BAB 5. TURUNAN - BAB 5 TURUNAN
BAB 5. TURUNAN
Program Studi Teknik Informatika
Fakultas Teknik
Universitas Muhammadiyah Jember
29th April 2018
Ilham Saifudin (TI)
KALKULUS
29th April 2018
1 / 17
Outline
1
Turunan
Konsep Turunan
Definisi turunan
Aturan turunan
Aplikasi turunan
Ilham Saifudin (TI)
KALKULUS
29th April 2018
2 / 17
Turunan
Konsep Turunan
KALKULUS
1
Turunan
Konsep Turunan
Definisi turunan
Aturan turunan
Aplikasi turunan
Ilham Saifudin (TI)
KALKULUS
29th April 2018
3 / 17
Turunan
Konsep Turunan
Untuk mendefinisikan pengertian garis singgung secara formal, perhatikanlah gambar
di samping kiri. Garis talibusur m1 menghubungkan titik P dan Q1 pada kurva.
Selanjutnya titik Q1 kita gerakkan mendekati titik P. Saat sampai di posisi Q2 ,
talibusurnya berubah menjadi garis m2 . Proses ini diteruskan sampai titik Q1 berimpit
dengan titik P, dan garis talibusurnya menjadi garis singgung m.
Ilham Saifudin (TI)
KALKULUS
29th April 2018
4 / 17
Turunan
Konsep Turunan
Gradien garis singgung tersebut dapat dinyatakan :
m = lim
h→0
Ilham Saifudin (TI)
f (c + h) − f (c)
= f ′ (c) = y ′
h
KALKULUS
29th April 2018
5 / 17
Turunan
Definisi turunan
KALKULUS
1
Turunan
Konsep Turunan
Definisi turunan
Aturan turunan
Aplikasi turunan
Ilham Saifudin (TI)
KALKULUS
29th April 2018
6 / 17
Turunan
Definisi turunan
Definisi turunan
Definisi
1
Misalkan f sebuah fungsi real dan x ∈ Df
2
Turunan dari f di titik x, ditulis
f ′ (x) = lim
h→0
f (x + h) − f (x)
h
contoh
Carilah kemiringan garis singgung terhadap y = x 2 − 2x di titik (2, 0)
Ilham Saifudin (TI)
KALKULUS
29th April 2018
7 / 17
Turunan
Definisi turunan
Definisi turunan
Definisi
1
Misalkan f sebuah fungsi real dan x ∈ Df
2
Turunan dari f di titik x, ditulis
f ′ (x) = lim
h→0
f (x + h) − f (x)
h
contoh
Carilah kemiringan garis singgung terhadap y = x 2 − 2x di titik (2, 0)
Ilham Saifudin (TI)
KALKULUS
29th April 2018
7 / 17
Turunan
Definisi turunan
Definisi turunan
Definisi
1
Misalkan f sebuah fungsi real dan x ∈ Df
2
Turunan dari f di titik x, ditulis
f ′ (x) = lim
h→0
f (x + h) − f (x)
h
contoh
Carilah kemiringan garis singgung terhadap y = x 2 − 2x di titik (2, 0)
Ilham Saifudin (TI)
KALKULUS
29th April 2018
7 / 17
Turunan
Definisi turunan
Definisi turunan
Definisi
1
Misalkan f sebuah fungsi real dan x ∈ Df
2
Turunan dari f di titik x, ditulis
f ′ (x) = lim
h→0
f (x + h) − f (x)
h
contoh
Carilah kemiringan garis singgung terhadap y = x 2 − 2x di titik (2, 0)
Ilham Saifudin (TI)
KALKULUS
29th April 2018
7 / 17
Turunan
Definisi turunan
Definisi turunan
Definisi
1
Misalkan f sebuah fungsi real dan x ∈ Df
2
Turunan dari f di titik x, ditulis
f ′ (x) = lim
h→0
f (x + h) − f (x)
h
contoh
Carilah kemiringan garis singgung terhadap y = x 2 − 2x di titik (2, 0)
Ilham Saifudin (TI)
KALKULUS
29th April 2018
7 / 17
Turunan
Aturan turunan
KALKULUS
1
Turunan
Konsep Turunan
Definisi turunan
Aturan turunan
Aplikasi turunan
Ilham Saifudin (TI)
KALKULUS
29th April 2018
8 / 17
Turunan
Aturan turunan
Aturan turunan
Aturan turunan
1
Misalkan k sebuah konstanta, maka Dx [k] = 0
2
Dx [x] = 1
3
Dx [x n ] = nx n−1
4
Dx [kf (x)] = kDx [f (x)]
5
Dx [(f ± g)(x)] = Dx [f (x)] ± Dx [g(x)]
6
Dx [(f .g)(x)] = Dx [f (x)].g(x) + f (x).Dx [g(x)]
7
Dx [( gf )(x)] =
Dx [f (x )].g(x )−f (x ).Dx [g(x )]
(g(x )2 )
Aturan turunan fungsi trigonometri
1
Dx [sinx] = cosx , Dx [cosx] = −sinx
2
Dx [tanx] = sec 2 x , Dx [cotx] = −cosec 2 x
3
Dx [secx] = secxtanx , Dx [cosecx] = −cosecxcotx
Ilham Saifudin (TI)
KALKULUS
29th April 2018
9 / 17
Turunan
Aturan turunan
Aturan turunan
Aturan turunan
1
Misalkan k sebuah konstanta, maka Dx [k] = 0
2
Dx [x] = 1
3
Dx [x n ] = nx n−1
4
Dx [kf (x)] = kDx [f (x)]
5
Dx [(f ± g)(x)] = Dx [f (x)] ± Dx [g(x)]
6
Dx [(f .g)(x)] = Dx [f (x)].g(x) + f (x).Dx [g(x)]
7
Dx [( gf )(x)] =
Dx [f (x )].g(x )−f (x ).Dx [g(x )]
(g(x )2 )
