Table 4.2 The Scores of Pre-Test and Post-Test of Control Class
No Pre-test
1 Post-test
2 Gained score
Y3
1. 55
65 10
2. 40
60 20
3. 45
65 20
4. 50
70 20
5. 55
85 30
6. 65
80 15
7. 60
85 25
8. 50
80 30
9. 55
75 20
10. 60
85 25
11. 55
65 10
12. 65
75 10
13. 45
60 15
14. 55
75 20
15. 50
75 25
23. 55
55 24.
55 70
15 25.
60 75
15 26.
45 65
20
Based on the table 4.2 above, it can be illustrated that the controlled class in which the class that used the explanatory method in teaching descriptive texts
showed that in the pre-test, the highest score was 65 sixty five and the lowest score was 35 thirty five. The overall students‟ mean score of the pre-test was
50. 71. Afterwards, the post test showed that the students‟ highest score was 85
eighty five and the lowest score was 50 fifty. The overall students‟ mean score
of the post-test was 67.86.
27. 45
70 25
28. 50
60 10
29. 45
75 30
30. 40
50 10
31. 50
65 15
31. 50
65 15
32. 35
50 15
33. 45
55 10
34. 55
60 5
35. 35
50 15
∑1 = 1775 M
1 = 50.71 ∑2 = 2370
M 2 = 67.86
∑Y = 595 MY= 17.15
No Pre-test
1 Post-test
2 Gained score
Y3
B. The Data Analysis
Table 4.3 The Analysis of Students’ Score of Experimental Class
No X
f fX
X-MX X-MX ²
fX-MX ²
1. 35
3 105
14.43 208.22
624.66 2.
30 4
120 9.43
88.92 355.68
3. 25
7 175
4.43 19.62
31.01 4.
20 9
180 -0.57
0.32 2.88
5. 15
6 90
-5.43 31.02
186.12 6.
10 4
40 -10.43
111.72 446.88
7. 5
2 10
-15.57 242.42
484.84 8.
-20.57 423.12
0.0
N=35 ∑fX=720
∑fX-MX² = 2238.4
MX = ∑fX = 720 = 20.57
N 35
SDx =
√
∑f X-MX ² =
√
2238.4= 8 N 35
SEMx = SD = 8 = 1.37
√
n-1
√
34
After collecting the students‟ test scores then finding the mean score both the experiment and the controlled class, the writer calculated the deviation
standard of each data; these functions were to test and hypothesis later, so that we need to find out the deviation standard from the two classes either the
experimental or the controlled class. First, the writer would like to analyze the students‟ scores of the
experiment class to obtain the deviation standard and error standard of students‟ test scores.
Based on the table 4.3, firstly the writer made interval from students‟ gained score as at table 4.1. In this case, 35 thirty five as the highest students‟
gained score was become the highest interval. The writer made the range score for interval was 5 five. Then, the writer inserted the number of students 35 thirty
five into each level of interval. It could be seen that there were 9 students who included into the interval of gained score 15-19. After completed, the writer
multiplied the interval of gained score with the number of students in a row f to get fX. The total fX in that table was 720. Furthermore, it was also calculated with
the mean score MX; 720 was divided by 35 equal with 20.57 for MX of the experiment class. Next, to complete the need of hypothesis counting, the writer
calculated the deviation standard and error standard of students‟ test score. The deviation standard was 8 eight meanwhile the error standard of students‟ test
score in the experiment class was 1.37. Both of them were needed as requirements
to compute in the hypothesis testing later to get the t
o
. Second, the writer would like to analyze the students‟ score of the
controlled class to obtain the deviation standard and error standard of students‟ test score to compute the hypothesis testing result as below:
