( b ) Find the recurrent and the transient states. (c ) Find the expected number of years for the professor to achieve the highest ranking
( b ) Find the recurrent and the transient states. (c ) Find the expected number of years for the professor to achieve the highest ranking
given that in the first year he achieved the ith ranking.
Consider the !vlarkov s pe c i fie d . The steady-state p robabi li t ie s are
to
71"1 == - .
== -.
== -.
u 1 j s t b e fo r e t h e fi r s t t r a n si t i o n . ( a )
Assume that the process is in s t a te
in state 1 sixth tr an s iti on?
is
t hat
process will
(b) Determine the expected value and variance of the number of transitions up to
n e xt
process ret urns to state 1.
(c) W h a t is (approximately) probability t hat th e s t a t e the system resulting
Consi der t he 1\I arkov chai n specified in Fig. 7.25.
Transition
for Problem 30.
(a) transient and recurrent states. Also. determine the recurrent classes
ones. if
are
(b) Do there exist steady-state probabilities given t he s tarts
state I?
are (c)
exist steady-state probabilities the process starts state
are
Problems 397
(d) Assume that the process starts in state 1 but we begin observing it after it reaches
steady-state. (i) Find the probability that the state increases by one during the first transi
tion we observe. (ii) Find the conditional probability that the process was in state 2 when we
started observing it, given that the state increased by one during the first transition that we observed.
(iii) Find the probability that the state increased by one during the first change of state that we observed.
( e) Assume that the process starts in state 4. (i) For each recurrent class, determine the probability that we eventually reach
that class. (ii) What is the expected number of transitions up to and including the tran
sition at which we reach a recurrent state for the first time? Problem 31.* Absorption probabilities. Consider a Markov chain where each
state is either transient or absorbing. Fix an absorbing state s. Show that the prob
abilities ai of eventually reaching s starting from a state i are the unique solution to
the equations
as = 1,
ai = 0,
for all absorbing i t= s,
ai = L Pijaj, for all transient i.
j=l
Hint: If there are two solutions, find a system of equations that is satisfied by their difference, and look for its solutions.
Solution. The fact that the at satisfy these equations was established in the text, using the total probability theorem. To show uniqueness, let ai be another solution, and let
t5i = ai - ai. Denoting by A the set of absorbing states and using the fact t5j = 0 for
all j E A, we have
t5i = L Pijt5j = L Pijt5j, for all transient i.
j=l
j�A
Applying this relation m successive times, we obtain
t5i = L P1it L Pith ' " L Pjm-ljm . t5jm ·
it �A h�A
jm�A
Hence
= P (XI � A , . . . , Xm � A I Xo = i) . lt5jm I
=:; P (XI � A . . . . , Xm � A I Xo = i) . max lt5jl·
jltA
398 Markov Chains Chap. 7
The above relation holds for all transient i, so we obtain
f3 = P (X I � A, . . . , Xm � A I Xo = i).
Note that f3 < 1 , because there is positive probability that Xm is absorbing, regardless
of the initial state. It follows that maXj�A 18j I = 0, or ai = at for all i that are not absorbing. We also have aj = aj for all absorbing j, so ai = ai for all i.
Problem 32.* Multiple recurrent classes. Consider a Markov chain that has more that one recurrent class, as well as some transient states. Assume that all the recurrent classes are aperiodic.