AFR yang dihasilkan bahan bakar P 50 + E 50 P = 202,5 watt = 0,2025 kW ⇒ n= 4280 rpm
109
��� = 7,657658
Tabel 4.18 AFR hasil pengujian dengan bahan bakar E 100 Bahan
Bakar Paramet
er Perform
ansi Jumlah beban lampu100 Watt
2 4
6 8
10 12
E 100
n rpm
4160 4200
4250 4128
4051 3862
P Watt
200 407,5
625 636,7
5 657,7
2 656
ṁa kgjam
10,08 57
10,08 57
10,08 57
10,08 57
10,08 57
10,08 57
ṁf kgjam
0,864 0,947
368 1,102
041 1,241
379 1,285
714 1,317
073 AFR
11,67 326
10,64 601
9,151 835
8,124 588
7,844 43
7,657 658
4.5.3 AFR yang dihasilkan bahan bakar P 50 + E 50 P = 202,5 watt = 0,2025 kW ⇒ n= 4280 rpm
ṁf = 0,824427 kgjam V
d
: 95 × 10
−6
�
3
V
c
: 10 × 10
−6
�
3
P
i
= 85 kPa R = 0,287 kJkg.K
T
i
= 333 K
�
�
= �
�
�
�
+ �
�
�. �
�
�
�
= 8595 × 10
−6
+ 10 × 10
−6
0,287 × 333 �
�
= 0,00009338 ��
��� − ����� Maka:
ṁ
�
= �0,00009338
�� ��� − ������
1 ��� �
3600 ���
60 ��� � �
1 �����
2 ��� �
ṁ
�
= 0,0028016 �����
ṁ
�
= 10,0857 �����
Universitas Sumatera Utara
110
Sehingga: ��� =
ṁ
�
ṁ
�
��� = 10,0857
����� 0824427
����� ��� = 12,23358
P = 406,62 watt = 0,4062 kW ⇒ n= 4329 rpm
ṁf = 0,907563 kgjam V
d
: 95 × 10
−6
�
3
V
c
: 10 × 10
−6
�
3
P
i
= 85 kPa R = 0,287 kJkg.K
T
i
= 333 K
�
�
= �
�
�
�
+ �
�
�. �
�
�
�
= 8595 × 10
−6
+ 10 × 10
−6
0,287 × 333 �
�
= 0,00009338 ��
��� − ����� Maka:
ṁ
�
= �0,00009338
�� ��� − ������
1 ��� �
3600 ���
60 ��� � �
1 �����
2 ��� �
ṁ
�
= 0,0028016 �����
ṁ
�
= 10,0857 �����
Sehingga: ��� =
ṁ
�
ṁ
�
��� = 10,0857
����� 0,907563
����� ��� = 11,11294
P = 620 watt = 0,620 kW ⇒ n= 4352 rpm
ṁf = 1,08 kgjam V
d
: 95 × 10
−6
�
3
Universitas Sumatera Utara
111
V
c
: 10 × 10
−6
�
3
P
i
= 85 kPa R = 0,287 kJkg.K
T
i
= 333 K
�
�
= �
�
�
�
+ �
�
�. �
�
�
�
= 8595 × 10
−6
+ 10 × 10
−6
0,287 × 333 �
�
= 0,00009338 ��
��� − ����� Maka:
ṁ
�
= �0,00009338
�� ��� − ������
1 ��� �
3600 ���
60 ��� � �
1 �����
2 ��� �
ṁ
�
= 0,0028016 �����
ṁ
�
= 10,0857 �����
Sehingga: ��� =
ṁ
�
ṁ
�
��� = 10,0857
����� 1,08
����� ��� = 9,338607
P = 820 watt = 0,820 kW ⇒ n= 4370 rpm
ṁf = 1,2 kgjam V
d
: 95 × 10
−6
�
3
V
c
: 10 × 10
−6
�
3
P
i
= 85 kPa R = 0,287 kJkg.K
T
i
= 333 K
�
�
= �
�
�
�
+ �
�
�. �
�
Universitas Sumatera Utara
112
�
�
= 8595 × 10
−6
+ 10 × 10
−6
0,287 × 333 �
�
= 0,00009338 ��
��� − ����� Maka:
ṁ
�
= �0,00009338
�� ��� − ������
1 ��� �
3600 ���
60 ��� � �
1 �����
2 ��� �
ṁ
�
= 0,0028016 �����
ṁ
�
= 10,0857 �����
Sehingga:
��� = ṁ
�
ṁ
�
��� = 10,0857
����� 1,2
����� ��� = 8,404746
P = 836 watt = 0,836 kW ⇒ n= 4169 rpm
ṁf = 1,255814 kgjam V
d
: 95 × 10
−6
�
3
V
c
: 10 × 10
−6
�
3
P
i
= 85 kPa R = 0,287 kJkg.K
T
i
= 333 K
�
�
= �
�
�
�
+ �
�
�. �
�
�
�
= 8595 × 10
−6
+ 10 × 10
−6
0,287 × 333 �
�
= 0,00009338 ��
��� − ����� Maka:
ṁ
�
= �0,00009338
�� ��� − ������
1 ��� �
3600 ���
60 ��� � �
1 �����
2 ��� �
Universitas Sumatera Utara
113
ṁ
�
= 0,0028016 �����
ṁ
�
= 10,0857 �����
Sehingga: ��� =
ṁ
�
ṁ
�
��� = 10,0857
����� 1,255814
����� ��� = 8,031202
P = 834,2 watt = 0,8342 kW ⇒ n= 4024 rpm
ṁf = 1,301205 kgjam V
d
: 95 × 10
−6
�
3
V
c
: 10 × 10
−6
�
3
P
i
= 85 kPa R = 0,287 kJkg.K
T
i
= 333 K
�
�
= �
�
�
�
+ �
�
�. �
�
�
�
= 8595 × 10
−6
+ 10 × 10
−6
0,287 × 333 �
�
= 0,00009338 ��
��� − ����� Maka:
ṁ
�
= �0,00009338
�� ��� − ������
1 ��� �
3600 ���
60 ��� � �
1 �����
2 ��� �
ṁ
�
= 0,0028016 �����
ṁ
�
= 10,0857 �����
Sehingga: ��� =
ṁ
�
ṁ
�
��� = 10,0857
����� 1,301205
����� ��� = 7,751044
Universitas Sumatera Utara
114
Tabel 4.19 AFR hasil pengujian dengan bahan bakar P 50 + E50 Bahan
Bakar Paramet
er Perform
ansi Jumlah beban lampu100 Watt
2 4
6 8
10 12
P 50 + E50
n rpm
4280 4329
4352 4370
4169 4024
P Watt
202,5 406,6
2 620
820 836
834,2 ṁa
kgjam 10,08
57 10,08
57 10,08
57 10,08
57 10,08
57 10,08
57 ṁf
kgjam 0,824
427 0,907
563 1,08
1,2 1,255
814 1,301
205 AFR
12,23 358
11,11 294
9,338 607
8,404 746
8,031 202
7,751 044
4.5.4 AFR yang dihasilkan bahan bakar P 50 + E 5097,5 + H 2,5