Perencanaan Struktur Gedung Laboratorium
109 109
=
fy 2m.Rn
1 1
m 1
=
240
0,385 .
11,294 .
2 1
1 11,294
1
= 0,0016
max
min
, di pakai
min
= 0,0025 As
=
min
. b . dx = 0,0025 . 1000 . 95
= 237,5 mm
2
Digunakan tulangan Ø 10 = ¼ .
. 10
2
= 78,5 mm
2
Jumlah tulangan =
78,5
237,5
3,025 ≈ 4 buah
Jarak tulangan dalam 1 m
1
=
4
1000
250 mm Jarak maksimum
= 2 × h = 2 × 120 = 240 mm As yang timbul
= 4. ¼ . . 10
2
= 314 mm
2
As …ok
Dipakai tulangan Ø 10 – 200 mm
5.6. Penulangan lapangan arah y
Mu = 151,301 kgm = 1,151301.10
6
Nmm
Mn =
0,8 .10
1,151301 M u
6
= 1,891.10
6
Nmm
Rn =
2 6
2
5 8
1000 10
. 1,891
b.d M n
= 0,262 Nmm
2
m =
0,85.25 240
c 0,85.f
fy
11,294
=
fy
2.m.Rn 1
1 m
1
Perencanaan Struktur Gedung Laboratorium
110 110
=
240
0,262 .
11,294 .
2 1
1 11,294
1
= 0,0011
max
min
, di pakai
min
= 0,0025 As
=
min
. b . dy = 0,0025 . 1000 . 85
= 212,5 mm
2
Digunakan tulangan 10 = ¼ . . 10
2
= 78,5 mm
2
Jumlah tulangan =
78,5
212,5
2,71 ≈ 3 buah
Jarak tulangan dalam 1 m
1
=
3
1000
333,33 mm Jarak maksimum
= 2 × h = 2 × 120 = 240 mm As yang timbul
= 3. ¼ . . 10
2
= 235,5 mm
2
As…..…ok Dipakai tulangan
10 – 200 mm
5.7. Penulangan tumpuan arah x
Mu = 592,387 kgm = 5,92387.10
6
Nmm Mn
= 0,8
.10 5,92387
M u
6
= 7,405.10
6
Nmm
Rn =
2 6
2
95 1000
10 7,405.
b.d M n
= 0,820 Nmm
2
m =
0,85.25 240
c 0,85.f
fy
11,294
=
fy
2m.Rn 1
1 m
1
=
240
0,820 .
11,294 .
2 1
1 11,294
1
Perencanaan Struktur Gedung Laboratorium
111 111
= 0,0035
max
min
, di pakai = 0,0035
As =
. b . dx = 0,0035 . 1000 . 95
= 332,5 mm
2
Digunakan tulangan 10
= ¼ . . 10
2
= 78,5 mm
2
Jumlah tulangan =
78,5
332,5
4,24 ≈ 5 buah
Jarak tulangan dalam 1 m
1
=
5
1000
200 mm Jarak maksimum
= 2 × h = 2 × 120 = 240 mm As yang timbul
=6. ¼ . . 10
2
= 471 mm
2
As……ok Dipakai tulangan
10 – 200 mm
5.8. Penulangan tumpuan arah y
Mu = 453,962 kgm = 4,53962.10
6
Nmm Mn
= 0,8
.10 4,53962
M u
6
= 5,675.10
6
Nmm
Rn =
2 6
2
85 1000
10 .
5,675 b.d
M n
= 0,785 Nmm
2
m =
0,85.25 240
c 0,85.f
fy
11,294
=
fy
2m.Rn 1
1 m
1
=
240
0,785 .
.11,94 2
1 1
. 11,294
1
= 0,0033
max
Perencanaan Struktur Gedung Laboratorium
112 112
min
, di pakai = 0,0033
As =
. b . dy = 0,0033 . 1000 . 85
= 280,5 mm
2
Digunakan tulangan 10
= ¼ . . 10
2
= 78,5 mm
2
Jumlah tulangan =
78,5
280,5
3,57 ~ 4 buah. Jarak tulangan dalam 1 m
1
=
4
1000
250 mm Jarak maksimum
= 2 × h = 2 × 120 = 240 mm As yang timbul
= 5. ¼ . . 10
2
= 392,5 mm
2
As …ok Dipakai tulangan
10 – 200 mm
5.9. Rekapitulasi Tulangan
