jawapan matematik kertas 2 pahang
SULIT
1449/2(GMP)
Mathematics
Kertas 2 ( Set 2 )
Peraturan
Pemarkahan
2017
1449/2(GMP)
SKEMA PRAKTIS BESTARI
PROJEK JAWAB UNTUK JAYA (JUJ) 2017
MATHEMATICS
Kertas 2
SET 2
PERATURAN PEMARKAHAN
UNTUK KEGUNAAN GURU MATA PELAJARAN SAHAJA
Peraturan pemarkahan ini mengandungi
1449/2(GMP) ©
2017 Hak Cipta JUJ Pahang
halaman bercetak
[Lihat halaman sebelah
SULIT
SULIT
Question
1
2
1449/2(GMP)
Solution and Mark Scheme
y 3x + 6
x+y6
y0
3t² - 4t - 15 = 0
(t - 3)(3t + 5) = 0 or equivalent
OR
Sub
Mark
Mark
P1
P1
P1
3
K1
K1
(K1)
2
N1
t=3,t=The particle will stop when t is 3 seconds.
N1
Note:
1. Accept correct terms on the same side, in any order.
2. Accept correct answer from three correct terms without factorisation
Or incomplete working for Kk2.
x + y = 3 or y – 3x = 10 (from y+5=3(x+5) or equivalent
OR
x = 3 – y or y = 3 – x or y = 10 + 3x or x = y – 10
(K1)
3
4x = 28 or 4y = 124
OR
4
K1
K1
3
(K2)
or
Umur Fatimah sekarang(x) = 7 tahun
Umur ibunya sekarang = 38-7
= 31 tahun
(a) NEM or MEN
N1
N1
4
P1
(b) LN:NM = 3:2
4
NM=
X 20 = 8
tan NEM =
NEM = 26.57º
1449/2(GMP) ©
2017 Hak Cipta JUJ Pahang
K1
K1
N1
4
SULIT
SULIT
3
Question
Solution and Mark Scheme
1449/2(GMP)
Sub
Mark
Mark
K1
K1
+
K1
5
N1
467.25
Note:
1. Accept π for K mark
2. Accept correct value incomplete subtitution for K mark
3. Correct answer from incomplete working award Kk2
P1
=
6
4
4=
(12) + c
K1
y=
x–4
N1
(b) y =
K1
(0) – 4
N1
x-intercept = 4
4
7
(a) False / Palsu
P1
(b) True / Benar
P1
B
P1
(d) 10² - 2(10) + 2
82
K1
N1
(c) A
5
(a) 6p – 3q = 14
3p + 2q = -7
P1
(P1)
8
P1
(b)
1449/2(GMP) ©
2017 Hak Cipta JUJ Pahang
[ Lihat halaman sebelah
SULIT
SULIT
4
Question
1449/2(GMP)
Solution and Mark Scheme
or
p=
K1
N1
q = -4
Note:
1. Do not accept
2.
Sub
Mark
Mark
N1
or
as final answer, award N1
or
p=
q = -4
Note:
1. Do not accept
2.
or
as final answer, award N1
3. Do not accept any solutions solved not using matrix method.
5
(a) 10 + 10 +
(K1)
9
K2
+
or
(K1)
39.38
1449/2(GMP) ©
2017 Hak Cipta JUJ Pahang
N1
SULIT
SULIT
5
Question
1449/2(GMP)
Sub
Mark
Mark
K2
Solution and Mark Scheme
(b)
(K1)
(K1)
N1
66.90
Note:
