Range R T 0 he number of classes Length class Median Me Modus Mo Standard Deviation S

Appendix 3 Pre-test Results of Control Class Pre-test results of Control Class is as follows : 30 40 25 20 40 15 30 25 20 30 25 25 20 30 25 35 30 30 30 15 20 25 25 40 15 30 20 30 30 40 20 30 From there it is obtained that the maximum val X max is 40 and minimum value X min is 15. So that it can be made of a frequency distribution table after first determining the value range R, the number of classes K, and length class P. Three values obtained based on the following calculation.

a. Range R

25 15 40 min      X X R mx

b. T 0 he number of classes

K 6 92 , 5 92 , 4 1 49 , 1 3 , 3 1 31 log 3 , 3 1 log 3 , 3 1            n K So the number of classes is 6

c. Length class

P 5 16 , 4 6 25     K R P So that the length class is 5 Distribution table is as follows : Class Class Limit Middle Class Values x i Frekuensi f i f i . x i f i . x i 2 15 - 19 14.5 17 3 51 867 20 - 24 19.5 22 6 132 2904 25 - 29 24.5 27 7 189 5103 30 - 34 29.5 32 10 320 10240 35 - 39 34.5 37 1 37 1369 40 - 44 39.5 42 4 168 7056 Jumlah ∑ 162 177 31 897 27539 Based on the frequency distribution table, it can be determined average value X , median Me, mode Mo, and standard deviation S value of this pre- test. Here is a calculation to determine those values. 93 , 28 31 897       i i i f x f X

a. Median Me

The median value is determined by the following statistical formula                f F n P b Me 2 1 Where : b = lower limit of the class median = 29,5 P = length class = 5 n = number of data = 31 F = value of cumulative frequency before the class median = 3 + 6 + 7 = 16 f = frequency of median class value = 10 Based on these data, the median value can be determined from the results of this pre-test are as follows.   25 , 29 25 , 5 , 29 05 , 5 5 , 29 10 16 31 . 2 1 5 5 , 29                       Me

b. Modus Mo

Mode value is determined using the following statistical formula          2 1 1 b b b P b Mo Where : b = lower limit of the class median = 29,5 P = length class = 5 b 1 = class frequency mode frequency is reduced previous class = 10 – 7 = 3 b 2 = class frequency mode frequency is reduced subsequent class = 10 – 1 = 9 Based on these data, it can be determined from the pre test value of this mode is as follows.   75 , 30 25 , 1 5 , 29 25 , 5 5 , 29 9 3 3 5 5 , 29                Mo

c. Standard Deviation S

Standard deviation value determined with the following statistical formula     27 , 7 79 , 52 30 87 , 1583 30 13 , 25955 27539 30 31 804609 27539 1 31 31 897 27539 1 . . 2 2 2                  i i i i i i f f x f x f S i Appendix 4 Post-test result of Experimental Class Post-test results of Experimental Class is as follows . 45 50 60 55 40 65 70 70 55 55 55 60 50 60 40 55 70 50 60 70 70 70 65 55 60 75 55 55 50 65 55 65 Baesd on the table, it is obtained that the maximum value X max is 75 and minimum value X min is 40. So that it can be made of a frequency distribution table after first determining the value range R, the number of classes K, and length class P. Nilai ketiganya diperoleh berdasarkan perhitungan berikut ini.

a. Range R

35 40 75 min      X X R mx

b. The number of classes

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