Participants Reading Comprehension
Scores Y
Student 5 57
Student 6 50
Student 7 93
Student 8 60
Student 9 83
Student 10 80
Student 11 73
Student 12 70
Student 13 93
Student 14 90
Student 15 67
Student 16 70
Student 17 57
Student 18 63
Student 19 60
Student 20 60
Student 21 40
Student 22 53
Student 23 67
Student 24 50
Student 25 70
Student 26 57
Student 27 75
Student 28 73
Student 29 63
Participants Reading Comprehension
Scores Y
Student 30 53
Student 31 75
To  find  out  the  statistical  scores  of  the  data  above,  the  researcher  used  SPSS. The descriptions of the finding were described below:
Table 4.4 Reading Comprehension
Statistics
Reading N
Valid 31
Missing Mean
64.68 Median
63.00 Mode
53
a
Std. Deviation 13.862
Variance 192.159
Minimum 40
Maximum 93
a. Multiple modes exist. The smallest value is shown
From  the  calculation  of  SPSS  above,  the  average  score  of  reading comprehension  is  64.68.  The  median  score  of  reading  comprehension  is  63.  The
mode  or  the  score  that  show  the  most  is  53,  and  57.  The  highest  score  of  reading comprehension is 93 and the lowest score is 40. The standard deviation is 13.862 with
variance 192.159
B.   Data Analysis
Table 4.5 Data Analysis Table
Participants X
Y XY
X
2
Y
2
Student 1 66
40 2640
4356 1600
Student 2 77
57 4389
5929 3249
Student 3 69
53 3657
4761 2809
Student 4 88
53 4664
7744 2809
Student 5 88
57 5016
7744 3249
Student 6 71
50 3550
5041 2500
Student 7 76
93 7068
5776 8649
Student 8 80
60 4800
6400 3600
Student 9 80
83 6640
6400 6889
Student 10 83
80 6640
6889 6400
Student 11 76
73 5548
5776 5329
Student 12 80
70 5600
6400 4900
Student 13 97
93 9021
9409 8649
Student 14 71
90 6390
5041 8100
Student 15 76
67 5092
5776 4489
Student 16 85
70 5950
7225 4900
Student 17 71
57 4047
5041 3249
Student 18 76
63 4788
5776 3969
Student 19 60
60 3600
3600 3600
Student 20 71
60 4260
5041 3600
Student 21 77
40 3080
5929 1600
Student 22 57
53 3021
3249 2809
Student 23 76
67 5092
5776 4489
Participants X
Y XY
X
2
Y
2
Student 24 76
50 3800
5776 2500
Student 25 71
70 4970
5041 4900
Student 26 57
57 3249
3249 3249
Student 27 63
75 4725
3969 5625
Student 28 80
73 5840
6400 5329
Student 29 77
63 4851
5929 3969
Student 30 60
53 3180
3600 2809
Student 31 90
75 6750
8100 5625
N = 31 ∑X= 2325  ∑Y= 2005  ∑XY = 151918  ∑X
2
= 177143 ∑Y
2
= 135443
N = 31 ∑X=2325
∑Y=2005 ∑XY = 151918
∑X
2
=177143 ∑Y
2
=135443 �
= �
− �
2
– 2    �
2
– 2
= 31 .  151918
−  2325  2005 31 . 177143 −  2325
2    31 . 135443 −  2005 2
= 4709458
−  4661625 5491433 − 5405625  4198733 −  4020025
= 47833
85808  178708 =
47833 15334576064
= 47833
123832.86 = 0.386
To ensure the result of the calculation above, the researcher used SPSS program in  order  to  know  whether  the  result  of  calculation  that  the  researcher  did  manually
was accurate. The description of the calculation of SPSS was described below:
Table 4.6 SPSS Correlation Table
Correlations
Grammar Reading
Grammar Pearson
Correlation 1
.386 Sig. 2-tailed
.032 N
31 31
Reading Pearson
Correlation .386
1 Sig. 2-tailed
.032 N
31 31
. Correlation is significant at the 0.05 level 2-tailed.
The  results  of  both  calculations  manual  and  SPSS  calculation  are  similar. The results showed that the value of r
xy
is 0.386. It means that there is no mistake in manual calculation process. In addition, the degree of freedom Df is 31-2=29. Then,
in table significant of 0.05 it is obtained 0.367. The  next  step  is  to  find  out  the  significant  of  the  variables  by  using  the
significant test formula:
� = �
�−2
1 − �
2
� = 0.386
31 − 2 1 − 0.149
� = 0.386   5.385
0.851 � =
2.079 0.923
� =  2.253
Based on the calculation above, the result is compared by t
table
in the significant of  5  and  the  degree  of  freedom  Df  =  31-2=29.  From  df,  it  is  obtained  t
table
of 5=2.045.
C.   Data Interpretation
After the writer calculated using the formula of Product Moment, it shows that the correlation value is r
xy
= 0.386 and the degree of freedom Df = 29. In the table of significant shows if Df value is 29, the table of significant of 5 is 0.367.
The statistical hypotheses state: 1.
If  r
o
the  same  as  or  higher  than  r
t
,  the  H
a
is  accepted.  It  means  there  is  a significant correlation between
the students’ grammar mastery and their reading comprehension at the 6
th
semester of Department of English Education of State Islamic University Jakarta on academic year 2015-2016.
2. If  r
o
is  lower  than  r
t
,  the  H
a
is  rejected.  It  means  there  is  no  significant correlation  between
the  students’  grammar  mastery  and  their  reading comprehension at the 6
th
semester of Department of English Education of State Islamic University Jakarta on academic year 2015-2016.
Based on the score of r
xy
= 0.386, it indicates that r
xy
is higher than r
t
, in which 0.386 ˃ 0.367 and the score of t
observed
= 2.253 is compared by t
table
of 5=2.045, that