Hirosawa’s counter-example Reissig

150 M. Reissig

4. Hirosawa’s counter-example

To end the proof of Theorem 8 we cite a result from [7] which explains that very fast oscillations have a deteriorating influence on C ∞ well-posedness. T HEOREM 9. [see [7]] Let ω : 0, 12] → 0, ∞ be a continuous, decreasing function satisfying lim ωs = ∞ for s → +0 and ωs2 ≤ c ωs for all s ∈ 0, 12]. Then there exists a function a ∈ C ∞ R \ {0} ∩ C R with the following properties: • 12 ≤ at ≤ 32 for all t ∈ R; • there exists a suitable positive T and to each p a positive constant C p such that |a p t | ≤ C p ω t 1 t ln 1 t p for all t ∈ 0, T ; • there exist two functions ϕ and ψ from C ∞ R such that the Cauchy problem u t t − atu x x = 0, u0, x = ϕx, u t 0, x = ψx, has no solution in C [0, r , D ′ R for all r 0. The coefficient a = at possesses the regularity a ∈ C ∞ R \ {0}. To attack the open problem 3 it is valuable to have a counter-example from [14] with lower regularity a ∈ C 2 R \ {0}. To understand this counter-example let us devote to the Cauchy problem u ss − b ln 1 s q 2 △ u = 0 , s, x ∈ 0, 1] × R n , 13 u1, x = ϕx, u s 1, x = ψx, x ∈ R n . Then the results of [14] imply the next statement. T HEOREM 10. Let us suppose that b = bs is a positive, 1-periodic, non-constant function belonging to C 2 . If q 2, then there exist data ϕ, ψ ∈ C ∞ R n such that 13 has no solution in C 2 [0, 1], D ′ R n . Proof. We divide the proof into several steps. Due to the cone of dependence property it is sufficient to prove H ∞ well-posedness. We will show that there exist positive real numbers s ξ = s|ξ| tending to 0 as |ξ| tends to infinity and data ϕ, ψ ∈ H ∞ R n such that with suitable positive constants C 1 , C 2 , and C 3 , |ξ| | ˆus ξ , ξ | + | ˆu s s ξ , ξ | ≥ C 1 |ξ| 1 2 expC 2 ln C 3 |ξ| γ . Here 1 γ q − 1. This estimate violates H ∞ well-posedness of the Cauchy problem 13. The assumption b ∈ C 2 guarantees that a unique solution u ∈ C 2 0, T ], H ∞ R n exists. Hyperbolic equations with non-Lipschitz coeffi cients 151 Step 1. Derivation of an auxiliary Cauchy problem After partial Fourier transformation we get from 13 v ss + b ln 1 s q 2 |ξ| 2 v = 0 , s, ξ ∈ 0, 1] × R n , v 1, ξ = ˆϕξ , v s 1, ξ = ˆ ψ ξ , ξ ∈ R n , where vs, ξ = ˆus, ξ. Let us define w = wt, ξ := τ t 1 2 v st, ξ , where t = t s : = ln 1 s q , τ = τ t := − dt ds st and s = st denotes the inverse function to t = t s. Then w is a solution to the Cauchy problem w t t + bt 2 λ t, ξ w = 0 , t, ξ ∈ [t 1, ∞ × R n , w t 1, ξ = τ t 1 1 2 ˆϕξ , w t t 1, ξ = τ t 1 − 1 2 1 2 τ t t 1 ˆϕξ − ˆ ψ ξ , where λ = λt, ξ = λ 1 t, ξ + λ 2 t, and λ 1 t, ξ = |ξ| 2 τ t 2 , λ 2 