Index of Difficulty Discriminating Power

36 880 . 106 50 50 930 22642 2 = − = S ⎟ ⎠ ⎞ ⎜ ⎝ ⎛ − ⎟ ⎠ ⎞ ⎜ ⎝ ⎛ − = 880 . 106 710 . 4 880 . 106 1 30 30 11 r 989 . = From the computation above, the writer got some results. First, the writer computed ∑pq The sum of the result p x q, the result was 4.71. s Standard deviation of the test, the result was 106.880. Then the writer took it into this formula, and the result was 0.989. In α = 5 with n = 40, so r table = 0,316 because r 11 r table , so that instruments is reliable.

4.1.3 Index of Difficulty

The index of difficulty level is generally expressed as the percentage of the students who answered the item correctly. The writer used this formula of index difficulty: P= JS B Where: P : index of difficulty B : number of the students who answered item correctly. JS : number of the students in a class. 37 Criteria ID interval Criteria 0.00 ID ≤ 0.30 0.30 ID ≤ 0.70 0.70 ID 1.00 difficult medium easy The computation item no.1 Upper group Lower group No code score No code score 1 UC-1 0 1 UC-21 2 UC-2 1 2 UC-22 3 UC-3 1 3 UC-23 1 4 UC-4 1 4 UC-24 1 5 UC-5 1 5 UC-25 1 6 UC-6 1 6 UC-26 1 7 UC-7 1 7 UC-27 1 8 UC-8 1 8 UC-28 1 9 UC-9 1 9 UC-29 1 10 UC-10 1 10 UC-30 1 11 UC-11 1 11 UC-31 12 UC-12 0 12 UC-32 13 UC-13 1 13 UC-33 1 14 UC-14 1 14 UC-34 1 15 UC-15 1 15 UC-35 1 16 UC-16 1 16 UC-36 1 17 UC-17 1 17 UC-37 1 18 UC-18 1 18 UC-38 1 19 UC-19 1 19 UC-39 1 20 UC-20 1 20 UC-40 total 18 total 15 825 , 40 15 18 = + = P From the computation above, the writer divided students in two groups. They were upper group was 18 and lower group was 15. Then the writer took it into this formula with counted up upper group and lower group and divided with number of students, the results was 0.825. 38 According the criteria above, so item no. 1 has difficulty level is easy.

4.1.4 Discriminating Power

The index of discriminating told us whether those students who performed well on the whole test tended to do well or unwell on each item in the test. Discriminating power can be obtained by using this following formula: Where: DP : Discriminating Power JB A : number of student in upper group who answered the item correctly JB B : number of student in lower group who answered the item incorrectly JS A : number of students in upper group. Criteria DP interval Criteria 0.00 DP ≤ 0.20 0.20 DP ≤ 0.40 0.40 DP ≤ 0.70 0.70 DP ≤ 1.00 poor satisfactory good excellent The computation item no.1: Upper group Lower group No code No code No code 1 UC-1 0 1 UC-21 2 UC-2 1 2 UC-22 3 UC-3 1 3 UC-23 1 4 UC-4 1 4 UC-24 1 5 UC-5 1 5 UC-25 1 6 UC-6 1 6 UC-26 1 A B A JS JB JB DP − = 39 7 UC-7 1 7 UC-27 1 8 UC-8 1 8 UC-28 1 9 UC-9 1 9 UC-29 1 10 UC-10 1 10 UC-30 1 11 UC-11 1 11 UC-31 12 UC-12 12 UC-32 13 UC-13 1 13 UC-33 1 14 UC-14 1 14 UC-34 1 15 UC-15 1 15 UC-35 1 16 UC-16 1 16 UC-36 1 17 UC-17 1 17 UC-37 1 18 UC-18 1 18 UC-38 1 19 UC-19 1 19 UC-39 1 20 UC-20 1 20 UC-40 total 18 Total 15 15 , 20 15 18 = − = DP From the computation above, the writer divided students in two groups. They were upper group was 18 and lower group was 15. Then the writer took it into this formula with subtract 15 from 18 and divided with number of students in upper group, the results was 0.825. According the criteria above, so item no. 1 has difficulty level is poor.

4.2 The Significant Difference of Pre Test Results