Aturan turunan fungsi trigonometri
1
Dx [sinx] = cosx , Dx [cosx] = −sinx
2
Dx [tanx] = sec 2 x , Dx [cotx] = −cosec 2 x
3
Dx [secx] = secxtanx , Dx [cosecx] = −cosecxcotx
Ilham Saifudin (TI)
KALKULUS
29th April 2018
9 / 17
Turunan
Aturan turunan
Aturan turunan
Aturan turunan
1
Misalkan k sebuah konstanta, maka Dx [k] = 0
2
Dx [x] = 1
3
Dx [x n ] = nx n−1
4
Dx [kf (x)] = kDx [f (x)]
5
Dx [(f ± g)(x)] = Dx [f (x)] ± Dx [g(x)]
6
Dx [(f .g)(x)] = Dx [f (x)].g(x) + f (x).Dx [g(x)]
7
Dx [( gf )(x)] =
Dx [f (x )].g(x )−f (x ).Dx [g(x )]
(g(x )2 )
Aturan turunan fungsi trigonometri
1
Dx [sinx] = cosx , Dx [cosx] = −sinx
2
Dx [tanx] = sec 2 x , Dx [cotx] = −cosec 2 x
3
Dx [secx] = secxtanx , Dx [cosecx] = −cosecxcotx
Ilham Saifudin (TI)
KALKULUS
29th April 2018
9 / 17
Turunan
Aturan turunan
Aturan turunan
Aturan turunan
1
Misalkan k sebuah konstanta, maka Dx [k] = 0
2
Dx [x] = 1
3
Dx [x n ] = nx n−1
4
Dx [kf (x)] = kDx [f (x)]
5
Dx [(f ± g)(x)] = Dx [f (x)] ± Dx [g(x)]
6
Dx [(f .g)(x)] = Dx [f (x)].g(x) + f (x).Dx [g(x)]
7
Dx [( gf )(x)] =
Dx [f (x )].g(x )−f (x ).Dx [g(x )]
(g(x )2 )
Aturan turunan fungsi trigonometri
1
Dx [sinx] = cosx , Dx [cosx] = −sinx
2
Dx [tanx] = sec 2 x , Dx [cotx] = −cosec 2 x
3
Dx [secx] = secxtanx , Dx [cosecx] = −cosecxcotx
Ilham Saifudin (TI)
KALKULUS
29th April 2018
9 / 17
Turunan
Aturan turunan
Aturan turunan
Aturan turunan
1
Misalkan k sebuah konstanta, maka Dx [k] = 0
2
Dx [x] = 1
3
Dx [x n ] = nx n−1
4
Dx [kf (x)] = kDx [f (x)]
5
Dx [(f ± g)(x)] = Dx [f (x)] ± Dx [g(x)]
6
Dx [(f .g)(x)] = Dx [f (x)].g(x) + f (x).Dx [g(x)]
7
Dx [( gf )(x)] =
Dx [f (x )].g(x )−f (x ).Dx [g(x )]
(g(x )2 )
Aturan turunan fungsi trigonometri
1
Dx [sinx] = cosx , Dx [cosx] = −sinx
2
Dx [tanx] = sec 2 x , Dx [cotx] = −cosec 2 x
3
Dx [secx] = secxtanx , Dx [cosecx] = −cosecxcotx
Ilham Saifudin (TI)
KALKULUS
29th April 2018
9 / 17
Turunan
Aturan turunan
Aturan turunan
Aturan turunan
1
Misalkan k sebuah konstanta, maka Dx [k] = 0
2
Dx [x] = 1
3
Dx [x n ] = nx n−1
4
Dx [kf (x)] = kDx [f (x)]
5
Dx [(f ± g)(x)] = Dx [f (x)] ± Dx [g(x)]
6
Dx [(f .g)(x)] = Dx [f (x)].g(x) + f (x).Dx [g(x)]
7
Dx [( gf )(x)] =
Dx [f (x )].g(x )−f (x ).Dx [g(x )]
(g(x )2 )
Aturan turunan fungsi trigonometri
1
Dx [sinx] = cosx , Dx [cosx] = −sinx
2
Dx [tanx] = sec 2 x , Dx [cotx] = −cosec 2 x
3
Dx [secx] = secxtanx , Dx [cosecx] = −cosecxcotx
Ilham Saifudin (TI)
KALKULUS
29th April 2018
9 / 17
Turunan
Aturan turunan
Aturan turunan
Aturan turunan
1
Misalkan k sebuah konstanta, maka Dx [k] = 0
2
Dx [x] = 1
3
Dx [x n ] = nx n−1
4
Dx [kf (x)] = kDx [f (x)]
5
Dx [(f ± g)(x)] = Dx [f (x)] ± Dx [g(x)]
6
Dx [(f .g)(x)] = Dx [f (x)].g(x) + f (x).Dx [g(x)]
7
Dx [( gf )(x)] =
Dx [f (x )].g(x )−f (x ).Dx [g(x )]
(g(x )2 )
Aturan turunan fungsi trigonometri
1
Dx [sinx] = cosx , Dx [cosx] = −sinx
2
Dx [tanx] = sec 2 x , Dx [cotx] = −cosec 2 x
3
Dx [secx] = secxtanx , Dx [cosecx] = −cosecxcotx
Ilham Saifudin (TI)
KALKULUS
29th April 2018
9 / 17
Turunan
Aturan turunan
Aturan turunan
Aturan turunan
1
Misalkan k sebuah konstanta, maka Dx [k] = 0
2
Dx [x] = 1
3
Dx [x n ] = nx n−1
4
Dx [kf (x)] = kDx [f (x)]
5
Dx [(f ± g)(x)] = Dx [f (x)] ± Dx [g(x)]
6
Dx [(f .g)(x)] = Dx [f (x)].g(x) + f (x).Dx [g(x)]
7
Dx [( gf )(x)] =
Dx [f (x )].g(x )−f (x ).Dx [g(x )]
(g(x )2 )
Aturan turunan fungsi trigonometri
1
Dx [sinx] = cosx , Dx [cosx] = −sinx
2
Dx [tanx] = sec 2 x , Dx [cotx] = −cosec 2 x
3
Dx [secx] = secxtanx , Dx [cosecx] = −cosecxcotx
Ilham Saifudin (TI)
KALKULUS
29th April 2018
9 / 17
Turunan
Aturan turunan
Aturan turunan
Aturan turunan
1
Misalkan k sebuah konstanta, maka Dx [k] = 0
2
Dx [x] = 1
3
Dx [x n ] = nx n−1
4
Dx [kf (x)] = kDx [f (x)]
5
Dx [(f ± g)(x)] = Dx [f (x)] ± Dx [g(x)]
6
Dx [(f .g)(x)] = Dx [f (x)].g(x) + f (x).Dx [g(x)]
7
Dx [( gf )(x)] =
Dx [f (x )].g(x )−f (x ).Dx [g(x )]
(g(x )2 )