t = θ t bt 2 τ t 2 , θ = τ ′2 − 2τ ′′ τ . Simple calculations show that τ t = q t q−1 q expt 1 q and θ t ≈ − exp2t 1 q . Hence, lim t →∞ λ 2 t = 0. Let λ be a positive real number, and let us define t ξ = t ξ λ by the definition λt ξ , ξ = λ . It follows from previous calculations that lim |ξ |→∞ t ξ = ∞. Using the mean value theorem we can prove the following result. L EMMA 7. There exist positive constants C and δ such that |λ 1 t, ξ − λ 1 t − d, ξ| ≤ C d τ ′ t τ t λ 1 t, ξ , |λ 2 t − λ 2 t − d| ≤ C τ ′ t τ t for any 0 ≤ d ≤ δ τ t τ ′ t . In particular, we have |λt ξ , ξ − λt ξ − d, ξ| ≤ Cd τ ′ t ξ τ t ξ λ t ξ , ξ , 1 ≤ d ≤ δ τ t ξ τ ′ t ξ . We have the hope that properties of solutions of w t t + bt 2 λ t, ξ w = 0 are not “far away” from properties of solutions of w t t + bt 2 λ t ξ , ξ w = 0. For this reason let us study the ordinary differential equation w t t + λ bt 2 w = 0. Step 2. Application of Floquet’s theory We are interested in the fundamental solution X = X t, t as the solution to the Cauchy problem d dt X = −λ bt 2 1 X , X t , t = 1 1 . 14 It is clear that X t + 1, t is independent of t ∈ N. 152 M. Reissig L EMMA 8 F LOQUET ’ S THEORY . Let b = bt ∈ C 2 , 1-periodic, positive and non-constant. Then there exists a positive real number λ such that λ belongs to an interval of instability for w t t + λ bt 2 w = 0, that is, X t + 1, t has eigenvalues µ and µ −1 satisfying |µ | 1. Let us define for t ξ ∈ N the matrix X t ξ + 1, t ξ = x 11 x 12 x 21 x 22 . According to Lemma 8 the eigenvalues of this matrix are µ and µ −1 . We suppose |x 11 − µ | ≥ 1 2 |µ − µ −1 | . 15 Then we have |x 22 − µ −1 | ≥ 1 2 |µ − µ −1 |, too. Step 3. A family of auxiliary problems For every non-negative integer n we shall consider the equation w t t + λt ξ − n + t, ξbt ξ + t 2 w = 0. 16 It can be written as a first-order system which has the fundamental matrix X n = X n t, t solving the Cauchy problem d t X = A n X , X t , t = I 17 A n = A n t, ξ = −λt ξ − n + t, ξbt ξ + t 2 1 . L EMMA 9. There exist positive constants C and δ such that max t 2 , t 1 ∈[0,1] kX n t 2 , t 1 k ≤ e C λ for 0 ≤ n ≤ δ τ t ξ τ ′ t ξ and t ξ large. Proof. The fundamental matrix X n has the following representation: X n t 2 , t 1 = I + ∞ X j =1 t 2 Z t 1 A n r 1 , ξ r 1 Z t 1 A n r 2 , ξ · · · r j −1 Z t 1 A n r j , ξ dr j · · · dr 1 . By Lemma 7 we have max t 2 , t 1 ∈[0,1] kX n t 2 , t 1 k ≤ exp1 + b 2 1 λ 1 t ξ − n, ξ + sup t 1 ≤t |λ 2 t | = exp1 + b 2 1 λ 1 t ξ − n, ξ − λ 1 t ξ , ξ + λ − λ 2 t ξ + sup t 1 ≤t |λ 2 t | ≤ e C λ Hyperbolic equations with non-Lipschitz coeffi cients 153 for large t ξ , ≤ n ≤ δ τ t ξ τ ′ t ξ , where b 1 = max [0,1] bt. L EMMA 10. Let η = ηt be a function satisfying lim t →∞ η t τ ′ t τ t = 0 . 