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Perencanaan Struktur dan Rencana Anggaran Biaya Restaurant dan Toko 2 lantai
BAB 5 Plat Lantai 1,0
4,0 4,0
Lx Ly
= =
Mlx = 0,001.qu . Lx
2
. x = 0.001. 973,2. 4,0
2
.21 = 576,13 kg m
Mly = 0,001.qu . Lx
2
. x = 0.001. 973,2. 4,0
2
.21 = 482,70 kg m
Mtx = - 0,001.qu . Lx
2
. x = - 0.001 .973,2. 4,0
2
.52 = - 1307,98 kg m
5.2. Penulangan Plat Lantai
Tabel 5.1. Perhitungan Plat Lantai Tipe Plat LyLx m
Mlx kgm Mly kgm Mtx kgm Mty kgm A1
4,04,0 = 1,0 435,99
435,99 - 1058,84
- 1058,84 A2
4,02,0= 2,0 225,78
73,69 -459,35
- 307,53 A3
4,01,5= 2,6 137,95
28,466 - 273,71
- 172,98 A4
2,01,5 = 1,3 91,96
59,12 - 201,45
- 166,41 B1
4,04,0 = 1,0 404,85
326,99 - 934,27
- 856,41 B2
4,01,5= 2,6 404,85
326,99 - 934,27
- 856,41 C
4,04,0 = 1,0 326,99
326,99 - 809,70
- 809,70 D
4,04,0 = 1,0 576,13
482,70 - 1307,98
-
Dari perhitungan momen diambil momen terbesar yaitu: Mlx
= 576,13 kgm
Mly = 482,70 kgm
Mtx = - 1307,98 kgm
Mty = - 1058,84 kgm
Data – data plat : Tebal plat h
= 12 cm = 120 mm
Diameter tulangan Æ = 10 mm fy
= 240 MPa f’c
= 25 MPa
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Perencanaan Struktur dan Rencana Anggaran Biaya Restaurant dan Toko 2 lantai
BAB 5 Plat Lantai b
= 1000 mm p
= 20 mm Tebal penutup d’
= p + ½Æ tul = 20 + 5
= 25 mm Tinggi Efektif d
= h - d’ = 120 – 25
= 95 mm Tingi efektif
Gambar 5.10 Perencanaan Tinggi Efektif
dx = h – p - ½Ø = 120 – 20 – 5 = 95 mm
dy = h – p – Ø - ½ Ø = 120 – 20 - 10 - ½ . 10 = 85 mm
rb =
÷÷ ø
ö çç
è æ
+ fy fy
fc 600
600 .
. .
85 ,
b
= ÷
ø ö
ç è
æ + 240
600 600
. 85
, .
240 25
. 85
, = 0,05376
r
max
= 0,75 . rb = 0,75 . 0,05376
= 0,04032 r
min
= 0,0025
h d y
d x d
commit to user
Perencanaan Struktur dan Rencana Anggaran Biaya Restaurant dan Toko 2 lantai
BAB 5 Plat Lantai
5.3. Penulangan tumpuan arah x
Mu = 1307,98 kgm = 13,0798. 10
7
Nmm
Mn =
f
Mu =
= 0,8
10 13,0798.
7
16,349.10
7
Nmm
Rn =
=
2
.
dx b
Mn =
2 7
95 .
1000 10
. 16,349.
1,811 Nmm
2
m =
2942 ,
11 25
. 85
, 240
. 85
, =
= c
f fy
r
perlu
=
÷ ÷
ø ö
ç ç
è æ
- -
fy Rn
. m
2 1
1 .
m 1
= .
2942 ,
11 1
÷ ÷
ø ö
ç ç
è æ
- -
240 811
, 1
. 2942
, 11
. 2
1 1
= 0,0079 r
r
max
r r
min
, di pakai r
perlu
= 0,0079 As
perlu
= r
perlu
. b . dx = 0,0079. 1000 . 95
= 750,58 mm
2
Digunakan tulangan Æ 10 As = ¼ . p . 10
2
= 78,5 mm
2
S =
perlu
As b
As .
= 750,58
1000 .
5 ,
78
= 104 ~ 100 mm n =
s b
=
100 1000
= 10
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Perencanaan Struktur dan Rencana Anggaran Biaya Restaurant dan Toko 2 lantai
BAB 5 Plat Lantai As yang timbul = 10. ¼ . p . 10
2
= 785 mm
2
As
perlu
…..…ok
Dipakai tulangan Æ 10 – 100 mm
5.4. Penulangan tumpuan arah y