Aturan turunan fungsi trigonometri
1
Dx [sinx] = cosx , Dx [cosx] = −sinx
2
Dx [tanx] = sec 2 x , Dx [cotx] = −cosec 2 x
3
Dx [secx] = secxtanx , Dx [cosecx] = −cosecxcotx
Ilham Saifudin (TI)
KALKULUS
29th April 2018
9 / 17
Turunan
Aturan turunan
Aturan turunan
Aturan turunan
1
Misalkan k sebuah konstanta, maka Dx [k] = 0
2
Dx [x] = 1
3
Dx [x n ] = nx n−1
4
Dx [kf (x)] = kDx [f (x)]
5
Dx [(f ± g)(x)] = Dx [f (x)] ± Dx [g(x)]
6
Dx [(f .g)(x)] = Dx [f (x)].g(x) + f (x).Dx [g(x)]
7
Dx [( gf )(x)] =
Dx [f (x )].g(x )−f (x ).Dx [g(x )]
(g(x )2 )
Aturan turunan fungsi trigonometri
1
Dx [sinx] = cosx , Dx [cosx] = −sinx
2
Dx [tanx] = sec 2 x , Dx [cotx] = −cosec 2 x
3
Dx [secx] = secxtanx , Dx [cosecx] = −cosecxcotx
Ilham Saifudin (TI)
KALKULUS
29th April 2018
9 / 17
Turunan
Aturan turunan
Aturan turunan
Aturan turunan
1
Misalkan k sebuah konstanta, maka Dx [k] = 0
2
Dx [x] = 1
3
Dx [x n ] = nx n−1
4
Dx [kf (x)] = kDx [f (x)]
5
Dx [(f ± g)(x)] = Dx [f (x)] ± Dx [g(x)]
6
Dx [(f .g)(x)] = Dx [f (x)].g(x) + f (x).Dx [g(x)]
7
Dx [( gf )(x)] =
Dx [f (x )].g(x )−f (x ).Dx [g(x )]
(g(x )2 )
Aturan turunan fungsi trigonometri
1
Dx [sinx] = cosx , Dx [cosx] = −sinx
2
Dx [tanx] = sec 2 x , Dx [cotx] = −cosec 2 x
3
Dx [secx] = secxtanx , Dx [cosecx] = −cosecxcotx
Ilham Saifudin (TI)
KALKULUS
29th April 2018
9 / 17
Turunan
Aturan turunan
Aturan turunan
Aturan turunan
1
Misalkan k sebuah konstanta, maka Dx [k] = 0
2
Dx [x] = 1
3
Dx [x n ] = nx n−1
4
Dx [kf (x)] = kDx [f (x)]
5
Dx [(f ± g)(x)] = Dx [f (x)] ± Dx [g(x)]
6
Dx [(f .g)(x)] = Dx [f (x)].g(x) + f (x).Dx [g(x)]
7
Dx [( gf )(x)] =
Dx [f (x )].g(x )−f (x ).Dx [g(x )]
(g(x )2 )
Aturan turunan fungsi trigonometri
1
Dx [sinx] = cosx , Dx [cosx] = −sinx
2
Dx [tanx] = sec 2 x , Dx [cotx] = −cosec 2 x
3
Dx [secx] = secxtanx , Dx [cosecx] = −cosecxcotx
Ilham Saifudin (TI)
KALKULUS
29th April 2018
9 / 17
Turunan
Aturan turunan
Aturan turunan
Aturan turunan
1
Misalkan k sebuah konstanta, maka Dx [k] = 0
2
Dx [x] = 1
3
Dx [x n ] = nx n−1
4
Dx [kf (x)] = kDx [f (x)]
5
Dx [(f ± g)(x)] = Dx [f (x)] ± Dx [g(x)]
6
Dx [(f .g)(x)] = Dx [f (x)].g(x) + f (x).Dx [g(x)]
7
Dx [( gf )(x)] =
Dx [f (x )].g(x )−f (x ).Dx [g(x )]
(g(x )2 )
Aturan turunan fungsi trigonometri
1
Dx [sinx] = cosx , Dx [cosx] = −sinx
2
Dx [tanx] = sec 2 x , Dx [cotx] = −cosec 2 x
3
Dx [secx] = secxtanx , Dx [cosecx] = −cosecxcotx
Ilham Saifudin (TI)
KALKULUS
29th April 2018
9 / 17
Turunan
Aturan turunan
Aturan turunan
Contoh
1
Jika f (x) = 5x 2 + sinx, maka f ′ (x) =?
2
Jika f (x) = x 2 .sinx, maka f ′ ( 2 ) =?
3
Jika f (x) =
Q
5x +1
.sinx,
3x −2
Ilham Saifudin (TI)
maka f ′ (1) =?
KALKULUS
29th April 2018
10 / 17
Turunan
Aturan turunan
Aturan turunan
Contoh
1
Jika f (x) = 5x 2 + sinx, maka f ′ (x) =?
2
Jika f (x) = x 2 .sinx, maka f ′ ( 2 ) =?
3
Jika f (x) =
Q
5x +1
.sinx,
3x −2
Ilham Saifudin (TI)
maka f ′ (1) =?
KALKULUS
29th April 2018
10 / 17
Turunan
Aturan turunan
Aturan turunan
Contoh
1
Jika f (x) = 5x 2 + sinx, maka f ′ (x) =?
2
Jika f (x) = x 2 .sinx, maka f ′ ( 2 ) =?
3
Jika f (x) =
Q
5x +1
.sinx,
3x −2
Ilham Saifudin (TI)
maka f ′ (1) =?
KALKULUS
29th April 2018
10 / 17
Turunan
Aturan turunan
Aturan turunan
Contoh
1
Jika f (x) = 5x 2 + sinx, maka f ′ (x) =?
2
Jika f (x) = x 2 .sinx, maka f ′ ( 2 ) =?
3
Jika f (x) =
Q
5x +1
.sinx,
3x −2
Ilham Saifudin (TI)
maka f ′ (1) =?
KALKULUS
29th April 2018
10 / 17
Turunan
Aturan turunan
Aturan turunan
Aturan Rantai
Misalkan y = f (u) dan u = g(x). Jika g terdefinisikan di x dan f terdefinisikan di
u = g(x), maka fungsi komposit f ◦ g, yang didefinisikan oleh (f ◦ g)(x) = f (g(x)),
adalah terdiferensiasikan di x dan (f ◦ g)′ (x) = f ′ (g(x))g ′ (x)
Dx (f (g(x))) =
yakni
f ′ (g(x))g ′ (x)
Ilham Saifudin (TI)
KALKULUS
29th April 2018
11 / 17
Turunan
Aturan turunan
Aturan turunan
Contoh
1
Jika f (x) = (x 2 − 3x + 5)3 , maka f ′ (x) =?
