46 fingers, now, friend, pal, we’ll, and nice. They also could not differentiate to
pronounce “faith” and “fight”. They pronounced those two words similarly.
4. 4 T Test
This research used T-Test as a way to make comparison between pre test and post test. The comparison of the mean of T test was usefull in making a
decision about the treament that had been given by the researcher. The researcher did the T test for the pre test and post test’s result of those two groups.
4.4.1 T Test for Experimental Group
Table 4.12 T Test of “Beautiful Day” for Experimental Group No
Name of Students Pre Test
Post Test D
d
2
1 At
14 7
7 49
2 Al
10 3
7 49
3 Wl
12 3
9 81
4 An
8 4
4 16
5 Ant
9 5
4 16
6 Ar
12 4
8 64
7 Lr
11 2
9 81
8 Ba
10 6
4 16
9 Da
8 6
2 4
10 Ni
7 2
5 25
11 Dv
10 4
6 36
12 Zf
9 3
6 36
13 Fr
11 7
4 16
14 Fa
10 3
7 49
15 Nd
8 3
5 25
16 Sv
9 2
7 49
∑ 94
612
t = d - µd Sd√n
d =
∑
= = 5.87
47 Sd =
∑ ∑
= =
√ .
=√38.49 = 6.2
t = 5.87-0 6.2√16
= 5.871.55 = 3.78 Based on the result of the T test calculation, the T obtained was 3.78.
Moreover, the T critical for this test was 1.753. The T critical came from dfn-1 df16-1 df15 1.753 with 5 significance. It could be seen that T
obtained fell in Ha area. Based on the result, it could be concluded that there was significant different between pre test and post test for experimental group by using
“Beautiful Day” to increase the students’ ability in pronouncing English.
Table 4.13 T Test of “Promise” for Experimental Group No
Name of Students Pre Test
Post Test D
d
2
1 At
15 6
9 81
2 Al
11 3
8 64
3 Wl
10 7
3 9
4 An
16 6
10 100
5 Ant
13 7
6 36
6 Ar
12 4
8 64
7 Lr
11 3
8 64
8 Ba
10 3
7 49
9 Da
10 5
5 25
10 Ni
12 2
10 100
11 Dv
10 4
6 36
12 Zf
11 4
7 49
48
No Name of Students
Pre Test Post Test
D d
2
13 Fr
13 5
8 64
14 Fa
11 3
8 64
15 Nd
8 2
6 36
16 Sv
9 3
6 36
∑ 115
877
t = d - µd Sd√n
d =
∑
= = 7.18
Sd =
∑ ∑
=
=
√ .
=√3.36 = 1.83
t = 7.18-0 1.83√16
= 7.180.46 = 15.6
Based on the T test calculation above, it could be seen that the T obtained was 15.6. Moreover, the T critical for this test was 1.753. The T criticial was from
dfn-1 df 16-1 df 15 1.753 with 5 significance. We could infer that there was significant different between pre test and post test by using “Promise”
to increase students’ pronunciation because the T obtained fell in Ha area.
49
4.3.2 T Test for Control Group
Table 4.14 T Test of “Beautiful Day” for Control Group No
Name of Students Pre Test
Post Test D
d
2
1 If
10 12
-2 4
2 Jt
9 10
-1 1
3 Bu
11 11
4 Mr
12 12
1 1
5 Fk
11 10
1 1
6 Nk
8 8
7 Dn
8 9
-1 1
8 Na
7 7
9 Rg
11 11
10 Sd
8 8
11 Ft
9 9
12 Tr
10 9
1 1
13 Vi
8 8
14 Am
10 9
1 1
15 Yd
8 7
1 1
16 Di
9 8
1 1
∑ 2
12
t = d - µd Sd√n
d =
∑
= = 0.125
Sd =
∑ ∑
= =
√ .
=√0.78 = 0.88
t = 0.125-0 0.88√16
= 0.1250.22 = 0.57
50 Based on the result of the T test calculation on the previous page, the T
obtained was 0.57. Moreover, the T critical for this test was 1.753 which came from dfn-1 df 16-1df 151.753 with 5 significance. It could be seen
that there was no significant different between the result of pre test and post test because the T obtained fell in Ho area.
Table 4.15 T Test of “Promise” for Control Group No
Name of Students Pre Test
Post Test D
d
2
1 If
10 10
2 Jt
13 11
2 4
3 Bu
11 11
4 Mr
12 12
5 Fk
11 10
1 1
6 Nk
9 8
1 1
7 Dn
7 6
1 1
8 Na
10 9
1 1
9 Rg
9 9
10 Sd
9 10
-1 1
11 Ft
9 10
-1 1
12 Tr
10 10
13 Vi
13 12
1 1
14 Am
10 8
2 4
15 Yd
13 12
1 1
16 Di
9 8
1 1
∑ 9
17
t = d - µd Sd√n
d =
∑
= = 0.56
Sd =
∑ ∑
=
51 =
√ .
=√11.94 = 3.45
t = 0.56-0 3.45√16
= 0.560.86 = 0.65 Based on the T test result above, the value of T obtained was 0.65.
Moreover, the T critical for this test was 1.753 which came from dfn-1 df 16-1 df 15 1.753 with 5 significance. It could be seen that there was no
significant different between the result of the pre test and post test due to the T obtained fell in the Ho area.
4.5 Analysis
