4) Mengolah Data Kelompok a) Ukuran Pemusatan 1) Mean (Nilai Rata-rata)

  

Statistika

A. Pengertian Statistika

  Definisi

  Data adalah seluruh keterangan, informasi, atau fakta tentang sesuatu atau permasalahan. Statistika adalah ilmu yang berhubungan dengan cara-cara mengumpulkan, mengurutkan, menyajikan, dan mengolah data.

  1) Mengumpulkan Data

  79, 80, 70, 68, 92, 48, 90, 92, 85, 76, 48, 90, 92, 85, 76, 88, 78, 74, 70, 38, 80, 63, 76, 49, 84, 61, 83, 88, 81, 82, 61, 83, 88, 81, 82, 51, 71, 72, 82, 70, 81, 91, 56, 65, 63, 74, 89, 73, 90, 97, 60, 66, 98, 93, 81, 93 72, 91, 67, 88, 75, 83, 79, 86

  2) Mengurutkan Data

  38, 48, 49, 51, 56, 60, 60, 61, 63, 63, 63, 65, 66, 67, 67, 68, 70, 70, 70, 71, 71, 72, 72, 72, 73, 74,74, 75, 75, 76, 76, 78, 79, 79, 80, 80, 80, 81, 81, 81, 82, 82, 83, 83, 84, 85, 86, 87, 88, 88, 88, 89, 90, 90, 90, 91, 91, 91, 92, 93, 93, 93, 97, 98

  3) Menyajikan Data

  a) Tabel

  Banyak data: = 64

  (1) Nilai Terendah

  Nilai Terendah =

  terkecil

  Contoh diatas: Nilai Terendah = 98

  (2) Nilai Tertinggi

  Nilai Tertinggi =

  terbesar

  Contoh diatas: Nilai Tertinggi = 38

  (3) Jangkauan

  Jangkauan = −

  terbesar terkecil

  Contoh diatas: Jangkauan = 98 − 38 = 60

  (4) Banyak Kelas

  Banyak Kelas = 1 + 3,3 ⋅ log Contoh diatas: Banyak Kelas = 1 + 3,3 ⋅ log

  = 1 + 3,3 ⋅ log 64 = 1 + 3,3 ⋅ 1,81 = 1 + 5,97 = 6,97

  ≈ 7

  1

  96 6 576 Jumlah 64 4875

  87 16 1392 7. 92-100

  78 17 1326 6. 83-91

  69 14 966 5. 74-82

  60 7 420 4. 65-73

  51 3 153 3. 56-64

  42 2. 47-55

  42

  (5) Panjang Kelas

  ) Nilai Tengah ( ) Frekuensi ( ) 1. 38-46

  No ( ) Panjang Kelas (

  = 8,57 ≈ 9

  7

  60

  =

  Banyak Kelas Contoh diatas:

  = Jangkauan

b) Diagram (1) Diagram Garis (2) Diagram Batang

   (3) Diagram Lingkaran

  1 Nilai 42 = = 5,625 64 × 360

  3 Nilai 51 = = 16,875 64 × 360

  7 Nilai 60 = = 39,375 64 × 360

  14 Nilai 69 = = 78,75 64 × 360

  17 Nilai 78 = = 95,625 64 × 360

  16 Nilai 87 = = 90 64 × 360

  6 Nilai 96 = = 33,75 64 × 360

4) Mengolah Data Kelompok

a) Ukuran Pemusatan 1) Mean (Nilai Rata-rata)

  ( )+( )+( )+⋯+( ) 1 ⋅

  1 2 ⋅

  2 3 ⋅ 3 ⋅

  ̅ =

  1

  2 + + 3 +⋯+

  Contoh: Diketahui: = 64

  No ( ) Nilai Tengah ( ) Frekuensi ( ) ) Panjang Kelas (

  1. 38-46

  42

  1

  42 2. 47-55

  51 3 153 3. 56-64

  60 7 420 4. 65-73

  69 14 966 5. 74-82

  78 17 1326 6. 83-91

  87 16 1392 7. 92-100

  96 6 576 Jumlah 64 4875

  • 2
  • 3
  • 4
  • 5
  • 6
  • 7

  14

  = 74 − 0,5 = 73,5 = 9

  = + (

  1

  2 −

  ) = 73,5 + (

  1

  2 (64)−25

  14

  ) (9) = 73,5 + (

  32−25

  ) (9) = 73,5 + (

  96 6 576 Jumlah 64 4875

  7

  14

  ) (9) = 73,5 + (

  1

  2

  ) (9) = 73,5 + 4,5 = 78

  3) Modus (Nilai Sering Muncul atau Frekuensi Terbesar)