2
Jika f (x) = sin2 (x 2 − 3x), maka f ′ (x) =?
Ilham Saifudin (TI)
KALKULUS
29th April 2018
12 / 17
Turunan
Aturan turunan
Aturan turunan
Contoh
1
Jika f (x) = (x 2 − 3x + 5)3 , maka f ′ (x) =?
2
Jika f (x) = sin2 (x 2 − 3x), maka f ′ (x) =?
Ilham Saifudin (TI)
KALKULUS
29th April 2018
12 / 17
Turunan
Aturan turunan
Aturan turunan
Contoh
1
Jika f (x) = (x 2 − 3x + 5)3 , maka f ′ (x) =?
2
Jika f (x) = sin2 (x 2 − 3x), maka f ′ (x) =?
Ilham Saifudin (TI)
KALKULUS
29th April 2018
12 / 17
Turunan
Aturan turunan
Aturan turunan
Turunan tingkat tinggi
Misalkan f (x) sebuah fungsi dan f ′ (x) turunan pertamanya. Turuna kedua dari f
adalah f ”(x) = Dx2 (f ). Dengan cara yang sama turunan ketiga , keempat dst. Salah
satu penggunaan turunan tingkat tinggi adalah pada masalah gerak partikel. Bila S(t)
menyatakan posisi sebuah partikel, maka kecepatannya adalah v (t) = S ′ (t) dan
percepatannya a(t) = v ′ (t) = S”(t)
Ilham Saifudin (TI)
KALKULUS
29th April 2018
13 / 17
Turunan
Aplikasi turunan
KALKULUS
1
Turunan
Konsep Turunan
Definisi turunan
Aturan turunan
Aplikasi turunan
Ilham Saifudin (TI)
KALKULUS
29th April 2018
14 / 17
Turunan
Aplikasi turunan
Aplikasi turunan
y=f’(x)
1
Gradien g singgung : m = y ′
2
fungsi naik : y ′ > 0
3
fungsi turun : y ′ < 0
4
fungsi stasioner : y ′ = 0
5
kecepatan : v ′ =
6
percepatan : a′ =
Ilham Saifudin (TI)
ds
dt
dv
dt
= S′
= v ′ = S”
KALKULUS
29th April 2018
15 / 17
Turunan
Aplikasi turunan
Aplikasi turunan
y=f’(x)
1
Gradien g singgung : m = y ′
2
fungsi naik : y ′ > 0
3
fungsi turun : y ′ < 0
4
fungsi stasioner : y ′ = 0
5
kecepatan : v ′ =
6
percepatan : a′ =
Ilham Saifudin (TI)
ds
dt
dv
dt
= S′
= v ′ = S”
KALKULUS
29th April 2018
15 / 17
Turunan
Aplikasi turunan
Aplikasi turunan
y=f’(x)
1
Gradien g singgung : m = y ′
2
fungsi naik : y ′ > 0
3
fungsi turun : y ′ < 0
4
fungsi stasioner : y ′ = 0
5
kecepatan : v ′ =
6
percepatan : a′ =
Ilham Saifudin (TI)
ds
dt
dv
dt
= S′
= v ′ = S”
KALKULUS
29th April 2018
15 / 17
Turunan
Aplikasi turunan
Aplikasi turunan
y=f’(x)
1
Gradien g singgung : m = y ′
2
fungsi naik : y ′ > 0
3
fungsi turun : y ′ < 0
4
fungsi stasioner : y ′ = 0
5
kecepatan : v ′ =
6
percepatan : a′ =
Ilham Saifudin (TI)
ds
dt
dv
dt
= S′
= v ′ = S”
KALKULUS
29th April 2018
15 / 17
Turunan
Aplikasi turunan
Aplikasi turunan
y=f’(x)
1
Gradien g singgung : m = y ′
2
fungsi naik : y ′ > 0
3
fungsi turun : y ′ < 0
4
fungsi stasioner : y ′ = 0
5
kecepatan : v ′ =
6
percepatan : a′ =
Ilham Saifudin (TI)
ds
dt
dv
dt
= S′
= v ′ = S”
KALKULUS
29th April 2018
15 / 17
Turunan
Aplikasi turunan
Aplikasi turunan
y=f’(x)
1
Gradien g singgung : m = y ′
2
fungsi naik : y ′ > 0
3
fungsi turun : y ′ < 0
4
fungsi stasioner : y ′ = 0
5
kecepatan : v ′ =
6
percepatan : a′ =
Ilham Saifudin (TI)
ds
dt
dv
dt
= S′
= v ′ = S”
KALKULUS
29th April 2018
15 / 17
Turunan
Aplikasi turunan
Aplikasi turunan
y=f’(x)
1
Gradien g singgung : m = y ′
2
fungsi naik : y ′ > 0
3
fungsi turun : y ′ < 0
4
fungsi stasioner : y ′ = 0
5
kecepatan : v ′ =
6
percepatan : a′ =
Ilham Saifudin (TI)
ds
dt
dv
dt
= S′
= v ′ = S”
KALKULUS
29th April 2018
15 / 17
Turunan
Aplikasi turunan
Aplikasi turunan
y=f”(x)
Uji jenis
1
maximum : y” > 0
2
minimum : y” < 0
3
titik belok : y” = 0
Ilham Saifudin (TI)
KALKULUS
29th April 2018
16 / 17
Turunan
Aplikasi turunan
Aplikasi turunan
y=f”(x)
Uji jenis
1
maximum : y” > 0
2
minimum : y” < 0
3
titik belok : y” = 0
Ilham Saifudin (TI)
KALKULUS
29th April 2018
16 / 17
Turunan
Aplikasi turunan
Aplikasi turunan
y=f”(x)
Uji jenis
1
maximum : y” > 0
2
minimum : y” < 0
3
titik belok : y” = 0
Ilham Saifudin (TI)
KALKULUS
29th April 2018
16 / 17
Turunan
Aplikasi turunan
Aplikasi turunan
y=f”(x)
Uji jenis
1
maximum : y” > 0
2
minimum : y” < 0
3
titik belok : y” = 0
Ilham Saifudin (TI)
KALKULUS
29th April 2018
16 / 17
Turunan
Aplikasi turunan
Thank You
Ilham Saifudin (TI)
KALKULUS
29th April 2018
17 / 17
Program Studi Teknik Informatika
Fakultas Teknik
Universitas Muhammadiyah Jember
29th April 2018
Ilham Saifudin (TI)
KALKULUS
29th April 2018
1 / 17
Outline
1
Turunan
Konsep Turunan
Definisi turunan
Aturan turunan
Aplikasi turunan
Ilham Saifudin (TI)
KALKULUS
29th April 2018
2 / 17
Turunan
Konsep Turunan
KALKULUS
1
Turunan
Konsep Turunan
Definisi turunan
Aturan turunan
Aplikasi turunan
Ilham Saifudin (TI)
KALKULUS
29th April 2018
3 / 17
Turunan
Konsep Turunan
Untuk mendefinisikan pengertian garis singgung secara formal, perhatikanlah gambar
di samping kiri. Garis talibusur m1 menghubungkan titik P dan Q1 pada kurva.
