Menghitung Panas Masuk 1 Panas Alur 22 Menghitung Panas Keluar 1 Panas Alur 24

b. Menghitung Panas Masuk 1 Panas Alur 22

CH 4 : Qi CH4 = N 22 CH4 .  303 298 4 dT Cpg CH = 20,0320 kmoljam x 255,2257 Jmol = 5.112,6799 kJjam C 2 H 6 : Qi C2H6 = N 22 C2H6 .  303 298 6 2 dT Cpg H C = 1,6693 kmoljam x 265,8178 Jmol = 443,7384 kJjam C 3 H 8 : Qi C3H8 = N 22 C3H8 .  303 298 8 3 dT Cpg H C = 0,2782 kmoljam x 370,2066 Jmol = 102,9997 kJjam C 4 H 10 : Qi C4H10 = N 22 C4H10 .  303 298 1 0 4 dT Cpg H C = 0,2782 kmoljam x 490,6778 Jmol = 136,5174 kJjam 2 Panas Alur 23 O 2 : Qi O2 = N 23 O2 .  303 298 2 dT Cpg O = 33,1867 kmoljam x 147,2875 Jmol = 12.120,7192 kJjam N 2 : Qi N2 = N 23 N2 .  303 298 2 dT Cpg N = 309,5781 kmoljam x 167,6749 Jmol = 51.908,4869 kJjam UNIVERSITAS SUMATERA UTARA

c. Menghitung Panas Keluar 1 Panas Alur 24

O 2 : Qo O2 = N 24 O2 .  O T O dT Cpg 298 2 = 33,1867 kmoljam .  O T O dT Cpg 298 2 N 2 : Qo N2 = N 24 N2 .  O T N dT Cpg 298 2 = 309,5781 kmoljam .  O T N dT Cpg 298 2 CO 2 : Qo CO2 = N 24 CO2 .  O T CO dT Cpg 298 2 = 25,3182 kmoljam .  O T CO dT Cpg 298 2 H 2 O : Tekanan di alur 24 sebesar 1 atm = 101,325 kPa Titik didih air = 373 K ∆H VL373 = 2257,3 kJkg Reklaitis, 1983 = 2257,3 kJkg x 18,016 kgkmol = 40667,5168 Qo H2O = N 24 H2O .  O T O H dT Cp 298 2 = 47,5760 x              dT Cpv H dT Cpl O T O H VL O H 373 373 298 2 2 Asumsi tidak ada panas yang hilang selama pembakaran, sehingga dQdt = 0 dQdt =   C Hr r i i i 4 4 30    + Qo – Qi = -19.682.442,6006 kJjam + Qo – 69.825,1415 kJjam Qo = 19.752.267,7422 kJjam Qo = N 24 O2 .  O T O dT Cpg 298 2 + N 24 N2 .  O T N dT Cpg 298 2 + N 24 CO2 .  O T CO dT Cpg 298 2 UNIVERSITAS SUMATERA UTARA + N 24 SO2 .  o T SO dT Cpg 298 2 + N 24 H2O .  O T O H dT Cp 298 2 = 33,1867.  O T O dT Cpg 298 2 + 309,5781 .  O T N dT Cpg 298 2 + 25,3182.  O T CO dT Cpg 298 2 + 47,5760.              dT Cpv H dT Cpl O T O H VL O H 373 373 298 2 2 Dengan menggunakan Metode Newton-Rapshon pada program Matlab diperoleh suhu To = 1135,6570 = 1136 K = 863 C UNIVERSITAS SUMATERA UTARA Maka, O 2 : Qi O2 = N 24 O2 .  1136 298 2 dT Cpg O = 33,1867 kmoljam x 27.494,7093 Jmol = 912.458,6299 kJjam N 2 : Qi N2 = N 24 N2 .  1136 298 2 dT Cpg N = 309,5781 kmoljam x 49.501,7634 Jmol = 15.324.661,3469 kJjam CO 2 : Qi CO2 = N 24 CO2 .  1136 298 2 dT Cpg CO = 25,3182 kmoljam x 40.858,0236 Jmol = 1.034.452,2923 kJjam H 2 O : Qi H2O = N 24 H2O .  1136 298 2 dT Cp O H = 47,5760 kmoljam x              dT Cpv H dT Cpl O H VL O H 1136 373 373 298 2 2 = 47,5760 x 52.141,7527 Jmol = 2.480.695,4730 kJjam Tabel B.7 Neraca Energi pada Burner B-101 Komponen Masuk kJjam Keluar kJjam H 22 H 23 H 24 CH 4 5.112,6799 - - C 2 H 6 443,7384 - - C 3 H 8 102,9997 - - C 4 H 10 136,5174 - - O 2 - 12.120,7192 912.458,6299 N 2 - 51.908,4869 15.324.661,3469 UNIVERSITAS SUMATERA UTARA Tabel B. 7 Neraca Energi...... Lanjutan CO 2 - - 1.034.452,2923 H 2 O - - 2.480.695,4730 Jumlah 5.795.9355 64.029,2061 19.752.267,7422 Sub Total 69.825.1415 19.752.267,7422 ∆Hr 19.682.442.6006 - Q - - Total 19.752.267.7422 19.752.267,7422 B.2.4 Rotary Kiln Pre-Heater B-102 Fungsi: Pemanas awal bahan baku sampai suhu 617 C, sebelum dikirim ke Electric Furnace B-103

c. Menghitung Panas Masuk 1 Panas Alur 21