Tugas Akhir Perencanaan Struktur Gedung Perpustakaan 2 Lantai
4.4 Perhitungan Tulangan Tangga dan Bordes
4.4.1 Perhitungan Tulangan Tumpuan
d = h
– p – ½ Ø tul - ½ Ø sengkang = 200
– 30 – 6 - 4 = 160 mm
M
u
= 2997,55 kgm = 2,99755 .10
7
Nmm Mn
= 0,8
10 .
99755 ,
2 φ
M u
7
= 3,7469 .10
7
Nmm m
=
294 ,
11 25
. 85
, 240
. 85
,
fc
fy
b =
fy 600
600 .
. fy
fc .
85 ,
=
240 600
600 .
. 240
25 .
85 ,
= 0,0538
max
= 0,75 . b
= 0,04032
min
= 0,002 Rn =
464 ,
1 160
. 1000
10 .
7469 ,
3 .
2 7
2
d b
Mn
Nmm
ada
=
fy 2.m.Rn
1 1
m 1
=
240 464
, 1
294 ,
11 2
1 1
294 ,
11 1
x x
= 0,0063
ada
max
min
di pakai
ada
= 0,0063
Tugas Akhir Perencanaan Struktur Gedung Perpustakaan 2 Lantai
As =
. b . d = 0,0063 x 1000 x 160
= 1008 mm
2
Dipakai tulangan 12 mm
= ¼ . x 12
2
= 113,097 mm
2
Jumlah tulangan =
097 ,
113 1008
= 8,9 ≈ 9 buah
Jarak tulangan =
9 1000
= 111,11 mm ≈ 100 mm
Dipakai tulangan 12 mm – 100 mm
As yang timbul = 9
. ¼ .π. d
2
= 1017,873 mm
2
As 1008 mm
2
........... Aman
4.4.2 Perhitungan Tulangan Lapangan
M
u
= 1460,55 kgm = 1,46055 . 10
7
Nmm Mn
= 8
, 10
. 46055
, 1
7
Mu
= 1,8257. 10
7
Nmm m
= 294
, 11
25 .
85 ,
240 fc
. 85
, fy
b =
fy 600
600 .
. fy
fc .
85 ,
=
240 600
600 .
85 ,
. 240
25 .
85 ,
= 0,0538
max
= 0,75 . b
= 0,04032
min
= 0,002 Rn
=
2 7
2
1000160 1,46055.10
b.d M n
0,713 Nmm
2
Tugas Akhir Perencanaan Struktur Gedung Perpustakaan 2 Lantai
ada
=
fy 2.m.Rn
1 1
m 1
=
240 713
, 294
, 11
2 1
1 294
, 11
1 x
x
= 0,003
ada
min
max
di pakai
ada
= 0,003 As
= . b . d
= 0,003 x 1000 x 160 = 480 mm
2
Dipakai tulangan 12 mm
= ¼ . x 12
2
= 113,097 mm
2
Jumlah tulangan dalam 1 m
2
= 097
, 113
480 = 4,2
5 tulangan
Jarak tulangan =
5 1000
= 200 mm
Dipakai tulangan 12 mm – 200 mm
As yang timbul = 5 . ¼ x
x d
2
= 565,485 mm
2
As 480 mm
2
....aman
4.5 Perencanaan Balok Bordes
qu balok 270
30 3 m
150
Tugas Akhir Perencanaan Struktur Gedung Perpustakaan 2 Lantai
Data perencanaan: h = 300 mm
b = 150 mm d`= 30 mm
d = h – d` = 300 – 30 = 270 mm
1. Pembebanan Balok Bordes
Beban mati qD Berat sendiri
= 0,15 x 0,3 x 2400 = 108 kgm
Berat dinding = 0,15 x 2 x 1700
= 510 kgm Berat plat bordes
= 0,20 x 2400 = 480 kgm
qD = 1098 kgm Beban Hidup qL
=500 Kgm Beban ultimate qU
qU = 1,2 . qD + 1,6.qL = 1,2 . 1098 + 1,6 .500
= 2117,6 Kgm Beban reaksi bordes
qU =
bordes lebar
bordes aksi
Re
= 3
3 .
6 ,
2117 .
2 1
= 1058,8 Kgm a.
Perhitungan tulangan lentur
M
u
= 24434,39 kgm = 2,443439.10
7
Nmm Mn
= 0,8
10 2,443439.
φ M u
7
= 3,0543 .10
7
Nmm m
=
294 ,
11 25
. 85
, 240
. 85
,
fc
fy
Tugas Akhir Perencanaan Struktur Gedung Perpustakaan 2 Lantai
b =
fy fy
fc
600 600
. .
. 85
,
=
240 600
600 .
. 240
25 .
85 ,
= 0,0538
max
= 0,75 . b
= 0,04032
min
= 0,002
Rn =
4189 ,
270 .
1000 10
. 0543
, 3
.
2 7
2
d b
Mn
Nmm
ada
=
fy 2.m.Rn
1 1
m 1
=
240 4189
, 294
, 11
2 1
1 294
, 11
1 x
x
= 0,00176
ada
max
min
di pakai
min
= 0,0020 As
= . b . d
= 0,0020 x 150 x 270 = 81 mm
2
Dipakai tulangan 12 mm
= ¼ . x 12
2
= 113,097 mm
2
Jumlah tulangan =
097 ,
113 81
= 0,716 ≈ β buah
As yang timbul = β. ¼ .π. d
2
= 226,08 mm
2
As 81 mm
2
...... Aman
Dipakai tulangan 2 12 mm
Tugas Akhir Perencanaan Struktur Gedung Perpustakaan 2 Lantai
b. Perhitungan Tulangan Geser
Vu = 3257,86 kg = 32578,6 N
Vc =
. c
f b.d.
. 6
1
= 16 . 150 . 270. 25 .
= 33750 N Vc = 0,6 . Vc
= 20250 N 3
Vc = 3 . Vc = 60750 N
Vu Vc perlu tulangan geser
Vs = Vu -
Vc = 3257,6
– 20250 = 12328,6 N
Vs perlu = 67
, 20547
6 ,
6 ,
12328
Vs
N Dipakai Sengkang begel
8 mm = ¼ . x 8
2
= 50,24 mm
2
As = 2 x 50,24 = 100,48 mm
2
Jarak sengkang S =
67
, 20547
270 .
240 .
48 ,
100 .
. .
perlu Vs
d fy
As
316,87 mm 300 mm
Jarak Sengkang Max =
2 h
=
2 300
= 150 mm Jadi dipakai sengkang
8 – 150 mm
Tugas Akhir Perencanaan Struktur Gedung Perpustakaan 2 Lantai
4.6 Perhitungan Pondasi Tangga
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