Selanjutnya titik Q1 kita gerakkan mendekati titik P. Saat sampai di posisi Q2 ,
talibusurnya berubah menjadi garis m2 . Proses ini diteruskan sampai titik Q1 berimpit
dengan titik P, dan garis talibusurnya menjadi garis singgung m.
Ilham Saifudin (TI)
KALKULUS
29th April 2018
4 / 17
Turunan
Konsep Turunan
Gradien garis singgung tersebut dapat dinyatakan :
m = lim
h→0
Ilham Saifudin (TI)
f (c + h) − f (c)
= f ′ (c) = y ′
h
KALKULUS
29th April 2018
5 / 17
Turunan
Definisi turunan
KALKULUS
1
Turunan
Konsep Turunan
Definisi turunan
Aturan turunan
Aplikasi turunan
Ilham Saifudin (TI)
KALKULUS
29th April 2018
6 / 17
Turunan
Definisi turunan
Definisi turunan
Definisi
1
Misalkan f sebuah fungsi real dan x ∈ Df
2
Turunan dari f di titik x, ditulis
f ′ (x) = lim
h→0
f (x + h) − f (x)
h
contoh
Carilah kemiringan garis singgung terhadap y = x 2 − 2x di titik (2, 0)
Ilham Saifudin (TI)
KALKULUS
29th April 2018
7 / 17
Turunan
Definisi turunan
Definisi turunan
Definisi
1
Misalkan f sebuah fungsi real dan x ∈ Df
2
Turunan dari f di titik x, ditulis
f ′ (x) = lim
h→0
f (x + h) − f (x)
h
contoh
Carilah kemiringan garis singgung terhadap y = x 2 − 2x di titik (2, 0)
Ilham Saifudin (TI)
KALKULUS
29th April 2018
7 / 17
Turunan
Definisi turunan
Definisi turunan
Definisi
1
Misalkan f sebuah fungsi real dan x ∈ Df
2
Turunan dari f di titik x, ditulis
f ′ (x) = lim
h→0
f (x + h) − f (x)
h
contoh
Carilah kemiringan garis singgung terhadap y = x 2 − 2x di titik (2, 0)
Ilham Saifudin (TI)
KALKULUS
29th April 2018
7 / 17
Turunan
Definisi turunan
Definisi turunan
Definisi
1
Misalkan f sebuah fungsi real dan x ∈ Df
2
Turunan dari f di titik x, ditulis
f ′ (x) = lim
h→0
f (x + h) − f (x)
h
contoh
Carilah kemiringan garis singgung terhadap y = x 2 − 2x di titik (2, 0)
Ilham Saifudin (TI)
KALKULUS
29th April 2018
7 / 17
Turunan
Definisi turunan
Definisi turunan
Definisi
1
Misalkan f sebuah fungsi real dan x ∈ Df
2
Turunan dari f di titik x, ditulis
f ′ (x) = lim
h→0
f (x + h) − f (x)
h
contoh
Carilah kemiringan garis singgung terhadap y = x 2 − 2x di titik (2, 0)
Ilham Saifudin (TI)
KALKULUS
29th April 2018
7 / 17
Turunan
Aturan turunan
KALKULUS
1
Turunan
Konsep Turunan
Definisi turunan
Aturan turunan
Aplikasi turunan
Ilham Saifudin (TI)
KALKULUS
29th April 2018
8 / 17
Turunan
Aturan turunan
Aturan turunan
Aturan turunan
1
Misalkan k sebuah konstanta, maka Dx [k] = 0
2
Dx [x] = 1
3
Dx [x n ] = nx n−1
4
Dx [kf (x)] = kDx [f (x)]
5
Dx [(f ± g)(x)] = Dx [f (x)] ± Dx [g(x)]
6
Dx [(f .g)(x)] = Dx [f (x)].g(x) + f (x).Dx [g(x)]
7
Dx [( gf )(x)] =
Dx [f (x )].g(x )−f (x ).Dx [g(x )]
(g(x )2 )
Aturan turunan fungsi trigonometri
1
Dx [sinx] = cosx , Dx [cosx] = −sinx
2
Dx [tanx] = sec 2 x , Dx [cotx] = −cosec 2 x
3
Dx [secx] = secxtanx , Dx [cosecx] = −cosecxcotx
Ilham Saifudin (TI)
KALKULUS
29th April 2018
9 / 17
Turunan
Aturan turunan
Aturan turunan
Aturan turunan
1
Misalkan k sebuah konstanta, maka Dx [k] = 0
2
Dx [x] = 1
3
Dx [x n ] = nx n−1
4
Dx [kf (x)] = kDx [f (x)]
5
Dx [(f ± g)(x)] = Dx [f (x)] ± Dx [g(x)]
6
Dx [(f .g)(x)] = Dx [f (x)].g(x) + f (x).Dx [g(x)]
7
Dx [( gf )(x)] =
Dx [f (x )].g(x )−f (x ).Dx [g(x )]
(g(x )2 )
Aturan turunan fungsi trigonometri
1
Dx [sinx] = cosx , Dx [cosx] = −sinx
2
Dx [tanx] = sec 2 x , Dx [cotx] = −cosec 2 x
3
Dx [secx] = secxtanx , Dx [cosecx] = −cosecxcotx
Ilham Saifudin (TI)
KALKULUS
29th April 2018
9 / 17
Turunan
Aturan turunan
Aturan turunan
Aturan turunan
1
Misalkan k sebuah konstanta, maka Dx [k] = 0
2
Dx [x] = 1
3
Dx [x n ] = nx n−1
4
Dx [kf (x)] = kDx [f (x)]
5
Dx [(f ± g)(x)] = Dx [f (x)] ± Dx [g(x)]
6
Dx [(f .g)(x)] = Dx [f (x)].g(x) + f (x).Dx [g(x)]
