The Data Analysis FINDING AND INTERPRATATION
SEDx-y = 1.85
t
o
= MX-MY SEDx-y
t
o
= 20.57 – 17
1.85
t
o
= 1.93 timed the interval of gained score with the number of students in a row f to get
fY. The total fY in that table was 595. Furthermore, it was also calculated with the mean score MY; 595 was divided by 35 equal with 17 for MY mean score of
the controlled class. Next, to complete the need of hypothesis counting, the writer calculated the deviation standard and error standard of students‟ test score. The
deviation standard was 7.29. Meanwhile, the erro r standard of students‟ test score
in the experiment class was 1.25. Both of them were needed as requirements to
compute in the hypothesis testing later to get thet
o
. Third, the writer would like to compute the students‟ mean score,
deviation standard and error standard from both the experiment class and the
controlled class to gain the error standard deviation and t
o
as a whole. Furthermore, the writer counted as following:
SEDx-y =
√
SEMx² + SEMy²
SEDx-y =
√
1.37 ² + 1.25 ²
Based on that computation above, the standard error of the two classes were joined, so the result was 1.85 and the
t
o was 1.93. It was derived from the
overall students‟ mean score of the pre-test and post-test of the experiment class was reduced by the overall students‟ mean score of the pre-test and post-test of the
controlled class 20.57 – 17. Then, its total was divided by the accumulative error
standard both two classes 1.85. Forth, the writer would like to find out the degree of freedom df to
complete the result of the research. It used the formula as following:
Based on that computation, the degree of freedom df was 68. So that, the writer used the closer of df, that was 70. From the t table
T
t, df=70 then the writer took degree of significance 5 since it was a social research to interpret
t
o that had already been gained, that was in degree of significance 5
T
t = 2.00.
Besides, as the writer calculated before, the
t
o
=1.93, so the result of
T
t
:
t
o
in degree of significance 5 was
T
t :
t
o =2.00 1.93 =
t
o
T
t . It meant that
t
o
lower than
T
t in degree of significance 5.
Fifth or the last was to obtain the test of hypothesis. The purpose of the test of hypothesis was used to find out the answer of the question in this research;
whether there was any significant difference in result between the students who had been taught of descriptive texts using one technique of mind mapping and the
explanatory method as the teacher usually adapted. df = N1 + N2
– 2
df = 35 + 35 – 2
df = 68
For that purpose there was alternative Hypothesis Ha and null Hypothesis Ho as below:
Ha = “There was an effect of using mind mapping technique toward comprehension of descriptive text of seventh grade student
of SMP Pelita YNH” Ho =
“There was not an effect of using mind mapping technique toward comprehension of descriptive text of seventh grade student
of SMP Pelita YNH” With note that: If
t
o
T
t, it meant Ha was accepted; if
t
o
T
t, it meant Ha was rejected and Ho was accepted.
Since it was calculated and known before that
t
o is lower than
T
t in
degree of significance 5 it meant that Ho was accepted in degree of significance 5. In another words, Ha was rejected. It could be concluded that there was not
an effect of using mind mapping technique toward comprehension of descriptive text of seventh grade student of SMP Pelita YNH Sukabumi.