  = + (

  1

  1

  = 1 + 3 + 7 + 14 = 25 = 17

  87 16 1392 7. 92-100

  )

  Keterangan: = Median = Frekuensi kumulatif sebelum kelas median

  ̅ =

  ( 1 ⋅ 1 )+( 2 ⋅ 2 )+( 3 ⋅ 3 )+( 4 ⋅ 4 )+( 5 ⋅ 5 )+( 6 ⋅ 6 )+( 7 ⋅ 7 )

  1

  ̅ =

  4875

  64

  = 76,17

  2) Median (Nilai Tengah)

  = + (

  1 2 − )

  = Frekuensi kelas median = Tepi bawah

  6. 83-91

  = Panjang kelas Contoh: Jika

  = 32, maka Letak data median = 32 No (

  ) Panjang Kelas ( ) Nilai Tengah ( ) Frekuensi ( )

  1. 38-46

  42

  1

  42 2. 47-55

  51 3 153 3. 56-64

  60 7 420 4. 65-73

  69 14 966 5. 74-82

  78 17 1326

  • 2
  • 2

  3

  1

  96 6 576 Jumlah 64 4875

  1

  = 17 − 14 = 3

  2

  = 17 − 16 = 1 = 74 − 0,5 = 73,5

  = 9 = + (

  1

  6. 83-91

  ) = 73,5 + (

  3 3+1

  ) (9) = 73,5 + (

  = 73,5 + 6,75 = 80,25

  4

  ) (9) = 73,5 +

  87 16 1392 7. 92-100

  78 17 1326

  4

  17, maka No (

  Keterangan: = Modus

  1

  = Selisih frekuensi kelas modus dengan frekuensi kelas sebelumnya

  2

  = Selisih frekuensi kelas modus dengan frekuensi kelas sesudahnya = Tepi bawah

  = Panjang kelas Contoh: Jika frekuensi terbesar adalah

  ) Panjang Kelas ( ) Nilai Tengah ( ) Frekuensi ( )

  69 14 966 5. 74-82

  1. 38-46

  42

  1

  42 2. 47-55

  51 3 153 3. 56-64

  60 7 420 4. 65-73

  27

b) Ukuran Letak (1) Kuartil

  1

  1

  4

  ( + 1) = + (

  4 −

  ) , dimana

  = 1,2,3; dan = banyak data

  (a) Kuartil Bawah ( )

  Letak data =

  =

  4 −

  • (

  1

  1

  1

  )

  (b) Kuartil Tengah ( ) atau Median

  2

  =

  2

  1

  2 −

  2

  • (
  • (

  2

  )

  = 64,5 + 3,86 = 68,36

  51 3 153 3. 56-64

  96 6 576 Jumlah 64 4875

  7. 92-100

  

87

16 1392

  6. 83-91

  

78

17 1326

  5. 74-82

  

69

14 966

  60 7 420 4. 65-73

  42 2. 47-55

  =

  1

  42

  ) Nilai Tengah ( ) Frekuensi ( ) 1. 38-46

  No ( ) Panjang Kelas (

  4 = 48,75

  195

  4 (64 + 1) =

  3

  4

( + 1) =

  1

  1

  3 =

  ) (9) = 64,5 + (

  7

  27

  ) (9) = 64,5 +

  7

  3

  ) (9) = 64,5 + (

  14

  6

  14

  1

  16−10

  ) (9) = 64,5 + (

  14

  4 (64)−10

  1

  ) = 64,5 + (

  1

  1

  4 −

  3

  Letak data

  (c) Kuartil Atas ( )

  2

  42 2. 47-55

  1

  42

  1. 38-46

  ) Panjang Kelas ( ) Nilai Tengah ( ) Frekuensi ( )

  dari data: No (

  

