Penulangan Lapangan Arah Y Penulangan Tumpuan Arah X Penulangan Lapangan Arah Y

commit to user 169 Tugas Akhir Perencanaan Struktur Gedung Swalayan 2 lantai RAB BAB 5 Plat Lantai As yang timbul = 6. ¼. .8 2 = 301,44 273,6 As ….ok  Dipakai tulangan 8 – 170 mm

5.2.5. Penulangan Lapangan Arah Y

Mu = 216,58 kgm = 2,1658.10 6 Nmm Mn = Mu = 6 6 10 . 707 , 2 8 , 10 . 1658 , 2 Nmm Rn = 2 .dx b Mn 2 6 68 × 1000 10 . 707 , 2 0,585 Nmm 2 m = 29 , 11 25 × 85 , 240 . 85 , c f fy perlu = fy Rn . m 2 1 1 . m 1 = × 29 , 11 1 240 0,585 × 29 , 11 × 2 1 1 = 0,00123 perlu max perlu min , di pakai min As perlu = min . b . dx = 0,0025 × 1000 × 68 = 170 mm 2 Digunakan tulangan 8 As = ¼ . . 8 2 = 50,24 mm 2 Jumlah tulangan = 38 , 3 24 , 50 170 ~ 4 buah. Jarak tulangan dalam 1 m 1 = 250 4 1000 mm ~ 200 mm. commit to user 170 Tugas Akhir Perencanaan Struktur Gedung Swalayan 2 lantai RAB BAB 5 Plat Lantai Jarak maksimum = 4x h = 4 x 100 = 400 mm As yang timbul = 4. ¼. .8 2 = 200,96 170 As ….ok  Dipakai tulangan 8 – 200 mm

5.2.6. Penulangan Tumpuan Arah X

Mu = 521,56 kgm = 5,2156.10 6 Nmm Mn = Mu = 6 6 10 . 519 , 6 8 , 10 . 2156 , 5 Nmm Rn = 2 .dx b Mn 2 6 76 × 1000 10 . 519 , 6 1,13 Nmm 2 m = 29 , 11 5 2 × 85 , 240 . 85 , c f fy perlu = fy Rn . m 2 1 1 . m 1 = × 29 , 11 1 240 1,13 × 29 , 11 × 2 1 1 = 0,0048 perlu max perlu min , di pakai min As perlu = min . b . dx = 0,0048 × 1000 × 76 = 367,88 mm 2 Digunakan tulangan 8 = ¼ . . 8 2 = 50,24 mm 2 Jumlah tulangan = 32 , 7 24 , 50 88 , 367 ~ 8 buah. Jarak tulangan dalam 1 m 1 = 125 8 1000 mm. commit to user 171 Tugas Akhir Perencanaan Struktur Gedung Swalayan 2 lantai RAB BAB 5 Plat Lantai Jarak maksimum = 8 x h = 8 x 100 = 800 mm As yang timbul = 8. ¼. .8 2 = 401,92 367,88 As ….ok  Dipakai tulangan 8 – 125 mm

5.2.7. Penulangan Lapangan Arah Y

Mu = 349,18 kgm = 3,4918.10 6 Nmm Mn = Mu = 6 6 10 . 365 , 4 8 , 10 . 4918 , 3 Nmm Rn = 2 .dx b Mn 2 6 68 × 1000 10 . 365 , 4 0,945 Nmm 2 m = 29 , 11 25 × 85 , 240 . 85 , c f fy perlu = fy Rn . m 2 1 1 . m 1 = × 29 , 11 1 240 0,945 × 29 , 11 × 2 1 1 = 0,004 perlu max perlu min , di pakai min As perlu = min . b . dx = 0,004 × 1000 × 68 = 272 mm 2 Digunakan tulangan 8 As = ¼ . . 8 2 = 50,24 mm 2 Jumlah tulangan = 41 , 5 24 , 50 272 ~ 6 buah. commit to user 172 Tugas Akhir Perencanaan Struktur Gedung Swalayan 2 lantai RAB BAB 5 Plat Lantai Jarak tulangan dalam 1 m 1 = 66 , 166 6 1000 mm ~ 150 mm. Jarak maksimum = 6x h = 6 x 100 = 600 mm As yang timbul = 6. ¼. .8 2 = 301,44 272 As ….ok  Dipakai tulangan 8 – 150 mm

5.2.8. Rekapitulasi Tulangan