1. Accept for KN mark.
2. Accept correct value from incomplete substitution for K mark.
3. Correct answer from incomplete working Kk2
(a)Sampel space,
S = {56,57,58,59,65,67,68,69,75,76,78,79,
85,86,87,89,95,96,97,98}
Note : Allow two mistake in listing the sample space for P1
(b)(i) {65,67,68,69}
10
6
P2
K1
N1
=
K1
(ii) {57,59,75,79,95,97,68,86}
=
N1
Note: Accept answer without working for K1N1
(a)
K1
=4
v = 17
N1
(b) Distance of particle Q =
+
(100-20) – 67
11
6
K2
K1
Note:
or
13 m
1449/2(GMP) ©
2017 Hak Cipta JUJ Pahang
award K1
N1
6
[ Lihat halaman sebelah
SULIT
SULIT
6
Question
Solution and Mark Scheme
1449/2(GMP)
Sub
Mark
Mark
(a)
x
y
-2
3
2.5
-2.4
(b Graph
Axes drawn in the correct directions with uniform scale for
0 t 3 and 13 h 7
All 5 points and *2 point correctly plotted or curve passes
through all the points for 0 t 34 and 13 h 7
A smooth and continuous curve without any straight line passes
through all 7 correct points using the given scale for
0 t 34 and 13 h 7
P1P1
P1
K2
N1
Note:
1. 5 or 6 points plotted correctly, award K1
2. Ignore curve out of range.
(c) (i) y = 5
12
(ii) x = 0.85
(d) Straight line y = –2x correctly drawn
Identify equation y = –2x award K1
1.65x1.85
-1.65x-1.85
P1
P1
K2
N1
N1
Note:
1. Allow N marks if values of t are shown on the graph.
2. Values of t obtained by calculation, award N0
12
1449/2(GMP) ©
2017 Hak Cipta JUJ Pahang
SULIT
SULIT
7
1449/2(GMP)
y
12
10
8
6
4
2
-4
-3
-2
-1
1
2
3
4
x
-2
-4
-6
-8
-10
-12
1449/2(GMP) ©
2017 Hak Cipta JUJ Pahang
[ Lihat halaman sebelah
SULIT
SULIT
8
Question
1449/2(GMP)
Solution and Mark Scheme
(a)(i)(a) (-2 , 1)
(b) (3 , 0)
Note:
(3,0) marked on diagram or (1,3) seen or (1,3) marked on diagram,
award P1
13
(b)(i)(a) Enlargement of scale factor 2 with centre (8,7)
Note:
1. Enlargement centre (8,7) or Enlargement scale factor 2,
award P2 .
Sub
Mark
Mark
P1
P2
P3
2. Enlargement, award P1 .
(b) Enlargement of scale factor 2 with centre (-4,3)
(ii) 25 × * 22
( 25*22 ) − 25
75
P3
K1
K1
N1
12
14
(a)(i) 40
(ii)
Time (minutes)
Masa (minit)
1-5
6-10
11-15
16-20
21-25
26-30
31-35
36-40
41-45
P1
Midpoint
Titik tengah
3
8
13
18
23
28
33
38
43
b)
= 21.63 minutes
1449/2(GMP) ©
2017 Hak Cipta JUJ Pahang
Frequency
Kekerapan
0
3
4
8
15
7
2
1
0
P1
P1
P1
K2
N1
SULIT
SULIT
9
Question
1449/2(GMP)
Sub
Mark
Mark
Solution and Mark Scheme
(c) Polygon
Axes drawn in correct directions with uniform scale for
3x43 and 0y15
P1
9 points correctly plotted or the straight line passes through all the
points for 3x43 and 0y15
K2
Note:
1. 8 or 7 points correctly plotted, award K1
2. Do not accept horizontal axis level with midpoints
Smooth and continuous line, passing through all 9 correct points
using given scales for 3x43 and 0y15
(d)
X 100%
7.5%
N1
K1
N1
12
1449/2(GMP) ©
2017 Hak Cipta JUJ Pahang
[ Lihat halaman sebelah
SULIT
SULIT
10
1449/2(GMP)
Frequency
16
14
12
10
8
6
4
2
3
8
13
18
23
28
33
38
43
Time(minutes)
1449/2(GMP) ©
2017 Hak Cipta JUJ Pahang
SULIT
SULIT
11
Question
1449/2(GMP)
Sub
Mark
Mark
Solution and Mark Scheme
(a)
H
G
K
J
E
F
K1
Correct shape with rectangles HGEF and line JK
All solid lines.
