commit to user
T ugas A khir
Perencanaan Struktur dan Rencana Anggaran Biay a Rumah Tinggal 2 Lantai
BA B 6 Balok A nak 143
6.3.2. Perhitungan Tulangan Balok Anak as C” 3 - 5
a.
Tulangan Lentur Balok Anak
Data Perencanaan : h
= 350 mm Ø
t
= 16 mm b
= 200 mm Ø
s
= 8 mm p
= 40 mm d
= h - p - ½ . Ø
t
- Ø
s
fy = 320 Mpa = 350 – 40 – ½ . 16 – 8
f’c = 25 MPa = 294 mm
1. Daerah Tumpuan
b =
fy fy
fc
600 600
. .
. 85
,
=
320
600 600
. 320
85 ,
. 25
. 85
, = 0,036
max
= 0,75 . b
= 0,75 . 0,036 = 0,027
min
= 320
4 ,
1 = 0,0043
Dari Perhitungan SAP 2000 diperoleh :
Mu = 2618,49 kgm = 2,62 .10
7
Nmm Mn
= φ
Mu =
8 ,
10 .
2,62
7
= 3,28 .10
7
Nmm Rn
=
2
.
d b
Mn
=
2 7
294 .
200 10
. 3,28
= 1,89 m
=
c f
fy
,
. 85
, =
25 .
85 ,
320 = 15,06
=
fy
2.m.Rn 1
1 m
1
commit to user
T ugas A khir
Perencanaan Struktur dan Rencana Anggaran Biay a Rumah Tinggal 2 Lantai
BA B 6 Balok A nak 144
=
320
89 ,
1 .
06 ,
15 .
2 1
1 .
06 ,
15 1
= 0,0062
min
max
dipakai
Digunakan
perlu
= 0,0062 As perlu
=
perlu
. b . d = 0,0062. 200 . 294
= 364,56 mm
2
n =
2
16 .
. 14
perlu As
=
96 ,
200 364,56
= 1,81
~
2 tulangan As ada
= 2 . ¼ . . 16
2
= 401,92 mm
2
As perlu Aman
a =
b c
f fy
Asada
. ,
85 ,
. 200
. 25
. 85
, 320
. 401,92
= 30,26 Mn ada
= As ada . fy d – a2 = 401,92. 320 294 – 30,262
= 3,59. 10
7
Nmm Mn ada Mn
Aman.. Kontrol Spasi :
S = 1
- n
sengkang 2
- tulangan
n -
2p -
b
= 1
2 8
. 2
16 .
2 40
. 2
200
= 72 mm 25 mm…..ok
Jadi dipakai tulangan 2 D 16 mm
commit to user
T ugas A khir
Perencanaan Struktur dan Rencana Anggaran Biay a Rumah Tinggal 2 Lantai
BA B 6 Balok A nak 145
2. Daerah Lapangan
b =
fy fy
fc
600 600
. .
. 85
,
=
320
600 600
. 320
85 ,
. 25
. 85
, = 0,036
max
= 0,75 . b
= 0,75 . 0,036 = 0,027
min
= 320
4 ,
1 = 0,0043
Dari Perhitungan SAP 2000 diperoleh :
Mu = 1341,16 kgm = 1,34.10
7
Nmm Mn =
Mu =
8 ,
1,34.10
7
= 1,68.10
7
Nmm Rn =
2 7
2
294 .
00 2
1,68.10 d
. b
Mn =
0.97 m
=
c f
fy
,
. 85
, =
25 .
85 ,
320 = 15,06
ada
=
fy
2.m.Rn 1
1 m
1
=
320
97 ,
. 06
, 15
. 2
1 1
06 ,
15 1
= 0,0031
min
max
dipakai
min
Digunakan
min
= 0,0043 As
perlu
=
min
. b . d = 0,0043. 200 . 294
= 252,84 mm
2
commit to user
T ugas A khir
Perencanaan Struktur dan Rencana Anggaran Biay a Rumah Tinggal 2 Lantai
BA B 6 Balok A nak 146
n =
2
.16 π
. 4
1 perlu
As
= 96
, 200
252,84 = 1,26
~
2 tulangan As ada = 2 . ¼ .
. 16
2
= 2. ¼ . 3,14 . 16
2
= 401,92 mm
2
As perlu Aman
a =
b c
f fy
Asada
. ,
85 ,
. 200
25 85
, 320
401,92
x x
x
= 30,26 Mn ada = As ada . fy d – a2
= 401,92 . 320 294 – 30,262 = 3,59.10
7
Nmm Mn ada Mn
Aman.. Kontrol Spasi :
S = 1
- n
sengkang 2
- tulangan
n -
2p -
b
= 1
2 8
. 2
16 .
2 40
. 2
200
= 72 25 mm…..ok
Jadi dipakai tulangan 2 D 16 mm
3. Tulangan Geser Balok anak