a. Menghitung Panas Reaksi ∆Hr
1 Panas Reaksi Reduksi
Reaksi: SiO
2
+ 3 C SiC + 2 CO ……. 1
∆Hr
1
1600
o
C = ∆H
r o
1
+
1873 298
3 2
2
dT Cps
Cps Cpg
Cps
C SiO
CO SiC
r
1
= 54,5894 kmoljam ∆H
r o
1
= ∆H
r o
SiC
+ 2 ∆H
r o
CO
–∆H
r o
SiO2
– 3 ∆H
r o
C
= -117.230,4000 + 2 x -110.541,1580 - -851.385,7800
– 3 x 0 = 513.073,0640 Jmol
∆Hr
1
1600
o
C = ∆H
r o
1
+
1873 298
3 2
2
dT Cps
Cps Cpg
Cps
C SiO
CO SiC
= 513.073,0640 + -43.900,5072
= 469.172,5568 Jmol
2 Panas Reaksi Pembakaran Karbon Monooksida
Reaksi: CO +
2 1
O
2
CO
2
……. 2
r
2
= 109,1789 kmoljam ∆H
r o
2
= ∆H
r o
CO2
- ∆H
r o
CO
–
2 1
∆H
r o
O2
= -393504,7656 – -110541,1580 –
2 1
x 0 = -282.963,6076 Jmol
UNIVERSITAS SUMATERA UTARA
∆Hr
2
1600
o
C = ∆H
r o
2
+
1873 298
2 1
2 2
dT Cpg
Cpg Cpg
O CO
CO
= -282.963,6076 + 19.721,2229 =
-263.242,3847 Jmol
Maka, panas reaksi total
T Hr
r
i i
i
2
2
=
C Hr
r
i i
i 2
2
1600
= r
1
∆Hr
1
1600
o
C + r
2
∆Hr
2
1600
o
C = 21,9165 x 469172,5568 + 43,883 x -263242,3847
= -3.128.641,0432 kJjam
b. Menghitung Panas Masuk 1 Panas Masuk Alur 25
Panas masuk pada alur 27 Electric Furnace B-103 sama dengan panas keluar pada alur 25 Rotary Kiln Pre-heater B-102
Q
SiO2
= 2.671.355,9083 kJjam Q
C
= 1.673.793,8874 kJjam Q
FePO4
= 37.597,9135 kJjam Q
Na2O
= 58.688,3334 kJjam
2 Panas Masuk Alur 27
O
2
: Qi
O2
= N
27 O2
.
303 298
2
dT Cpg
O
= 8.070,0748 kJjam
N
2 :
Qi
N2
= N
27 N2
303 298
2
dT Cpg
N
= 38.384,7444 kJjam
UNIVERSITAS SUMATERA UTARA
∑ Qi = Q
25
+ Q
27
= 4.487.890,8619 kJjam
c. Menghitung Panas Keluar 1 Panas Keluar Alur 28
CO
2
: Qi
CO2
= N
28 CO2
.
1673 298
2
dT Cpg
CO
= 7.849.714,6188 kJjam
N
2 :
Qi
N2
= N
28 N2
1673 298
2
dT Cpg
N
= 24.705.031,1608 kJjam
2 Panas Keluar Alur 29
SiO
2
: Qo
SiO2
= N
29 SiO2
.
1873 298
2
dT Cp
SiO
= 255.595,3521 kJjam
C : Qo
C
= N
29 C
.
1873 298
dT Cp
C
= 237.645,8671 kJjam
FePO
4
: Qo
FePO4
= N
29 FePO4
.
1873 298
4
dT Cp
FePO
= 143.242,0035 kJjam
Na
2
O: Qo
Na
= N
29 Na2O
.
1873 298
2
dT Cp
O Na
= 219.255,9652 kJjam
UNIVERSITAS SUMATERA UTARA
SiC: Qo
SiC
= N
29 SiC
.
1873 298
2
dT Cp
SiO
= 4.198.999,2511 kJjam ∑ Qo
= Q
28
+ Q
29
= 37.609.484,2186 kJjam
dQdt =
T Hr
r
i i
i
2
2
+ Qo
– Qi = -3.128.641,0432 + 37.609.484,2186
– 4.487.890,8619 = 29.992.952,3136 kJjam
Tabel B.9 Neraca Panas pada Electric Furnace B-103
Komponen Masuk kJjam
Keluar kJjam H
25
H
27
H
28
H
29
SiO
2
2.671.355,9083 -
- 255.595,3521
C 1.673.793,8874
- -
237.645,8671 FePO
4
37.597,9135 -
- 143.242,0035
Na
2
O 58.688,3334
- -
219.255,9652 SiC
- -
- 41.98.999,2511
O
2
- 8.070,748
- -
N
2
- 38.384,7444 24.705.031,1608
- CO
2
- -
7.849.714,6188 -
Jumlah 4.441.436,0427 46.454,8192 32.554.745,7796 5.054.738,4390
Sub Total 4.487.890,8619
37.609.484,2186 ∆Hr
3.128.641,0432 -
Q 29.992.952,3136
- Total
37.609.484,2186 37.609.484,2186
UNIVERSITAS SUMATERA UTARA
B.2.6 Mixing Point M-102
a. Panas Masuk 1 Panas Masuk Alur 40 :
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