HG =JK = EF = HE = GF
Measurements correct to ± 0.2 cm (one way) and
all angles at vertices = 90o ± 1o
K1
N1
(b)(i)
15
F
S
G
K
P
A
D
Correct shape SFGPAD and point K with semicircle SF. All solid lines.
PA = AD < SP = FA = GD
FD = GD
Measurements correct to ± 0.2 cm (one way) and P,A ,D= 90o ± 1o
1449/2(GMP) ©
2017 Hak Cipta JUJ Pahang
K1
K1
N2
[ Lihat halaman sebelah
SULIT
SULIT
12
Question
Solution and Mark Scheme
1449/2(GMP)
Sub
Mark
Mark
(b)(ii)
R
S
R
U
J
K
Q
P
Correct shape with rectangles RSGP and RUJK
Note: Ignore dashed line
K1
dashed line EF and JK.
K1
JG = JP = RE = SF > EJ = FK
K1
Measurements correct to ± 0.2 cm (one way) and
All angles at vertices of rectangles = 90o ± 1o
N2
(a)( 30ºS,152ºW)
P2
180º-28º or 152º W/B or 152º
(b) 180º ÷ 5 X 3
108º - 28º
/b.n
(d) Maria = 180 X 60 X cos 30
1449/2(GMP) ©
K1
N1
(c) (180 – 30 – 30) X 60
7200
(P1)
(K1)
80W/B
16
12
2017 Hak Cipta JUJ Pahang
K1
N1
K1
SULIT
SULIT
13
Question
Solution and Mark Scheme
Sub
Mark
Mark
K1
or
K1
Shirley = (30 + 30) X 60
or
1449/2(GMP)
(7.2 hours)
Shirley will reach her destination first.
K1
N2
12
PERATURAN PEMARKAHAN TAMAT
1449/2(GMP) ©
2017 Hak Cipta JUJ Pahang
SULIT
1449/2(GMP)
Mathematics
Kertas 2 ( Set 2 )
Peraturan
Pemarkahan
2017
1449/2(GMP)
SKEMA PRAKTIS BESTARI
PROJEK JAWAB UNTUK JAYA (JUJ) 2017
MATHEMATICS
Kertas 2
SET 2
PERATURAN PEMARKAHAN
UNTUK KEGUNAAN GURU MATA PELAJARAN SAHAJA
Peraturan pemarkahan ini mengandungi
1449/2(GMP) ©
2017 Hak Cipta JUJ Pahang
halaman bercetak
[Lihat halaman sebelah
SULIT
SULIT
Question
1
2
1449/2(GMP)
Solution and Mark Scheme
y 3x + 6
x+y6
y0
3t² - 4t - 15 = 0
(t - 3)(3t + 5) = 0 or equivalent
OR
Sub
Mark
Mark
P1
P1
P1
3
K1
K1
(K1)
2
N1
t=3,t=The particle will stop when t is 3 seconds.
N1
Note:
1. Accept correct terms on the same side, in any order.
2. Accept correct answer from three correct terms without factorisation
Or incomplete working for Kk2.
