104
��� = 10,0857
����� 1
����� ��� = 10,0857
Tabel 4.17 AFR hasil pengujian dengan bahan bakar P 100 Bahan
Bakar Parame
ter Perfor
mansi Jumlah beban lampu100 Watt
2 4
6 8
10 12
P100 n rpm
4330 4410
4510 4600
4690 4560
P Watt
201,6 401,6
607,2 806,4
1008 1012,
5 ṁ
a kgjam
10,085 7
10,085 7
10,085 7
10,085 7
10,085 7
10,08 57
ṁf kgjam
0,6136 36
0,7105 26
0,7941 18
0,8059 7
0,9310 34
1 AFR
16,435 95
14,194 68
12,700 51
12,513 73
10,832 78
10,08 57
4.5.2 AFR yang dihasilkan bahan bakar E 100 P = 200 watt = 0,200 kW ⇒ n= 4160 rpm
ṁf = 0,947368 kgjam V
d
: 95 × 10
−6
�
3
V
c
: 10 × 10
−6
�
3
P
i
= 85 kPa R = 0,287 kJkg.K
T
i
= 333 K
�
�
= �
�
�
�
+ �
�
�. �
�
�
�
= 8595 × 10
−6
+ 10 × 10
−6
0,287 × 333 �
�
= 0,00009338 ��
��� − ����� Maka:
ṁ
�
= �0,00009338
�� ��� − ������
1 ��� �
3600 ���
60 ��� � �
1 �����
2 ��� �
Universitas Sumatera Utara
105
ṁ
�
= 0,0028016 �����
ṁ
�
= 10,0857 �����
Sehingga: ��� =
ṁ
�
ṁ
�
��� = 10,0857
����� 0,864
����� ��� = 11,67326
P = 407,5 watt = 0,4075 kW ⇒ n= 4200 rpm
ṁf = 0,947368 kgjam V
d
: 95 × 10
−6
�
3
V
c
: 10 × 10
−6
�
3
P
i
= 85 kPa R = 0,287 kJkg.K
T
i
= 333 K
�
�
= �
�
�
�
+ �
�
�. �
�
�
�
= 8595 × 10
−6
+ 10 × 10
−6
0,287 × 333 �
�
= 0,00009338 ��
��� − ����� Maka:
ṁ
�
= �0,00009338
�� ��� − ������
1 ��� �
3600 ���
60 ��� � �
1 �����
2 ��� �
ṁ
�
= 0,0028016 �����
ṁ
�
= 10,0857 �����
Sehingga: ��� =
ṁ
�
ṁ
�
��� = 10,0857
����� 0,947368
����� ��� = 10,64601
P = 625watt = 0,625 kW ⇒ n= 4250 rpm
Universitas Sumatera Utara
106
ṁf = 1,102041 kgjam V
d
: 95 × 10
−6
�
3
V
c
: 10 × 10
−6
�
3
P
i
= 85 kPa R = 0,287 kJkg.K
T
i
= 333 K
�
�
= �
�
�
�
+ �
�
�. �
�
�
�
= 8595 × 10
−6
+ 10 × 10
−6
0,287 × 333 �
�
= 0,00009338 ��
��� − ����� Maka:
ṁ
�
= �0,00009338
�� ��� − ������
1 ��� �
3600 ���
60 ��� � �
1 �����
2 ��� �
ṁ
�
= 0,0028016 �����
ṁ
�
= 10,0857 �����
Sehingga: ��� =
ṁ
�
ṁ
�
��� = 10,0857
����� 1,102041
����� ��� = 9,151835
P = 801,6 watt = 0,8016 kW ⇒ n= 4610 rpm
ṁf = 1,241379 kgjam V
d
: 95 × 10
−6
�
3
V
c
: 10 × 10
−6
�
3
P
i
= 85 kPa R = 0,287 kJkg.K
T
i
= 333 K
�
�
= �
�
�
�
+ �
�
�. �
�
Universitas Sumatera Utara
107
�
�
= 8595 × 10
−6
+ 10 × 10
−6
0,287 × 333 �
�
= 0,00009338 ��
��� − ����� Maka:
ṁ
�
= �0,00009338
�� ��� − ������
1 ��� �
3600 ���
60 ��� � �
1 �����
2 ��� �
ṁ
�
= 0,0028016 �����
ṁ
�
= 10,0857 �����
Sehingga: ��� =
ṁ
�
ṁ
�
��� = 10,0857
����� 1,241379
����� ��� = 8,124588
P = 1002 watt = 1,002 kW ⇒ n= 4710 rpm
ṁf = 1,285714 kgjam V
d
: 95 × 10
−6
�
3
V
c
: 10 × 10
−6
�
3
P
i
= 85 kPa R = 0,287 kJkg.K
T
i
= 333 K
�
�
= �
�
�
�
+ �
�
�. �
�
�
�
= 8595 × 10
−6
+ 10 × 10
−6
0,287 × 333 �
�
= 0,00009338 ��
��� − ����� Maka:
ṁ
�
= �0,00009338
�� ��� − ������
1 ��� �
3600 ���
60 ��� � �
1 �����
2 ��� �
ṁ
�
= 0,0028016 �����
Universitas Sumatera Utara
108
ṁ
�
= 10,0857 �����
Sehingga: ��� =
ṁ
�
ṁ
�
��� = 10,0857
����� 1,285714
����� ��� = 7,84443
P = 959,6 watt = 0,9596 kW ⇒ n= 4448 rpm
ṁf = 1,317073 kgjam V
d
: 95 × 10
−6
�
3
V
c
: 10 × 10
−6
�
3
P
i
= 85 kPa R = 0,287 kJkg.K
T
i
= 333 K
�
�
= �
�
�
�
+ �
�
�. �
�
�
�
= 8595 × 10
−6
+ 10 × 10
−6
0,287 × 333 �
�
= 0,00009338 ��
��� − ����� Maka:
ṁ
�
= �0,00009338
�� ��� − ������
1 ��� �
3600 ���
60 ��� � �
1 �����
2 ��� �
ṁ
�
= 0,0028016 �����
ṁ
�
= 10,0857 �����
Sehingga: ��� =
ṁ
�
ṁ
�
��� = 10,0857
����� 1,317073
�����
Universitas Sumatera Utara
109
��� = 7,657658
Tabel 4.18 AFR hasil pengujian dengan bahan bakar E 100 Bahan
Bakar Paramet
er Perform
ansi Jumlah beban lampu100 Watt
2 4
6 8
10 12
E 100
n rpm
4160 4200
4250 4128
4051 3862
P Watt
200 407,5
625 636,7
5 657,7
2 656
ṁa kgjam
10,08 57
10,08 57
10,08 57
10,08 57
10,08 57
10,08 57
ṁf kgjam
0,864 0,947
368 1,102
041 1,241
379 1,285
714 1,317
073 AFR
11,67 326
10,64 601
9,151 835
8,124 588
7,844 43
7,657 658
4.5.3 AFR yang dihasilkan bahan bakar P 50 + E 50 P = 202,5 watt = 0,2025 kW ⇒ n= 4280 rpm