18 Then there exist constants C and δ such that kX n 1, 0 − X t ξ + 1, t ξ k ≤ C λ η t ξ τ ′ t ξ τ t ξ for 0 ≤ n ≤ δ ηt ξ . Consequently, kX n 1, 0 − X t ξ + 1, t ξ k ≤ ε for any given ε 0, sufficiently large t ξ ∈ N and 0 ≤ n ≤ δ ηt ξ . Proof. Using the representation of X n 1, 0 and of X t ξ + 1, t ξ , then the application of Lemma 7 to kX n 1, 0 − X t ξ + 1, t ξ k gives kX n 1, 0 − X t ξ + 1, t ξ k ≤ C λ n + 1 τ ′ t ξ τ t ξ expC λ n + 1 τ ′ t ξ τ t ξ ≤ C λ δ η t ξ + 1 τ ′ t ξ τ t ξ expC λ δ η t ξ + 1 τ ′ t ξ τ t ξ → 0 for t ξ → ∞ and 1 ≤ n ≤ δ ηt ξ . Repeating the proofs of Lemmas 9 and 10 gives the following result. L EMMA 11. There exist positive constants C and δ such that kX n +1 1, 0 − X n 1, 0 k ≤ C λ τ ′ t ξ − n τ t ξ − n for 1 ≤ n ≤ δ ηt ξ and large ξ . We will later choose η = ηt ∼ t α with α ∈ 1 2 , q −1 q . That the interval is non-empty follows from the assumptions of our theorem. If we denote X n 1, 0 = x 11 n x 12 n x 21 n x 22 n , then the statements of Lemmas 8 and 10 imply • |µ n − µ | ≤ ε, where µ n and µ −1 n are the eigenvalues of X n 1, 0; • |µ n | ≥ 1 + ε for ε ≤ |µ | − 12; • |x 11 n − µ n | ≥ 1 4 |µ − µ −1 | , |x 22 n − µ −1 n | ≥ 1 4 |µ − µ −1 |. From Lemma 11 we conclude • |x i j n + 1 − x i j n | ≤ C λ τ ′ t ξ −n τ t ξ −n . This implies 154 M. Reissig • |µ n +1 − µ n | ≤ C λ τ ′ t ξ −n τ t ξ −n . Step 4. An energy estimate from below L EMMA 12. Let n satisfy 0 ≤ n ≤ δ ηt ξ ≤ n + 1. Then there exist positive constants C and C 1 such that the solution w = wt, ξ to w t t + bt 2 λ t, ξ w = 0, w t ξ − n − 1, ξ = 1 , w t t ξ − n − 1, ξ = x 12 n µ n − x 11 n satisfies |wt ξ , ξ | + |w t t ξ , ξ | ≥ C expC 1 η t ξ 19 for large ξ and η = ηt fulfilling 18. Proof. The function w = wt ξ − n + t, ξ satisfies 16 with n = n . It follows that d dt w t ξ , ξ w t ξ , ξ = X 1 1, 0X 2 1, 0 · · · · · · X n −1 1, 0X n 1, 0 d dt w t ξ − n , ξ w t ξ − n , ξ . The matrix B n = x 12 n µ n −x 11 n 1 1 x 21 n µ − 1 n −x 22 n is a diagonalizer for X n 1, 0, that is, X n 1, 0B n = B n diag µ n , µ −1 n . Since det X n 1, 0 = 1 and trace of X n 1, 0 is µ n + µ −1 n we get det B n = µ n −µ − 1 n µ − 1 n −x 22 n . Us- ing the properties of µ n from the previous step we conclude | det B n | ≥ C 0 for all 0 n ≤ δ ηt ξ . Moreover, by Lemma 9 we have |x i j n | ≤ C , kB n k + kB −1 n k ≤ C for all 0 n ≤ δ ηt ξ . All constants C are independent of n. These estimates lead to kB −1 n −1 B n − I k = kB −1 n −1 B n − B n −1 k ≤ C λ τ ′ t ξ − n τ t ξ − n 20 Hyperbolic equations with non-Lipschitz coeffi cients 155 for large t ξ . If we denote G n : = B −1 n −1 B n − I , then we can write X 1 1, 0X 2 1, 0 · · · X n −1 1, 0X n 1, 0 = B 1 µ 1 µ −1 1 B −1 1 B 2 µ 2 µ −1 2 B −1 2 B 3 · · · B −1 n −1 B n µ n µ −1 n B −1 n = B 1 µ 1 µ −1 1 I + G 2 µ 2 µ −1 2 I + G 3 · · · I + G n µ n µ −1 n B −1 n . We shall show that the 1, 1 element y 11 of the matrix µ 1 µ −1 1 I + G 2 µ 2 µ −1 2 I + G 3 · · · · · · I + G n µ n µ −1 n can be estimated with suitable positive constants C and C 1 by C expC 1 η t ξ . It is evident from 20 that |y 11 − n Y n =1 µ n | ≤ C n Y n =1 |µ n | n X n =1 τ ′ t ξ − n τ t ξ − n for large t ξ . We have n X n =1 τ ′ t ξ − n τ t ξ − n ≤ δ η t ξ Z τ ′ t ξ − t − 1 τ t ξ − t − 1 dt ≤ ln τ t ξ − 1 τ t ξ − δ ηt ξ − 1 ≤ ln 1 − δ ηt ξ τ ′ t ξ − 1 τ t ξ − 1 −1 → 0 as t ξ → ∞ . Hence, we can find a positive real ν such that |y 11 | ≥ 1 − ν n Y n =1 |µ n | ≥ 1 − νµ − ε n ≥ 1 − νµ − ε δ η t ξ −1 . The vector of data on t = t ξ − n is an eigenvector of B n . Thus the estimate for y 11 holds for the vector d t w t ξ , ξ , w t ξ , ξ T too. This proves the energy estimate from below of the lemma. 156 M. Reissig Step 5. Conclusion After choosing s ξ = st ξ = exp−t 1q ξ for large t ξ and taking account of w t t, ξ = 1 2 τ t tτ t − 1 2 v st, ξ + τ t 1 2 v s st, ξ we obtain |wt s, ξ| + |w t t s, ξ | ≤ τ t s 1 2 1 + τ t t s 2τ t s |vs, ξ| + τ t s − 1 2 |v s s, ξ | ≤ 2τ t s 1 2 |vs, ξ| + τ t s − 1 2 |v s s, ξ | for large ξ . Finally, we use τ t s ∼ |ξ|. This follows from the definition λt ξ , ξ = λ and lim t ξ →∞ λ 2 t ξ = 0. Thus we have shown |ξ| | ˆus ξ , ξ | + | ˆu s s ξ , ξ | ≥ C 1 |ξ| 1 2 expC 2 η t ξ . The function ηt = t α satisfies 18 if α q −1 q . The function t ξ behaves as ln |ξ| q . Together these relations give |ξ| | ˆus ξ , ξ | + | ˆu s s ξ , ξ | ≥ C 1 |ξ| 1 2 expC 2 ln |ξ| qα ≥ C 1 |ξ| 1 2 expC 2 ln |ξ| γ , where γ ∈ 1, q − 1 . From this inequality we conclude the statement of Theorem 10. R EMARK 6. The idea to apply Floquet’s theory to construct a counter-example goes back to [25] to study C ∞ well-posedness for weakly hyperbolic equations. This idea was employed in connection to L p − L q decay estimates for solutions of wave equations with time-dependent coefficients in [24]. The merit of [14] is the application of Floquet’s theory to strictly hyperbolic Cauchy problems with non-Lipschitz coef- ficients. We underline that the assumed regularity b ∈ C 2 comes from statements of Floquet’s theory itself. An attempt to consider non-Lipschitz theory, weakly hyperbolic theory and theory of L p − L q decay estimates for solutions of wave equations with a time-dependent coefficient is presented in [23].

5. How to weaken C