REKAYASA JALAN 1 sem 5

REKAYASA JALAN 1
SEMESTER 5

PERBEDAAN JALAN
PERKOTAAN DAN JALAN
ANTAR KOTA
JALAN PERKOTAAN

JALAN ANTAR KOTA

KLASIFIKASI JALAN

KLASIFIKASI MENURUT FUNGSI
JALAN
ARTERI PRIMER
V TINGGI, JARAK
JAUH
AKSES MASUK
DIBATASI

LOKAL

V RENDAH, JARAK
DEKAT
AKSES MASUK TAK
DIBATASI

KOLEKTOR
V SEDANG, JARAK
SEDANG
AKSES MASUK
DIBATASI

KLASIFIKASI MENURUT KELAS JALAN
FUNGSI

KELAS

MST [ton]

ARTERI


I

>10

II

10

III A

8

III B

8

III C

8


KOLEKTOR

MUATAN SUMBU TERBERAT

KLASIFIKASI MENURUT MEDAN
JALAN
JENIS MEDAN

NOTASI

KEMIRINGAN
MEDAN [%]

DATAR

D

50.000

4-6


0,9 -1

30.000 – 50.000

6–8

0,8 – 1

10.000 – 30.000

6–8

0,8 – 1

5.000 – 10.000

8 – 10

0,6 – 0,8


1.000 – 5.000

10 – 12

0,6 – 0,8

< 1.000

12 – 16

< 0,6

KECEPATAN RENCANA
FUNGSI

KECEPATAN RENCANA [km/jam]

JALAN


DATAR

BUKIT

GUNUNG

ARTERI

70 - 120

60 -80

40 – 70

KOLEKTOR

60 - 90

50 -60


30 – 50

LOKAL

40 - 70

30 -50

20 – 30

DAERAH YG SULIT, NILAI DI TABEL BISA DITURUNKAN 20
km/jam

BAGIAN-BAGIAN JALAN

x

d
c


b

Ruang manfaat jalan
(Rumaja)
= Ruang milik jalan
(Rumija)
=

5
m

a

b
1,5 m

c

d


Ruang pengawasan jalan
(Ruwasja)
= Bangunan
=

a = jalur lalu lintas
d = ambang
pengaman
b = bahu jalan
x = b+a+b =
jalan
SJA DARI ASbadan
JALAN,
ARTERI 20 M, KOLEKTOR 15 M, LOKAL 10 M
c = saluran tepi
 

CV

CV


2/2 D
2 LAJUR – 2 ARAH DG
MEDIAN
CV

2/2 UD
2 LAJUR – 2 ARAH TANPA
MEDIAN
CV

CV

CV

4/2 D
4 LAJUR – 2 ARAH DG
MEDIAN

4/2 UD

4 LAJUR – 2 ARAH TANPA
MEDIAN

CV

2/1 UD
2 LAJUR – 1 ARAH TANPA
MEDIAN

ALINEMEN HORIZONTAL

PANJANG MAKSIMUM BAGIAN LURUS
T SEPARUH Vr

PANJANG KRITIS
BILA V > SEPARUH Vr DAN T < 1 MENIT

Vertical Alignment
• Objective:
– Determine elevation to ensure
• Proper drainage
• Acceptable level of safety

• Primary challenge
– Transition between two grades
– Vertical curves
Sag Vertical Curve
G1

G2

Crest Vertical Curve

G1

G2

Vertical Curve
Fundamentals
• Parabolic function
– Constant rate of change of slope
– Implies equal curve tangents
2

y ax  bx  c
• y is the roadway elevation x stations
(or feet) from the beginning of the
curve

Vertical Curve
Fundamentals
PVI

G1

PVC

δ

G2
PVT

L/2

L
x

2

y ax  bx  c

Choose Either:
• G1, G2 in decimal form, L in feet
• G1, G2 in percent, L in stations

Choose Either:
• G1, G2 in decimal form, L in feet
• G1, G2 in percent, L in stations

Relationships
At the PVC : x 0 and Y c

dY
b G1
dx

At the PVC : x 0 and

d 2Y
G2  G1
G2  G1
Anywhere :
2a 
 a
2
dx
L
2L
G1

PVC

PVI

L/2

L
x

δ

G2

PVT

Example
A 400 ft. equal tangent crest vertical curve has a PVC station of 100+00 at 59
ft. elevation. The initial grade is 2.0 percent and the final grade is -4.5
percent. Determine the elevation and stationing of PVI, PVT, and the high
point of the curve.
PVI
.0%
2
=
G1

PVT
G=
2

PVC: STA 100+00
EL 59 ft.

- 4.

5%

PVI
.0%
2
=
G1

PVC: STA 100+00
EL 59 ft.

PVT
G=
2

-4.5

%

•G1, G2 in percent
•L in feet

Other Properties
G1

x
PVT

PVC
Y

A  G1  G2
A 2
Y
x
200 L

Ym

G2

PVI

AL
Ym 
800

Yf

AL
Yf 
200