7
Dx [( gf )(x)] =
Dx [f (x )].g(x )−f (x ).Dx [g(x )]
(g(x )2 )
Aturan turunan fungsi trigonometri
1
Dx [sinx] = cosx , Dx [cosx] = −sinx
2
Dx [tanx] = sec 2 x , Dx [cotx] = −cosec 2 x
3
Dx [secx] = secxtanx , Dx [cosecx] = −cosecxcotx
Ilham Saifudin (TI)
KALKULUS
29th April 2018
9 / 17
Turunan
Aturan turunan
Aturan turunan
Aturan turunan
1
Misalkan k sebuah konstanta, maka Dx [k] = 0
2
Dx [x] = 1
3
Dx [x n ] = nx n−1
4
Dx [kf (x)] = kDx [f (x)]
5
Dx [(f ± g)(x)] = Dx [f (x)] ± Dx [g(x)]
6
Dx [(f .g)(x)] = Dx [f (x)].g(x) + f (x).Dx [g(x)]
7
Dx [( gf )(x)] =
Dx [f (x )].g(x )−f (x ).Dx [g(x )]
(g(x )2 )
Aturan turunan fungsi trigonometri
1
Dx [sinx] = cosx , Dx [cosx] = −sinx
2
Dx [tanx] = sec 2 x , Dx [cotx] = −cosec 2 x
3
Dx [secx] = secxtanx , Dx [cosecx] = −cosecxcotx
Ilham Saifudin (TI)
KALKULUS
29th April 2018
9 / 17
Turunan
Aturan turunan
Aturan turunan
Aturan turunan
1
Misalkan k sebuah konstanta, maka Dx [k] = 0
2
Dx [x] = 1
3
Dx [x n ] = nx n−1
4
Dx [kf (x)] = kDx [f (x)]
5
Dx [(f ± g)(x)] = Dx [f (x)] ± Dx [g(x)]
6
Dx [(f .g)(x)] = Dx [f (x)].g(x) + f (x).Dx [g(x)]
7
Dx [( gf )(x)] =
Dx [f (x )].g(x )−f (x ).Dx [g(x )]
(g(x )2 )
Aturan turunan fungsi trigonometri
1
Dx [sinx] = cosx , Dx [cosx] = −sinx
2
Dx [tanx] = sec 2 x , Dx [cotx] = −cosec 2 x
3
Dx [secx] = secxtanx , Dx [cosecx] = −cosecxcotx
Ilham Saifudin (TI)
KALKULUS
29th April 2018
9 / 17
Turunan
Aturan turunan
Aturan turunan
Aturan turunan
1
Misalkan k sebuah konstanta, maka Dx [k] = 0
2
Dx [x] = 1
3
Dx [x n ] = nx n−1
4
Dx [kf (x)] = kDx [f (x)]
5
Dx [(f ± g)(x)] = Dx [f (x)] ± Dx [g(x)]
6
Dx [(f .g)(x)] = Dx [f (x)].g(x) + f (x).Dx [g(x)]
7
Dx [( gf )(x)] =
Dx [f (x )].g(x )−f (x ).Dx [g(x )]
(g(x )2 )
Aturan turunan fungsi trigonometri
1
Dx [sinx] = cosx , Dx [cosx] = −sinx
2
Dx [tanx] = sec 2 x , Dx [cotx] = −cosec 2 x
3
Dx [secx] = secxtanx , Dx [cosecx] = −cosecxcotx
Ilham Saifudin (TI)
KALKULUS
29th April 2018
9 / 17
Turunan
Aturan turunan
Aturan turunan
Aturan turunan
1
Misalkan k sebuah konstanta, maka Dx [k] = 0
2
Dx [x] = 1
3
Dx [x n ] = nx n−1
4
Dx [kf (x)] = kDx [f (x)]
5
Dx [(f ± g)(x)] = Dx [f (x)] ± Dx [g(x)]
6
Dx [(f .g)(x)] = Dx [f (x)].g(x) + f (x).Dx [g(x)]
7
Dx [( gf )(x)] =
Dx [f (x )].g(x )−f (x ).Dx [g(x )]
(g(x )2 )
Aturan turunan fungsi trigonometri
1
Dx [sinx] = cosx , Dx [cosx] = −sinx
2
Dx [tanx] = sec 2 x , Dx [cotx] = −cosec 2 x
3
Dx [secx] = secxtanx , Dx [cosecx] = −cosecxcotx
Ilham Saifudin (TI)
KALKULUS
29th April 2018
9 / 17
Turunan
Aturan turunan
Aturan turunan
Aturan turunan
1
Misalkan k sebuah konstanta, maka Dx [k] = 0
2
Dx [x] = 1
3
Dx [x n ] = nx n−1
4
Dx [kf (x)] = kDx [f (x)]
5
Dx [(f ± g)(x)] = Dx [f (x)] ± Dx [g(x)]
6
Dx [(f .g)(x)] = Dx [f (x)].g(x) + f (x).Dx [g(x)]
7
Dx [( gf )(x)] =
Dx [f (x )].g(x )−f (x ).Dx [g(x )]
(g(x )2 )
Aturan turunan fungsi trigonometri
1
Dx [sinx] = cosx , Dx [cosx] = −sinx
2
Dx [tanx] = sec 2 x , Dx [cotx] = −cosec 2 x
3
Dx [secx] = secxtanx , Dx [cosecx] = −cosecxcotx
Ilham Saifudin (TI)
KALKULUS
29th April 2018
9 / 17
Turunan
Aturan turunan
Aturan turunan
Aturan turunan
1
Misalkan k sebuah konstanta, maka Dx [k] = 0
2
Dx [x] = 1
3
Dx [x n ] = nx n−1
4
Dx [kf (x)] = kDx [f (x)]
5
Dx [(f ± g)(x)] = Dx [f (x)] ± Dx [g(x)]
6
Dx [(f .g)(x)] = Dx [f (x)].g(x) + f (x).Dx [g(x)]
7
Dx [( gf )(x)] =
Dx [f (x )].g(x )−f (x ).Dx [g(x )]
(g(x )2 )
Aturan turunan fungsi trigonometri
1
Dx [sinx] = cosx , Dx [cosx] = −sinx
2
Dx [tanx] = sec 2 x , Dx [cotx] = −cosec 2 x
3
Dx [secx] = secxtanx , Dx [cosecx] = −cosecxcotx
Ilham Saifudin (TI)
KALKULUS
29th April 2018
9 / 17
Turunan