3

  , dan

  ,

  60 7 420 4. 65-73

  1

  ) Contoh: Tentukan

  3

  3

  4 −

  3

  3

  =

  3

  51 3 153 3. 56-64

  69 14 966 5. 74-82

  2 = 32,5

  65

  65

  2 (64 + 1) =

  1

  2

( + 1) =

  1

  2 =

  Letak data

  4 = 16,25

  4 (64 + 1) =

  78 17 1326 6. 83-91

  1

  4

( + 1) =

  1

  1 =

  ( + 1) Letak data

  4

  Jawab: Letak data =

  96 6 576 Jumlah 64 4875

  87 16 1392 7. 92-100

  • (

  1 −

  2

  2

  = + ( )

  2

  2

  1

  1 (64)−25

  2

  = 73,5 + ( ) (9)

  17 32−25

  = 73,5 + ( ) (9)

  17

  7

  = 73,5 + ( ) (9)

  17

  63

  = 73,5 +

  17

  = 73,5 + 3,71 = 77,21

  3 −

  3

  4

  = + ( )

  3

  3

  1

  3 (64)−42

  4

  = 82,5 + ( ) (9)

  16 48−42

  = 82,5 + ( ) (9)

  16

  6

  = 82,5 + ( ) (9)

  16

  54

  = 82,5 +

  16

  = 82,5 + 3,38 = 85,88

   (2) Desil

  Letak data = ( + 1)

  10 −

  10

  , dimana = + ( ) = 1,2,3, ⋯ ,9; dan = banyak data

  Contoh: Tentukan , , dan dari data:

  4

  7

  

9

No ( ) Nilai Tengah ( ) Frekuensi ( )

  ) Panjang Kelas ( 1. 38-46

  42

  1

  42 2. 47-55

  51 3 153 3. 56-64

  60 7 420 4. 65-73

  69 14 966 5. 74-82

  78 17 1326 6. 83-91

  87 16 1392 7. 92-100

  96 6 576 Jumlah 64 4875

  Jawab: Letak data =

  ( + 1)

  10

  4 2 130

  Letak data

  = = 26 ( + 1) = (64 + 1) =

  4

  10

  5

  5

  7 7 455

  Letak data

  = ( + 1) = (64 + 1) = = 45,5

  7

  10

  10

  10

  9 9 585

  Letak data

  = = 58,5 ( + 1) = (64 + 1) =

  9

  10

  10

  10 No ( ) Nilai Tengah ( ) Frekuensi ( ) ) Panjang Kelas (

  1. 38-46

  42

  1

  42 2. 47-55

  51 3 153 3. 56-64

  60 7 420 4. 65-73

  69 14 966 5. 74-82

  

78

17 1326

  6. 83-91

  

87

16 1392

  7. 92-100

  

96

6 576

  Jumlah 64 4875

  4 −

  4

  10

  = + ( )

  4

  4

  4

  4 (64)−25

  10

  = 73,5 + ( ) (9)

  17 25,6−25

  = 73,5 + ( ) (9)

  17 0,6

  = 73,5 + ( ) (9)

  17 0,54

  = 73,5 +

  17

  = 73,5 + 0,03 = 73,53

  7 −

  7

  10

  = + ( )

  7

  7

  7

  7 (64)−42

  10

  = 82,5 + ( ) (9)

  16 44,8−42

  = 82,5 + ( ) (9)

  16 2,8

  = 82,5 + ( ) (9)

  16 25,2

  = 82,5 +

  16

  = 82,5 + 1,58 = 84,08

  9 −

  9

  10

  = + ( )

  9

  9

  9

  9 (64)−58

  10

  = 91,5 + ( ) (9)

  16 57,6−58

  = 91,5 + ( ) (9)

  16 −0,4

  = 91,5 + ( ) (9)

  16 3,6

  = 82,5 −

  16

  = 82,5 − 0,23 = 82,27

c) Ukuran Penyebaran (1) Jangkauan

  4 = 48,75

  51 3 153 3. 56-64

  42 2. 47-55

  1

  42

  ) Nilai Tengah ( ) Frekuensi ( ) 1. 38-46

  No ( ) Panjang Kelas (

  195

  69 14 966

  4 (64 + 1) =

  3

  4 ( + 1) =

  3

  3 =

  Letak data

  2 = 32,5

  60 7 420 4. 65-73

  5. 74-82

  2 (64 + 1) =

  4 −

  ) (9)

