Penulangan plat atap Penulangan tumpuan arah x Penulangan tumpuan arah y

commit to user Tugas Akhir Perencanaan Struktur Gedung Sekolah 2 Lantai 103 BAB 5 Plat Lantai

5.13. Penulangan plat atap

Data – data plat : Tebal plat h = 10 cm = 100 mm Diameter tulangan Æ = 8 mm fy = 240 MPa f’c = 25 MPa p = 20 mm Tebal penutup d’ = p + ½Æ tul = 20 + 4 = 24 mm Tinggi Efektif d = h - d’ = 120 – 24 = 96 mm Tingi efektif Gambar 5.5 Perencanaan Tinggi Efektif dx = h – p - ½Ø = 100 – 20 – 4 = 76 mm dy = h – d’ – Ø - ½ Ø = 100 – 20 - 8 - ½ . 8 = 68 mm h d y d x d commit to user Tugas Akhir Perencanaan Struktur Gedung Sekolah 2 Lantai 103 BAB 5 Plat Lantai rb = ÷÷ ø ö çç è æ + fy fy fc 600 600 . . . 85 , b = ÷ ø ö ç è æ + 240 600 600 . 85 , . 240 25 . 85 , = 0,05376 r max = 0,75 . rb = 0,75 . 0,05376 = 0,04032 r min = 0,0025

5.14. Penulangan tumpuan arah x

Mu = 225,616 kgm = 2,528.10 6 Nmm Mn = f Mu = = 8 , 10 . 2,528 6 3,16.10 6 Nmm Rn = = 2 .dx b Mn = 2 6 76 . 1000 10 . 16 , 3 0,547 Nmm 2 m = 2942 , 11 25 . 85 , 240 . 85 , = = c f fy r perlu = ÷ ÷ ø ö ç ç è æ - - fy Rn . m 2 1 1 . m 1 = . 2942 , 11 1 ÷ ÷ ø ö ç ç è æ - - 240 547 , . 2942 , 11 . 2 1 1 = 0,002 r r max r r min , di pakai r min As perlu = r min . b . dx = 0,0025 . 1000 . 76 = 190 mm 2 Digunakan tulangan Æ 8 As = ¼ . p . 8 2 commit to user Tugas Akhir Perencanaan Struktur Gedung Sekolah 2 Lantai 103 BAB 5 Plat Lantai = 50,24 mm 2 S = perlu As b As . = 190 1000 . 24 , 50 = 264,42 ~ 200 mm Smax = 2h n = s b = 200 1000 = 5 As ada = 5. ¼ . p . 8 2 = 251,2 mm 2 As perlu …..… OK J Dipakai tulangan Æ8 – 200 mm

5.15. Penulangan tumpuan arah y

Mu = 151,048 kgm =1,6925.10 6 Nmm Mn = f Mu = = 8 , 10 . 6925 , 1 6 2,036.10 6 Nmm Rn = = 2 .dx b Mn = 2 6 76 . 1000 10 . 036 , 2 0,3525 Nmm 2 m = 2942 , 11 25 . 85 , 240 . 85 , = = c f fy r perlu = ÷ ÷ ø ö ç ç è æ - - fy Rn . m 2 1 1 . m 1 = . 2942 , 11 1 ÷ ÷ ø ö ç ç è æ - - 240 3525 , . 2942 , 11 . 2 1 1 = 0,00148 r r max r r min , di pakai r min As perlu = r min . b . dx = 0,0025 . 1000 . 76 commit to user Tugas Akhir Perencanaan Struktur Gedung Sekolah 2 Lantai 103 BAB 5 Plat Lantai = 190 mm 2 Digunakan tulangan Æ 8 As = ¼ . p . 8 2 = 50,24 mm 2 S = perlu As b As . = 190 1000 . 24 , 50 = 264,42 ~ 200 mm Smax = 2h n = s b = 200 1000 = 5 As ada = 5. ¼ . p . 8 2 = 251,2 mm 2 As perlu …..… OK J Dipakai tulangan Æ8 – 200 mm

5.16. Penulangan lapangan arah x