Aturan turunan
Aturan turunan
Aturan turunan
1
Misalkan k sebuah konstanta, maka Dx [k] = 0
2
Dx [x] = 1
3
Dx [x n ] = nx n−1
4
Dx [kf (x)] = kDx [f (x)]
5
Dx [(f ± g)(x)] = Dx [f (x)] ± Dx [g(x)]
6
Dx [(f .g)(x)] = Dx [f (x)].g(x) + f (x).Dx [g(x)]
7
Dx [( gf )(x)] =
Dx [f (x )].g(x )−f (x ).Dx [g(x )]
(g(x )2 )
Aturan turunan fungsi trigonometri
1
Dx [sinx] = cosx , Dx [cosx] = −sinx
2
Dx [tanx] = sec 2 x , Dx [cotx] = −cosec 2 x
3
Dx [secx] = secxtanx , Dx [cosecx] = −cosecxcotx
Ilham Saifudin (TI)
KALKULUS
29th April 2018
9 / 17
Turunan
Aturan turunan
Aturan turunan
Aturan turunan
1
Misalkan k sebuah konstanta, maka Dx [k] = 0
2
Dx [x] = 1
3
Dx [x n ] = nx n−1
4
Dx [kf (x)] = kDx [f (x)]
5
Dx [(f ± g)(x)] = Dx [f (x)] ± Dx [g(x)]
6
Dx [(f .g)(x)] = Dx [f (x)].g(x) + f (x).Dx [g(x)]
7
Dx [( gf )(x)] =
Dx [f (x )].g(x )−f (x ).Dx [g(x )]
(g(x )2 )
Aturan turunan fungsi trigonometri
1
Dx [sinx] = cosx , Dx [cosx] = −sinx
2
Dx [tanx] = sec 2 x , Dx [cotx] = −cosec 2 x
3
Dx [secx] = secxtanx , Dx [cosecx] = −cosecxcotx
Ilham Saifudin (TI)
KALKULUS
29th April 2018
9 / 17
Turunan
Aturan turunan
Aturan turunan
Aturan turunan
1
Misalkan k sebuah konstanta, maka Dx [k] = 0
2
Dx [x] = 1
3
Dx [x n ] = nx n−1
4
Dx [kf (x)] = kDx [f (x)]
5
Dx [(f ± g)(x)] = Dx [f (x)] ± Dx [g(x)]
6
Dx [(f .g)(x)] = Dx [f (x)].g(x) + f (x).Dx [g(x)]
7
Dx [( gf )(x)] =
Dx [f (x )].g(x )−f (x ).Dx [g(x )]
(g(x )2 )
Aturan turunan fungsi trigonometri
1
Dx [sinx] = cosx , Dx [cosx] = −sinx
2
Dx [tanx] = sec 2 x , Dx [cotx] = −cosec 2 x
3
Dx [secx] = secxtanx , Dx [cosecx] = −cosecxcotx
Ilham Saifudin (TI)
KALKULUS
29th April 2018
9 / 17
Turunan
Aturan turunan
Aturan turunan
Aturan turunan
1
Misalkan k sebuah konstanta, maka Dx [k] = 0
2
Dx [x] = 1
3
Dx [x n ] = nx n−1
4
Dx [kf (x)] = kDx [f (x)]
5
Dx [(f ± g)(x)] = Dx [f (x)] ± Dx [g(x)]
6
Dx [(f .g)(x)] = Dx [f (x)].g(x) + f (x).Dx [g(x)]
7
Dx [( gf )(x)] =
Dx [f (x )].g(x )−f (x ).Dx [g(x )]
(g(x )2 )
Aturan turunan fungsi trigonometri
1
Dx [sinx] = cosx , Dx [cosx] = −sinx
2
Dx [tanx] = sec 2 x , Dx [cotx] = −cosec 2 x
3
Dx [secx] = secxtanx , Dx [cosecx] = −cosecxcotx
Ilham Saifudin (TI)
KALKULUS
29th April 2018
9 / 17
Turunan
Aturan turunan
Aturan turunan
Contoh
1
Jika f (x) = 5x 2 + sinx, maka f ′ (x) =?
2
Jika f (x) = x 2 .sinx, maka f ′ ( 2 ) =?
3
Jika f (x) =
Q
5x +1
.sinx,
3x −2
Ilham Saifudin (TI)
maka f ′ (1) =?
KALKULUS
29th April 2018
10 / 17
Turunan
Aturan turunan
Aturan turunan
Contoh
1
Jika f (x) = 5x 2 + sinx, maka f ′ (x) =?
2
Jika f (x) = x 2 .sinx, maka f ′ ( 2 ) =?
3
Jika f (x) =
Q
5x +1
.sinx,
3x −2
Ilham Saifudin (TI)
maka f ′ (1) =?
KALKULUS
29th April 2018
10 / 17
Turunan
Aturan turunan
Aturan turunan
Contoh
1
Jika f (x) = 5x 2 + sinx, maka f ′ (x) =?
2
Jika f (x) = x 2 .sinx, maka f ′ ( 2 ) =?
3
Jika f (x) =
Q
5x +1
.sinx,
3x −2
Ilham Saifudin (TI)
maka f ′ (1) =?
KALKULUS
29th April 2018
10 / 17
Turunan
Aturan turunan
Aturan turunan
Contoh
1
Jika f (x) = 5x 2 + sinx, maka f ′ (x) =?
2
Jika f (x) = x 2 .sinx, maka f ′ ( 2 ) =?
3
Jika f (x) =
Q
5x +1
.sinx,
3x −2
Ilham Saifudin (TI)
maka f ′ (1) =?
KALKULUS
29th April 2018
10 / 17
Turunan
Aturan turunan
Aturan turunan
Aturan Rantai
Misalkan y = f (u) dan u = g(x). Jika g terdefinisikan di x dan f terdefinisikan di
u = g(x), maka fungsi komposit f ◦ g, yang didefinisikan oleh (f ◦ g)(x) = f (g(x)),
adalah terdiferensiasikan di x dan (f ◦ g)′ (x) = f ′ (g(x))g ′ (x)
Dx (f (g(x))) =
yakni
f ′ (g(x))g ′ (x)
Ilham Saifudin (TI)
KALKULUS
29th April 2018
11 / 17
Turunan
Aturan turunan
Aturan turunan
Contoh
1
Jika f (x) = (x 2 − 3x + 5)3 , maka f ′ (x) =?
