterangan : A : Berat Tabung Kosong B : Berat Tabung + Isi C : Berat Basah (B-A) D : Berat Soluble (D-C) E : Pembacaan AAS Fp : 10

  Persamaan Kurva Standar : y = 0,8673x + 1,4165; dimana y merupakan nilai dari pembacaan AAS

  1. A= 5,555 ; B= 15,885; C=10,546 ; D=5,339 ;E= 4,4 Nilai x = ( y – 1,4165)/ 0,8673 = (4,4 – 1,4165)/0,8673 = 3,44 Jumlah Cd= Nilai x * D = 3,44 * 5,339= 22,73 = 18,37

  Nilai x= Nilai x = ( y – 1,4165)/ 0,8673 = (4,2– 1,4165)/0,8673 = 3,21 Jumlah Cd= Nilai x * D = 3,21 * 5,533= 17,76 μg

  3. A= 5,557; B=16,244 ; C= 10,807; D=5,437 ; E=5,1 Nilai x = ( y – 1,4165)/ 0,8673 = (5,2– 1,4165)/0,8673 = 4,25 Jumlah Cd= Nilai x * D = 4,25 * 5,437= 23,09 μg

  4. A= 5,613; B=14,82 ; C=10,624 ; D=4,196 ; E=4,2 Nilai x = ( y – 1,4165)/ 0,8673 = (4,2– 1,4165)/0,8673 = 3,21 Jumlah Cd= Nilai x * D = 3,21* 4,196= 13,47 μg

  5. A= 5,573; B=15,917 ; C=10,614 ; D=5,303 ; E=4,6 Nilai x = ( y – 1,4165)/ 0,8673 = (4,6– 1,4165)/0,8673 = 3,67 Jumlah Cd= Nilai x * D = 3,67 * 5,303= 19,47

  μg

• Fraksi Tidak Terlarut

  A : Berat Cawan Kosong B : Berat Cawan + Berat Kering C : Berat Insoluble (B-A) D : Pembacaan AAS Fp: Faktor Pengenceran = 10

  Persamaan Kurva Standar : y = 0,8673x + 1,4165; dimana y merupakan nilai dari pembacaan AAS

  1. A= 28,413 ; B= 29,797 ; C= 1,384 ; D= 8,1 Nilai x = ( y – 1,4165)/ 0,8673 = (8,1 – 1,4165)/0,8673 = 7,71 Jumlah Cd= Nilai x * C* Fp = 7,71 * 1,384* 10 = 53,33 μg

  2.A= 20,492 ; B= 21,862; C=1,37 ; D= 8,4 Nilai x = ( y – 1,4165)/ 0,8673 = (8,4 – 1,4165)/0,8673 = 8,05

  3.A= 18,985 ; B= 20,385; C= 1,4 ; D= 7,8 Nilai x = ( y – 1,4165)/ 0,8673 = (7,8 – 1,4165)/0,8673 = 7,36 Jumlah Cd= Nilai x * C* Fp = 7,36 * 1,4* 10 = 51,52

  μg

  4. A= 22,091 ; B= 23,477; C= 1,386 ; D= 8,2 Nilai x = ( y – 1,4165)/ 0,8673 = (8,2– 1,4165)/0,8673 = 7,82 Jumlah Cd= Nilai x * C* Fp = 7,82* 1,386* 10 = 54,20 μg

  5. A= 26,1 ; B= 27,477; C= 1,377 ; D= 7,6 Nilai x = ( y – 1,4165)/ 0,8673 = (7,6 – 1,4165)/0,8673 = 7,13 Jumlah Cd= Nilai x * C* Fp = 7,13* 1,377* 10 = 49,09 μg

5.3.3. Konsentrasi 20%

• Fraksi Terlarut

  Keterangan : A : Berat Tabung Kosong B : Berat Tabung + Isi C : Berat Basah (B-A) D : Berat Soluble (D-C) E : Pembacaan AAS Fp : 10

  Persamaan Kurva Standar : y = 0,8673x + 1,4165; dimana y merupakan nilai dari pembacaan AAS

  1. A= 5,552 ; B= 16,329; C=12,04 ; D=4,289 ;E= 4,1 Nilai x = ( y – 1,4165)/ 0,8673 = (4,1 – 1,4165)/0,8673 = 3,09 Jumlah Cd= Nilai x * D = 3,09 * 4,289= 22,73 = 13,27

  Nilai x= Nilai x = ( y – 1,4165)/ 0,8673 = (3,9– 1,4165)/0,8673 = 2,86 Jumlah Cd= Nilai x * D = 2,86 * 3,951= 11,31 μg

  3. A= 5,519; B=16,324 ; C= 12,265; D=4,059 ; E=3,3 Nilai x = ( y – 1,4165)/ 0,8673 = (3,3– 1,4165)/0,8673 = 2,17 Jumlah Cd= Nilai x * D = 2,17 * 4,059= 8,81 μg

  4. A= 5,56; B=16,046 ; C=12,577 ; D=3,469 ; E=4,3 Nilai x = ( y – 1,4165)/ 0,8673 = (4,3– 1,4165)/0,8673 = 3,32 Jumlah Cd= Nilai x * D = 3,32* 3,469= 11,53 μg

  5. A= 5,582; B=16,322 ; C=12,367 ; D=3,955 ; E=4,9 Nilai x = ( y – 1,4165)/ 0,8673 = (4,9– 1,4165)/0,8673 = 4,02 Jumlah Cd= Nilai x * D = 4,02 * 3,955= 15,89

  μg

• Fraksi Tidak Terlarut

  A : Berat Cawan Kosong B : Berat Cawan + Berat Kering C : Berat Insoluble (B-A) D : Pembacaan AAS Fp: Faktor Pengenceran = 10

  Persamaan Kurva Standar : y = 0,8673x + 1,4165; dimana y merupakan nilai dari pembacaan AAS

  1. A= 24,467 ; B= 26,303 ; C= 1,836 ; D= 8,9 Nilai x = ( y – 1,4165)/ 0,8673 = (8,9 – 1,4165)/0,8673 = 8,63 Jumlah Cd= Nilai x * C* Fp = 8,63 * 1,836* 10 = 79,21 μg

  2.A= 23,13 ; B= 24,951; C=1,821 ; D= 8,8

  Jumlah Cd= Nilai x * C* Fp = 8,51 * 1,821* 10 = 77,51

  3.A= 24,952 ; B= 26,839; C= 1,887 ; D= 9 Nilai x = ( y – 1,4165)/ 0,8673 = (9 – 1,4165)/0,8673 = 8,74 Jumlah Cd= Nilai x * C* Fp = 8,74 * 1,887* 10 = 82,50 μg

  4. A= 22,718 ; B= 24,539; C= 1,821 ; D= 8,7 Nilai x = ( y – 1,4165)/ 0,8673 = (8,7– 1,4165)/0,8673 = 8,40 Jumlah Cd= Nilai x * C* Fp = 8,40* 1,821* 10 = 76,46 μg

  5. A= 22,059 ; B= 23,9; C= 1,841 ; D= 8,6 Nilai x = ( y – 1,4165)/ 0,8673 = (8,6 – 1,4165)/0,8673 = 8,28 Jumlah Cd= Nilai x * C* Fp = 8,28* 1,841* 10 = 76,24 μg