e. both magnitude and direction needs

3 • Vector sum of all the forces acting on the object is called the net force.

i.e. both magnitude and direction needs

to be considered What is the net force on the car ? 4 Inertial Reference Frame Newton’s laws are valid in an inertial frame, i.e. the acceleration of the frame should be zero Constant Velocity . Ideally we do not have such a frame, but earth is a very good approximation. 5 Newton’s Second Law • First law: no net force no change in velocity • Second law: What happens if there is an external force? net Acceleration of the object Net Force Acceleration inversely proportional to mass  m 1  6 Only two factors determine the acceleration--- Force and Mass Force Units Newton N = kg. ms 2 What is 1 Newton ? m F a     ma F or 7 Newton’s Second Law Of Motion When a net external force acts on an object of mass m, the acceleration a results is directly proportional to the net force and has a magnitude that is inversely proportional to the mass. The direction of the acceleration is the same as the direction of the net force.  F     ma F or m F a SI Unit of Force: kg.ms 2 = newton N 8 Units for Mass, Acceleration Force System Mass Acceleration Force SI kilogramkg metersecond 2 ms 2 newtonN CGS gramg centimetersescond 2 cms 2 dynedyn BE slugsl footsecond 2 fts 2 poundlb 9 Frictional force = 560 N Push = 275 N+ 395 N = 670 N Net force = 670 N – 560 N, N= 110 N F = ma , 110 N = 1850 kg a a = 110 N1850 kg = 0.059 ms 2 what is the direction ? 10 Forces In 2-D F x = ma x F y = ma y Two forces are applied onto an object. 1. 12N towards North, and 2. 5N towards East, what is the direction of the motion of the object? tan θ = 125 =2.4 θ = tan -1 125 = 67.38 12N 5N θ Resultant force = 13 5 12 2 2   11 1300 kg raft P= Force by the man A= Force of wind In 65 seconds, where will the boat be if v 0x = 0.15 ms ? a a x = ?, a y = ? d 12 Force X- component Y- Component P 17 N 0 N A 15cos67 N 15sin67 N Resultant , 23 67 cos 15 17     N F x , 018 . 1300 23 2 s m kg N m F a x x         N F y 14 67 sin 15 2 011 . 1300 14 s m kg N m F a y y     13 Displacement Of The Boat In 65 sec y = v 0y t + ½ a y t 2 = 0 65 + ½ 0.011 65 2 = 23 m For x: v 0x = 0.15 ms, a x = 0.018 ms 2 t = 65 sec, x = ? x = v 0x t + ½a x t 2 = 0.15 65 +12 0.018 65 2 = 48 m For y: v 0y = 0, a y = 0.011 ms 2 , t = 65 sec 14 acceleration to be doubled ? a All of the forces acting on the object doubles b The net force acting on the object doubles c Both the net force and the mass doubles d The mass of the object is reduced by a factor of two.

a, b, d