2
Jika f (x) = sin2 (x 2 − 3x), maka f ′ (x) =?
Ilham Saifudin (TI)
KALKULUS
29th April 2018
12 / 17
Turunan
Aturan turunan
Aturan turunan
Contoh
1
Jika f (x) = (x 2 − 3x + 5)3 , maka f ′ (x) =?
2
Jika f (x) = sin2 (x 2 − 3x), maka f ′ (x) =?
Ilham Saifudin (TI)
KALKULUS
29th April 2018
12 / 17
Turunan
Aturan turunan
Aturan turunan
Contoh
1
Jika f (x) = (x 2 − 3x + 5)3 , maka f ′ (x) =?
2
Jika f (x) = sin2 (x 2 − 3x), maka f ′ (x) =?
Ilham Saifudin (TI)
KALKULUS
29th April 2018
12 / 17
Turunan
Aturan turunan
Aturan turunan
Turunan tingkat tinggi
Misalkan f (x) sebuah fungsi dan f ′ (x) turunan pertamanya. Turuna kedua dari f
adalah f ”(x) = Dx2 (f ). Dengan cara yang sama turunan ketiga , keempat dst. Salah
satu penggunaan turunan tingkat tinggi adalah pada masalah gerak partikel. Bila S(t)
menyatakan posisi sebuah partikel, maka kecepatannya adalah v (t) = S ′ (t) dan
percepatannya a(t) = v ′ (t) = S”(t)
Ilham Saifudin (TI)
KALKULUS
29th April 2018
13 / 17
Turunan
Aplikasi turunan
KALKULUS
1
Turunan
Konsep Turunan
Definisi turunan
Aturan turunan
Aplikasi turunan
Ilham Saifudin (TI)
KALKULUS
29th April 2018
14 / 17
Turunan
Aplikasi turunan
Aplikasi turunan
y=f’(x)
1
Gradien g singgung : m = y ′
2
fungsi naik : y ′ > 0
3
fungsi turun : y ′ < 0
4
fungsi stasioner : y ′ = 0
5
kecepatan : v ′ =
6
percepatan : a′ =
Ilham Saifudin (TI)
ds
dt
dv
dt
= S′
= v ′ = S”
KALKULUS
29th April 2018
15 / 17
Turunan
Aplikasi turunan
Aplikasi turunan
y=f’(x)
1
Gradien g singgung : m = y ′
2
fungsi naik : y ′ > 0
3
fungsi turun : y ′ < 0
4
fungsi stasioner : y ′ = 0
5
kecepatan : v ′ =
6
percepatan : a′ =
Ilham Saifudin (TI)
ds
dt
dv
dt
= S′
= v ′ = S”
KALKULUS
29th April 2018
15 / 17
Turunan
Aplikasi turunan
Aplikasi turunan
y=f’(x)
1
Gradien g singgung : m = y ′
2
fungsi naik : y ′ > 0
3
fungsi turun : y ′ < 0
4
fungsi stasioner : y ′ = 0
5
kecepatan : v ′ =
6
percepatan : a′ =
Ilham Saifudin (TI)
ds
dt
dv
dt
= S′
= v ′ = S”
KALKULUS
29th April 2018
15 / 17
Turunan
Aplikasi turunan
Aplikasi turunan
y=f’(x)
1
Gradien g singgung : m = y ′
2
fungsi naik : y ′ > 0
3
fungsi turun : y ′ < 0
4
fungsi stasioner : y ′ = 0
5
kecepatan : v ′ =
6
percepatan : a′ =
Ilham Saifudin (TI)
ds
dt
dv
dt
= S′
= v ′ = S”
KALKULUS
29th April 2018
15 / 17
Turunan
Aplikasi turunan
Aplikasi turunan
y=f’(x)
1
Gradien g singgung : m = y ′
2
fungsi naik : y ′ > 0
3
fungsi turun : y ′ < 0
4
fungsi stasioner : y ′ = 0
5
kecepatan : v ′ =
6
percepatan : a′ =
Ilham Saifudin (TI)
ds
dt
dv
dt
= S′
= v ′ = S”
KALKULUS
29th April 2018
15 / 17
Turunan
Aplikasi turunan
Aplikasi turunan
y=f’(x)
1
Gradien g singgung : m = y ′
2
fungsi naik : y ′ > 0
3
fungsi turun : y ′ < 0
4
fungsi stasioner : y ′ = 0
5
kecepatan : v ′ =
6
percepatan : a′ =
Ilham Saifudin (TI)
ds
dt
dv
dt
= S′
= v ′ = S”
KALKULUS
29th April 2018
15 / 17
Turunan
Aplikasi turunan
Aplikasi turunan
y=f’(x)
1
Gradien g singgung : m = y ′
2
fungsi naik : y ′ > 0
3
fungsi turun : y ′ < 0
4
fungsi stasioner : y ′ = 0
5
kecepatan : v ′ =
6
percepatan : a′ =
Ilham Saifudin (TI)
ds
dt
dv
dt
= S′
= v ′ = S”
KALKULUS
29th April 2018
15 / 17
Turunan
Aplikasi turunan
Aplikasi turunan
y=f”(x)
Uji jenis
1
maximum : y” > 0
2
minimum : y” < 0
3
titik belok : y” = 0
Ilham Saifudin (TI)
KALKULUS
29th April 2018
16 / 17
Turunan
Aplikasi turunan
Aplikasi turunan
y=f”(x)
Uji jenis
1
maximum : y” > 0
2
minimum : y” < 0
3
titik belok : y” = 0
Ilham Saifudin (TI)
KALKULUS
29th April 2018
16 / 17
Turunan
Aplikasi turunan
Aplikasi turunan
y=f”(x)
Uji jenis
1
maximum : y” > 0
2
minimum : y” < 0
3
titik belok : y” = 0
Ilham Saifudin (TI)
KALKULUS
29th April 2018
16 / 17
Turunan
Aplikasi turunan
Aplikasi turunan
y=f”(x)
Uji jenis
1
maximum : y” > 0
2
minimum : y” < 0
3
titik belok : y” = 0
Ilham Saifudin (TI)
KALKULUS
29th April 2018
16 / 17
Turunan
Aplikasi turunan
Thank You
Ilham Saifudin (TI)
KALKULUS
29th April 2018
17 / 17