93
3.3 Perhitungan Stationing
Data-data tikungan: PI
– 1 : Circle – Circle Lc
1
= 131,62 m Tc
1
= 65,95 m PI
– 2 : Spiral – Circle – Spiral Ls
2
= 72 m Lc
2
= 155,61 m Tt
2
= 152,90 m PI
– 3 : Spiral – Circle – Spiral Ls
3
= 75 m Lc
3
= 202,61 m Tt
3
= 184,49 m PI
– 4 : Spiral – Circle – Spiral Ls
4
= 75 m Lc
4
= 246,61 m Tt
4
= 211,15 m d
A – 1
: 599,27 m d
1 – 2
: 693,49 m d
2 – 3
: 802,31 m d
3 – 4
: 619,29 m d
4 – B
: 653,85 m
94 STA A
= Sta 0+000 m STA PI
1
= Sta A + d
A – 1
= 0+000 + 599,27 = 0+599,27 m
STA TC
1
= Sta PI
1
– Tc
1
=0+599,27 – 65,95
= 0+533,32 m STA CT
1
= Sta TC
1
+ Lc
1
= 0+533,32 + 131,62 = 0+664,94 m
STA PI
2
= Sta CT
1
+ d
1-2
– Tc
1
= 0+664,94 + 693,49 – 65,95
= 1+292,48 m STA TS
2
= Sta PI
2
– Tt
2
=1+292,48 – 152,90
= 1+139,58 m STA SC
2
= Sta TS
2
+ Ls
2
= 1+139,58 + 72 = 1+211,58 m
STA CS
2
= Sta SC
2
+ Lc
2
= 1+211,58 + 155,61 = 1+367,19 m
STA ST
2
= Sta CS
2
+ Ls
2
= 1+367,19 + 72 = 1+439,19 m
95 STA PI
3
= Sta ST
2
+ d
2 – 3
–Tt
2
=1+439,19 + 802,31 – 152,90
= 2+088,60 m STA TS
3
= Sta PI
3
– Tt
3
=2+088,60 – 184,49
= 1+904,11 m STA SC
3
= Sta TS
3
+ Ls
3
= 1+904,11 + 75 = 1+979,11 m
STA CS
3
= Sta SC
3
+ Lc
3
= 1+979,11 + 202,61 = 2+181,72 m
STA ST
3
= Sta CS
3
+ Ls
3
= 2+181,72 + 75 = 2+256,72 m
STA PI
4
= Sta ST
3
+ d
3 – 4
–Tt
3
=2+256,72 + 619,29 – 184,49
= 2+691,52 m STA TS
4
= Sta PI
4
– Tt
4
=2+691,52 – 211,15
= 2+480,37m STA SC
4
= Sta TS
4
+ Ls
4
= 2+480,37 + 75 = 2+555,37 m
STA CS
4
= Sta SC
4
+ Lc
4
= 2+555,37 + 246,61 = 2+801,98 m
96
STA ST
4
= Sta CS
4
+ Ls
4
= 2+801,98 + 75 = 2+876,98 m
STA B = Sta ST
4
+ d
4 – B
–Tt
4
= 2+876,98 + 653,85 – 211,15
= 3+319,68 m ∑ d..........ok
= 3 + 320 m 3368 m
3.4 Kontrol Overlapping
Diketahui: Vrencana
= 80
km jam
= 3600
1000 80 x
= 22,222
m detik
Syarat overlapping:
d a Aman
d 66,67 m Aman m
ik V
a
ren
67 ,
66 666
, 66
3 222
, 22
det 3
97 Koordinat Titik :
A = 0 ; 0
PI
1
= 535 ; 270 PI
2
= 1105 ; 665 PI
3
= 1415 ; 1405 PI
4
= 1990 ; 1635 B
= 2165 ; 2265 Jembatan
1
= 1235 ; 975 Jembatan
2
= 2090 ; 1975
Jarak PI
2
– Jembatan
1
=
2 2
665 975
1105 1235
=
m 15
, 336
Jarak Jembatan
1
– PI
3
=
2 2
975 1405
1235 1415
=
m 15
, 466
Jarak PI
4
- Jembatan
2
=
2 2
1635 1975
1990 2090
=
m 40
, 354
Jarak Jembatan
2
– B =
2 2
1975 2265
2090 2165
=
m 99,54
2
STA Jembatan
1
= STA PI
2
+ Jarak PI
2
- Jembatan
1
= 1+292,48 + 336,51 = 1+628,99 m
STA Jembatan
2
= STA PI
4
+ Jarak PI
4
- Jembatan
2
= 2+691,52 + 354,40 = 3+045,92 m
98 Sehingga agar tidak over laping d
n
66,67 m 1. Awal proyek dengan PI
1
d
1
= STA PI
1
– STA A – Tc
1
= 599,27 – 0+000 – 65,95
= 533,32 m 66,67 m
Aman 2. PI
1
dengan PI
2
d
2
= STA TS
2
– STA CT
1
= 1+139,58 – 0+664,94
= 474,64 m 66,67 m
Aman 3. PI
2
dengan Jembatan
1
d
3
= Jarak PI
2
-jembatan 1 – ½ asumsi panjang jembatan – Tt
2
= 336,15 – ½ x 100 – 152,90
= 133,25 m 66,67 m
Aman 4. Jembatan
1
dengan PI
3
d
4
= Jarak jembatan 1- PI
3
– Tt
3
- ½ asumsi panjang jembatan = 466,15
– 184,49 – ½ x 100 = 231,66 m
66,67 m Aman
5. PI
3
dengan PI
4
d
5
= STA TS
4
– STA ST
3
= 2+480,37 – 2+256,72
= 223,65 m 66,67 m
Aman 6. PI
4
dengan Jembatan
2
d
6
= Jarak PI
4
-jembatan 2 – Tt
4
- ½ asumsi panjang jembatan = 354,40
– 211,15 – ½ x 100 = 93,25 m
66,67 m Aman
7. Jembatan
2
dengan B Akhir Proyek d
7
= Jarak jembatan 2- B – ½ panjang jembatan
= 299,54 – ½ x 100
= 249,54 m 66,67 m
Aman
99
B NGANOM
A DRONO
PI-1; PI-2; STA 1+292,48
ST; STA 2+876,98 CS;
SC; STA 2+801,98
STA 2+555,37 STA 2+480,37
TS;
SC; STA 1+979,11 STA 1+904,16
TS;
STA 1+139,58 TS;
SC; STA 1+211,58 CS; STA 2+181,72
CS; STA 1+367,19 ST; STA 2+876,98
ST; STA 1+439,19
STA 0+664,94 CT;
STA 0+533,32 TC;
STA 0+533,32 PI-3; STA 2+088,60
PI-4; STA 2+691,52
Gambar 3.11 Stasioning
100
STA B
STA A
PI-1 PI-2
PI-3
PI-4 ST
CS SC
TS ST
CS SC
TS
CS ST
SC TS
CT TC
d1 d2
d3 d4
d5
d ove rla
pin g 1
d ove rla
pin g 2
d ove rlap
ing 5
d ove
rla p
in g
7
d ov er
la pi
ng 6
d ove
rla p
in g
4
d ove
rla pi
ng 3
Gambar 3.12 Sket Overlaping
101
3.5 Perhitungan Alinemen Vertikal
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