x + y = 3 or y – 3x = 10 (from y+5=3(x+5) or equivalent
OR
x = 3 – y or y = 3 – x or y = 10 + 3x or x = y – 10
(K1)
3
4x = 28 or 4y = 124
OR
4
K1
K1
3
(K2)
or
Umur Fatimah sekarang(x) = 7 tahun
Umur ibunya sekarang = 38-7
= 31 tahun
(a) NEM or MEN
N1
N1
4
P1
(b) LN:NM = 3:2
4
NM=
X 20 = 8
tan NEM =
NEM = 26.57º
1449/2(GMP) ©
2017 Hak Cipta JUJ Pahang
K1
K1
N1
4
SULIT
SULIT
3
Question
Solution and Mark Scheme
1449/2(GMP)
Sub
Mark
Mark
K1
K1
+
K1
5
N1
467.25
Note:
1. Accept π for K mark
2. Accept correct value incomplete subtitution for K mark
3. Correct answer from incomplete working award Kk2
P1
=
6
4
4=
(12) + c
K1
y=
x–4
N1
(b) y =
K1
(0) – 4
N1
x-intercept = 4
4
7
(a) False / Palsu
P1
(b) True / Benar
P1
B
P1
(d) 10² - 2(10) + 2
82
K1
N1
(c) A
5
(a) 6p – 3q = 14
3p + 2q = -7
P1
(P1)
8
P1
(b)
1449/2(GMP) ©
2017 Hak Cipta JUJ Pahang
[ Lihat halaman sebelah
SULIT
SULIT
4
Question
1449/2(GMP)
Solution and Mark Scheme
or
p=
K1
N1
q = -4
Note:
1. Do not accept
2.
Sub
Mark
Mark
N1
or
as final answer, award N1
or
p=
q = -4
Note:
1. Do not accept
2.
or
as final answer, award N1
3. Do not accept any solutions solved not using matrix method.
5
(a) 10 + 10 +
(K1)
9
K2
+
or
(K1)
39.38
1449/2(GMP) ©
2017 Hak Cipta JUJ Pahang
N1
SULIT
SULIT
5
Question
1449/2(GMP)
Sub
Mark
Mark
K2
Solution and Mark Scheme
(b)
(K1)
(K1)
N1
66.90
Note:
1. Accept for KN mark.
2. Accept correct value from incomplete substitution for K mark.
3. Correct answer from incomplete working Kk2
(a)Sampel space,
S = {56,57,58,59,65,67,68,69,75,76,78,79,
85,86,87,89,95,96,97,98}
Note : Allow two mistake in listing the sample space for P1
(b)(i) {65,67,68,69}
10
6
P2
K1
N1
=
K1
(ii) {57,59,75,79,95,97,68,86}
=
N1
Note: Accept answer without working for K1N1
(a)
K1
=4
v = 17
N1
(b) Distance of particle Q =
+
(100-20) – 67
11
6
K2
K1
Note:
or
13 m
1449/2(GMP) ©
2017 Hak Cipta JUJ Pahang
award K1
N1
6
[ Lihat halaman sebelah
SULIT
SULIT
6
Question
Solution and Mark Scheme
1449/2(GMP)
Sub
Mark
Mark
(a)
x
y
-2
3
2.5
-2.4
(b Graph
Axes drawn in the correct directions with uniform scale for
0 t 3 and 13 h 7
All 5 points and *2 point correctly plotted or curve passes
through all the points for 0 t 34 and 13 h 7
A smooth and continuous curve without any straight line passes
through all 7 correct points using the given scale for
0 t 34 and 13 h 7
P1P1
P1
K2
N1
Note:
1. 5 or 6 points plotted correctly, award K1
2. Ignore curve out of range.
(c) (i) y = 5
12
(ii) x = 0.85
(d) Straight line y = –2x correctly drawn
Identify equation y = –2x award K1
1.65x1.85
-1.65x-1.85
P1
P1
K2
N1
N1
Note:
1. Allow N marks if values of t are shown on the graph.
2. Values of t obtained by calculation, award N0
12
1449/2(GMP) ©
2017 Hak Cipta JUJ Pahang
SULIT
SULIT
7
1449/2(GMP)
y
12
10
8
6
4
2
-4
-3
-2
-1
1
2
3
4
x
-2
-4
-6
-8
-10
-12
1449/2(GMP) ©
2017 Hak Cipta JUJ Pahang
[ Lihat halaman sebelah
SULIT
SULIT
8
Question
1449/2(GMP)
Solution and Mark Scheme
(a)(i)(a) (-2 , 1)
(b) (3 , 0)
Note:
(3,0) marked on diagram or (1,3) seen or (1,3) marked on diagram,
award P1
13
(b)(i)(a) Enlargement of scale factor 2 with centre (8,7)
Note:
1. Enlargement centre (8,7) or Enlargement scale factor 2,
award P2 .