  14

  4 (64)−10

  1

  ) = 64,5 + (

  1

  1

  1

  78 17 1326

  1

  =

  1

  96 6 576 Jumlah 64 4875

  7. 92-100

  87 16 1392

  6. 83-91

  65

  1

  38, 48, 49, 51, 56, 60, 60, 61, 63, 63, 63, 65, 66, 67, 67, 68, 70, 70, 70, 71, 71, 72, 72, 72, 73, 74,74, 75, 75, 76, 76, 78, 79, 79, 80, 80, 80, 81, 81, 81, 82, 82, 83, 83, 84, 85, 86, 87, 88, 88, 88, 89, 90, 90, 90, 91, 91, 91, 92, 93, 93, 93, 97, 98 Contoh diatas: Jangkauan = 98 − 38 = 60

  ,

  1

  42

  1. 38-46

  ) Panjang Kelas ( ) Nilai Tengah ( ) Frekuensi ( )

  , dan Simpangan Kuartil dari data: No (

  3

  2

  51 3 153 3. 56-64

  ,

  1

  1 Contoh: Tentukan

  −

  3

  Simpangan Kuartil =

  (2) Simpangan Kuartil

  42 2. 47-55

  60 7 420 4. 65-73

  2 ( + 1) =

  4 ( + 1) =

  1

  2 =

  Letak data

  4 = 16,25

  65

  4 (64 + 1) =

  1

  1

  69 14 966 5. 74-82

  1 =

  ( + 1) Letak data

  4

  Jawab: Letak data =

  96 6 576 Jumlah 64 4875

  87 16 1392 7. 92-100

  78 17 1326 6. 83-91

  • (

  16−10

  = 64,5 + ( ) (9)

  14

  6

  = 64,5 + ( ) (9)

  14

  3

  = 64,5 + ( ) (9)

  7

  27

  = 64,5 +

  7

  = 64,5 + 3,86 = 68,36

  1 −

  2

  2

  = + ( )

  2

  2

  1

  1 (64)−25

  2

  = 73,5 + ( ) (9)

  17 32−25

  = 73,5 + ( ) (9)

  17

  7

  = 73,5 + ( ) (9)

  17

  63

  = 73,5 +

  17

  = 73,5 + 3,71 = 77,21

  3 −

  3

  4

  = + ( )

  3

  3

  1

  3 (64)−42

  4

  = 82,5 + ( ) (9)

  16 48−42

  = 82,5 + ( ) (9)

  16

  6

  = 82,5 + ( ) (9)

  16

  54

  = 82,5 +

  16

  = 82,5 + 3,38 = 85,88

  Simpangan Kuartil = −

  3

  1 Simpangan Kuartil = 85,88 − 68,36

  Simpangan Kuartil = 17,52

  (3) Simpangan Rata-rata

  − ̅|] + [ − ̅|] + [ − ̅|] + ⋯ + [ − ̅|] [ | | | |

  1

  1

  2

  2

  3

  3

  =

   (4) Simpangan Baku (Varian)

  2

  2

  2

  2 [ ( − ̅) ] + [ ( − ̅) ] + [ ( − ̅) ] + ⋯ + [ ( − ̅) ]

  1

  1

  2

  2

  3

  3 = √ Contoh: Diketahui: ̅ = 76,17; tentukan simpangan rata-rata dan sinpangan bakunya!

  

2

  2

  ̅ − ̅ | − ̅| ( − ̅) − ̅| − ̅) | ( 42 76,17 −34,17 34,17 11167,59

  1 34,17 11167,59 51 76,17 −25,17 25,17 633,53 3 75,51 1900,59 60 76,17 −16,17 16,17 261,47 7 113,19 1830,29 69 76,17 −7,17 7,17 51,41

  14 100,38 719,74 78 76,17 1,83 1,83 3,34 17 31,11 56,78 87 76,17 10,83 10,83 117,29 16 173,28 173,28 96 76,17 13,83 13,83 191,27

  6 82,98 1147,62 Jumlah

  = 64 610,62 16995,89 [ | − ̅|] + [ | − ̅|] + [ | − ̅|] + ⋯ + [ | − ̅|]

  1

  1

  2

  2

  3

  3

  = 610,62

  =

  64 = 9,54

  16995,89

  = √

  64 = √2665,56 = 51,63