Based on the table 4.4, the result showed that the T
count
of experimental class reached 0.20 and the controlled class reached 0.19. Moreover, both of the
results of Tcount were smaller than T
tabel,
T
count
T
tabel
, 0.20 0.30 and 0.19 0.30. It calculated with the degree of significance 0.05. It meant Null Hypothesis
H was accepted that indicated both of the data were in normal distribution.
2. Homogeneity Test a. Homogeneity Test of Pre-Test
The homogeneity test was used to know whether the group sample of the population was homogeneous or not. It was calculated based on the formula
below: Variance of Pre-Test of experimental Class:
S X
n S
90499 19
1293 19
= 4763.10 – 4631.16 = 139.27
Variance of Pre-Test of Controlled class: S
y n
S 99636
19 1364
19 = 5244 – 5153.72
= 95.28 Homogeneity Test of Pre-Test
F
F
. .
= 1.46
Table 4.5 The Result of Homogeneity Pre -Test
No. Class
Variance N
F
count
F
table
Criteria
1 Experimental
139.27 19
1.46 2.27
Homogeneous 2
Controlled 95.28
19
The assumption of the homogeneity value was: H
: the data was in a homogeneous variance, F
1-αn1-1
F F
count
H
1
: the data was not in a homogeneous variance, F ≥ F
count
Based on the table 4.5, it showed that F
count
was smaller than F
table
with degree of significance 0.05 which was F
count
F
table
1.46 2.27. It meant H was
accepted, or in another word the data of pre-test of both sample was homogenous.
b. Homogeneity Test of Post-Test
The homogeneity test was used to find out whether the sample comes from the homogeneous variance or not. The data will be calculated by the formula
below: The variance of the experimental class’ post-test:
S X
n S
90394 19
1294 19
= 4757.57 – 4638.32 = 125.87
The variance of the controlled class’ post-test:
S y
n S
93302 19
1322 19
= 4910.63 – 4841.22 = 73.25
Homogeneity Test of Post-Test
F
count
F
. .
= 1.71
Table 4.6 The Result of Homogeneity Test of Post-Test
No. Class
Variance N
F
count
F
table
Criteria 1
Experimental 125.87
19 1.71
2.27 Homogeneo
us 2
Controlled 73.25
19
The assumption was: H
: the data was in a homogeneous variance, F
1-αn1-1
F F
count
H
1
: the data was not in a homogeneous variance, F ≥ F
count
Based on the table 4.6, it pointed out that the variance S
2
of the experimental class was 125.87, while the variance S
2
of the controlled class was 73.25. In addition, the F
count
of both samples was 1.71 while the F
table
was 2.27 which was gained from the table of F table. The result of the statistic calculation
was F
count
F
table
, = 1.71 2.27. So, it concluded that both of the data, the experimental class and the controlled class, was from homogeneous variance.
Moreover, since the data were from the normal distribution and the homogeneous variance, so the next calculation was using statistical parametric
