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Tugas Akhir Perencanaan Struktur Factory Outlet dan Resto 2 Lantai
BAB 6 Balok Anak
2
6.3.Pembebanan Balok Anak as A’ 6.3.1.
Pembebanan
Gambar 6. 3 Lebar Equivalen Balok Anak as A’
Perencanaan Dimensi Balok : h = 112 . Ly
= 112 . 3750 = 312,5 mm = 350 mm
b = 23 . h = 23 . 312,5
= 233,33 mm h dipakai = 350 mm, b = 250 mm 1. Beban Mati q
D
Pembebanan balok as A’ 6 – 8 Berat sendiri = 0,25 x 0,35 – 0,12 x 2400 kgm
3
= 138 kgm Beban Plat
= 2 x 1,06 x 411 kgm
2
= 871,32 kgm qD = 1009,32 kgm
2. Beban hidup q
L
Beban hidup digunakan 250 kgm
2
qL = 2 x 1,06 x 250 kgm
2
= 530 kgm 3. Beban berfaktor q
U
q
U
= 1,2. q
D
+ 1,6. q
L
= 1,2 x 1009,32 + 1,6 x 530 = 2059,18 kgm
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Tugas Akhir Perencanaan Struktur Factory Outlet dan Resto 2 Lantai
BAB 6 Balok Anak 6.3.2. Perhitungan Tulangan
Tulangan Lentur Balok Anak Data Perencanaan :
h = 350 mm Ø
t
= 16
mm b = 250 mm
Ø
s
= 8 mm p = 40 mm
d = h - p - 12 Ø
t
- Ø
s
fy = 360 Mpa = 350 – 40 - 12.16 - 8
f’c = 25 MPa = 294
Tulangan Lentur Daerah Lapangan
ρb = ⎟⎟
⎠ ⎞
⎜⎜ ⎝
⎛ + fy
600 600
fy c.
β 0,85.f
= ⎟
⎠ ⎞
⎜ ⎝
⎛ + 360
600 600
85 ,
360 25
. 85
, = 0,0313
ρ
max
= 0,75 . ρb
= 0,75 . 0,0313 =
0,0234 ρ
min
= 0038
, 360
4 ,
1 4
, 1
= =
fy
Daerah Tumpuan Dari perhitungan SAP 2000 diperoleh :
Mu = 3413.81 kgm = 3,413 . 10
7
Nmm Mn =
φ Mu
=
7 7
10 .
266 ,
4 8
, 10
. 413
, 3
= Nmm
Rn =
=
2
.d b
Mn =
×
2 7
294 250
10 .
266 ,
4 1,97 Nmm
2
m = =
= 0,85.25
360 c
0,85.f fy
17
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Tugas Akhir Perencanaan Struktur Factory Outlet dan Resto 2 Lantai
BAB 6 Balok Anak
ρ
perlu
= ⎟
⎟ ⎠
⎞ ⎜
⎜ ⎝
⎛ −
− fy
Rn .
m 2
1 1
. m
1
= ⎟⎟
⎠ ⎞
⎜⎜ ⎝
⎛ ×
× −
− 360
97 ,
1 17
2 1
1 .
17 1
= 0,006 ρ ρ
max
ρ ρ
min
, di pakai ρ
perlu
= 0,006 As =
ρ
perlu
. b . d = 0,006. 250 . 294
= 441 mm
2
Digunakan tulangan D 16 = ¼ .
π . 16
2
= 200,96 mm
2
Jumlah tulangan =
19 ,
2 96
, 200
441 =
~ 3 buah.
Dipakai tulangan 3 D 16 mm
As ada = 3 . ¼ .
π . 16
2
= 602,88 mm
2
As ……… aman a =
250 25
85 ,
360 88
, 602
b c
f 0,85
fy ada
As ×
× ×
= ×
× ×
= 40,85 Mn ada = As ada × fy
⎟ ⎠
⎞ ⎜
⎝ ⎛ −
2 a
d = 602,88 × 360
⎟ ⎠
⎞ ⎜
⎝ ⎛
− 2
85 ,
40 294
= 5,9375 . 10
7
Nmm Mn ada Mn ......... aman
Kontrol Spasi : S
= 1
- n
sengkang 2
- tulangan
n -
2p -
b φ
φ
= 1
3 8
. 2
- 16
. 3
- 40
. 2
- 50
2 −
= 53 25 mm......oke
Jadi dipakai tulangan D 16 mm
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Tugas Akhir Perencanaan Struktur Factory Outlet dan Resto 2 Lantai
BAB 6 Balok Anak Daerah Lapangan
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