Chart 1
The polygon describes the result of writing test obtained by the experimental and control group when pre-test Chart 1 shows the C were 60.66.
While the achievement of the control group, the student who got E were 06.06, the students who got D were 45,45 and the students who got C were 48.48,
and the students who got E were 6.06.
Chart 2
PRE TEST
0.00 0.00
0.00 0.00
60.61 48.48
33.33 45.45
6.06 6.06
0.00 10.00
20.00 30.00
40.00 50.00
60.00 70.00
A B
C D
E Experimental
Control
POST TEST
15.15 0.00
51.51 27.27
33.33 57.58
0.00 15.15
0.00 0.00
0.00 10.00
20.00 30.00
40.00 50.00
60.00
A A
B C
D Experimental
Control
Chart 2 shows the achievement of post-test obtained by the experimental group, the students who got A were 15.15; the students who got B were
51.51; the students who got C were 33.33. Post-test achievement of control group who got C, and D were 27.27, 57.58 and 15.15.
4. 3 The Difference Between the Two Means
The score of descriptive writing post-test in the experimental and control group are discussed here. The computation of the mean of experimental and
control group is follows :
Me =
=
= 82.33
The mean score of the experimental group was 82.33
∑
Xe N
2510 33
Where :
Me : the mean score of the experimental group,
Xe : the percentage score of the experimental group, and
N : the number of the subject sample.
Mc =
=
= 76.06 The mean score of the control group was 76.06
Where, Mc
: the mean score of the control group, Xc
: the percentage score of the control group, and N
: the number of the subject sample. The mean score of the control group was 76.06
The result shows that the experimental group out-performed the control group.
The difference between two means was 6.27.
4.4 T-test Result
To see the difference between the experimental and control group in scores, t-test was used :
∑
Xc N
2510 33
Where :
X
1
= the average score of the experimental group, X
2
= the average score of the control group, S
= standard deviation, ne
= the number of the students in the experimental group, and nc
= the number of the students in the control group.
First, we must find out the s by using the following formula:
Based on the formula, it was found : 33 - 1 28.9167 + 33 - 1 26.9962
S =
= 5.28739
√
33 + 33 – 2
After s was found, the next step was to find t x
1
– x
2
t = s 1 1
√
n
1
n
2
+
n
1
- 1
s
1
+ n
2
- 1s
2
s =
√
n
1
+ n
2
- 2
2 2
82.33 – 76.06 t =
= 4.816 5.28739 1 1
√
33 33
After the getting t-test result, then she consulted the critical value of the t- table to check whether the difference is significant or not. For
α = 5, and the numbers of student, 33 + 33 – 2 = 64, she found that t-table
0.95 64
= 2.00. Based on the computation she found that t-value 4.816 is higher than the critical value
of the table 4.816 2.00. It is proven that there is significance of difference between the experimental and control groups.
4.5 Discussion of the Research Findings
