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CHAPTER IV RESULTS AND DISCUSSION
In this chapter, the results are presented in the form of data compiled from the activities. Additionally, the analysis of each activity from pre-test to post-test is
discussed.
4.1 Results
This research was conducted every Tuesday from 1:30 pm to 3:00 pm in the language and computer laboratory from October 19
th
2010 to November 16
th
2010. The Participants of the research were students in class XI Science of SMA Nasima, Semarang. The schedule of the study is displayed in the table below:
Table 4.1 Schedule of Research in SMA Nasima, Semarang No Activities
Dates 1
Pre-Test Tuesday, October 19
th
2010 2
Cycle 1 Activity 1
Tuesday, October 26
th
2010 Activity 2
Tuesday, November 2
nd
2010 3
Cycle 2 Activity 3
Tuesday, November 9
th
2010 Activity 4 Post test
Tuesday, November 16
th
2010
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The result of those activities can be seen in table below: Table 4.2 The Students’ Pre-test Result
No Students
Code Component of Writing Scoring
Score C
O V
LU M
1 A - 01
16 15
11 17
1 60
2 A - 02
17 16
14 18
2 67
3 A - 03
15 17
11 18
3 64
4 A - 04
15 15
11 16
1 58
5 A - 05
21 15
15 13
2 66
6 A - 06
15 16
11 15
2 59
7 A - 07
17 16
13 18
2 66
8 A - 08
16 16
15 17
2 66
9 A - 09
18 16
12 15
2 63
10 A - 10
20 15
14 16
2 67
11 A - 11
20 13
10 15
1 59
12 A - 12
21 17
16 17
2 73
13 A - 13
19 15
10 15
2 61
14 A - 14
17 14
14 17
2 64
15 A - 15
21 18
14 18
2 73
16 A - 16
17 16
17 17
2 69
17 A - 17
19 15
14 16
1 65
18 A - 18
21 17
16 17
2 73
19 A - 19
16 14
12 18
2 62
20 A - 20
16 15
14 15
1 61
21 A - 21
18 15
10 16
1 60
∑ 21
375 326 274 344 37 1356
Mean
17.85714 15.52381 13.04762 16.38095 1.761905 64.57143
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C = Content O = Organization
V = Vocabulary LU = Language Use
M = Mechanics In order to know the students’ pre-test achievement in details, the
following formula was used to find the average of the students’ achievement. The formula is the following:
The average score of pre-test = ∑Students’ Score X 100
∑ Students =
∑ 1426 X 100 ∑ 21
= 64. 571
The formula used for computing the mean was as follows: M =
∑x n
Where: M
: The mean ∑x
: The sum of the item scores, and n
: The number of the students.
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Table 4.3 The Result of the Students’ Achievement in the
First Cycle No
Students Code
Component of Writing Scoring Score
C O
V LU
M 1
A - 01 22
17 17
19 3
78 2
A - 02 27
18 18
18 3
84 3
A - 03 29
19 20
15 4
87 4
A - 04 14
18 15
15 2
64 5
A - 05 27
18 18
18 1
82 6
A - 06 26
18 18
18 1
81 7
A - 07 25
17 20
17 1
80 8
A - 08 27
18 18
21 4
88 9
A - 09 25
18 17
17 1
78 10
A - 10 27
17 17
21 1
83 11
A - 11 21
17 17
17 1
73 12
A - 12 14
19 17
17 1
68 13
A - 13 22
18 14
16 1
71 14
A - 14 27
18 17
18 2
82 15
A - 15 24
19 17
20 3
83 16
A - 16 29
19 17
22 2
89 17
A - 17 29
19 19
22 4
93 18
A - 18 28
18 17
20 2
85 19
A - 19 23
17 16
18 1
75 20
A - 20 26
17 17
20 1
81 21
A - 21 27
18 18
21 2
86 ∑ 22 519 377 364 390 41 1691
Mean 24.714 17.952
17.3333 18.571
1.95238 80.52381
The average score of the first cycle = ∑Students’ Score X 100
∑ Students
64
= ∑ 1691 X 100
∑ 21 = 80. 52
Table 4.4 The Result of the Students’ Achievement in the Second Cycle Post-test
No Students
Code Component of Writing Scoring
Score C
O V
LU M
1 A - 01
22 17
17 21
4 81
2 A - 02
27 18
18 20
4 87
3 A - 03
29 19
20 16
4 88
4 A - 04
14 18
15 17
2 66
5 A - 05
27 18
18 19
2 84
6 A - 06
26 18
18 19
2 83
7 A - 07
25 17
20 20
3 85
8 A - 08
27 18
18 22
5 90
9 A - 09
25 18
17 19
4 83
10 A - 10
27 17
17 21
2 84
11 A - 11
21 17
17 17
2 74
12 A - 12
14 19
17 17
1 68
13 A - 13
22 18
14 16
2 72
14 A - 14
27 18
17 18
4 84
15 A - 15
24 19
17 20
4 84
16 A - 16
29 19
17 23
4 92
17 A - 17
29 19
19 24
5 96
18 A - 18
28 18
17 21
3 87
19 A - 19
23 17
16 18
1 75
20 A - 20
26 17
17 20
1 81
21 A - 21
27 18
18 21
3 87
∑ 21 519 377 364 409 62 1731
Average Score 24.71428
17.95238 17.33333 19.47619
2.95238 82.42857
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The average score the third activity = ∑Students’ Score X 100
∑ Students
= ∑ 1731 X 100
∑ 21
= 82. 43
4.2 Discussion
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