CHAPTER IV RESEARCH FINDINGS
D. Data Description
To know the result of the test, the writer makes the table of student’s score for each class as follows:
Table 4.1 The Test Scores of the Experimental Class Students
Student Score Student
Score Student
Score
1 80
16 80
31 92
2
66
17
88
32
92
3 70
18 84
33 84
4
54
19
60
34
84
5 84
20 92
35 72
6
76
21
96
36
80
7 72
22 88
37 92
8 84
23 88
38 88
9 80
24 84
39 84
10 56
25 84
40 88
11
80
26
72
41
92
12 84
27 84
42 72
13
84
28
84
43
84
14 88
29 80
44 80
15
88
30
80
45
82
Score f
92 – 96 87 – 91
82 – 86 77 – 81
72 – 76 67 – 71
62 – 66 57 – 61
52 - 56 6
7 14
8 5
2 1
2
45 = N
1
33
Table 4.2 The Test Scores of the Controlled Class Students
Student Score Student
Score Student
Score
1 60
16 80
31 88
2 52
17 78
32 88
3 70
18 78
33 80
4 68
19 66
34 80
5 76
20 84
35 80
6
74
21
88
36
74
7 82
22 76
37 80
8
76
23
84
38
72
9 76
24 74
39 80
10 76
25 88
40 86
11 88
26 80
41 80
12 88
27 84
42 80
13 84
28 76
43 80
14 84
29 72
44 80
15
80
30
84
Score f
92 – 96 87 – 91
82 – 86 77 – 81
72 – 76 67 – 71
62 – 66 57 – 61
52 - 56 6
8 14
11 2
1 1
1
44 = N
2
Table 4.3 The Result Calculation of Experimental Class
Score f
X x’ x’
2
fx’ fx’
2
92 – 96 6
+ 2 4
+ 12 24
87 – 91 7
+ 1 1
+ 7 7
82 – 86 14
M’ 84 77 – 81
8 - 1
1 - 8
8 72 – 76
5 - 2
4 - 10
20 67 – 71
2 - 3
9 - 6
18 62 – 66
- 4 16 57 – 61
1 - 5 25
- 5 25
52 - 56 2
- 6 36 - 12
72 45 = N
- -
- - 22 =
∑ fx’ 174 =
∑ fx’
2
Table 4.4 The Result Calculation of Controlled Class
Score f
Y y’ y’
2
fy’ fy’
2
92 – 96 + 3
9 87 – 91
6 + 2
4 + 12
24 82 – 86
8 + 1
1 + 8
8 77 – 81
14 M’ 79
72 – 76 11
- 1 1
- 11 11
67 – 71 2
- 2 4
- 4 8
62 – 66 1
- 3 9
- 3 9
57 – 61 1
- 4 16 - 4
16 52 - 56
1 - 5 25
- 5 25
44 = N -
- -
- 7 = ∑ fy’
101 = ∑ fy’
2
1. Determining Mean I with formula:
2. Determining Mean II with formula:
3. Determining of Standard of Deviation of Variable I:
N fx
i M
M
∑
+ =
1
45 22
5 84
− +
= 556
, 81
444 ,
2 84
= −
=
N fy
i M
M
∑
+ =
2
44 7
5 79
− +
= 205
, 78
795 ,
79 =
− =
N fx
N fx
i SD
2 2
1
∑ ∑
− =
2 2
45 22
45 174
5 −
− =
4. Determining of Standard Deviation of Variable II:
5. Determining of Standard Error Mean Variable I:
6. Determining of Standard Error Mean Variable II:
7. Determining Standard Error Mean Difference of M
1
and M
2
:
8. Determining t
o
with formula:
9. Determining t-table in significance level 5 and 1 with df:
The writer gained t table: S.L. 5 = 1,99
S.L. 1 = 2,63 10.
The Comparison between t-score with t-table t-score = 1,99 1,822 2,63
1
1 1
1
− =
N SD
SE
M
2 2
2 2
2 1
2 1
149 ,
1 436
, 1
+ =
+ =
− M
M M
M
SE SE
SE
2 1
2 1
M M
o
SE M
M t
−
− =
87 2
44 45
2 2
1 =
− +
= −
+ =
N N
df 1
45 525
, 9
− =
436 ,
1 =
320 ,
1 062
, 2
+ =
382 ,
3 =
839 ,
1 =
839 ,
1 205
, 78
556 ,
81 −
= 822
, 1
839 ,
1 351
, 3
= =
1
2 2
2
− =
N SD
SE
M
633 ,
6 525
, 9
=
1 44
535 ,
7 −
= 149
. 1
= 557
, 6
535 ,
7 =
525 ,
9 905
, 1
5 628
, 3
5 239
, 867
, 3
5 =
= =
− =
X
2 2
2 2
N fy
N fy
i SD
∑ ∑
− =
2 2
44 7
44 101
5 −
− =
535 ,
7 507
, 1
5 27
, 2
5 025
, 295
, 2
5 =
= =
− =
X
E. Test of Hypothesis