Sub
Mark
Mark
P1
P2
P3
2. Enlargement, award P1 .
(b) Enlargement of scale factor 2 with centre (-4,3)
(ii) 25 × * 22
( 25*22 ) − 25
75
P3
K1
K1
N1
12
14
(a)(i) 40
(ii)
Time (minutes)
Masa (minit)
1-5
6-10
11-15
16-20
21-25
26-30
31-35
36-40
41-45
P1
Midpoint
Titik tengah
3
8
13
18
23
28
33
38
43
b)
= 21.63 minutes
1449/2(GMP) ©
2017 Hak Cipta JUJ Pahang
Frequency
Kekerapan
0
3
4
8
15
7
2
1
0
P1
P1
P1
K2
N1
SULIT
SULIT
9
Question
1449/2(GMP)
Sub
Mark
Mark
Solution and Mark Scheme
(c) Polygon
Axes drawn in correct directions with uniform scale for
3x43 and 0y15
P1
9 points correctly plotted or the straight line passes through all the
points for 3x43 and 0y15
K2
Note:
1. 8 or 7 points correctly plotted, award K1
2. Do not accept horizontal axis level with midpoints
Smooth and continuous line, passing through all 9 correct points
using given scales for 3x43 and 0y15
(d)
X 100%
7.5%
N1
K1
N1
12
1449/2(GMP) ©
2017 Hak Cipta JUJ Pahang
[ Lihat halaman sebelah
SULIT
SULIT
10
1449/2(GMP)
Frequency
16
14
12
10
8
6
4
2
3
8
13
18
23
28
33
38
43
Time(minutes)
1449/2(GMP) ©
2017 Hak Cipta JUJ Pahang
SULIT
SULIT
11
Question
1449/2(GMP)
Sub
Mark
Mark
Solution and Mark Scheme
(a)
H
G
K
J
E
F
K1
Correct shape with rectangles HGEF and line JK
All solid lines.
HG =JK = EF = HE = GF
Measurements correct to ± 0.2 cm (one way) and
all angles at vertices = 90o ± 1o
K1
N1
(b)(i)
15
F
S
G
K
P
A
D
Correct shape SFGPAD and point K with semicircle SF. All solid lines.
PA = AD < SP = FA = GD
FD = GD
Measurements correct to ± 0.2 cm (one way) and P,A ,D= 90o ± 1o
1449/2(GMP) ©
2017 Hak Cipta JUJ Pahang
K1
K1
N2
[ Lihat halaman sebelah
SULIT
SULIT
12
Question
Solution and Mark Scheme
1449/2(GMP)
Sub
Mark
Mark
(b)(ii)
R
S
R
U
J
K
Q
P
Correct shape with rectangles RSGP and RUJK
Note: Ignore dashed line
K1
dashed line EF and JK.
K1
JG = JP = RE = SF > EJ = FK
K1
Measurements correct to ± 0.2 cm (one way) and
All angles at vertices of rectangles = 90o ± 1o
N2
(a)( 30ºS,152ºW)
P2
180º-28º or 152º W/B or 152º
(b) 180º ÷ 5 X 3
108º - 28º
/b.n
(d) Maria = 180 X 60 X cos 30
1449/2(GMP) ©
K1
N1
(c) (180 – 30 – 30) X 60
7200
(P1)
(K1)
80W/B
16
12
2017 Hak Cipta JUJ Pahang
K1
N1
K1
SULIT
SULIT
13
Question
Solution and Mark Scheme
Sub
Mark
Mark
K1
or
K1
Shirley = (30 + 30) X 60
or
1449/2(GMP)
(7.2 hours)
Shirley will reach her destination first.
K1
N2
12
PERATURAN PEMARKAHAN TAMAT
1449/2(GMP) ©
2017 Hak Cipta JUJ Pahang
SULIT