AFR yang dihasilkan bahan bakar P 50 + E 50  P = 202,5 watt = 0,2025 kW ⇒ n= 4280 rpm

109 ��� = 7,657658 Tabel 4.18 AFR hasil pengujian dengan bahan bakar E 100 Bahan Bakar Paramet er Perform ansi Jumlah beban lampu100 Watt 2 4 6 8 10 12 E 100 n rpm 4160 4200 4250 4128 4051 3862 P Watt 200 407,5 625 636,7 5 657,7 2 656 ṁa kgjam 10,08 57 10,08 57 10,08 57 10,08 57 10,08 57 10,08 57 ṁf kgjam 0,864 0,947 368 1,102 041 1,241 379 1,285 714 1,317 073 AFR 11,67 326 10,64 601 9,151 835 8,124 588 7,844 43 7,657 658 4.5.3 AFR yang dihasilkan bahan bakar P 50 + E 50  P = 202,5 watt = 0,2025 kW ⇒ n= 4280 rpm ṁf = 0,824427 kgjam V d : 95 × 10 −6 � 3 V c : 10 × 10 −6 � 3 P i = 85 kPa R = 0,287 kJkg.K T i = 333 K � � = � � � � + � � �. � � � � = 8595 × 10 −6 + 10 × 10 −6 0,287 × 333 � � = 0,00009338 �� ��� − ����� Maka: ṁ � = �0,00009338 �� ��� − ������ 1 ��� � 3600 ��� 60 ��� � � 1 ����� 2 ��� � ṁ � = 0,0028016 ����� ṁ � = 10,0857 ����� Universitas Sumatera Utara 110 Sehingga: ��� = ṁ � ṁ � ��� = 10,0857 ����� 0824427 ����� ��� = 12,23358  P = 406,62 watt = 0,4062 kW ⇒ n= 4329 rpm ṁf = 0,907563 kgjam V d : 95 × 10 −6 � 3 V c : 10 × 10 −6 � 3 P i = 85 kPa R = 0,287 kJkg.K T i = 333 K � � = � � � � + � � �. � � � � = 8595 × 10 −6 + 10 × 10 −6 0,287 × 333 � � = 0,00009338 �� ��� − ����� Maka: ṁ � = �0,00009338 �� ��� − ������ 1 ��� � 3600 ��� 60 ��� � � 1 ����� 2 ��� � ṁ � = 0,0028016 ����� ṁ � = 10,0857 ����� Sehingga: ��� = ṁ � ṁ � ��� = 10,0857 ����� 0,907563 ����� ��� = 11,11294  P = 620 watt = 0,620 kW ⇒ n= 4352 rpm ṁf = 1,08 kgjam V d : 95 × 10 −6 � 3 Universitas Sumatera Utara 111 V c : 10 × 10 −6 � 3 P i = 85 kPa R = 0,287 kJkg.K T i = 333 K � � = � � � � + � � �. � � � � = 8595 × 10 −6 + 10 × 10 −6 0,287 × 333 � � = 0,00009338 �� ��� − ����� Maka: ṁ � = �0,00009338 �� ��� − ������ 1 ��� � 3600 ��� 60 ��� � � 1 ����� 2 ��� � ṁ � = 0,0028016 ����� ṁ � = 10,0857 ����� Sehingga: ��� = ṁ � ṁ � ��� = 10,0857 ����� 1,08 ����� ��� = 9,338607  P = 820 watt = 0,820 kW ⇒ n= 4370 rpm ṁf = 1,2 kgjam V d : 95 × 10 −6 � 3 V c : 10 × 10 −6 � 3 P i = 85 kPa R = 0,287 kJkg.K T i = 333 K � � = � � � � + � � �. � � Universitas Sumatera Utara 112 � � = 8595 × 10 −6 + 10 × 10 −6 0,287 × 333 � � = 0,00009338 �� ��� − ����� Maka: ṁ � = �0,00009338 �� ��� − ������ 1 ��� � 3600 ��� 60 ��� � � 1 ����� 2 ��� � ṁ � = 0,0028016 ����� ṁ � = 10,0857 ����� Sehingga: ��� = ṁ � ṁ � ��� = 10,0857 ����� 1,2 ����� ��� = 8,404746  P = 836 watt = 0,836 kW ⇒ n= 4169 rpm ṁf = 1,255814 kgjam V d : 95 × 10 −6 � 3 V c : 10 × 10 −6 � 3 P i = 85 kPa R = 0,287 kJkg.K T i = 333 K � � = � � � � + � � �. � � � � = 8595 × 10 −6 + 10 × 10 −6 0,287 × 333 � � = 0,00009338 �� ��� − ����� Maka: ṁ � = �0,00009338 �� ��� − ������ 1 ��� � 3600 ��� 60 ��� � � 1 ����� 2 ��� � Universitas Sumatera Utara 113 ṁ � = 0,0028016 ����� ṁ � = 10,0857 ����� Sehingga: ��� = ṁ � ṁ � ��� = 10,0857 ����� 1,255814 ����� ��� = 8,031202  P = 834,2 watt = 0,8342 kW ⇒ n= 4024 rpm ṁf = 1,301205 kgjam V d : 95 × 10 −6 � 3 V c : 10 × 10 −6 � 3 P i = 85 kPa R = 0,287 kJkg.K T i = 333 K � � = � � � � + � � �. � � � � = 8595 × 10 −6 + 10 × 10 −6 0,287 × 333 � � = 0,00009338 �� ��� − ����� Maka: ṁ � = �0,00009338 �� ��� − ������ 1 ��� � 3600 ��� 60 ��� � � 1 ����� 2 ��� � ṁ � = 0,0028016 ����� ṁ � = 10,0857 ����� Sehingga: ��� = ṁ � ṁ � ��� = 10,0857 ����� 1,301205 ����� ��� = 7,751044 Universitas Sumatera Utara 114 Tabel 4.19 AFR hasil pengujian dengan bahan bakar P 50 + E50 Bahan Bakar Paramet er Perform ansi Jumlah beban lampu100 Watt 2 4 6 8 10 12 P 50 + E50 n rpm 4280 4329 4352 4370 4169 4024 P Watt 202,5 406,6 2 620 820 836 834,2 ṁa kgjam 10,08 57 10,08 57 10,08 57 10,08 57 10,08 57 10,08 57 ṁf kgjam 0,824 427 0,907 563 1,08 1,2 1,255 814 1,301 205 AFR 12,23 358 11,11 294 9,338 607 8,404 746 8,031 202 7,751 044 4.5.4 AFR yang dihasilkan bahan bakar P 50 + E 5097,5 + H 2,5