AFR yang dihasilkan bahan bakar E 100  P = 200 watt = 0,200 kW ⇒ n= 4160 rpm

104 ��� = 10,0857 ����� 1 ����� ��� = 10,0857 Tabel 4.17 AFR hasil pengujian dengan bahan bakar P 100 Bahan Bakar Parame ter Perfor mansi Jumlah beban lampu100 Watt 2 4 6 8 10 12 P100 n rpm 4330 4410 4510 4600 4690 4560 P Watt 201,6 401,6 607,2 806,4 1008 1012, 5 ṁ a kgjam 10,085 7 10,085 7 10,085 7 10,085 7 10,085 7 10,08 57 ṁf kgjam 0,6136 36 0,7105 26 0,7941 18 0,8059 7 0,9310 34 1 AFR 16,435 95 14,194 68 12,700 51 12,513 73 10,832 78 10,08 57

4.5.2 AFR yang dihasilkan bahan bakar E 100  P = 200 watt = 0,200 kW ⇒ n= 4160 rpm

ṁf = 0,947368 kgjam V d : 95 × 10 −6 � 3 V c : 10 × 10 −6 � 3 P i = 85 kPa R = 0,287 kJkg.K T i = 333 K � � = � � � � + � � �. � � � � = 8595 × 10 −6 + 10 × 10 −6 0,287 × 333 � � = 0,00009338 �� ��� − ����� Maka: ṁ � = �0,00009338 �� ��� − ������ 1 ��� � 3600 ��� 60 ��� � � 1 ����� 2 ��� � Universitas Sumatera Utara 105 ṁ � = 0,0028016 ����� ṁ � = 10,0857 ����� Sehingga: ��� = ṁ � ṁ � ��� = 10,0857 ����� 0,864 ����� ��� = 11,67326  P = 407,5 watt = 0,4075 kW ⇒ n= 4200 rpm ṁf = 0,947368 kgjam V d : 95 × 10 −6 � 3 V c : 10 × 10 −6 � 3 P i = 85 kPa R = 0,287 kJkg.K T i = 333 K � � = � � � � + � � �. � � � � = 8595 × 10 −6 + 10 × 10 −6 0,287 × 333 � � = 0,00009338 �� ��� − ����� Maka: ṁ � = �0,00009338 �� ��� − ������ 1 ��� � 3600 ��� 60 ��� � � 1 ����� 2 ��� � ṁ � = 0,0028016 ����� ṁ � = 10,0857 ����� Sehingga: ��� = ṁ � ṁ � ��� = 10,0857 ����� 0,947368 ����� ��� = 10,64601  P = 625watt = 0,625 kW ⇒ n= 4250 rpm Universitas Sumatera Utara 106 ṁf = 1,102041 kgjam V d : 95 × 10 −6 � 3 V c : 10 × 10 −6 � 3 P i = 85 kPa R = 0,287 kJkg.K T i = 333 K � � = � � � � + � � �. � � � � = 8595 × 10 −6 + 10 × 10 −6 0,287 × 333 � � = 0,00009338 �� ��� − ����� Maka: ṁ � = �0,00009338 �� ��� − ������ 1 ��� � 3600 ��� 60 ��� � � 1 ����� 2 ��� � ṁ � = 0,0028016 ����� ṁ � = 10,0857 ����� Sehingga: ��� = ṁ � ṁ � ��� = 10,0857 ����� 1,102041 ����� ��� = 9,151835  P = 801,6 watt = 0,8016 kW ⇒ n= 4610 rpm ṁf = 1,241379 kgjam V d : 95 × 10 −6 � 3 V c : 10 × 10 −6 � 3 P i = 85 kPa R = 0,287 kJkg.K T i = 333 K � � = � � � � + � � �. � � Universitas Sumatera Utara 107 � � = 8595 × 10 −6 + 10 × 10 −6 0,287 × 333 � � = 0,00009338 �� ��� − ����� Maka: ṁ � = �0,00009338 �� ��� − ������ 1 ��� � 3600 ��� 60 ��� � � 1 ����� 2 ��� � ṁ � = 0,0028016 ����� ṁ � = 10,0857 ����� Sehingga: ��� = ṁ � ṁ � ��� = 10,0857 ����� 1,241379 ����� ��� = 8,124588  P = 1002 watt = 1,002 kW ⇒ n= 4710 rpm ṁf = 1,285714 kgjam V d : 95 × 10 −6 � 3 V c : 10 × 10 −6 � 3 P i = 85 kPa R = 0,287 kJkg.K T i = 333 K � � = � � � � + � � �. � � � � = 8595 × 10 −6 + 10 × 10 −6 0,287 × 333 � � = 0,00009338 �� ��� − ����� Maka: ṁ � = �0,00009338 �� ��� − ������ 1 ��� � 3600 ��� 60 ��� � � 1 ����� 2 ��� � ṁ � = 0,0028016 ����� Universitas Sumatera Utara 108 ṁ � = 10,0857 ����� Sehingga: ��� = ṁ � ṁ � ��� = 10,0857 ����� 1,285714 ����� ��� = 7,84443  P = 959,6 watt = 0,9596 kW ⇒ n= 4448 rpm ṁf = 1,317073 kgjam V d : 95 × 10 −6 � 3 V c : 10 × 10 −6 � 3 P i = 85 kPa R = 0,287 kJkg.K T i = 333 K � � = � � � � + � � �. � � � � = 8595 × 10 −6 + 10 × 10 −6 0,287 × 333 � � = 0,00009338 �� ��� − ����� Maka: ṁ � = �0,00009338 �� ��� − ������ 1 ��� � 3600 ��� 60 ��� � � 1 ����� 2 ��� � ṁ � = 0,0028016 ����� ṁ � = 10,0857 ����� Sehingga: ��� = ṁ � ṁ � ��� = 10,0857 ����� 1,317073 ����� Universitas Sumatera Utara 109 ��� = 7,657658 Tabel 4.18 AFR hasil pengujian dengan bahan bakar E 100 Bahan Bakar Paramet er Perform ansi Jumlah beban lampu100 Watt 2 4 6 8 10 12 E 100 n rpm 4160 4200 4250 4128 4051 3862 P Watt 200 407,5 625 636,7 5 657,7 2 656 ṁa kgjam 10,08 57 10,08 57 10,08 57 10,08 57 10,08 57 10,08 57 ṁf kgjam 0,864 0,947 368 1,102 041 1,241 379 1,285 714 1,317 073 AFR 11,67 326 10,64 601 9,151 835 8,124 588 7,844 43 7,657 658 4.5.3 AFR yang dihasilkan bahan bakar P 50 + E 50  P = 202,5 watt = 0,2025 kW ⇒ n= 4280 rpm