2.1 1st type roots of the Riemann zeta functions 2
st
Eq.set.
For the first category roots and by taking the logarithm of two sides of the equations, and thus we Рet…
we will have for total roots 3 groups fieldsbut i have interest for first group, and therefore for our case we will get, if we replace s=x:
which means that , but with an initial value for x is
and total form from theory Lagrange for the root is..
With k:=0,1,2,3,4,5 …
…………………………………………………………………………………………………………………… …………..
…………………………………………………………………………………………………………………… …………..
But because the infinite sum approaching zero theoretically x get initial value
So we have in this case, in part, the consecutive intervals with k=n and k=n+1 for any n=4 and for the imaginary roots.
2.2 1st type roots of the Riemann zeta functions 1
st
Eq.set.
Same as in the first category roots
by taking the logarithm of two sides of the equations,
and thus we get..
i k
s s
Cos Log
sLog Log
s s
Log s
s Cos
s s
s
2
] 2
[ ]
2 [
] 2
[ ]
1 [
2 2
2 1
and total form from theory Lagrange for the root is..
WitС k:=0,1,2,3,4,5… аe СКve..
…………………………………………………………………………………………………………………… ………………..
…………………………………………………………………………………………………………………… ………………..
But because the infinite sum approaching zero theoretically x get initial value
So we have in this case, in part, the consecutive intervals with k=n and k=n+1 for any n=4 and for the imaginary roots.
AnН toа МКses СКve to Пor Imб tСe relКtionsСip…
N k
With Log
k x
, ,
, ]
2 [
2 Im
2.3 2st type roots of the Riemann zeta functions 1
st
Eq.set.
For the second category roots taking the logarithm of two sides of the equations, КnН tСus аe Рet…
and therefore for our case we will get, if we replace s=x:
k2 2
i] k1
2 [y]
ArcCos[Exp 2
] 2
[
1
in
x x
Cos Log
y x
p
And
k2 2
i] k1
2 [y]
ArcCos[Exp 2
] 2
[
1
in
x x
Cos Log
y x
p
which means that ,
and total form from theory Lagrange for the root is.. for 1
st
form
And for 2
st
form
] 2
[ ],
2 [
, ,
, ,
,
2 1
Log x
Log m
N k
k With
2.4 2st type roots of the Riemann zeta functions 2